Theorems in the form of “if and only if” such that the proof of one direction is extremely EASY to prove...
I believe this is a common phenomenon in mathematics, but surprisingly, no such list has been created on this site. I don't know if it's of value, just out of curiosity, I want to see more examples. So my request is:
Theorems in the form of "if and only if" that the proof of one direction is extremely EASY, or intuitive, or make use of some standard techniques (e.g. diagram chasing), while the other one is extremely HARD, or counterintuitive, or require a certain amount of creativity. The contrast should be as apparent as possible.
Thanks in advance.
soft-question big-list
asked 2 hours ago
YuiTo ChengYuiTo Cheng
154112
add a comment |
I believe this is a common phenomenon in mathematics, but surprisingly, no such list has been created on this site. I don't know if it's of value, just out of curiosity, I want to see more examples. So my request is:
Theorems in the form of "if and only if" that the proof of one direction is extremely EASY, or intuitive, or make use of some standard techniques (e.g. diagram chasing), while the other one is extremely HARD, or counterintuitive, or require a certain amount of creativity. The contrast should be as apparent as possible.
Thanks in advance.
soft-question big-list
asked 2 hours ago
YuiTo ChengYuiTo Cheng
154112
One of my college professors likened this phenomenon to running one's palm along one's face. Down is easy; up is not.
– Blue
2 hours ago
1
That's a good metaphor!
– YuiTo Cheng
2 hours ago
2
The reason nobody has created such a list may be the fact that most (nontrivial) "iff" theorems belong on your list. It would be more interesting to see a list of "iff" theorems where both directions are nontrivial.
– bof
1 hour ago
@bof I've mentioned I don't know if this question is of any value. I just think this phenomenon is intriguing, and want to know more of that nature.
– YuiTo Cheng
1 hour ago
add a comment |
I believe this is a common phenomenon in mathematics, but surprisingly, no such list has been created on this site. I don't know if it's of value, just out of curiosity, I want to see more examples. So my request is:
Theorems in the form of "if and only if" that the proof of one direction is extremely EASY, or intuitive, or make use of some standard techniques (e.g. diagram chasing), while the other one is extremely HARD, or counterintuitive, or require a certain amount of creativity. The contrast should be as apparent as possible.
Thanks in advance.
soft-question big-list
asked 2 hours ago
YuiTo ChengYuiTo Cheng
154112
I believe this is a common phenomenon in mathematics, but surprisingly, no such list has been created on this site. I don't know if it's of value, just out of curiosity, I want to see more examples. So my request is:
Theorems in the form of "if and only if" that the proof of one direction is extremely EASY, or intuitive, or make use of some standard techniques (e.g. diagram chasing), while the other one is extremely HARD, or counterintuitive, or require a certain amount of creativity. The contrast should be as apparent as possible.
Thanks in advance.
soft-question big-list
soft-question big-list
asked 2 hours ago
YuiTo ChengYuiTo Cheng
154112
asked 2 hours ago
YuiTo ChengYuiTo Cheng
154112
asked 2 hours ago
YuiTo ChengYuiTo Cheng
154112
asked 2 hours ago
YuiTo ChengYuiTo Cheng
154112
asked 2 hours ago
YuiTo ChengYuiTo Cheng
154112
154112
One of my college professors likened this phenomenon to running one's palm along one's face. Down is easy; up is not.
– Blue
2 hours ago
1
That's a good metaphor!
– YuiTo Cheng
2 hours ago
2
The reason nobody has created such a list may be the fact that most (nontrivial) "iff" theorems belong on your list. It would be more interesting to see a list of "iff" theorems where both directions are nontrivial.
– bof
1 hour ago
@bof I've mentioned I don't know if this question is of any value. I just think this phenomenon is intriguing, and want to know more of that nature.
– YuiTo Cheng
1 hour ago
add a comment |
One of my college professors likened this phenomenon to running one's palm along one's face. Down is easy; up is not.
– Blue
2 hours ago
1
That's a good metaphor!
– YuiTo Cheng
2 hours ago
2
The reason nobody has created such a list may be the fact that most (nontrivial) "iff" theorems belong on your list. It would be more interesting to see a list of "iff" theorems where both directions are nontrivial.
– bof
1 hour ago
@bof I've mentioned I don't know if this question is of any value. I just think this phenomenon is intriguing, and want to know more of that nature.
– YuiTo Cheng
1 hour ago
One of my college professors likened this phenomenon to running one's palm along one's face. Down is easy; up is not.
– Blue
2 hours ago
One of my college professors likened this phenomenon to running one's palm along one's face. Down is easy; up is not.
– Blue
2 hours ago
1
1
That's a good metaphor!
– YuiTo Cheng
2 hours ago
That's a good metaphor!
– YuiTo Cheng
2 hours ago
2
2
The reason nobody has created such a list may be the fact that most (nontrivial) "iff" theorems belong on your list. It would be more interesting to see a list of "iff" theorems where both directions are nontrivial.
– bof
1 hour ago
The reason nobody has created such a list may be the fact that most (nontrivial) "iff" theorems belong on your list. It would be more interesting to see a list of "iff" theorems where both directions are nontrivial.
– bof
1 hour ago
@bof I've mentioned I don't know if this question is of any value. I just think this phenomenon is intriguing, and want to know more of that nature.
– YuiTo Cheng
1 hour ago
@bof I've mentioned I don't know if this question is of any value. I just think this phenomenon is intriguing, and want to know more of that nature.
– YuiTo Cheng
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
"A compact 3-manifold is simply-connected if and only if it is homeomorphic to the 3-sphere."
One direction [only if] is the Poincaré conjecture. The other direction shouldn't be too bad hopefully.
answered 2 hours ago
Alvin JinAlvin Jin
2,127918
add a comment |
The bisectors of two angles of a triangle are of equal length if and only if the two bisected angles are equal. If the two angles are equal, the triangle is isosceles and the proof is very easy. However proving that a triangle must be isosceles if the bisectors of two of its angles are of equal length seems to be quite difficult.
answered 26 mins ago
lonza leggieralonza leggiera
1534
New contributor
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
The product of topological spaces is compact if and only if all of them are compact. One direction is trivial because the projections are continuous and surjective functions. The another direction, well, is the axiom of choice.
answered 49 mins ago
Carlos JiménezCarlos Jiménez
2,3551519
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
"A compact 3-manifold is simply-connected if and only if it is homeomorphic to the 3-sphere."
One direction [only if] is the Poincaré conjecture. The other direction shouldn't be too bad hopefully.
answered 2 hours ago
Alvin JinAlvin Jin
2,127918
add a comment |
"A compact 3-manifold is simply-connected if and only if it is homeomorphic to the 3-sphere."
One direction [only if] is the Poincaré conjecture. The other direction shouldn't be too bad hopefully.
answered 2 hours ago
Alvin JinAlvin Jin
2,127918
add a comment |
"A compact 3-manifold is simply-connected if and only if it is homeomorphic to the 3-sphere."
One direction [only if] is the Poincaré conjecture. The other direction shouldn't be too bad hopefully.
answered 2 hours ago
Alvin JinAlvin Jin
2,127918
"A compact 3-manifold is simply-connected if and only if it is homeomorphic to the 3-sphere."
One direction [only if] is the Poincaré conjecture. The other direction shouldn't be too bad hopefully.
answered 2 hours ago
Alvin JinAlvin Jin
2,127918
answered 2 hours ago
Alvin JinAlvin Jin
2,127918
answered 2 hours ago
Alvin JinAlvin Jin
2,127918
answered 2 hours ago
Alvin JinAlvin Jin
2,127918
2,127918
add a comment |
add a comment |
The bisectors of two angles of a triangle are of equal length if and only if the two bisected angles are equal. If the two angles are equal, the triangle is isosceles and the proof is very easy. However proving that a triangle must be isosceles if the bisectors of two of its angles are of equal length seems to be quite difficult.
answered 26 mins ago
lonza leggieralonza leggiera
1534
New contributor
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
The bisectors of two angles of a triangle are of equal length if and only if the two bisected angles are equal. If the two angles are equal, the triangle is isosceles and the proof is very easy. However proving that a triangle must be isosceles if the bisectors of two of its angles are of equal length seems to be quite difficult.
answered 26 mins ago
lonza leggieralonza leggiera
1534
New contributor
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
The bisectors of two angles of a triangle are of equal length if and only if the two bisected angles are equal. If the two angles are equal, the triangle is isosceles and the proof is very easy. However proving that a triangle must be isosceles if the bisectors of two of its angles are of equal length seems to be quite difficult.
answered 26 mins ago
lonza leggieralonza leggiera
1534
New contributor
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
The bisectors of two angles of a triangle are of equal length if and only if the two bisected angles are equal. If the two angles are equal, the triangle is isosceles and the proof is very easy. However proving that a triangle must be isosceles if the bisectors of two of its angles are of equal length seems to be quite difficult.
answered 26 mins ago
lonza leggieralonza leggiera
1534
New contributor
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 26 mins ago
lonza leggieralonza leggiera
1534
New contributor
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 26 mins ago
lonza leggieralonza leggiera
1534
answered 26 mins ago
lonza leggieralonza leggiera
1534
1534
New contributor
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
lonza leggiera is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
The product of topological spaces is compact if and only if all of them are compact. One direction is trivial because the projections are continuous and surjective functions. The another direction, well, is the axiom of choice.
answered 49 mins ago
Carlos JiménezCarlos Jiménez
2,3551519
add a comment |
The product of topological spaces is compact if and only if all of them are compact. One direction is trivial because the projections are continuous and surjective functions. The another direction, well, is the axiom of choice.
answered 49 mins ago
Carlos JiménezCarlos Jiménez
2,3551519
add a comment |
The product of topological spaces is compact if and only if all of them are compact. One direction is trivial because the projections are continuous and surjective functions. The another direction, well, is the axiom of choice.
answered 49 mins ago
Carlos JiménezCarlos Jiménez
2,3551519
The product of topological spaces is compact if and only if all of them are compact. One direction is trivial because the projections are continuous and surjective functions. The another direction, well, is the axiom of choice.
answered 49 mins ago
Carlos JiménezCarlos Jiménez
2,3551519
answered 49 mins ago
Carlos JiménezCarlos Jiménez
2,3551519
answered 49 mins ago
Carlos JiménezCarlos Jiménez
2,3551519
answered 49 mins ago
Carlos JiménezCarlos Jiménez
2,3551519
2,3551519
add a comment |
add a comment |
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One of my college professors likened this phenomenon to running one's palm along one's face. Down is easy; up is not.
– Blue
2 hours ago
1
That's a good metaphor!
– YuiTo Cheng
2 hours ago
2
The reason nobody has created such a list may be the fact that most (nontrivial) "iff" theorems belong on your list. It would be more interesting to see a list of "iff" theorems where both directions are nontrivial.
– bof
1 hour ago
@bof I've mentioned I don't know if this question is of any value. I just think this phenomenon is intriguing, and want to know more of that nature.
– YuiTo Cheng
1 hour ago