How to sed chunks text from a stream of files from find












2















I have a directory of many *.org files. I want to select a section of text out of all these org files.
There is a * Learnings header in the content. I would like to select from the * Learnings header to the end of the file.



My current attempt is



find ~/org/journal -name "*.org" -type f | xargs sed -n -e '/* Learnings/,$p'


This however just outputs one concatenated stream.



Expected output would be a stream of the content after the * Learnings header for each file returned from the find



also the solution does not have to use sed






sed find xargs







share|improve this question

























  • What output do you expect/need?

    – choroba
    Mar 30 at 18:50











  • @choroba added expected output

    – kevzettler
    Mar 30 at 21:08
















2















I have a directory of many *.org files. I want to select a section of text out of all these org files.
There is a * Learnings header in the content. I would like to select from the * Learnings header to the end of the file.



My current attempt is



find ~/org/journal -name "*.org" -type f | xargs sed -n -e '/* Learnings/,$p'


This however just outputs one concatenated stream.



Expected output would be a stream of the content after the * Learnings header for each file returned from the find



also the solution does not have to use sed






sed find xargs







share|improve this question

























  • What output do you expect/need?

    – choroba
    Mar 30 at 18:50











  • @choroba added expected output

    – kevzettler
    Mar 30 at 21:08














2












2








2








I have a directory of many *.org files. I want to select a section of text out of all these org files.
There is a * Learnings header in the content. I would like to select from the * Learnings header to the end of the file.



My current attempt is



find ~/org/journal -name "*.org" -type f | xargs sed -n -e '/* Learnings/,$p'


This however just outputs one concatenated stream.



Expected output would be a stream of the content after the * Learnings header for each file returned from the find



also the solution does not have to use sed






sed find xargs







share|improve this question
















I have a directory of many *.org files. I want to select a section of text out of all these org files.
There is a * Learnings header in the content. I would like to select from the * Learnings header to the end of the file.



My current attempt is



find ~/org/journal -name "*.org" -type f | xargs sed -n -e '/* Learnings/,$p'


This however just outputs one concatenated stream.



Expected output would be a stream of the content after the * Learnings header for each file returned from the find



also the solution does not have to use sed






sed find xargs




sed find xargs






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 30 at 21:08







kevzettler

















asked Mar 30 at 18:45









kevzettlerkevzettler

14817




14817













  • What output do you expect/need?

    – choroba
    Mar 30 at 18:50











  • @choroba added expected output

    – kevzettler
    Mar 30 at 21:08



















  • What output do you expect/need?

    – choroba
    Mar 30 at 18:50











  • @choroba added expected output

    – kevzettler
    Mar 30 at 21:08

















What output do you expect/need?

– choroba
Mar 30 at 18:50





What output do you expect/need?

– choroba
Mar 30 at 18:50













@choroba added expected output

– kevzettler
Mar 30 at 21:08





@choroba added expected output

– kevzettler
Mar 30 at 21:08










3 Answers
3






active

oldest

votes


















2














In Perl, you can use eof that will be true for each end of file:



find . -type f -name '*.org' -exec perl -ne 'print if /* Learnings/ .. eof' {} +


Using the + form of -exec works similarly to xargs: it builds the arguments to the specified command by appending all the found files.






share|improve this answer































    2














    With the GNU implementation of sed, you can use the -s aka --separate option for each file to be treated separately in that regard.



    find . -name '*.org' -type f -exec sed -s '/* Learnings/,$!d' {} +


    With awk:



    find . -name '*.org' -type f -exec awk '
    
  FNR == 1 {found = 0}; /* Learnings/ {found = 1}; found' {} +





    share|improve this answer































      0














      Unless this is some kind of homework ;-), you can use the same trick as here with GNU or *BSD grep:



      grep -hrFA 10000 '* Learnings' directory


      Replace 10000 with something bigger if your files have more than 10000 lines.






      share|improve this answer
























        Your Answer








        StackExchange.ready(function() {
        var channelOptions = {
        tags: "".split(" "),
        id: "106"
        };
        initTagRenderer("".split(" "), "".split(" "), channelOptions);

        StackExchange.using("externalEditor", function() {
        // Have to fire editor after snippets, if snippets enabled
        if (StackExchange.settings.snippets.snippetsEnabled) {
        StackExchange.using("snippets", function() {
        createEditor();
        });
        }
        else {
        createEditor();
        }
        });

        function createEditor() {
        StackExchange.prepareEditor({
        heartbeatType: 'answer',
        autoActivateHeartbeat: false,
        convertImagesToLinks: false,
        noModals: true,
        showLowRepImageUploadWarning: true,
        reputationToPostImages: null,
        bindNavPrevention: true,
        postfix: "",
        imageUploader: {
        brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
        contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
        allowUrls: true
        },
        onDemand: true,
        discardSelector: ".discard-answer"
        ,immediatelyShowMarkdownHelp:true
        });


        }
        });














        draft saved

        draft discarded


















        StackExchange.ready(
        function () {
        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f509619%2fhow-to-sed-chunks-text-from-a-stream-of-files-from-find%23new-answer', 'question_page');
        }
        );

        Post as a guest















        Required, but never shown

























        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        In Perl, you can use eof that will be true for each end of file:



        find . -type f -name '*.org' -exec perl -ne 'print if /* Learnings/ .. eof' {} +


        Using the + form of -exec works similarly to xargs: it builds the arguments to the specified command by appending all the found files.






        share|improve this answer




























          2














          In Perl, you can use eof that will be true for each end of file:



          find . -type f -name '*.org' -exec perl -ne 'print if /* Learnings/ .. eof' {} +


          Using the + form of -exec works similarly to xargs: it builds the arguments to the specified command by appending all the found files.






          share|improve this answer


























            2












            2








            2







            In Perl, you can use eof that will be true for each end of file:



            find . -type f -name '*.org' -exec perl -ne 'print if /* Learnings/ .. eof' {} +


            Using the + form of -exec works similarly to xargs: it builds the arguments to the specified command by appending all the found files.






            share|improve this answer













            In Perl, you can use eof that will be true for each end of file:



            find . -type f -name '*.org' -exec perl -ne 'print if /* Learnings/ .. eof' {} +


            Using the + form of -exec works similarly to xargs: it builds the arguments to the specified command by appending all the found files.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Mar 30 at 21:22









            chorobachoroba

            27k45176




            27k45176

























                2














                With the GNU implementation of sed, you can use the -s aka --separate option for each file to be treated separately in that regard.



                find . -name '*.org' -type f -exec sed -s '/* Learnings/,$!d' {} +


                With awk:



                find . -name '*.org' -type f -exec awk '
                
  FNR == 1 {found = 0}; /* Learnings/ {found = 1}; found' {} +





                share|improve this answer




























                  2














                  With the GNU implementation of sed, you can use the -s aka --separate option for each file to be treated separately in that regard.



                  find . -name '*.org' -type f -exec sed -s '/* Learnings/,$!d' {} +


                  With awk:



                  find . -name '*.org' -type f -exec awk '
                  
  FNR == 1 {found = 0}; /* Learnings/ {found = 1}; found' {} +





                  share|improve this answer


























                    2












                    2








                    2







                    With the GNU implementation of sed, you can use the -s aka --separate option for each file to be treated separately in that regard.



                    find . -name '*.org' -type f -exec sed -s '/* Learnings/,$!d' {} +


                    With awk:



                    find . -name '*.org' -type f -exec awk '
                    
  FNR == 1 {found = 0}; /* Learnings/ {found = 1}; found' {} +





                    share|improve this answer













                    With the GNU implementation of sed, you can use the -s aka --separate option for each file to be treated separately in that regard.



                    find . -name '*.org' -type f -exec sed -s '/* Learnings/,$!d' {} +


                    With awk:



                    find . -name '*.org' -type f -exec awk '
                    
  FNR == 1 {found = 0}; /* Learnings/ {found = 1}; found' {} +






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Mar 30 at 21:28









                    Stéphane ChazelasStéphane Chazelas

                    312k57592948




                    312k57592948























                        0














                        Unless this is some kind of homework ;-), you can use the same trick as here with GNU or *BSD grep:



                        grep -hrFA 10000 '* Learnings' directory


                        Replace 10000 with something bigger if your files have more than 10000 lines.






                        share|improve this answer




























                          0














                          Unless this is some kind of homework ;-), you can use the same trick as here with GNU or *BSD grep:



                          grep -hrFA 10000 '* Learnings' directory


                          Replace 10000 with something bigger if your files have more than 10000 lines.






                          share|improve this answer


























                            0












                            0








                            0







                            Unless this is some kind of homework ;-), you can use the same trick as here with GNU or *BSD grep:



                            grep -hrFA 10000 '* Learnings' directory


                            Replace 10000 with something bigger if your files have more than 10000 lines.






                            share|improve this answer













                            Unless this is some kind of homework ;-), you can use the same trick as here with GNU or *BSD grep:



                            grep -hrFA 10000 '* Learnings' directory


                            Replace 10000 with something bigger if your files have more than 10000 lines.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 2 days ago









                            mosvymosvy

                            8,8821833




                            8,8821833






























                                draft saved

                                draft discarded




















































                                Thanks for contributing an answer to Unix & Linux Stack Exchange!


                                • Please be sure to answer the question. Provide details and share your research!

                                But avoid …



                                • Asking for help, clarification, or responding to other answers.

                                • Making statements based on opinion; back them up with references or personal experience.


                                To learn more, see our tips on writing great answers.




                                draft saved


                                draft discarded














                                StackExchange.ready(
                                function () {
                                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f509619%2fhow-to-sed-chunks-text-from-a-stream-of-files-from-find%23new-answer', 'question_page');
                                }
                                );

                                Post as a guest















                                Required, but never shown





















































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown

































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown







                                -

                                Popular posts from this blog

                                How did Captain America manage to do this?

                                Image
                                2 How does Captain America lift Thor's hammer? In Avengers: Age of Ultron , he is not worthy but how he is worthy in this film. plot-explanation marvel-cinematic-universe avengers-age-of-ultron avengers-endgame share | improve this question edited 19 mins ago A J ♦ 42.7k 16 229 246 asked 39 mins ago Andi AR Andi AR 325 1 4 14
                                Read more

                                迪纳利

                                Image
                                迪纳利峰 位于迪纳利国家公园和保留区的迪纳利峰（旧名麦金利峰） 最高点 海拔 20,237英尺（6,168米）   NGVD 29 . [1] [2] 相對高度 20,073英尺（6,118米） 列表 各洲最高峰列表 特独立山峰 各国最高点列表 美国最高点  排名第一 [3] 坐标 63°04′10″N 151°00′27″W  /  63.06944°N 151.00750°W  / 63.06944; -151.00750  ( Mount McKinley ) 坐标： 63°04′10″N 151°00′27″W  /  63.06944°N 151.00750°W  / 63.06944; -151.00750  ( Mount McKinley )   地理 位置   美國阿拉斯加州迪纳利自治市镇 迪纳利国家公园和保留区 山脈 阿拉斯加山脉 攀山 首次登頂 （ 英语 ： First ascent ） 1913年6月7日 哈德逊·史塔克 哈里·卡斯坦斯 沃尔特·哈珀 罗伯特·塔特姆 最簡路線 西坡路线（攀登冰川/雪） 迪纳利 （北阿萨巴斯卡语支、 英语： Denali ， / d ᵻ ˈ n ɑː l i / ，直译“高山”），1917年至2015年官方名称为 麦金利山 （另译作 麦金利峰 ， 英语： Mount McKinley ），位于阿拉斯加州东南部、阿拉斯加山脉中段，海拔6194米，是北美洲最高峰，也是美国的最高峰。它的俄语名称是 Большая Гора ， 罗马化：Bolshaya Gora ，意思是“大山”。 迪纳利山地区拥有变幻莫测的高山风、典型的北极植被以及野生动植物。这里大部分地区终年积雪，山间经常浓雾不断，雾气在皑皑白雪中缭绕弥漫时，几百米之外的景物便不可见。夏季，迪纳利山的青青山坡上鲜花盛开，紫色的杜鹃和精巧的铃状石南花随处可见。迪纳利山还是世界登山爱好者的汇集之地。每年5月到7月有数百人登山，只有一半不到的人能登顶成功。一次登山约花3个星期。 2015年8月31日，美國政府宣佈將山名由“麦金利山”改回原名“迪纳利山”。美國內政部發表聲
                                Read more

                                南乌拉尔铁路局

                                Image
                                南乌拉尔铁路局 Южно-Уральская железная дорога 成立 1934年1月4日 国家   蘇聯（1934年—1991年）   俄羅斯（1991年—） 总部 车里雅宾斯克 隶属 俄罗斯铁路股份公司 路局代码 80 铁路里程 4,934.9公里 奖项 网址 http://yuzd.rzd.ru/ 查 论 编 南乌拉尔铁路局 （俄语： Южно-Уральская железная дорога ， 羅馬化： Yuzhno-Uralskaya zheleznaya doroga ，简称 ЮУЖД ）是俄罗斯铁路股份公司属下的铁路管理局之一，总部位于车里雅宾斯克，负责管辖俄罗斯联邦乌拉尔南部地区的铁路系统，范围包括奥伦堡州、车里雅宾斯克州、库尔干州的大部分铁路，以及萨马拉州、斯维尔德洛夫斯克州、巴什科尔托斯坦共和国的少部分铁路，并有部分铁路延伸至或穿过哈萨克斯坦境内。南乌拉尔铁路局的营业里程为4,934.9公里，与伏尔加铁路局、古比雪夫铁路局、斯维尔德洛夫斯克铁路局、西西伯利亚铁路局相邻，并与南方的哈萨克斯坦铁路连接。 外部链接 （俄文） Южно-Уральская железная дорога — филиал ОАО РЖД （俄文） 南乌拉尔铁路局管辖路线图（一） （俄文） 南乌拉尔铁路局管辖路线图（二） 查 论 编 俄罗斯铁路（集团）股份公司 十月铁路局 · 莫斯科铁路局 · 北高加索铁路局 · 高尔基铁路局 · 古比雪夫铁路局 · 北方铁路局 · 伏尔加铁路局 · 东南铁路局 · 斯维尔德洛夫斯克铁路局 · 南乌拉尔铁路局 · 西西伯利亚铁路局 · 克拉斯诺亚尔斯克铁路局 · 东西伯利亚铁路局 · 后贝加尔铁路局 · 远东铁路局 · 加里宁格勒铁路局 This page is only for reference, If you need detailed information, please check here
                                Read more