Truth table with logical gates for a traffic light





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$begingroup$


I want to create this truth table:
truth table



So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.

This is my design for it, but I could not make the last row.



enter image description here



Does anyone have a sample or a tip about what I can do to fix this?

Thanks!






logic-gates simulink







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John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • $begingroup$
    I remember doing a traffic light problem like this in one of my school labs.
    $endgroup$
    – user4574
    yesterday










  • $begingroup$
    @user4574 yep it is one of my assignments
    $endgroup$
    – John wiliam
    yesterday


















3












$begingroup$


I want to create this truth table:
truth table



So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.

This is my design for it, but I could not make the last row.



enter image description here



Does anyone have a sample or a tip about what I can do to fix this?

Thanks!






logic-gates simulink







share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    I remember doing a traffic light problem like this in one of my school labs.
    $endgroup$
    – user4574
    yesterday










  • $begingroup$
    @user4574 yep it is one of my assignments
    $endgroup$
    – John wiliam
    yesterday














3












3








3





$begingroup$


I want to create this truth table:
truth table



So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.

This is my design for it, but I could not make the last row.



enter image description here



Does anyone have a sample or a tip about what I can do to fix this?

Thanks!






logic-gates simulink







share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I want to create this truth table:
truth table



So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.

This is my design for it, but I could not make the last row.



enter image description here



Does anyone have a sample or a tip about what I can do to fix this?

Thanks!






logic-gates simulink




logic-gates simulink






share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited yesterday









Niteesh Shanbog

519416




519416






New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









John wiliamJohn wiliam

163




163




New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    I remember doing a traffic light problem like this in one of my school labs.
    $endgroup$
    – user4574
    yesterday










  • $begingroup$
    @user4574 yep it is one of my assignments
    $endgroup$
    – John wiliam
    yesterday


















  • $begingroup$
    I remember doing a traffic light problem like this in one of my school labs.
    $endgroup$
    – user4574
    yesterday










  • $begingroup$
    @user4574 yep it is one of my assignments
    $endgroup$
    – John wiliam
    yesterday
















$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
yesterday




$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
yesterday












$begingroup$
@user4574 yep it is one of my assignments
$endgroup$
– John wiliam
yesterday




$begingroup$
@user4574 yep it is one of my assignments
$endgroup$
– John wiliam
yesterday










4 Answers
4






active

oldest

votes


















2












$begingroup$

You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    yesterday



















2












$begingroup$

YELLOW = $B$.



RED = $bar A$.



GREEN = $overline {RED + YELLOW}$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.






share|improve this answer











$endgroup$













  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    yesterday





















2












$begingroup$

I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.






share|improve this answer









$endgroup$













  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    yesterday



















0












$begingroup$

I will be honest and say, i am not all that good at designing logic diagrams, way too long since i had it in school. But there is one thing i remember: Logic Friday. Its a freeware program that is an immense help when designing such diagrams and solving the equations. Using Logic Friday, i got these results:



A - input 1



B - input 2



F3 - red



F4 - yellow



F5 - green



Logic input gave me this truthtable after minimizing:



F3 = A';



F4 = B;



F5 = A B';



And this diagram followed:



Logic diagram



I know a program like this is no substitute for real knowledge, but it works for a home fiddler like me.



Good luck :)






share|improve this answer









$endgroup$













  • $begingroup$
    thanks for the help :)
    $endgroup$
    – John wiliam
    4 hours ago












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4 Answers
4






active

oldest

votes








4 Answers
4






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    yesterday
















2












$begingroup$

You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    yesterday














2












2








2





$begingroup$

You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here






share|improve this answer









$endgroup$



You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered yesterday









RenanRenan

4,35022244




4,35022244








  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    yesterday














  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    yesterday








1




1




$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
yesterday




$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
yesterday













2












$begingroup$

YELLOW = $B$.



RED = $bar A$.



GREEN = $overline {RED + YELLOW}$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.






share|improve this answer











$endgroup$













  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    yesterday


















2












$begingroup$

YELLOW = $B$.



RED = $bar A$.



GREEN = $overline {RED + YELLOW}$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.






share|improve this answer











$endgroup$













  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    yesterday
















2












2








2





$begingroup$

YELLOW = $B$.



RED = $bar A$.



GREEN = $overline {RED + YELLOW}$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.






share|improve this answer











$endgroup$



YELLOW = $B$.



RED = $bar A$.



GREEN = $overline {RED + YELLOW}$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.







share|improve this answer














share|improve this answer



share|improve this answer








edited yesterday

























answered yesterday









Andy akaAndy aka

245k11186425




245k11186425












  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    yesterday




















  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    yesterday


















$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
yesterday






$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
yesterday













2












$begingroup$

I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.






share|improve this answer









$endgroup$













  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    yesterday
















2












$begingroup$

I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.






share|improve this answer









$endgroup$













  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    yesterday














2












2








2





$begingroup$

I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.






share|improve this answer









$endgroup$



I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.







share|improve this answer












share|improve this answer



share|improve this answer










answered yesterday









Tanner SwettTanner Swett

42437




42437












  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    yesterday


















  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    yesterday
















$begingroup$
thanks for the advice :)
$endgroup$
– John wiliam
yesterday




$begingroup$
thanks for the advice :)
$endgroup$
– John wiliam
yesterday











0












$begingroup$

I will be honest and say, i am not all that good at designing logic diagrams, way too long since i had it in school. But there is one thing i remember: Logic Friday. Its a freeware program that is an immense help when designing such diagrams and solving the equations. Using Logic Friday, i got these results:



A - input 1



B - input 2



F3 - red



F4 - yellow



F5 - green



Logic input gave me this truthtable after minimizing:



F3 = A';



F4 = B;



F5 = A B';



And this diagram followed:



Logic diagram



I know a program like this is no substitute for real knowledge, but it works for a home fiddler like me.



Good luck :)






share|improve this answer









$endgroup$













  • $begingroup$
    thanks for the help :)
    $endgroup$
    – John wiliam
    4 hours ago
















0












$begingroup$

I will be honest and say, i am not all that good at designing logic diagrams, way too long since i had it in school. But there is one thing i remember: Logic Friday. Its a freeware program that is an immense help when designing such diagrams and solving the equations. Using Logic Friday, i got these results:



A - input 1



B - input 2



F3 - red



F4 - yellow



F5 - green



Logic input gave me this truthtable after minimizing:



F3 = A';



F4 = B;



F5 = A B';



And this diagram followed:



Logic diagram



I know a program like this is no substitute for real knowledge, but it works for a home fiddler like me.



Good luck :)






share|improve this answer









$endgroup$













  • $begingroup$
    thanks for the help :)
    $endgroup$
    – John wiliam
    4 hours ago














0












0








0





$begingroup$

I will be honest and say, i am not all that good at designing logic diagrams, way too long since i had it in school. But there is one thing i remember: Logic Friday. Its a freeware program that is an immense help when designing such diagrams and solving the equations. Using Logic Friday, i got these results:



A - input 1



B - input 2



F3 - red



F4 - yellow



F5 - green



Logic input gave me this truthtable after minimizing:



F3 = A';



F4 = B;



F5 = A B';



And this diagram followed:



Logic diagram



I know a program like this is no substitute for real knowledge, but it works for a home fiddler like me.



Good luck :)






share|improve this answer









$endgroup$



I will be honest and say, i am not all that good at designing logic diagrams, way too long since i had it in school. But there is one thing i remember: Logic Friday. Its a freeware program that is an immense help when designing such diagrams and solving the equations. Using Logic Friday, i got these results:



A - input 1



B - input 2



F3 - red



F4 - yellow



F5 - green



Logic input gave me this truthtable after minimizing:



F3 = A';



F4 = B;



F5 = A B';



And this diagram followed:



Logic diagram



I know a program like this is no substitute for real knowledge, but it works for a home fiddler like me.



Good luck :)







share|improve this answer












share|improve this answer



share|improve this answer










answered 18 hours ago









FiskelordFiskelord

83




83












  • $begingroup$
    thanks for the help :)
    $endgroup$
    – John wiliam
    4 hours ago


















  • $begingroup$
    thanks for the help :)
    $endgroup$
    – John wiliam
    4 hours ago
















$begingroup$
thanks for the help :)
$endgroup$
– John wiliam
4 hours ago




$begingroup$
thanks for the help :)
$endgroup$
– John wiliam
4 hours ago










John wiliam is a new contributor. Be nice, and check out our Code of Conduct.










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John wiliam is a new contributor. Be nice, and check out our Code of Conduct.
















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南乌拉尔铁路局

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南乌拉尔铁路局 Южно-Уральская железная дорога 成立 1934年1月4日 国家   蘇聯（1934年—1991年）   俄羅斯（1991年—） 总部 车里雅宾斯克 隶属 俄罗斯铁路股份公司 路局代码 80 铁路里程 4,934.9公里 奖项 网址 http://yuzd.rzd.ru/ 查 论 编 南乌拉尔铁路局 （俄语： Южно-Уральская железная дорога ， 羅馬化： Yuzhno-Uralskaya zheleznaya doroga ，简称 ЮУЖД ）是俄罗斯铁路股份公司属下的铁路管理局之一，总部位于车里雅宾斯克，负责管辖俄罗斯联邦乌拉尔南部地区的铁路系统，范围包括奥伦堡州、车里雅宾斯克州、库尔干州的大部分铁路，以及萨马拉州、斯维尔德洛夫斯克州、巴什科尔托斯坦共和国的少部分铁路，并有部分铁路延伸至或穿过哈萨克斯坦境内。南乌拉尔铁路局的营业里程为4,934.9公里，与伏尔加铁路局、古比雪夫铁路局、斯维尔德洛夫斯克铁路局、西西伯利亚铁路局相邻，并与南方的哈萨克斯坦铁路连接。 外部链接 （俄文） Южно-Уральская железная дорога — филиал ОАО РЖД （俄文） 南乌拉尔铁路局管辖路线图（一） （俄文） 南乌拉尔铁路局管辖路线图（二） 查 论 编 俄罗斯铁路（集团）股份公司 十月铁路局 · 莫斯科铁路局 · 北高加索铁路局 · 高尔基铁路局 · 古比雪夫铁路局 · 北方铁路局 · 伏尔加铁路局 · 东南铁路局 · 斯维尔德洛夫斯克铁路局 · 南乌拉尔铁路局 · 西西伯利亚铁路局 · 克拉斯诺亚尔斯克铁路局 · 东西伯利亚铁路局 · 后贝加尔铁路局 · 远东铁路局 · 加里宁格勒铁路局 This page is only for reference, If you need detailed information, please check here
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