Speeding up object name check by record ID





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I have been able to piece together some code that determines object name based on record ID without any hard-coding or SOQL. It works with both custom and standard objects but it is very slow, I'm guessing due to loading so much schema data and a lot of looping.



I am looking for a way to speed this function up, potentially by limiting the object names searched or the amount of data being sorted through.



Here is the entire (working, but slow) function:



// Get sObject type by record ID
public static String getObjName(String recordId) {
// Get record prefix
String recordPrefix = recordId.substring(0, 3);

// Get global "describe"
Map<String, Schema.SObjectType> gd = Schema.getGlobalDescribe();

// Loop through all objects to find match for record ID prefix
for (Schema.SObjectType otype : gd.values()) {
Schema.DescribeSObjectResult r = otype.getDescribe();
String prefix = r.getKeyPrefix();

// Found match!
if (prefix != null && prefix.equals(recordPrefix)) return r.getName();
}

return '';
}


Any ideas?










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    up vote
    2
    down vote

    favorite












    I have been able to piece together some code that determines object name based on record ID without any hard-coding or SOQL. It works with both custom and standard objects but it is very slow, I'm guessing due to loading so much schema data and a lot of looping.



    I am looking for a way to speed this function up, potentially by limiting the object names searched or the amount of data being sorted through.



    Here is the entire (working, but slow) function:



    // Get sObject type by record ID
    public static String getObjName(String recordId) {
    // Get record prefix
    String recordPrefix = recordId.substring(0, 3);

    // Get global "describe"
    Map<String, Schema.SObjectType> gd = Schema.getGlobalDescribe();

    // Loop through all objects to find match for record ID prefix
    for (Schema.SObjectType otype : gd.values()) {
    Schema.DescribeSObjectResult r = otype.getDescribe();
    String prefix = r.getKeyPrefix();

    // Found match!
    if (prefix != null && prefix.equals(recordPrefix)) return r.getName();
    }

    return '';
    }


    Any ideas?










    share|improve this question







    New contributor




    Ixalmida is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I have been able to piece together some code that determines object name based on record ID without any hard-coding or SOQL. It works with both custom and standard objects but it is very slow, I'm guessing due to loading so much schema data and a lot of looping.



      I am looking for a way to speed this function up, potentially by limiting the object names searched or the amount of data being sorted through.



      Here is the entire (working, but slow) function:



      // Get sObject type by record ID
      public static String getObjName(String recordId) {
      // Get record prefix
      String recordPrefix = recordId.substring(0, 3);

      // Get global "describe"
      Map<String, Schema.SObjectType> gd = Schema.getGlobalDescribe();

      // Loop through all objects to find match for record ID prefix
      for (Schema.SObjectType otype : gd.values()) {
      Schema.DescribeSObjectResult r = otype.getDescribe();
      String prefix = r.getKeyPrefix();

      // Found match!
      if (prefix != null && prefix.equals(recordPrefix)) return r.getName();
      }

      return '';
      }


      Any ideas?










      share|improve this question







      New contributor




      Ixalmida is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I have been able to piece together some code that determines object name based on record ID without any hard-coding or SOQL. It works with both custom and standard objects but it is very slow, I'm guessing due to loading so much schema data and a lot of looping.



      I am looking for a way to speed this function up, potentially by limiting the object names searched or the amount of data being sorted through.



      Here is the entire (working, but slow) function:



      // Get sObject type by record ID
      public static String getObjName(String recordId) {
      // Get record prefix
      String recordPrefix = recordId.substring(0, 3);

      // Get global "describe"
      Map<String, Schema.SObjectType> gd = Schema.getGlobalDescribe();

      // Loop through all objects to find match for record ID prefix
      for (Schema.SObjectType otype : gd.values()) {
      Schema.DescribeSObjectResult r = otype.getDescribe();
      String prefix = r.getKeyPrefix();

      // Found match!
      if (prefix != null && prefix.equals(recordPrefix)) return r.getName();
      }

      return '';
      }


      Any ideas?







      apex






      share|improve this question







      New contributor




      Ixalmida is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Ixalmida is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      Ixalmida is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 7 hours ago









      Ixalmida

      1113




      1113




      New contributor




      Ixalmida is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Ixalmida is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Ixalmida is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          6
          down vote













          The Id class already contains an instance method to do exactly what you wish, named getSObjectType. The entire body of your method can be simplified to the below:



          return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());





          share|improve this answer























          • Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
            – Ixalmida
            7 hours ago






          • 1




            You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
            – Sebastian Kessel
            6 hours ago






          • 1




            First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually: return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName(); I will accept the answer when it is corrected.
            – Ixalmida
            6 hours ago






          • 1




            You can just use String.valueOf, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType. Static types are preferable to String where they fit.
            – Adrian Larson
            6 hours ago






          • 1




            @AdrianLarson you can also just return recordId == null? '': ''+recordId.getSobjectType(); the string + operator takes care of the String.valueOf for you.
            – sfdcfox
            2 hours ago











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          6
          down vote













          The Id class already contains an instance method to do exactly what you wish, named getSObjectType. The entire body of your method can be simplified to the below:



          return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());





          share|improve this answer























          • Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
            – Ixalmida
            7 hours ago






          • 1




            You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
            – Sebastian Kessel
            6 hours ago






          • 1




            First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually: return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName(); I will accept the answer when it is corrected.
            – Ixalmida
            6 hours ago






          • 1




            You can just use String.valueOf, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType. Static types are preferable to String where they fit.
            – Adrian Larson
            6 hours ago






          • 1




            @AdrianLarson you can also just return recordId == null? '': ''+recordId.getSobjectType(); the string + operator takes care of the String.valueOf for you.
            – sfdcfox
            2 hours ago















          up vote
          6
          down vote













          The Id class already contains an instance method to do exactly what you wish, named getSObjectType. The entire body of your method can be simplified to the below:



          return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());





          share|improve this answer























          • Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
            – Ixalmida
            7 hours ago






          • 1




            You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
            – Sebastian Kessel
            6 hours ago






          • 1




            First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually: return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName(); I will accept the answer when it is corrected.
            – Ixalmida
            6 hours ago






          • 1




            You can just use String.valueOf, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType. Static types are preferable to String where they fit.
            – Adrian Larson
            6 hours ago






          • 1




            @AdrianLarson you can also just return recordId == null? '': ''+recordId.getSobjectType(); the string + operator takes care of the String.valueOf for you.
            – sfdcfox
            2 hours ago













          up vote
          6
          down vote










          up vote
          6
          down vote









          The Id class already contains an instance method to do exactly what you wish, named getSObjectType. The entire body of your method can be simplified to the below:



          return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());





          share|improve this answer














          The Id class already contains an instance method to do exactly what you wish, named getSObjectType. The entire body of your method can be simplified to the below:



          return (recordId == null) ? '' : String.valueOf(recordId.getSObjectType());






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 6 hours ago

























          answered 7 hours ago









          Adrian Larson

          103k19110233




          103k19110233












          • Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
            – Ixalmida
            7 hours ago






          • 1




            You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
            – Sebastian Kessel
            6 hours ago






          • 1




            First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually: return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName(); I will accept the answer when it is corrected.
            – Ixalmida
            6 hours ago






          • 1




            You can just use String.valueOf, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType. Static types are preferable to String where they fit.
            – Adrian Larson
            6 hours ago






          • 1




            @AdrianLarson you can also just return recordId == null? '': ''+recordId.getSobjectType(); the string + operator takes care of the String.valueOf for you.
            – sfdcfox
            2 hours ago


















          • Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
            – Ixalmida
            7 hours ago






          • 1




            You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
            – Sebastian Kessel
            6 hours ago






          • 1




            First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually: return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName(); I will accept the answer when it is corrected.
            – Ixalmida
            6 hours ago






          • 1




            You can just use String.valueOf, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType. Static types are preferable to String where they fit.
            – Adrian Larson
            6 hours ago






          • 1




            @AdrianLarson you can also just return recordId == null? '': ''+recordId.getSobjectType(); the string + operator takes care of the String.valueOf for you.
            – sfdcfox
            2 hours ago
















          Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
          – Ixalmida
          7 hours ago




          Indeed...that worked, thanks! I hope my question makes this answer easier for others to find because Google was not helping me at all.
          – Ixalmida
          7 hours ago




          1




          1




          You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
          – Sebastian Kessel
          6 hours ago




          You should mark it as "Accepted" (The tick next to the number of votes) so it comes up properly in searches;
          – Sebastian Kessel
          6 hours ago




          1




          1




          First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually: return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName(); I will accept the answer when it is corrected.
          – Ixalmida
          6 hours ago




          First...it wouldn't let me mark as accepted for 10 minutes or whatever, so I was waiting. Second...I just figured out for myself that this answer actually won't work because it mixes return types (String / Schema.SObjectType). The correct answer is actually: return (recordId == null) ? '' : recordId.getSObjectType().getDescribe().getName(); I will accept the answer when it is corrected.
          – Ixalmida
          6 hours ago




          1




          1




          You can just use String.valueOf, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType. Static types are preferable to String where they fit.
          – Adrian Larson
          6 hours ago




          You can just use String.valueOf, which should be much faster. Depending on your use case, it would actually be much better to just change your return type to SObjectType. Static types are preferable to String where they fit.
          – Adrian Larson
          6 hours ago




          1




          1




          @AdrianLarson you can also just return recordId == null? '': ''+recordId.getSobjectType(); the string + operator takes care of the String.valueOf for you.
          – sfdcfox
          2 hours ago




          @AdrianLarson you can also just return recordId == null? '': ''+recordId.getSobjectType(); the string + operator takes care of the String.valueOf for you.
          – sfdcfox
          2 hours ago










          Ixalmida is a new contributor. Be nice, and check out our Code of Conduct.










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          Ixalmida is a new contributor. Be nice, and check out our Code of Conduct.
















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