Statements in Java












2














Each code block translates to a specific statement in English. There is a theme behind the statements. As code puzzles tend to be "easier" (relative to other PSE puzzles) than expected, it will not be revealed unless people are unable to make any progress on the phrases.



1:



public class Statement() {
void Riddle1() {
Citizen you = new Citizen();
Government() g = new Government();
\g.getService(you)
\after a code revision, I've determined the following is better:
you.getService(g)
}
}


2:



System.out.println(listofconcerns.length); \returns 1
System.out.println(listofconcerns[0]); \returns the string "concerns"


3:



(house has been declared and initialized at some point before this line)
int quotient = house/house;
Boolean b = quotient == 1;
System.out.println(b); \returns false, with a compiler specific error on the result not holding up


4:



int anglevel = anger();
if(anglevel > threshold1) {
wait(10000);
if( anglevel > threshold2) {
wait(90000);
}
}









share|improve this question





























    2














    Each code block translates to a specific statement in English. There is a theme behind the statements. As code puzzles tend to be "easier" (relative to other PSE puzzles) than expected, it will not be revealed unless people are unable to make any progress on the phrases.



    1:



    public class Statement() {
    void Riddle1() {
    Citizen you = new Citizen();
    Government() g = new Government();
    \g.getService(you)
    \after a code revision, I've determined the following is better:
    you.getService(g)
    }
    }


    2:



    System.out.println(listofconcerns.length); \returns 1
    System.out.println(listofconcerns[0]); \returns the string "concerns"


    3:



    (house has been declared and initialized at some point before this line)
    int quotient = house/house;
    Boolean b = quotient == 1;
    System.out.println(b); \returns false, with a compiler specific error on the result not holding up


    4:



    int anglevel = anger();
    if(anglevel > threshold1) {
    wait(10000);
    if( anglevel > threshold2) {
    wait(90000);
    }
    }









    share|improve this question



























      2












      2








      2







      Each code block translates to a specific statement in English. There is a theme behind the statements. As code puzzles tend to be "easier" (relative to other PSE puzzles) than expected, it will not be revealed unless people are unable to make any progress on the phrases.



      1:



      public class Statement() {
      void Riddle1() {
      Citizen you = new Citizen();
      Government() g = new Government();
      \g.getService(you)
      \after a code revision, I've determined the following is better:
      you.getService(g)
      }
      }


      2:



      System.out.println(listofconcerns.length); \returns 1
      System.out.println(listofconcerns[0]); \returns the string "concerns"


      3:



      (house has been declared and initialized at some point before this line)
      int quotient = house/house;
      Boolean b = quotient == 1;
      System.out.println(b); \returns false, with a compiler specific error on the result not holding up


      4:



      int anglevel = anger();
      if(anglevel > threshold1) {
      wait(10000);
      if( anglevel > threshold2) {
      wait(90000);
      }
      }









      share|improve this question















      Each code block translates to a specific statement in English. There is a theme behind the statements. As code puzzles tend to be "easier" (relative to other PSE puzzles) than expected, it will not be revealed unless people are unable to make any progress on the phrases.



      1:



      public class Statement() {
      void Riddle1() {
      Citizen you = new Citizen();
      Government() g = new Government();
      \g.getService(you)
      \after a code revision, I've determined the following is better:
      you.getService(g)
      }
      }


      2:



      System.out.println(listofconcerns.length); \returns 1
      System.out.println(listofconcerns[0]); \returns the string "concerns"


      3:



      (house has been declared and initialized at some point before this line)
      int quotient = house/house;
      Boolean b = quotient == 1;
      System.out.println(b); \returns false, with a compiler specific error on the result not holding up


      4:



      int anglevel = anger();
      if(anglevel > threshold1) {
      wait(10000);
      if( anglevel > threshold2) {
      wait(90000);
      }
      }






      english computer-puzzle






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      share|improve this question




      share|improve this question








      edited 3 hours ago

























      asked 4 hours ago









      Display name

      577216




      577216






















          1 Answer
          1






          active

          oldest

          votes


















          2














          public class Statement() {
          void Riddle1() {
          Citizen you = new Citizen();
          Government() g = new Government();
          \g.getService(you)
          \after a code revision, I've determined the following is better:



          Ask not what your country can do for you...




                you.getService(g)



          ...ask what you can do for your country.




             }
          }

          System.out.println(listofconcerns.length); \returns 1



          Our only fear ("concern") is...




          System.out.println(listofconcerns[0]); \returns the string "concerns"



          ...fear itself




          (house has been declared and initialized at some point before this line)
          int quotient = house/house;



          A house divided against itself...




          Boolean b = quotient == 1;
          System.out.println(b); \returns false, with a compiler specific error on the result not holding up



          ...cannot stand (does not hold up)




          int anglevel = anger();
          if(anglevel > threshold1) {



          When angry...




              wait(10000);



          count to ten before you speak. (wait() is in milliseconds)




              if( anglevel > threshold2) {



          If very angry...




                 wait(90000);



          ...count to one hundred. (we've already counted to 10 at this point, so 10+90)




              }
          }


          Theme:




          Things said by dead american presidents: Kennedy, Roosevelt, Lincoln, and Jefferson respectively.







          share|improve this answer





















          • Correct. I suppose there's no way that code puzzles like these will ever be too difficult.
            – Display name
            4 hours ago










          • @Displayname Putting them together makes them easier, because once you get one, you get a hint to the others. However, easy doesn't mean bad, I think theme makes it better.
            – deep thought
            4 hours ago










          • @Displayname If you like code puzzles that are apparently not easy enough try <plug>this</plug>!
            – WAF
            12 mins ago











          Your Answer





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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          public class Statement() {
          void Riddle1() {
          Citizen you = new Citizen();
          Government() g = new Government();
          \g.getService(you)
          \after a code revision, I've determined the following is better:



          Ask not what your country can do for you...




                you.getService(g)



          ...ask what you can do for your country.




             }
          }

          System.out.println(listofconcerns.length); \returns 1



          Our only fear ("concern") is...




          System.out.println(listofconcerns[0]); \returns the string "concerns"



          ...fear itself




          (house has been declared and initialized at some point before this line)
          int quotient = house/house;



          A house divided against itself...




          Boolean b = quotient == 1;
          System.out.println(b); \returns false, with a compiler specific error on the result not holding up



          ...cannot stand (does not hold up)




          int anglevel = anger();
          if(anglevel > threshold1) {



          When angry...




              wait(10000);



          count to ten before you speak. (wait() is in milliseconds)




              if( anglevel > threshold2) {



          If very angry...




                 wait(90000);



          ...count to one hundred. (we've already counted to 10 at this point, so 10+90)




              }
          }


          Theme:




          Things said by dead american presidents: Kennedy, Roosevelt, Lincoln, and Jefferson respectively.







          share|improve this answer





















          • Correct. I suppose there's no way that code puzzles like these will ever be too difficult.
            – Display name
            4 hours ago










          • @Displayname Putting them together makes them easier, because once you get one, you get a hint to the others. However, easy doesn't mean bad, I think theme makes it better.
            – deep thought
            4 hours ago










          • @Displayname If you like code puzzles that are apparently not easy enough try <plug>this</plug>!
            – WAF
            12 mins ago
















          2














          public class Statement() {
          void Riddle1() {
          Citizen you = new Citizen();
          Government() g = new Government();
          \g.getService(you)
          \after a code revision, I've determined the following is better:



          Ask not what your country can do for you...




                you.getService(g)



          ...ask what you can do for your country.




             }
          }

          System.out.println(listofconcerns.length); \returns 1



          Our only fear ("concern") is...




          System.out.println(listofconcerns[0]); \returns the string "concerns"



          ...fear itself




          (house has been declared and initialized at some point before this line)
          int quotient = house/house;



          A house divided against itself...




          Boolean b = quotient == 1;
          System.out.println(b); \returns false, with a compiler specific error on the result not holding up



          ...cannot stand (does not hold up)




          int anglevel = anger();
          if(anglevel > threshold1) {



          When angry...




              wait(10000);



          count to ten before you speak. (wait() is in milliseconds)




              if( anglevel > threshold2) {



          If very angry...




                 wait(90000);



          ...count to one hundred. (we've already counted to 10 at this point, so 10+90)




              }
          }


          Theme:




          Things said by dead american presidents: Kennedy, Roosevelt, Lincoln, and Jefferson respectively.







          share|improve this answer





















          • Correct. I suppose there's no way that code puzzles like these will ever be too difficult.
            – Display name
            4 hours ago










          • @Displayname Putting them together makes them easier, because once you get one, you get a hint to the others. However, easy doesn't mean bad, I think theme makes it better.
            – deep thought
            4 hours ago










          • @Displayname If you like code puzzles that are apparently not easy enough try <plug>this</plug>!
            – WAF
            12 mins ago














          2












          2








          2






          public class Statement() {
          void Riddle1() {
          Citizen you = new Citizen();
          Government() g = new Government();
          \g.getService(you)
          \after a code revision, I've determined the following is better:



          Ask not what your country can do for you...




                you.getService(g)



          ...ask what you can do for your country.




             }
          }

          System.out.println(listofconcerns.length); \returns 1



          Our only fear ("concern") is...




          System.out.println(listofconcerns[0]); \returns the string "concerns"



          ...fear itself




          (house has been declared and initialized at some point before this line)
          int quotient = house/house;



          A house divided against itself...




          Boolean b = quotient == 1;
          System.out.println(b); \returns false, with a compiler specific error on the result not holding up



          ...cannot stand (does not hold up)




          int anglevel = anger();
          if(anglevel > threshold1) {



          When angry...




              wait(10000);



          count to ten before you speak. (wait() is in milliseconds)




              if( anglevel > threshold2) {



          If very angry...




                 wait(90000);



          ...count to one hundred. (we've already counted to 10 at this point, so 10+90)




              }
          }


          Theme:




          Things said by dead american presidents: Kennedy, Roosevelt, Lincoln, and Jefferson respectively.







          share|improve this answer












          public class Statement() {
          void Riddle1() {
          Citizen you = new Citizen();
          Government() g = new Government();
          \g.getService(you)
          \after a code revision, I've determined the following is better:



          Ask not what your country can do for you...




                you.getService(g)



          ...ask what you can do for your country.




             }
          }

          System.out.println(listofconcerns.length); \returns 1



          Our only fear ("concern") is...




          System.out.println(listofconcerns[0]); \returns the string "concerns"



          ...fear itself




          (house has been declared and initialized at some point before this line)
          int quotient = house/house;



          A house divided against itself...




          Boolean b = quotient == 1;
          System.out.println(b); \returns false, with a compiler specific error on the result not holding up



          ...cannot stand (does not hold up)




          int anglevel = anger();
          if(anglevel > threshold1) {



          When angry...




              wait(10000);



          count to ten before you speak. (wait() is in milliseconds)




              if( anglevel > threshold2) {



          If very angry...




                 wait(90000);



          ...count to one hundred. (we've already counted to 10 at this point, so 10+90)




              }
          }


          Theme:




          Things said by dead american presidents: Kennedy, Roosevelt, Lincoln, and Jefferson respectively.








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 4 hours ago









          deep thought

          2,4361633




          2,4361633












          • Correct. I suppose there's no way that code puzzles like these will ever be too difficult.
            – Display name
            4 hours ago










          • @Displayname Putting them together makes them easier, because once you get one, you get a hint to the others. However, easy doesn't mean bad, I think theme makes it better.
            – deep thought
            4 hours ago










          • @Displayname If you like code puzzles that are apparently not easy enough try <plug>this</plug>!
            – WAF
            12 mins ago


















          • Correct. I suppose there's no way that code puzzles like these will ever be too difficult.
            – Display name
            4 hours ago










          • @Displayname Putting them together makes them easier, because once you get one, you get a hint to the others. However, easy doesn't mean bad, I think theme makes it better.
            – deep thought
            4 hours ago










          • @Displayname If you like code puzzles that are apparently not easy enough try <plug>this</plug>!
            – WAF
            12 mins ago
















          Correct. I suppose there's no way that code puzzles like these will ever be too difficult.
          – Display name
          4 hours ago




          Correct. I suppose there's no way that code puzzles like these will ever be too difficult.
          – Display name
          4 hours ago












          @Displayname Putting them together makes them easier, because once you get one, you get a hint to the others. However, easy doesn't mean bad, I think theme makes it better.
          – deep thought
          4 hours ago




          @Displayname Putting them together makes them easier, because once you get one, you get a hint to the others. However, easy doesn't mean bad, I think theme makes it better.
          – deep thought
          4 hours ago












          @Displayname If you like code puzzles that are apparently not easy enough try <plug>this</plug>!
          – WAF
          12 mins ago




          @Displayname If you like code puzzles that are apparently not easy enough try <plug>this</plug>!
          – WAF
          12 mins ago


















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