Creating nested elements dynamically












9















I have this array of strings var arr = ["ul", "li", "strong", "em", "u"].



How can I make these into DOM Elements one inside another from left to right, first element as the root element. Without using ID because of some reason.



And maybe by using loop for it to be flexible to any number of elements.



var new_element = document.createElement(arr[0]);



I'm expecting something like this:



<ul>

    <li><strong><em><u>Text Here</u></em></strong></li>

</ul>


Thank you.






javascript html dom







share|improve this question




















  • 1





    You want to know about Node.appendChild.

    – moonwave99
    yesterday
















9















I have this array of strings var arr = ["ul", "li", "strong", "em", "u"].



How can I make these into DOM Elements one inside another from left to right, first element as the root element. Without using ID because of some reason.



And maybe by using loop for it to be flexible to any number of elements.



var new_element = document.createElement(arr[0]);



I'm expecting something like this:



<ul>

    <li><strong><em><u>Text Here</u></em></strong></li>

</ul>


Thank you.






javascript html dom







share|improve this question




















  • 1





    You want to know about Node.appendChild.

    – moonwave99
    yesterday














9












9








9


1






I have this array of strings var arr = ["ul", "li", "strong", "em", "u"].



How can I make these into DOM Elements one inside another from left to right, first element as the root element. Without using ID because of some reason.



And maybe by using loop for it to be flexible to any number of elements.



var new_element = document.createElement(arr[0]);



I'm expecting something like this:



<ul>

    <li><strong><em><u>Text Here</u></em></strong></li>

</ul>


Thank you.






javascript html dom







share|improve this question
















I have this array of strings var arr = ["ul", "li", "strong", "em", "u"].



How can I make these into DOM Elements one inside another from left to right, first element as the root element. Without using ID because of some reason.



And maybe by using loop for it to be flexible to any number of elements.



var new_element = document.createElement(arr[0]);



I'm expecting something like this:



<ul>

    <li><strong><em><u>Text Here</u></em></strong></li>

</ul>


Thank you.






javascript html dom




javascript html dom






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday









Community♦

11




11










asked yesterday









MuyieMuyie

728




728








  • 1





    You want to know about Node.appendChild.

    – moonwave99
    yesterday














  • 1





    You want to know about Node.appendChild.

    – moonwave99
    yesterday








1




1





You want to know about Node.appendChild.

– moonwave99
yesterday





You want to know about Node.appendChild.

– moonwave99
yesterday












3 Answers
3






active

oldest

votes


















7














You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






var arr = ["ul", "li", "strong", "em", "u"]



let el = arr.reduceRight((el, n) => {

  let d = document.createElement(n)

  d.appendChild(el)

  return d

}, document.createTextNode("Text Here"))



document.getElementById('container').appendChild(el)

<div id = "container"></div>





It also fails gracefully with an empty array:






var arr = 



let el = arr.reduceRight((el, n) => {

  let d = document.createElement(n)

  d.appendChild(el)

  return d

}, document.createTextNode("Text Here"))



document.getElementById('container').appendChild(el)

<div id = "container"></div>








share|improve this answer



















  • 1





    Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

    – Muyie
    yesterday



















11














You can use Array.prototype.reduce and Node.prototype.appendChild.



https://jsbin.com/hizetekato/edit?html,js,output






var arr = ["ul", "li", "strong", "em", "u"];



function createChildren(mount, arr) {

  return arr.reduce((parent, elementName, i) => {

    const element = document.createElement(elementName);

    parent.appendChild(element);

    return element;

  }, mount);

}



const deepest = createChildren(document.querySelector('#root'), arr);



deepest.innerText = 'WebDevNSK'

<div id="root"></div>








share|improve this answer


























  • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

    – Muyie
    yesterday











  • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

    – Solomon Ucko
    yesterday



















0














createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






const frag = document.createDocumentFragment();

const useless = ["ul", "li", "strong", "em", "u"];



let previous;

for (let u = 0; u < useless.length; u++) {

  const current = document.createElement(useless[u]);

  if (u === 0) {

    frag.appendChild(current);

  } else {

    previous.appendChild(current);

  }

  previous = current;

}



document.body.appendChild(frag);

ul {

  outline: 5px dashed green;

  padding: 15px;

}



li {

  outline: 5px solid blue;

  padding: 12px;

}



strong {

  outline: 5px dashed red;

  padding: 9px

}



em {

  outline: 5px dashed grey;

  padding: 6px

}



u {

  outline: 5px solid black;

  padding: 3px;

}



u::before {

  content: 'THIS TEXT SHOULD BE UNDERLINED'

}








share|improve this answer























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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7














    You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






    var arr = ["ul", "li", "strong", "em", "u"]
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    It also fails gracefully with an empty array:






    var arr = 
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>








    share|improve this answer



















    • 1





      Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

      – Muyie
      yesterday
















    7














    You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






    var arr = ["ul", "li", "strong", "em", "u"]
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    It also fails gracefully with an empty array:






    var arr = 
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>








    share|improve this answer



















    • 1





      Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

      – Muyie
      yesterday














    7












    7








    7







    You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






    var arr = ["ul", "li", "strong", "em", "u"]
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    It also fails gracefully with an empty array:






    var arr = 
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>








    share|improve this answer













    You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






    var arr = ["ul", "li", "strong", "em", "u"]
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    It also fails gracefully with an empty array:






    var arr = 
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>








    var arr = ["ul", "li", "strong", "em", "u"]
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    var arr = ["ul", "li", "strong", "em", "u"]
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    var arr = 
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    var arr = 
    

    
let el = arr.reduceRight((el, n) => {
    
  let d = document.createElement(n)
    
  d.appendChild(el)
    
  return d
    
}, document.createTextNode("Text Here"))
    

    
document.getElementById('container').appendChild(el)

    <div id = "container"></div>






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered yesterday









    Mark MeyerMark Meyer

    39.5k33162




    39.5k33162








    • 1





      Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

      – Muyie
      yesterday














    • 1





      Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

      – Muyie
      yesterday








    1




    1





    Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

    – Muyie
    yesterday





    Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

    – Muyie
    yesterday













    11














    You can use Array.prototype.reduce and Node.prototype.appendChild.



    https://jsbin.com/hizetekato/edit?html,js,output






    var arr = ["ul", "li", "strong", "em", "u"];
    

    
function createChildren(mount, arr) {
    
  return arr.reduce((parent, elementName, i) => {
    
    const element = document.createElement(elementName);
    
    parent.appendChild(element);
    
    return element;
    
  }, mount);
    
}
    

    
const deepest = createChildren(document.querySelector('#root'), arr);
    

    
deepest.innerText = 'WebDevNSK'

    <div id="root"></div>








    share|improve this answer


























    • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

      – Muyie
      yesterday











    • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

      – Solomon Ucko
      yesterday
















    11














    You can use Array.prototype.reduce and Node.prototype.appendChild.



    https://jsbin.com/hizetekato/edit?html,js,output






    var arr = ["ul", "li", "strong", "em", "u"];
    

    
function createChildren(mount, arr) {
    
  return arr.reduce((parent, elementName, i) => {
    
    const element = document.createElement(elementName);
    
    parent.appendChild(element);
    
    return element;
    
  }, mount);
    
}
    

    
const deepest = createChildren(document.querySelector('#root'), arr);
    

    
deepest.innerText = 'WebDevNSK'

    <div id="root"></div>








    share|improve this answer


























    • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

      – Muyie
      yesterday











    • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

      – Solomon Ucko
      yesterday














    11












    11








    11







    You can use Array.prototype.reduce and Node.prototype.appendChild.



    https://jsbin.com/hizetekato/edit?html,js,output






    var arr = ["ul", "li", "strong", "em", "u"];
    

    
function createChildren(mount, arr) {
    
  return arr.reduce((parent, elementName, i) => {
    
    const element = document.createElement(elementName);
    
    parent.appendChild(element);
    
    return element;
    
  }, mount);
    
}
    

    
const deepest = createChildren(document.querySelector('#root'), arr);
    

    
deepest.innerText = 'WebDevNSK'

    <div id="root"></div>








    share|improve this answer















    You can use Array.prototype.reduce and Node.prototype.appendChild.



    https://jsbin.com/hizetekato/edit?html,js,output






    var arr = ["ul", "li", "strong", "em", "u"];
    

    
function createChildren(mount, arr) {
    
  return arr.reduce((parent, elementName, i) => {
    
    const element = document.createElement(elementName);
    
    parent.appendChild(element);
    
    return element;
    
  }, mount);
    
}
    

    
const deepest = createChildren(document.querySelector('#root'), arr);
    

    
deepest.innerText = 'WebDevNSK'

    <div id="root"></div>








    var arr = ["ul", "li", "strong", "em", "u"];
    

    
function createChildren(mount, arr) {
    
  return arr.reduce((parent, elementName, i) => {
    
    const element = document.createElement(elementName);
    
    parent.appendChild(element);
    
    return element;
    
  }, mount);
    
}
    

    
const deepest = createChildren(document.querySelector('#root'), arr);
    

    
deepest.innerText = 'WebDevNSK'

    <div id="root"></div>





    var arr = ["ul", "li", "strong", "em", "u"];
    

    
function createChildren(mount, arr) {
    
  return arr.reduce((parent, elementName, i) => {
    
    const element = document.createElement(elementName);
    
    parent.appendChild(element);
    
    return element;
    
  }, mount);
    
}
    

    
const deepest = createChildren(document.querySelector('#root'), arr);
    

    
deepest.innerText = 'WebDevNSK'

    <div id="root"></div>






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited yesterday









    Jack Bashford

    13k31847




    13k31847










    answered yesterday









    dangreendangreen

    1498




    1498













    • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

      – Muyie
      yesterday











    • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

      – Solomon Ucko
      yesterday



















    • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

      – Muyie
      yesterday











    • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

      – Solomon Ucko
      yesterday

















    Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

    – Muyie
    yesterday





    Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

    – Muyie
    yesterday













    What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

    – Solomon Ucko
    yesterday





    What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

    – Solomon Ucko
    yesterday











    0














    createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






    const frag = document.createDocumentFragment();
    
const useless = ["ul", "li", "strong", "em", "u"];
    

    
let previous;
    
for (let u = 0; u < useless.length; u++) {
    
  const current = document.createElement(useless[u]);
    
  if (u === 0) {
    
    frag.appendChild(current);
    
  } else {
    
    previous.appendChild(current);
    
  }
    
  previous = current;
    
}
    

    
document.body.appendChild(frag);

    ul {
    
  outline: 5px dashed green;
    
  padding: 15px;
    
}
    

    
li {
    
  outline: 5px solid blue;
    
  padding: 12px;
    
}
    

    
strong {
    
  outline: 5px dashed red;
    
  padding: 9px
    
}
    

    
em {
    
  outline: 5px dashed grey;
    
  padding: 6px
    
}
    

    
u {
    
  outline: 5px solid black;
    
  padding: 3px;
    
}
    

    
u::before {
    
  content: 'THIS TEXT SHOULD BE UNDERLINED'
    
}








    share|improve this answer




























      0














      createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






      const frag = document.createDocumentFragment();
      
const useless = ["ul", "li", "strong", "em", "u"];
      

      
let previous;
      
for (let u = 0; u < useless.length; u++) {
      
  const current = document.createElement(useless[u]);
      
  if (u === 0) {
      
    frag.appendChild(current);
      
  } else {
      
    previous.appendChild(current);
      
  }
      
  previous = current;
      
}
      

      
document.body.appendChild(frag);

      ul {
      
  outline: 5px dashed green;
      
  padding: 15px;
      
}
      

      
li {
      
  outline: 5px solid blue;
      
  padding: 12px;
      
}
      

      
strong {
      
  outline: 5px dashed red;
      
  padding: 9px
      
}
      

      
em {
      
  outline: 5px dashed grey;
      
  padding: 6px
      
}
      

      
u {
      
  outline: 5px solid black;
      
  padding: 3px;
      
}
      

      
u::before {
      
  content: 'THIS TEXT SHOULD BE UNDERLINED'
      
}








      share|improve this answer


























        0












        0








        0







        createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






        const frag = document.createDocumentFragment();
        
const useless = ["ul", "li", "strong", "em", "u"];
        

        
let previous;
        
for (let u = 0; u < useless.length; u++) {
        
  const current = document.createElement(useless[u]);
        
  if (u === 0) {
        
    frag.appendChild(current);
        
  } else {
        
    previous.appendChild(current);
        
  }
        
  previous = current;
        
}
        

        
document.body.appendChild(frag);

        ul {
        
  outline: 5px dashed green;
        
  padding: 15px;
        
}
        

        
li {
        
  outline: 5px solid blue;
        
  padding: 12px;
        
}
        

        
strong {
        
  outline: 5px dashed red;
        
  padding: 9px
        
}
        

        
em {
        
  outline: 5px dashed grey;
        
  padding: 6px
        
}
        

        
u {
        
  outline: 5px solid black;
        
  padding: 3px;
        
}
        

        
u::before {
        
  content: 'THIS TEXT SHOULD BE UNDERLINED'
        
}








        share|improve this answer













        createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






        const frag = document.createDocumentFragment();
        
const useless = ["ul", "li", "strong", "em", "u"];
        

        
let previous;
        
for (let u = 0; u < useless.length; u++) {
        
  const current = document.createElement(useless[u]);
        
  if (u === 0) {
        
    frag.appendChild(current);
        
  } else {
        
    previous.appendChild(current);
        
  }
        
  previous = current;
        
}
        

        
document.body.appendChild(frag);

        ul {
        
  outline: 5px dashed green;
        
  padding: 15px;
        
}
        

        
li {
        
  outline: 5px solid blue;
        
  padding: 12px;
        
}
        

        
strong {
        
  outline: 5px dashed red;
        
  padding: 9px
        
}
        

        
em {
        
  outline: 5px dashed grey;
        
  padding: 6px
        
}
        

        
u {
        
  outline: 5px solid black;
        
  padding: 3px;
        
}
        

        
u::before {
        
  content: 'THIS TEXT SHOULD BE UNDERLINED'
        
}








        const frag = document.createDocumentFragment();
        
const useless = ["ul", "li", "strong", "em", "u"];
        

        
let previous;
        
for (let u = 0; u < useless.length; u++) {
        
  const current = document.createElement(useless[u]);
        
  if (u === 0) {
        
    frag.appendChild(current);
        
  } else {
        
    previous.appendChild(current);
        
  }
        
  previous = current;
        
}
        

        
document.body.appendChild(frag);

        ul {
        
  outline: 5px dashed green;
        
  padding: 15px;
        
}
        

        
li {
        
  outline: 5px solid blue;
        
  padding: 12px;
        
}
        

        
strong {
        
  outline: 5px dashed red;
        
  padding: 9px
        
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