Draw some expanding arrows











up vote
21
down vote

favorite
4












This challenge is about printing a series of growing ASCII-art arrows. I'll describe the pattern in words, but it might be easier to look at what the start of this series looks like:



>
<
->
<-
-->
<--
--->
<---
---->
<----
----->
<-----
------>
<------
...


An arrow with length n contains an arrowhead (< or >) and n-1 dashes (-). A right-facing arrow has the dashes first, then a >. A left-facing arrow starts with <, and is followed by the dashes. The series consists of a length n right-facing arrow followed by a length n left-facing arrow, with n from 1 to infinity.



To complete the challenge, write a program or function that takes one input, an integer i >= 1, and outputs the first i arrows. Arrows are individual, not in right-left pairs, so for i=3 you should output:



>
<
->


You can return a list of strings, or print them one after the other. If printing, the arrows must be delimited by some consistent delimiter, which doesn't have to be a newline as in the example.



This is code-golf, so fewest bytes wins.










share|improve this question


















  • 2




    Related.
    – AdmBorkBork
    Dec 12 at 16:23










  • Can we have spaces before/after each line?
    – Olivier Grégoire
    Dec 12 at 16:54










  • @OlivierGrégoire Yes, trailing whitespace is ok.
    – Pavel
    Dec 12 at 16:55










  • And heading whitespace?
    – Olivier Grégoire
    Dec 12 at 16:58










  • @OlivierGrégoire Yeah, that's fine.
    – Pavel
    Dec 12 at 17:00

















up vote
21
down vote

favorite
4












This challenge is about printing a series of growing ASCII-art arrows. I'll describe the pattern in words, but it might be easier to look at what the start of this series looks like:



>
<
->
<-
-->
<--
--->
<---
---->
<----
----->
<-----
------>
<------
...


An arrow with length n contains an arrowhead (< or >) and n-1 dashes (-). A right-facing arrow has the dashes first, then a >. A left-facing arrow starts with <, and is followed by the dashes. The series consists of a length n right-facing arrow followed by a length n left-facing arrow, with n from 1 to infinity.



To complete the challenge, write a program or function that takes one input, an integer i >= 1, and outputs the first i arrows. Arrows are individual, not in right-left pairs, so for i=3 you should output:



>
<
->


You can return a list of strings, or print them one after the other. If printing, the arrows must be delimited by some consistent delimiter, which doesn't have to be a newline as in the example.



This is code-golf, so fewest bytes wins.










share|improve this question


















  • 2




    Related.
    – AdmBorkBork
    Dec 12 at 16:23










  • Can we have spaces before/after each line?
    – Olivier Grégoire
    Dec 12 at 16:54










  • @OlivierGrégoire Yes, trailing whitespace is ok.
    – Pavel
    Dec 12 at 16:55










  • And heading whitespace?
    – Olivier Grégoire
    Dec 12 at 16:58










  • @OlivierGrégoire Yeah, that's fine.
    – Pavel
    Dec 12 at 17:00















up vote
21
down vote

favorite
4









up vote
21
down vote

favorite
4






4





This challenge is about printing a series of growing ASCII-art arrows. I'll describe the pattern in words, but it might be easier to look at what the start of this series looks like:



>
<
->
<-
-->
<--
--->
<---
---->
<----
----->
<-----
------>
<------
...


An arrow with length n contains an arrowhead (< or >) and n-1 dashes (-). A right-facing arrow has the dashes first, then a >. A left-facing arrow starts with <, and is followed by the dashes. The series consists of a length n right-facing arrow followed by a length n left-facing arrow, with n from 1 to infinity.



To complete the challenge, write a program or function that takes one input, an integer i >= 1, and outputs the first i arrows. Arrows are individual, not in right-left pairs, so for i=3 you should output:



>
<
->


You can return a list of strings, or print them one after the other. If printing, the arrows must be delimited by some consistent delimiter, which doesn't have to be a newline as in the example.



This is code-golf, so fewest bytes wins.










share|improve this question













This challenge is about printing a series of growing ASCII-art arrows. I'll describe the pattern in words, but it might be easier to look at what the start of this series looks like:



>
<
->
<-
-->
<--
--->
<---
---->
<----
----->
<-----
------>
<------
...


An arrow with length n contains an arrowhead (< or >) and n-1 dashes (-). A right-facing arrow has the dashes first, then a >. A left-facing arrow starts with <, and is followed by the dashes. The series consists of a length n right-facing arrow followed by a length n left-facing arrow, with n from 1 to infinity.



To complete the challenge, write a program or function that takes one input, an integer i >= 1, and outputs the first i arrows. Arrows are individual, not in right-left pairs, so for i=3 you should output:



>
<
->


You can return a list of strings, or print them one after the other. If printing, the arrows must be delimited by some consistent delimiter, which doesn't have to be a newline as in the example.



This is code-golf, so fewest bytes wins.







code-golf ascii-art sequence






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share|improve this question










asked Dec 12 at 15:56









Pavel

4,80013389




4,80013389








  • 2




    Related.
    – AdmBorkBork
    Dec 12 at 16:23










  • Can we have spaces before/after each line?
    – Olivier Grégoire
    Dec 12 at 16:54










  • @OlivierGrégoire Yes, trailing whitespace is ok.
    – Pavel
    Dec 12 at 16:55










  • And heading whitespace?
    – Olivier Grégoire
    Dec 12 at 16:58










  • @OlivierGrégoire Yeah, that's fine.
    – Pavel
    Dec 12 at 17:00
















  • 2




    Related.
    – AdmBorkBork
    Dec 12 at 16:23










  • Can we have spaces before/after each line?
    – Olivier Grégoire
    Dec 12 at 16:54










  • @OlivierGrégoire Yes, trailing whitespace is ok.
    – Pavel
    Dec 12 at 16:55










  • And heading whitespace?
    – Olivier Grégoire
    Dec 12 at 16:58










  • @OlivierGrégoire Yeah, that's fine.
    – Pavel
    Dec 12 at 17:00










2




2




Related.
– AdmBorkBork
Dec 12 at 16:23




Related.
– AdmBorkBork
Dec 12 at 16:23












Can we have spaces before/after each line?
– Olivier Grégoire
Dec 12 at 16:54




Can we have spaces before/after each line?
– Olivier Grégoire
Dec 12 at 16:54












@OlivierGrégoire Yes, trailing whitespace is ok.
– Pavel
Dec 12 at 16:55




@OlivierGrégoire Yes, trailing whitespace is ok.
– Pavel
Dec 12 at 16:55












And heading whitespace?
– Olivier Grégoire
Dec 12 at 16:58




And heading whitespace?
– Olivier Grégoire
Dec 12 at 16:58












@OlivierGrégoire Yeah, that's fine.
– Pavel
Dec 12 at 17:00






@OlivierGrégoire Yeah, that's fine.
– Pavel
Dec 12 at 17:00












38 Answers
38






active

oldest

votes













1 2
next











up vote
6
down vote



accepted











Canvas, 10 bytes



⇵-×<n¹[↔}]


Try it here!






share|improve this answer





















  • I don't know any Canvas, but is that an arrow-drawing builtin I see? kinda looks like it!
    – Pavel
    Dec 12 at 16:03










  • is the "reverse horizontally" built-in (also swapping > & <), sadly no arrow built-ins :p
    – dzaima
    Dec 12 at 16:04


















up vote
8
down vote














R, 69 bytes





for(i in 1:scan()-1)cat('<'[i%%2],rep('-',i/2),'>'[!i%%2],'
',sep='')


Try it online!




  • -5 bytes thanks to @Giuseppe

  • -3 bytes thanks to @Robert S.






share|improve this answer























  • strrep coerces its second argument to integer so you can use / in place of %/%
    – Giuseppe
    Dec 12 at 16:40










  • you can also get rid of a entirely by indexing over 0...(n-1) instead: Try it online!
    – Giuseppe
    Dec 12 at 16:44










  • I'm an idiot... thanks ! :D
    – digEmAll
    Dec 12 at 17:17










  • @Giuseppe :also I just noticed the deleted question of Robert S. I can use rep instead of strrep and save 3 bytes...(facepalm)
    – digEmAll
    Dec 12 at 17:21


















up vote
8
down vote













Haskell, 41 40 bytes



(`take`g">")
g p=p:('<':init p):g('-':p)


Try it online!



Plain old recursion: start with string p = ">", collect p, a < in front of all but the last char of p and a recursive call with one - put in front of p. Take the first n items of this list.



Edit: -1 byte thanks to @xnor.






share|improve this answer



















  • 1




    A weird change to save a byte.
    – xnor
    Dec 13 at 5:44


















up vote
7
down vote














Java (JDK), 81 bytes





n->{for(int i=0;i<n;)System.out.printf(i%2<1?"<%s%n":"%s>%n","-".repeat(i++/2));}


Try it online!



Explanations



n->{                  // int-accepting consumer
for(int i=0;i<n;) // for each i from 0 to n-1 included
System.out.printf( // output on stdout with a pattern
i%2<1 // if i is even:
?"<%s%n" // use the left-arrow pattern
:"%s>%n", // else: use the right-arrow pattern
"-".repeat(i++/2) // fill the "%s" in the pattern with i/2 dashes, and increment i
); //
} //





share|improve this answer























  • Consider removing static reference to System.out
    – candied_orange
    Dec 15 at 18:11












  • @candied_orange That's not self-contained.
    – Olivier Grégoire
    Dec 15 at 18:32










  • How about done like this?
    – candied_orange
    Dec 15 at 18:52












  • @candied_orange It's the same: the imports are required in the count.
    – Olivier Grégoire
    Dec 15 at 19:38










  • Why doesn't import java.util.function.*; count?
    – candied_orange
    Dec 15 at 19:44


















up vote
6
down vote














Commodore BASIC V2 (C64), 94 bytes



0inputn:fOi=1ton:oniaN1gO1:?"<";
1on-(i<3)gO2:fOj=1.5toi/2:?"-";:nE
2on-nOiaN1gO3:?">";
3?:nE


Not entirely sure about the byte count, this is based on the text representation for typing the valid program. It's a bit shorter on disk (91 bytes) because BASIC V2 uses a "tokenized" representation of programs.



Online Demo



Slightly "ungolfed":



0 inputn:fori=1ton:oniand1goto1:print"<";    :rem read n from user, loop to n, if odd skip "<"
1 on-(i<3)goto2:forj=1.5toi/2:print"-";:next :rem skip for i<3, print (i-1)/2 times "-"
2 on-notiand1goto3:print">"; :rem if even skip ">"
3 print:next :rem newline and next loop iteration





share|improve this answer




























    up vote
    6
    down vote














    Python 2, 54 bytes



    thanks to the and Jo King for fixing a bug.





    k=0
    exec"print k%2*'<'+k/2*'-'+~k%2*'>';k+=1;"*input()


    Try it online!






    share|improve this answer



















    • 3




      Your arrows have too many dashes; only every other one should lengthen by a dash.
      – xnor
      Dec 13 at 2:35






    • 1




      54 bytes
      – tsh
      Dec 13 at 5:23










    • 54 bytes with the arrows pointing the right way
      – Jo King
      Dec 13 at 9:52


















    up vote
    5
    down vote













    Pyth, 17 bytes



    m_W%d2+*-/d2@"><


    Output is a list of strings. Try it online here.



    m_W%d2+*-/d2@"><"dQ   Implicit: Q=eval(input())
    Trailing "dQ inferred
    m Q Map [0-Q), as d, using:
    /d2 Floored division of d by 2
    *- Repeat "-" the above number of times
    + Append to the above...
    @"><"d Modular index d into "><" - yields ">" for even d, "<" for odd
    - examples: d=4 gives "-->", d=7 gives "---<"
    _W Reverse the above if...
    %d2 ... (d % 2) != 0
    Implicit print result of the map





    share|improve this answer




























      up vote
      5
      down vote













      Python 3, 53 bytes



      My first codegolf answer.



      lambda x:[i%2*"<"+i//2*"-"+~i%2*">"for i in range(x)]


      -10 bytes thanks to Jo King






      share|improve this answer










      New contributor




      van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.














      • 1




        Welcome to PPCG! You can remove the brackets by putting the string after the number, use ~i instead of i+1 and use // to integer divide, assuming you're using Python 3. 53 bytes
        – Jo King
        Dec 13 at 9:45








      • 1




        I've linked the updated solution in my previous comment. If you like, you can use the auto-formatter in the TIO link to help create your answer
        – Jo King
        Dec 13 at 9:54


















      up vote
      5
      down vote














      Self-modifying Brainfuck, 55 bytes



      Take input as character code.

      Only support input up to 255.

      Use null character to separate lines.



      Coincidentally, all arrow-drawing characters are used as BF commands. Unfortunately, it doesn't save any bytes (currently).



      >>,[<<[-<.>>+<]<<.>>.+>>-[<<<<<.>>>>[-<+<.>>].>-<]>]<>-


      Try it online!



      Explanation



       Code  |              Memory         | Output | Comment
      -------+-----------------------------+--------+--------------------------
      | '<' '>' '-' [0] 0 0 0 | |
      >>, | '<' '>' '-' 0 0 [x] 0 | |
      [ | | |
      | '<' '>' '-' l 0 [x] 0 | | l = arrow length
      <<[-< | | | copy l to next cell
      .>>+<] | | | and print '-'
      | '<' '>' '-' [0] l x 0 | ----- | there are l '-'s
      <<. | '<' [>] '-' 0 l x 0 | > |
      >>.+ | '<' '>' '-' [1] l x 0 | <null> |
      >>- | '<' '>' '-' 1 l [y] 0 | | y=x-1
      [ | | | execute if y>0
      <<<<<. | [<] '>' '-' 1 l y 0 | < |
      >>>> | '<' '>' '-' 1 [l] y 0 | |
      [-<+<. | | |
      >>] | '<' '>' '-' L [0] y 0 | ----- | L=l+1
      . | '<' '>' '-' L [0] y 0 | <null> |
      >-<]>] | | | decrement y
      <>- | | | do nothing, used as data





      share|improve this answer






























        up vote
        5
        down vote














        Haskell, 51 44 bytes



        -7 bytes thanks to xnor (using iterate over list-comprehension)!





        (`take`do b<-iterate('-':)"";[b++">",'<':b])


        Try it online!



        Explanation / Ungolfed



        Using do-notation saves us a concat, and using infix-notation allows a pointfree function with take, undoing these would give:



        f n = take n $ concat [ [b++">", '<':b] | b <- iterate ('-':) "" ]





        share|improve this answer



















        • 1




          You can shorten the part after do to b<-iterate('-':)"".
          – xnor
          Dec 13 at 5:33


















        up vote
        5
        down vote













        Japt -m, 16 15 13 bytes



        g"><" iUUz ç-


        Test it online



        Explanation:



        -m              // Map the program through [0...Input); U becomes the item
        g"><" iUUz ç-
        "><" // Literal "><"
        g // Get the char at index U (with wrapping)
        i // Insert:
        U // At index U (with wrapping)
        ç- // "-" repeated:
        Uz // U/2 times





        share|improve this answer






























          up vote
          4
          down vote














          PowerShell, 62 56 50 bytes





          param($n)(0..$n|%{($j='-'*$_)+'>';"<$j"})[0..--$n]


          Try it online!



          Loops from 0 up to input $n, each iteration creating two arrow strings. Those are then indexed with 0..--$n to pull out the correct number of elements.



          Saved 6 bytes thanks to KGlasier.






          share|improve this answer























          • Messing around with my own solution I found a way to cut a few bytes on yours: Can save 4 bytes by wrapping the loop in brackets and indexing directly. ie param($n)(0..$n|%{($j='-'*$_++)+'>';"<$j"})[0..--$n]. So now you don't have to write $x twice.
            – KGlasier
            Dec 12 at 17:00










          • Also you can save two more bytes by not using ++ in ($j='-'*$_++) as you don't use $_ anywhere else.
            – KGlasier
            Dec 12 at 17:03








          • 1




            @KGlasier Awesome - thanks for the obvious golfs! :)
            – AdmBorkBork
            Dec 12 at 17:16


















          up vote
          4
          down vote














          Jelly, 15 bytes



          ị⁾><;’H”-ẋƲṚ⁸¡)


          Try it online!






          share|improve this answer





















          • -1 byte using tie: TIO.
            – HyperNeutrino
            Dec 14 at 14:29


















          up vote
          4
          down vote














          MathGolf, 17 15 bytes



          Saved 2 bytes thanks to Jo King and Kevin Cruijssen



          {ï½'-*'>ï¥╛Å⌡n


          Try it online!



          Explanation



          The 15-byte approach is different compared to my original solution, I can't take any credit for the implementation.



          {                 start block or arbitrary length
          ï index of current loop, or length of last loop
          ½ pop a : push(a//2 if int else a/2)
          '- push single character "-"
          * pop a, b : push(a*b)
          '> push single character ">"
          ï index of current loop, or length of last loop
          ¥ modulo 2
          ╛ if without else
          Å start block of length 2
          ⌡ decrement twice
          swap top elements
          n newline char, or map array with newlines





          share|improve this answer























          • How does the if/else work in MathGolf? I know how the if-without-else and else-without-if statements work, but how to create an if{ ... } else{ ... } in MathGolf with ¿? (Maybe I should post this in the chat instead of here.. But I might perhaps have a save of 1 byte if I can fix the if-else.)
            – Kevin Cruijssen
            Dec 13 at 10:20








          • 1




            @KevinCruijssen I think it works with the next two commands/blocks. e.g. ¿12 will push 1 if true, else 2, ¿Å3*Å1+ will add one if true else triple the next element
            – Jo King
            Dec 13 at 10:30












          • @KevinCruijssen The if/else pops two operators or blocks from the code. Jo King is correct in his example, but you could also do ¿{"foo"}{"bar"} or ¿1{2}.
            – maxb
            Dec 13 at 10:34










          • @JoKing I'll add a TODO to fix the docs for the slicing operators.
            – maxb
            Dec 13 at 10:35






          • 1




            15 bytes using @KevinCruijssen's solution
            – Jo King
            Dec 13 at 10:46




















          up vote
          4
          down vote














          Japt -m, 14 bytes



          "<>"¬hUUz ç-)q


          Try it online!



          Updated with a completely new method.



          Explanation:



                            #Implicitly map over the range [0..input) as U
          "<>" #The string "<>"
          ¬ #Split into the array ["<",">"]
          hU ) #Replace the element at index U with wrapping:
          - # The character '-'
          ç # Repeated a number of times equal to
          Uz # U integer divided by 2
          q #Join the array to a string





          share|improve this answer



















          • 1




            ç auto-casts its first parameter into a string, so you can drop the '.
            – Oliver
            Dec 13 at 0:21






          • 1




            You don't need the u method thanks to index wrapping so this can be 14 bytes.
            – Shaggy
            Dec 13 at 8:13


















          up vote
          3
          down vote













          JavaScript (ES6), 58 bytes



          Returns a space-separated string.





          n=>(g=p=>n--?k++&1?`<${p} `+g(p+'-'):p+'> '+g(p):'')(k='')


          Try it online!






          share|improve this answer




























            up vote
            3
            down vote














            SNOBOL4 (CSNOBOL4), 123 122 118 bytes



            	N =INPUT - 1
            P H =X / 2
            Y =DUPL('-',H)
            OUTPUT =EQ(H,X - H) Y '>' :S(I)
            OUTPUT ='<' Y
            I X =LT(X,N) X + 1 :S(P)
            END


            Try it online!






            share|improve this answer






























              up vote
              3
              down vote














              V, 22 bytes



              i>
              <Àñäkjjé-já-ñÀGjdG


              Try it online!






              share|improve this answer

















              • 5




                This looks like some weird scandinavian language
                – Pavel
                Dec 12 at 18:02


















              up vote
              3
              down vote














              Charcoal, 16 bytes



              NθFθ«⊘ι↓>‖T»Fθ‖T


              Try it online! Link is to verbose version of code. I had three 17-byte solutions before I eventually stumbled over this one. Explanation:



              Nθ


              Input n.



              Fθ«


              Repeat n times, 0-indexed.



              ⊘ι


              Draw a line of -s of length half the index (truncated).



              ↓>


              Draw the arrowhead and move to the next line.



              ‖T»


              Reflect everything, flipping the arrowheads.



              Fθ‖T


              The above loop has n reflections, but we need an even number of reflections, so perform another n reflections.






              share|improve this answer




























                up vote
                3
                down vote














                Clean, 76 73 bytes



                import StdEnv,StdLib
                $n=take n[s\i<-inits['--'..],s<-[i++['>'],['<':i]]]


                Try it online!



                Uses the neat fact that ['-','-'..] is the same as ['--'..] to save a bit.






                share|improve this answer




























                  up vote
                  3
                  down vote













                  JavaScript, 49 bytes





                  f=n=>--n?f(n,l='')+(n%2?`
                  <`+l:`
                  ${l+='-'}>`):'>'


                  Try it online!






                  share|improve this answer























                  • Wow, pretty cool
                    – Levitator Imbalance
                    Dec 14 at 10:41










                  • ...but it throws on 10000, meanwhile my ES6 solution is still works :D Anyway, your solution is very cool)
                    – Levitator Imbalance
                    Dec 14 at 10:53




















                  up vote
                  2
                  down vote














                  6502 machine code (C64), 49 bytes



                  00 C0 20 9B B7 A2 00 8A 4A A8 90 05 A9 3C 20 D2 FF A9 2D C0 00 F0 06 20 D2 FF 
                  88 D0 FA 8A 4A B0 05 A9 3E 20 D2 FF A9 0D 20 D2 FF E8 E4 65 D0 D7 60


                  Still quite a bit shorter than BASIC ;) This one has a number range only up to 255 because the natural integer size of the machine has only 8 bits.



                  Online demo



                  Usage: SYS49152,[n] (e.g. SYS49152,3 for the example from the challenge)



                  Commented disassembly:



                           00 C0       .WORD $C000        ; load address
                  .C:c000 20 9B B7 JSR $B79B ; get unsigned byte from commandline
                  .C:c003 A2 00 LDX #$00 ; main loop counter
                  .C:c005 .loop:
                  .C:c005 8A TXA ; loop counter to accumulator
                  .C:c006 4A LSR A ; divide by 2, shift lowest bit to C
                  .C:c007 A8 TAY ; result to Y
                  .C:c008 90 05 BCC .toright ; C clear -> counter even, skip '<'
                  .C:c00a A9 3C LDA #$3C ; load character '<'
                  .C:c00c 20 D2 FF JSR $FFD2 ; output character
                  .C:c00f .toright:
                  .C:c00f A9 2D LDA #$2D ; load character '-'
                  .C:c011 C0 00 CPY #$00 ; counter/2 == 0 ? then no dashes
                  .C:c013 F0 06 BEQ .skipdashes
                  .C:c015 .printdashes:
                  .C:c015 20 D2 FF JSR $FFD2 ; output character
                  .C:c018 88 DEY ; decrement Y
                  .C:c019 D0 FA BNE .printdashes ; not 0 yet -> repeat
                  .C:c01b .skipdashes:
                  .C:c01b 8A TXA ; loop counter to accumulator
                  .C:c01c 4A LSR A ; shift lowest bit to C
                  .C:c01d B0 05 BCS .toleft ; C set -> counter odd, skip '>'
                  .C:c01f A9 3E LDA #$3E ; load character '>'
                  .C:c021 20 D2 FF JSR $FFD2 ; output character
                  .C:c024 .toleft:
                  .C:c024 A9 0D LDA #$0D ; load newline character
                  .C:c026 20 D2 FF JSR $FFD2 ; output character
                  .C:c029 E8 INX ; next loop iteration
                  .C:c02a E4 65 CPX $65 ; compare to command line argument
                  .C:c02c D0 D7 BNE .loop ; not reached yet -> repeat main loop
                  .C:c02e 60 RTS ; exit





                  share|improve this answer




























                    up vote
                    2
                    down vote














                    Perl 6, 39 bytes





                    {map {'<'x$_%2~'-'x$_/2~'>'x$_%%2},^$_}


                    Try it online!



                    Anonymous code block that returns a list of lines.






                    share|improve this answer




























                      up vote
                      2
                      down vote














                      K (ngn/k), 31 29 bytes



                      {"<->"x#2,x{(1=*x)_1,2-|x}}


                      Try it online!



                      first we generate lists with 0 instead of "<", 1 instead of "-", and 2 instead of ">":



                      { } function with argument x



                      x{...} apply the inner function x times, starting with an initial value of 0 and preserving intermediate results



                      |x reverse



                      2- replace 0 with 2 and vice versa, keep the 1s as they are



                      1, prepend a 1



                      (1=*x)_ is the first of x equal to 1? if yes, drop one element, otherwise drop 0 elements (do nothing)



                      2, prepend a 2 for the initial ">" arrow



                      x# we have a little too many lists, so take only the first x of them



                      "<->" use the lists' elements (0/1/2) as indices in this string






                      share|improve this answer























                      • I would like to ask for an explanation (I haven't started learning K yet, I don't know which version to start with...)
                        – Galen Ivanov
                        Dec 13 at 12:14






                      • 1




                        @GalenIvanov i tried to write an explanation, i hope it makes sense. thanks for your interest in my favourite language :) there are multiple implementations with different advantages and disadvantages (kx's original, kona, oK and i'm working on my own). would you like to join the apl chat room so i can give you more details?
                        – ngn
                        Dec 13 at 12:44












                      • Thank you, I'm already there
                        – Galen Ivanov
                        Dec 13 at 12:49


















                      up vote
                      2
                      down vote














                      05AB1E, 23 20 bytes



                      FNÉD„><è'-N;∍«s_iR},


                      Try it online!



                      First time using 05AB1E or any other golfing language for that matter. Any ideas welcome.



                      -3 from Kevin Cruijssen






                      share|improve this answer



















                      • 1




                        Welcome to the world of 05AB1E, and nice first answer. +1 from me. :) "><" can be „>< to save a byte. There are builtins for 1, 2, and 3 char strings, being ', , and respectively. Here is a 18 bytes alternative I came up with, but perhaps it could be golfed a bit more. If you haven't seen it yet, we have a tips for golfing in 05AB1E page, and also feel free to ask anything in the chat.
                        – Kevin Cruijssen
                        Dec 13 at 8:54








                      • 1




                        @KevinCruijssen Thanks so much for your ideas. I don't feel right just using your code, as it feels fairly different from mine, but I did use the idea of modulo 2 as checking for if a number is odd. I also use the two char string idea. I would not mind at all if you posted the 18 byte version on your own.
                        – nedla2004
                        Dec 13 at 23:09










                      • I've posted my answer in that case. :)
                        – Kevin Cruijssen
                        Dec 14 at 8:31


















                      up vote
                      2
                      down vote













                      ES6, 96 82 79 70 bytes



                      Try it online! (Thanks to @Oliver)



                      n=>[...Array(n)].map((_,i)=>(i%2?"<":"")+"-".repeat(i/2)+(i%2?"":">"))





                      share|improve this answer










                      New contributor




                      Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.














                      • 1




                        Welcome to PPCG! By default, taking input as a variable is disallowed; you have to either make it a function (just stick a i=> in front of your code!) or from a command-line argument or STDIN or something.
                        – HyperNeutrino
                        Dec 14 at 14:40










                      • @HyperNeutrino okay, edited answer. However, the most voted answer contains only the body of the function, but ok. Anyway I'm outsider)
                        – Levitator Imbalance
                        Dec 14 at 15:09












                      • Can you link it? I don't think any of them are invalid, at least not the top few.
                        – HyperNeutrino
                        Dec 14 at 15:16






                      • 1




                        A few more bytes: Try it online
                        – Oliver
                        Dec 14 at 16:15






                      • 1




                        A few more bytes if you re-arrange that last ternary operator and remove the center parenthesis: Try it online
                        – Oliver
                        Dec 14 at 16:59


















                      up vote
                      2
                      down vote














                      Red, 109 108 bytes



                      -1 byte thanks to NK1406



                      func[n][repeat i n[print reduce[pick[pad/with pad/left/with]k: i% 2 + 1
                      pick copy"<>"k i / 2 + k - 1 #"-"]]]


                      Try it online!






                      share|improve this answer



















                      • 1




                        -1 for removing a space
                        – NK1406
                        Dec 15 at 18:28










                      • @NK1406 Thank you! I didn't know this is valid.
                        – Galen Ivanov
                        Dec 15 at 19:01


















                      up vote
                      2
                      down vote














                      C (gcc), 127 95 + 26 = 121 bytes





                      i,j;f(x){for(i=0;i<x;putchar(10),i+=2){for(j=0;E;printf(">n%c",x-i-1?60:9);for(j=0;x-i-1&&E;}}


                      Try it online!



                      Compile with -DE=j<i/2;++j)putchar(45)



                      -6 bytes from Logern



                      Yay mismatched parentheses!



                      Ungolfed:





                      void f(int x) {
                      for (int i = 0; i < x; i += 2) {
                      for (int j = 0; j < i/2; ++j) {
                      printf("-");
                      }
                      printf(">n");
                      if (x - i - 1) { // Test for last loop: only print <-- if x is even
                      printf("<");
                      for (int j = 0; j < i/2; ++j) {
                      printf("-");
                      }
                      }
                      else {
                      printf("t"); // This is the 9 in the x-i-1?60:9
                      }
                      printf("n");
                      }
                      }



                      Try it online!






                      share|improve this answer



















                      • 1




                        121 bytes with a -D compiler flag instead of #define - Try it online!
                        – Logern
                        Dec 14 at 17:31










                      • Another -3 bytes by taking out the i=0 like this
                        – NK1406
                        Dec 15 at 18:19










                      • @NK1406 Functions have to be reusable, that edit would break this rule. Try it online!
                        – pizzapants184
                        2 days ago










                      • Suggest x+~i instead of x-i-1
                        – ceilingcat
                        2 days ago










                      • @pizzapants184 Sorry, didn't see that!
                        – NK1406
                        2 days ago


















                      up vote
                      1
                      down vote













                      Powershell, 51 bytes





                      param($n)0..$n|%{'-'*$_+'>';'<'+'-'*$_}|?{$n---gt0}





                      share|improve this answer




























                        up vote
                        1
                        down vote














                        Perl 5, 44 bytes





                        map{$_/=2;say'<'x/./,'-'x$_,'>'x!$&}0..<>-1


                        Try it online!






                        share|improve this answer

























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                          up vote
                          6
                          down vote



                          accepted











                          Canvas, 10 bytes



                          ⇵-×<n¹[↔}]


                          Try it here!






                          share|improve this answer





















                          • I don't know any Canvas, but is that an arrow-drawing builtin I see? kinda looks like it!
                            – Pavel
                            Dec 12 at 16:03










                          • is the "reverse horizontally" built-in (also swapping > & <), sadly no arrow built-ins :p
                            – dzaima
                            Dec 12 at 16:04















                          up vote
                          6
                          down vote



                          accepted











                          Canvas, 10 bytes



                          ⇵-×<n¹[↔}]


                          Try it here!






                          share|improve this answer





















                          • I don't know any Canvas, but is that an arrow-drawing builtin I see? kinda looks like it!
                            – Pavel
                            Dec 12 at 16:03










                          • is the "reverse horizontally" built-in (also swapping > & <), sadly no arrow built-ins :p
                            – dzaima
                            Dec 12 at 16:04













                          up vote
                          6
                          down vote



                          accepted







                          up vote
                          6
                          down vote



                          accepted







                          Canvas, 10 bytes



                          ⇵-×<n¹[↔}]


                          Try it here!






                          share|improve this answer













                          Canvas, 10 bytes



                          ⇵-×<n¹[↔}]


                          Try it here!







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Dec 12 at 16:01









                          dzaima

                          14.4k21754




                          14.4k21754












                          • I don't know any Canvas, but is that an arrow-drawing builtin I see? kinda looks like it!
                            – Pavel
                            Dec 12 at 16:03










                          • is the "reverse horizontally" built-in (also swapping > & <), sadly no arrow built-ins :p
                            – dzaima
                            Dec 12 at 16:04


















                          • I don't know any Canvas, but is that an arrow-drawing builtin I see? kinda looks like it!
                            – Pavel
                            Dec 12 at 16:03










                          • is the "reverse horizontally" built-in (also swapping > & <), sadly no arrow built-ins :p
                            – dzaima
                            Dec 12 at 16:04
















                          I don't know any Canvas, but is that an arrow-drawing builtin I see? kinda looks like it!
                          – Pavel
                          Dec 12 at 16:03




                          I don't know any Canvas, but is that an arrow-drawing builtin I see? kinda looks like it!
                          – Pavel
                          Dec 12 at 16:03












                          is the "reverse horizontally" built-in (also swapping > & <), sadly no arrow built-ins :p
                          – dzaima
                          Dec 12 at 16:04




                          is the "reverse horizontally" built-in (also swapping > & <), sadly no arrow built-ins :p
                          – dzaima
                          Dec 12 at 16:04










                          up vote
                          8
                          down vote














                          R, 69 bytes





                          for(i in 1:scan()-1)cat('<'[i%%2],rep('-',i/2),'>'[!i%%2],'
                          ',sep='')


                          Try it online!




                          • -5 bytes thanks to @Giuseppe

                          • -3 bytes thanks to @Robert S.






                          share|improve this answer























                          • strrep coerces its second argument to integer so you can use / in place of %/%
                            – Giuseppe
                            Dec 12 at 16:40










                          • you can also get rid of a entirely by indexing over 0...(n-1) instead: Try it online!
                            – Giuseppe
                            Dec 12 at 16:44










                          • I'm an idiot... thanks ! :D
                            – digEmAll
                            Dec 12 at 17:17










                          • @Giuseppe :also I just noticed the deleted question of Robert S. I can use rep instead of strrep and save 3 bytes...(facepalm)
                            – digEmAll
                            Dec 12 at 17:21















                          up vote
                          8
                          down vote














                          R, 69 bytes





                          for(i in 1:scan()-1)cat('<'[i%%2],rep('-',i/2),'>'[!i%%2],'
                          ',sep='')


                          Try it online!




                          • -5 bytes thanks to @Giuseppe

                          • -3 bytes thanks to @Robert S.






                          share|improve this answer























                          • strrep coerces its second argument to integer so you can use / in place of %/%
                            – Giuseppe
                            Dec 12 at 16:40










                          • you can also get rid of a entirely by indexing over 0...(n-1) instead: Try it online!
                            – Giuseppe
                            Dec 12 at 16:44










                          • I'm an idiot... thanks ! :D
                            – digEmAll
                            Dec 12 at 17:17










                          • @Giuseppe :also I just noticed the deleted question of Robert S. I can use rep instead of strrep and save 3 bytes...(facepalm)
                            – digEmAll
                            Dec 12 at 17:21













                          up vote
                          8
                          down vote










                          up vote
                          8
                          down vote










                          R, 69 bytes





                          for(i in 1:scan()-1)cat('<'[i%%2],rep('-',i/2),'>'[!i%%2],'
                          ',sep='')


                          Try it online!




                          • -5 bytes thanks to @Giuseppe

                          • -3 bytes thanks to @Robert S.






                          share|improve this answer















                          R, 69 bytes





                          for(i in 1:scan()-1)cat('<'[i%%2],rep('-',i/2),'>'[!i%%2],'
                          ',sep='')


                          Try it online!




                          • -5 bytes thanks to @Giuseppe

                          • -3 bytes thanks to @Robert S.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Dec 12 at 17:18

























                          answered Dec 12 at 16:36









                          digEmAll

                          2,43148




                          2,43148












                          • strrep coerces its second argument to integer so you can use / in place of %/%
                            – Giuseppe
                            Dec 12 at 16:40










                          • you can also get rid of a entirely by indexing over 0...(n-1) instead: Try it online!
                            – Giuseppe
                            Dec 12 at 16:44










                          • I'm an idiot... thanks ! :D
                            – digEmAll
                            Dec 12 at 17:17










                          • @Giuseppe :also I just noticed the deleted question of Robert S. I can use rep instead of strrep and save 3 bytes...(facepalm)
                            – digEmAll
                            Dec 12 at 17:21


















                          • strrep coerces its second argument to integer so you can use / in place of %/%
                            – Giuseppe
                            Dec 12 at 16:40










                          • you can also get rid of a entirely by indexing over 0...(n-1) instead: Try it online!
                            – Giuseppe
                            Dec 12 at 16:44










                          • I'm an idiot... thanks ! :D
                            – digEmAll
                            Dec 12 at 17:17










                          • @Giuseppe :also I just noticed the deleted question of Robert S. I can use rep instead of strrep and save 3 bytes...(facepalm)
                            – digEmAll
                            Dec 12 at 17:21
















                          strrep coerces its second argument to integer so you can use / in place of %/%
                          – Giuseppe
                          Dec 12 at 16:40




                          strrep coerces its second argument to integer so you can use / in place of %/%
                          – Giuseppe
                          Dec 12 at 16:40












                          you can also get rid of a entirely by indexing over 0...(n-1) instead: Try it online!
                          – Giuseppe
                          Dec 12 at 16:44




                          you can also get rid of a entirely by indexing over 0...(n-1) instead: Try it online!
                          – Giuseppe
                          Dec 12 at 16:44












                          I'm an idiot... thanks ! :D
                          – digEmAll
                          Dec 12 at 17:17




                          I'm an idiot... thanks ! :D
                          – digEmAll
                          Dec 12 at 17:17












                          @Giuseppe :also I just noticed the deleted question of Robert S. I can use rep instead of strrep and save 3 bytes...(facepalm)
                          – digEmAll
                          Dec 12 at 17:21




                          @Giuseppe :also I just noticed the deleted question of Robert S. I can use rep instead of strrep and save 3 bytes...(facepalm)
                          – digEmAll
                          Dec 12 at 17:21










                          up vote
                          8
                          down vote













                          Haskell, 41 40 bytes



                          (`take`g">")
                          g p=p:('<':init p):g('-':p)


                          Try it online!



                          Plain old recursion: start with string p = ">", collect p, a < in front of all but the last char of p and a recursive call with one - put in front of p. Take the first n items of this list.



                          Edit: -1 byte thanks to @xnor.






                          share|improve this answer



















                          • 1




                            A weird change to save a byte.
                            – xnor
                            Dec 13 at 5:44















                          up vote
                          8
                          down vote













                          Haskell, 41 40 bytes



                          (`take`g">")
                          g p=p:('<':init p):g('-':p)


                          Try it online!



                          Plain old recursion: start with string p = ">", collect p, a < in front of all but the last char of p and a recursive call with one - put in front of p. Take the first n items of this list.



                          Edit: -1 byte thanks to @xnor.






                          share|improve this answer



















                          • 1




                            A weird change to save a byte.
                            – xnor
                            Dec 13 at 5:44













                          up vote
                          8
                          down vote










                          up vote
                          8
                          down vote









                          Haskell, 41 40 bytes



                          (`take`g">")
                          g p=p:('<':init p):g('-':p)


                          Try it online!



                          Plain old recursion: start with string p = ">", collect p, a < in front of all but the last char of p and a recursive call with one - put in front of p. Take the first n items of this list.



                          Edit: -1 byte thanks to @xnor.






                          share|improve this answer














                          Haskell, 41 40 bytes



                          (`take`g">")
                          g p=p:('<':init p):g('-':p)


                          Try it online!



                          Plain old recursion: start with string p = ">", collect p, a < in front of all but the last char of p and a recursive call with one - put in front of p. Take the first n items of this list.



                          Edit: -1 byte thanks to @xnor.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Dec 13 at 18:05

























                          answered Dec 12 at 17:33









                          nimi

                          31.1k31985




                          31.1k31985








                          • 1




                            A weird change to save a byte.
                            – xnor
                            Dec 13 at 5:44














                          • 1




                            A weird change to save a byte.
                            – xnor
                            Dec 13 at 5:44








                          1




                          1




                          A weird change to save a byte.
                          – xnor
                          Dec 13 at 5:44




                          A weird change to save a byte.
                          – xnor
                          Dec 13 at 5:44










                          up vote
                          7
                          down vote














                          Java (JDK), 81 bytes





                          n->{for(int i=0;i<n;)System.out.printf(i%2<1?"<%s%n":"%s>%n","-".repeat(i++/2));}


                          Try it online!



                          Explanations



                          n->{                  // int-accepting consumer
                          for(int i=0;i<n;) // for each i from 0 to n-1 included
                          System.out.printf( // output on stdout with a pattern
                          i%2<1 // if i is even:
                          ?"<%s%n" // use the left-arrow pattern
                          :"%s>%n", // else: use the right-arrow pattern
                          "-".repeat(i++/2) // fill the "%s" in the pattern with i/2 dashes, and increment i
                          ); //
                          } //





                          share|improve this answer























                          • Consider removing static reference to System.out
                            – candied_orange
                            Dec 15 at 18:11












                          • @candied_orange That's not self-contained.
                            – Olivier Grégoire
                            Dec 15 at 18:32










                          • How about done like this?
                            – candied_orange
                            Dec 15 at 18:52












                          • @candied_orange It's the same: the imports are required in the count.
                            – Olivier Grégoire
                            Dec 15 at 19:38










                          • Why doesn't import java.util.function.*; count?
                            – candied_orange
                            Dec 15 at 19:44















                          up vote
                          7
                          down vote














                          Java (JDK), 81 bytes





                          n->{for(int i=0;i<n;)System.out.printf(i%2<1?"<%s%n":"%s>%n","-".repeat(i++/2));}


                          Try it online!



                          Explanations



                          n->{                  // int-accepting consumer
                          for(int i=0;i<n;) // for each i from 0 to n-1 included
                          System.out.printf( // output on stdout with a pattern
                          i%2<1 // if i is even:
                          ?"<%s%n" // use the left-arrow pattern
                          :"%s>%n", // else: use the right-arrow pattern
                          "-".repeat(i++/2) // fill the "%s" in the pattern with i/2 dashes, and increment i
                          ); //
                          } //





                          share|improve this answer























                          • Consider removing static reference to System.out
                            – candied_orange
                            Dec 15 at 18:11












                          • @candied_orange That's not self-contained.
                            – Olivier Grégoire
                            Dec 15 at 18:32










                          • How about done like this?
                            – candied_orange
                            Dec 15 at 18:52












                          • @candied_orange It's the same: the imports are required in the count.
                            – Olivier Grégoire
                            Dec 15 at 19:38










                          • Why doesn't import java.util.function.*; count?
                            – candied_orange
                            Dec 15 at 19:44













                          up vote
                          7
                          down vote










                          up vote
                          7
                          down vote










                          Java (JDK), 81 bytes





                          n->{for(int i=0;i<n;)System.out.printf(i%2<1?"<%s%n":"%s>%n","-".repeat(i++/2));}


                          Try it online!



                          Explanations



                          n->{                  // int-accepting consumer
                          for(int i=0;i<n;) // for each i from 0 to n-1 included
                          System.out.printf( // output on stdout with a pattern
                          i%2<1 // if i is even:
                          ?"<%s%n" // use the left-arrow pattern
                          :"%s>%n", // else: use the right-arrow pattern
                          "-".repeat(i++/2) // fill the "%s" in the pattern with i/2 dashes, and increment i
                          ); //
                          } //





                          share|improve this answer















                          Java (JDK), 81 bytes





                          n->{for(int i=0;i<n;)System.out.printf(i%2<1?"<%s%n":"%s>%n","-".repeat(i++/2));}


                          Try it online!



                          Explanations



                          n->{                  // int-accepting consumer
                          for(int i=0;i<n;) // for each i from 0 to n-1 included
                          System.out.printf( // output on stdout with a pattern
                          i%2<1 // if i is even:
                          ?"<%s%n" // use the left-arrow pattern
                          :"%s>%n", // else: use the right-arrow pattern
                          "-".repeat(i++/2) // fill the "%s" in the pattern with i/2 dashes, and increment i
                          ); //
                          } //






                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Dec 13 at 11:01

























                          answered Dec 12 at 16:41









                          Olivier Grégoire

                          8,74711843




                          8,74711843












                          • Consider removing static reference to System.out
                            – candied_orange
                            Dec 15 at 18:11












                          • @candied_orange That's not self-contained.
                            – Olivier Grégoire
                            Dec 15 at 18:32










                          • How about done like this?
                            – candied_orange
                            Dec 15 at 18:52












                          • @candied_orange It's the same: the imports are required in the count.
                            – Olivier Grégoire
                            Dec 15 at 19:38










                          • Why doesn't import java.util.function.*; count?
                            – candied_orange
                            Dec 15 at 19:44


















                          • Consider removing static reference to System.out
                            – candied_orange
                            Dec 15 at 18:11












                          • @candied_orange That's not self-contained.
                            – Olivier Grégoire
                            Dec 15 at 18:32










                          • How about done like this?
                            – candied_orange
                            Dec 15 at 18:52












                          • @candied_orange It's the same: the imports are required in the count.
                            – Olivier Grégoire
                            Dec 15 at 19:38










                          • Why doesn't import java.util.function.*; count?
                            – candied_orange
                            Dec 15 at 19:44
















                          Consider removing static reference to System.out
                          – candied_orange
                          Dec 15 at 18:11






                          Consider removing static reference to System.out
                          – candied_orange
                          Dec 15 at 18:11














                          @candied_orange That's not self-contained.
                          – Olivier Grégoire
                          Dec 15 at 18:32




                          @candied_orange That's not self-contained.
                          – Olivier Grégoire
                          Dec 15 at 18:32












                          How about done like this?
                          – candied_orange
                          Dec 15 at 18:52






                          How about done like this?
                          – candied_orange
                          Dec 15 at 18:52














                          @candied_orange It's the same: the imports are required in the count.
                          – Olivier Grégoire
                          Dec 15 at 19:38




                          @candied_orange It's the same: the imports are required in the count.
                          – Olivier Grégoire
                          Dec 15 at 19:38












                          Why doesn't import java.util.function.*; count?
                          – candied_orange
                          Dec 15 at 19:44




                          Why doesn't import java.util.function.*; count?
                          – candied_orange
                          Dec 15 at 19:44










                          up vote
                          6
                          down vote














                          Commodore BASIC V2 (C64), 94 bytes



                          0inputn:fOi=1ton:oniaN1gO1:?"<";
                          1on-(i<3)gO2:fOj=1.5toi/2:?"-";:nE
                          2on-nOiaN1gO3:?">";
                          3?:nE


                          Not entirely sure about the byte count, this is based on the text representation for typing the valid program. It's a bit shorter on disk (91 bytes) because BASIC V2 uses a "tokenized" representation of programs.



                          Online Demo



                          Slightly "ungolfed":



                          0 inputn:fori=1ton:oniand1goto1:print"<";    :rem read n from user, loop to n, if odd skip "<"
                          1 on-(i<3)goto2:forj=1.5toi/2:print"-";:next :rem skip for i<3, print (i-1)/2 times "-"
                          2 on-notiand1goto3:print">"; :rem if even skip ">"
                          3 print:next :rem newline and next loop iteration





                          share|improve this answer

























                            up vote
                            6
                            down vote














                            Commodore BASIC V2 (C64), 94 bytes



                            0inputn:fOi=1ton:oniaN1gO1:?"<";
                            1on-(i<3)gO2:fOj=1.5toi/2:?"-";:nE
                            2on-nOiaN1gO3:?">";
                            3?:nE


                            Not entirely sure about the byte count, this is based on the text representation for typing the valid program. It's a bit shorter on disk (91 bytes) because BASIC V2 uses a "tokenized" representation of programs.



                            Online Demo



                            Slightly "ungolfed":



                            0 inputn:fori=1ton:oniand1goto1:print"<";    :rem read n from user, loop to n, if odd skip "<"
                            1 on-(i<3)goto2:forj=1.5toi/2:print"-";:next :rem skip for i<3, print (i-1)/2 times "-"
                            2 on-notiand1goto3:print">"; :rem if even skip ">"
                            3 print:next :rem newline and next loop iteration





                            share|improve this answer























                              up vote
                              6
                              down vote










                              up vote
                              6
                              down vote










                              Commodore BASIC V2 (C64), 94 bytes



                              0inputn:fOi=1ton:oniaN1gO1:?"<";
                              1on-(i<3)gO2:fOj=1.5toi/2:?"-";:nE
                              2on-nOiaN1gO3:?">";
                              3?:nE


                              Not entirely sure about the byte count, this is based on the text representation for typing the valid program. It's a bit shorter on disk (91 bytes) because BASIC V2 uses a "tokenized" representation of programs.



                              Online Demo



                              Slightly "ungolfed":



                              0 inputn:fori=1ton:oniand1goto1:print"<";    :rem read n from user, loop to n, if odd skip "<"
                              1 on-(i<3)goto2:forj=1.5toi/2:print"-";:next :rem skip for i<3, print (i-1)/2 times "-"
                              2 on-notiand1goto3:print">"; :rem if even skip ">"
                              3 print:next :rem newline and next loop iteration





                              share|improve this answer













                              Commodore BASIC V2 (C64), 94 bytes



                              0inputn:fOi=1ton:oniaN1gO1:?"<";
                              1on-(i<3)gO2:fOj=1.5toi/2:?"-";:nE
                              2on-nOiaN1gO3:?">";
                              3?:nE


                              Not entirely sure about the byte count, this is based on the text representation for typing the valid program. It's a bit shorter on disk (91 bytes) because BASIC V2 uses a "tokenized" representation of programs.



                              Online Demo



                              Slightly "ungolfed":



                              0 inputn:fori=1ton:oniand1goto1:print"<";    :rem read n from user, loop to n, if odd skip "<"
                              1 on-(i<3)goto2:forj=1.5toi/2:print"-";:next :rem skip for i<3, print (i-1)/2 times "-"
                              2 on-notiand1goto3:print">"; :rem if even skip ">"
                              3 print:next :rem newline and next loop iteration






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered Dec 12 at 16:53









                              Felix Palmen

                              3,331525




                              3,331525






















                                  up vote
                                  6
                                  down vote














                                  Python 2, 54 bytes



                                  thanks to the and Jo King for fixing a bug.





                                  k=0
                                  exec"print k%2*'<'+k/2*'-'+~k%2*'>';k+=1;"*input()


                                  Try it online!






                                  share|improve this answer



















                                  • 3




                                    Your arrows have too many dashes; only every other one should lengthen by a dash.
                                    – xnor
                                    Dec 13 at 2:35






                                  • 1




                                    54 bytes
                                    – tsh
                                    Dec 13 at 5:23










                                  • 54 bytes with the arrows pointing the right way
                                    – Jo King
                                    Dec 13 at 9:52















                                  up vote
                                  6
                                  down vote














                                  Python 2, 54 bytes



                                  thanks to the and Jo King for fixing a bug.





                                  k=0
                                  exec"print k%2*'<'+k/2*'-'+~k%2*'>';k+=1;"*input()


                                  Try it online!






                                  share|improve this answer



















                                  • 3




                                    Your arrows have too many dashes; only every other one should lengthen by a dash.
                                    – xnor
                                    Dec 13 at 2:35






                                  • 1




                                    54 bytes
                                    – tsh
                                    Dec 13 at 5:23










                                  • 54 bytes with the arrows pointing the right way
                                    – Jo King
                                    Dec 13 at 9:52













                                  up vote
                                  6
                                  down vote










                                  up vote
                                  6
                                  down vote










                                  Python 2, 54 bytes



                                  thanks to the and Jo King for fixing a bug.





                                  k=0
                                  exec"print k%2*'<'+k/2*'-'+~k%2*'>';k+=1;"*input()


                                  Try it online!






                                  share|improve this answer















                                  Python 2, 54 bytes



                                  thanks to the and Jo King for fixing a bug.





                                  k=0
                                  exec"print k%2*'<'+k/2*'-'+~k%2*'>';k+=1;"*input()


                                  Try it online!







                                  share|improve this answer














                                  share|improve this answer



                                  share|improve this answer








                                  edited Dec 13 at 17:25

























                                  answered Dec 12 at 16:14









                                  ovs

                                  18.7k21059




                                  18.7k21059








                                  • 3




                                    Your arrows have too many dashes; only every other one should lengthen by a dash.
                                    – xnor
                                    Dec 13 at 2:35






                                  • 1




                                    54 bytes
                                    – tsh
                                    Dec 13 at 5:23










                                  • 54 bytes with the arrows pointing the right way
                                    – Jo King
                                    Dec 13 at 9:52














                                  • 3




                                    Your arrows have too many dashes; only every other one should lengthen by a dash.
                                    – xnor
                                    Dec 13 at 2:35






                                  • 1




                                    54 bytes
                                    – tsh
                                    Dec 13 at 5:23










                                  • 54 bytes with the arrows pointing the right way
                                    – Jo King
                                    Dec 13 at 9:52








                                  3




                                  3




                                  Your arrows have too many dashes; only every other one should lengthen by a dash.
                                  – xnor
                                  Dec 13 at 2:35




                                  Your arrows have too many dashes; only every other one should lengthen by a dash.
                                  – xnor
                                  Dec 13 at 2:35




                                  1




                                  1




                                  54 bytes
                                  – tsh
                                  Dec 13 at 5:23




                                  54 bytes
                                  – tsh
                                  Dec 13 at 5:23












                                  54 bytes with the arrows pointing the right way
                                  – Jo King
                                  Dec 13 at 9:52




                                  54 bytes with the arrows pointing the right way
                                  – Jo King
                                  Dec 13 at 9:52










                                  up vote
                                  5
                                  down vote













                                  Pyth, 17 bytes



                                  m_W%d2+*-/d2@"><


                                  Output is a list of strings. Try it online here.



                                  m_W%d2+*-/d2@"><"dQ   Implicit: Q=eval(input())
                                  Trailing "dQ inferred
                                  m Q Map [0-Q), as d, using:
                                  /d2 Floored division of d by 2
                                  *- Repeat "-" the above number of times
                                  + Append to the above...
                                  @"><"d Modular index d into "><" - yields ">" for even d, "<" for odd
                                  - examples: d=4 gives "-->", d=7 gives "---<"
                                  _W Reverse the above if...
                                  %d2 ... (d % 2) != 0
                                  Implicit print result of the map





                                  share|improve this answer

























                                    up vote
                                    5
                                    down vote













                                    Pyth, 17 bytes



                                    m_W%d2+*-/d2@"><


                                    Output is a list of strings. Try it online here.



                                    m_W%d2+*-/d2@"><"dQ   Implicit: Q=eval(input())
                                    Trailing "dQ inferred
                                    m Q Map [0-Q), as d, using:
                                    /d2 Floored division of d by 2
                                    *- Repeat "-" the above number of times
                                    + Append to the above...
                                    @"><"d Modular index d into "><" - yields ">" for even d, "<" for odd
                                    - examples: d=4 gives "-->", d=7 gives "---<"
                                    _W Reverse the above if...
                                    %d2 ... (d % 2) != 0
                                    Implicit print result of the map





                                    share|improve this answer























                                      up vote
                                      5
                                      down vote










                                      up vote
                                      5
                                      down vote









                                      Pyth, 17 bytes



                                      m_W%d2+*-/d2@"><


                                      Output is a list of strings. Try it online here.



                                      m_W%d2+*-/d2@"><"dQ   Implicit: Q=eval(input())
                                      Trailing "dQ inferred
                                      m Q Map [0-Q), as d, using:
                                      /d2 Floored division of d by 2
                                      *- Repeat "-" the above number of times
                                      + Append to the above...
                                      @"><"d Modular index d into "><" - yields ">" for even d, "<" for odd
                                      - examples: d=4 gives "-->", d=7 gives "---<"
                                      _W Reverse the above if...
                                      %d2 ... (d % 2) != 0
                                      Implicit print result of the map





                                      share|improve this answer












                                      Pyth, 17 bytes



                                      m_W%d2+*-/d2@"><


                                      Output is a list of strings. Try it online here.



                                      m_W%d2+*-/d2@"><"dQ   Implicit: Q=eval(input())
                                      Trailing "dQ inferred
                                      m Q Map [0-Q), as d, using:
                                      /d2 Floored division of d by 2
                                      *- Repeat "-" the above number of times
                                      + Append to the above...
                                      @"><"d Modular index d into "><" - yields ">" for even d, "<" for odd
                                      - examples: d=4 gives "-->", d=7 gives "---<"
                                      _W Reverse the above if...
                                      %d2 ... (d % 2) != 0
                                      Implicit print result of the map






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered Dec 12 at 16:16









                                      Sok

                                      3,509722




                                      3,509722






















                                          up vote
                                          5
                                          down vote













                                          Python 3, 53 bytes



                                          My first codegolf answer.



                                          lambda x:[i%2*"<"+i//2*"-"+~i%2*">"for i in range(x)]


                                          -10 bytes thanks to Jo King






                                          share|improve this answer










                                          New contributor




                                          van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                          Check out our Code of Conduct.














                                          • 1




                                            Welcome to PPCG! You can remove the brackets by putting the string after the number, use ~i instead of i+1 and use // to integer divide, assuming you're using Python 3. 53 bytes
                                            – Jo King
                                            Dec 13 at 9:45








                                          • 1




                                            I've linked the updated solution in my previous comment. If you like, you can use the auto-formatter in the TIO link to help create your answer
                                            – Jo King
                                            Dec 13 at 9:54















                                          up vote
                                          5
                                          down vote













                                          Python 3, 53 bytes



                                          My first codegolf answer.



                                          lambda x:[i%2*"<"+i//2*"-"+~i%2*">"for i in range(x)]


                                          -10 bytes thanks to Jo King






                                          share|improve this answer










                                          New contributor




                                          van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                          Check out our Code of Conduct.














                                          • 1




                                            Welcome to PPCG! You can remove the brackets by putting the string after the number, use ~i instead of i+1 and use // to integer divide, assuming you're using Python 3. 53 bytes
                                            – Jo King
                                            Dec 13 at 9:45








                                          • 1




                                            I've linked the updated solution in my previous comment. If you like, you can use the auto-formatter in the TIO link to help create your answer
                                            – Jo King
                                            Dec 13 at 9:54













                                          up vote
                                          5
                                          down vote










                                          up vote
                                          5
                                          down vote









                                          Python 3, 53 bytes



                                          My first codegolf answer.



                                          lambda x:[i%2*"<"+i//2*"-"+~i%2*">"for i in range(x)]


                                          -10 bytes thanks to Jo King






                                          share|improve this answer










                                          New contributor




                                          van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                          Check out our Code of Conduct.









                                          Python 3, 53 bytes



                                          My first codegolf answer.



                                          lambda x:[i%2*"<"+i//2*"-"+~i%2*">"for i in range(x)]


                                          -10 bytes thanks to Jo King







                                          share|improve this answer










                                          New contributor




                                          van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                          Check out our Code of Conduct.









                                          share|improve this answer



                                          share|improve this answer








                                          edited Dec 13 at 9:54





















                                          New contributor




                                          van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                          Check out our Code of Conduct.









                                          answered Dec 13 at 9:28









                                          van der Zon Stef

                                          1513




                                          1513




                                          New contributor




                                          van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                          Check out our Code of Conduct.





                                          New contributor





                                          van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                          Check out our Code of Conduct.






                                          van der Zon Stef is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                          Check out our Code of Conduct.








                                          • 1




                                            Welcome to PPCG! You can remove the brackets by putting the string after the number, use ~i instead of i+1 and use // to integer divide, assuming you're using Python 3. 53 bytes
                                            – Jo King
                                            Dec 13 at 9:45








                                          • 1




                                            I've linked the updated solution in my previous comment. If you like, you can use the auto-formatter in the TIO link to help create your answer
                                            – Jo King
                                            Dec 13 at 9:54














                                          • 1




                                            Welcome to PPCG! You can remove the brackets by putting the string after the number, use ~i instead of i+1 and use // to integer divide, assuming you're using Python 3. 53 bytes
                                            – Jo King
                                            Dec 13 at 9:45








                                          • 1




                                            I've linked the updated solution in my previous comment. If you like, you can use the auto-formatter in the TIO link to help create your answer
                                            – Jo King
                                            Dec 13 at 9:54








                                          1




                                          1




                                          Welcome to PPCG! You can remove the brackets by putting the string after the number, use ~i instead of i+1 and use // to integer divide, assuming you're using Python 3. 53 bytes
                                          – Jo King
                                          Dec 13 at 9:45






                                          Welcome to PPCG! You can remove the brackets by putting the string after the number, use ~i instead of i+1 and use // to integer divide, assuming you're using Python 3. 53 bytes
                                          – Jo King
                                          Dec 13 at 9:45






                                          1




                                          1




                                          I've linked the updated solution in my previous comment. If you like, you can use the auto-formatter in the TIO link to help create your answer
                                          – Jo King
                                          Dec 13 at 9:54




                                          I've linked the updated solution in my previous comment. If you like, you can use the auto-formatter in the TIO link to help create your answer
                                          – Jo King
                                          Dec 13 at 9:54










                                          up vote
                                          5
                                          down vote














                                          Self-modifying Brainfuck, 55 bytes



                                          Take input as character code.

                                          Only support input up to 255.

                                          Use null character to separate lines.



                                          Coincidentally, all arrow-drawing characters are used as BF commands. Unfortunately, it doesn't save any bytes (currently).



                                          >>,[<<[-<.>>+<]<<.>>.+>>-[<<<<<.>>>>[-<+<.>>].>-<]>]<>-


                                          Try it online!



                                          Explanation



                                           Code  |              Memory         | Output | Comment
                                          -------+-----------------------------+--------+--------------------------
                                          | '<' '>' '-' [0] 0 0 0 | |
                                          >>, | '<' '>' '-' 0 0 [x] 0 | |
                                          [ | | |
                                          | '<' '>' '-' l 0 [x] 0 | | l = arrow length
                                          <<[-< | | | copy l to next cell
                                          .>>+<] | | | and print '-'
                                          | '<' '>' '-' [0] l x 0 | ----- | there are l '-'s
                                          <<. | '<' [>] '-' 0 l x 0 | > |
                                          >>.+ | '<' '>' '-' [1] l x 0 | <null> |
                                          >>- | '<' '>' '-' 1 l [y] 0 | | y=x-1
                                          [ | | | execute if y>0
                                          <<<<<. | [<] '>' '-' 1 l y 0 | < |
                                          >>>> | '<' '>' '-' 1 [l] y 0 | |
                                          [-<+<. | | |
                                          >>] | '<' '>' '-' L [0] y 0 | ----- | L=l+1
                                          . | '<' '>' '-' L [0] y 0 | <null> |
                                          >-<]>] | | | decrement y
                                          <>- | | | do nothing, used as data





                                          share|improve this answer



























                                            up vote
                                            5
                                            down vote














                                            Self-modifying Brainfuck, 55 bytes



                                            Take input as character code.

                                            Only support input up to 255.

                                            Use null character to separate lines.



                                            Coincidentally, all arrow-drawing characters are used as BF commands. Unfortunately, it doesn't save any bytes (currently).



                                            >>,[<<[-<.>>+<]<<.>>.+>>-[<<<<<.>>>>[-<+<.>>].>-<]>]<>-


                                            Try it online!



                                            Explanation



                                             Code  |              Memory         | Output | Comment
                                            -------+-----------------------------+--------+--------------------------
                                            | '<' '>' '-' [0] 0 0 0 | |
                                            >>, | '<' '>' '-' 0 0 [x] 0 | |
                                            [ | | |
                                            | '<' '>' '-' l 0 [x] 0 | | l = arrow length
                                            <<[-< | | | copy l to next cell
                                            .>>+<] | | | and print '-'
                                            | '<' '>' '-' [0] l x 0 | ----- | there are l '-'s
                                            <<. | '<' [>] '-' 0 l x 0 | > |
                                            >>.+ | '<' '>' '-' [1] l x 0 | <null> |
                                            >>- | '<' '>' '-' 1 l [y] 0 | | y=x-1
                                            [ | | | execute if y>0
                                            <<<<<. | [<] '>' '-' 1 l y 0 | < |
                                            >>>> | '<' '>' '-' 1 [l] y 0 | |
                                            [-<+<. | | |
                                            >>] | '<' '>' '-' L [0] y 0 | ----- | L=l+1
                                            . | '<' '>' '-' L [0] y 0 | <null> |
                                            >-<]>] | | | decrement y
                                            <>- | | | do nothing, used as data





                                            share|improve this answer

























                                              up vote
                                              5
                                              down vote










                                              up vote
                                              5
                                              down vote










                                              Self-modifying Brainfuck, 55 bytes



                                              Take input as character code.

                                              Only support input up to 255.

                                              Use null character to separate lines.



                                              Coincidentally, all arrow-drawing characters are used as BF commands. Unfortunately, it doesn't save any bytes (currently).



                                              >>,[<<[-<.>>+<]<<.>>.+>>-[<<<<<.>>>>[-<+<.>>].>-<]>]<>-


                                              Try it online!



                                              Explanation



                                               Code  |              Memory         | Output | Comment
                                              -------+-----------------------------+--------+--------------------------
                                              | '<' '>' '-' [0] 0 0 0 | |
                                              >>, | '<' '>' '-' 0 0 [x] 0 | |
                                              [ | | |
                                              | '<' '>' '-' l 0 [x] 0 | | l = arrow length
                                              <<[-< | | | copy l to next cell
                                              .>>+<] | | | and print '-'
                                              | '<' '>' '-' [0] l x 0 | ----- | there are l '-'s
                                              <<. | '<' [>] '-' 0 l x 0 | > |
                                              >>.+ | '<' '>' '-' [1] l x 0 | <null> |
                                              >>- | '<' '>' '-' 1 l [y] 0 | | y=x-1
                                              [ | | | execute if y>0
                                              <<<<<. | [<] '>' '-' 1 l y 0 | < |
                                              >>>> | '<' '>' '-' 1 [l] y 0 | |
                                              [-<+<. | | |
                                              >>] | '<' '>' '-' L [0] y 0 | ----- | L=l+1
                                              . | '<' '>' '-' L [0] y 0 | <null> |
                                              >-<]>] | | | decrement y
                                              <>- | | | do nothing, used as data





                                              share|improve this answer















                                              Self-modifying Brainfuck, 55 bytes



                                              Take input as character code.

                                              Only support input up to 255.

                                              Use null character to separate lines.



                                              Coincidentally, all arrow-drawing characters are used as BF commands. Unfortunately, it doesn't save any bytes (currently).



                                              >>,[<<[-<.>>+<]<<.>>.+>>-[<<<<<.>>>>[-<+<.>>].>-<]>]<>-


                                              Try it online!



                                              Explanation



                                               Code  |              Memory         | Output | Comment
                                              -------+-----------------------------+--------+--------------------------
                                              | '<' '>' '-' [0] 0 0 0 | |
                                              >>, | '<' '>' '-' 0 0 [x] 0 | |
                                              [ | | |
                                              | '<' '>' '-' l 0 [x] 0 | | l = arrow length
                                              <<[-< | | | copy l to next cell
                                              .>>+<] | | | and print '-'
                                              | '<' '>' '-' [0] l x 0 | ----- | there are l '-'s
                                              <<. | '<' [>] '-' 0 l x 0 | > |
                                              >>.+ | '<' '>' '-' [1] l x 0 | <null> |
                                              >>- | '<' '>' '-' 1 l [y] 0 | | y=x-1
                                              [ | | | execute if y>0
                                              <<<<<. | [<] '>' '-' 1 l y 0 | < |
                                              >>>> | '<' '>' '-' 1 [l] y 0 | |
                                              [-<+<. | | |
                                              >>] | '<' '>' '-' L [0] y 0 | ----- | L=l+1
                                              . | '<' '>' '-' L [0] y 0 | <null> |
                                              >-<]>] | | | decrement y
                                              <>- | | | do nothing, used as data






                                              share|improve this answer














                                              share|improve this answer



                                              share|improve this answer








                                              edited Dec 13 at 11:12

























                                              answered Dec 13 at 10:48









                                              user202729

                                              13.9k12551




                                              13.9k12551






















                                                  up vote
                                                  5
                                                  down vote














                                                  Haskell, 51 44 bytes



                                                  -7 bytes thanks to xnor (using iterate over list-comprehension)!





                                                  (`take`do b<-iterate('-':)"";[b++">",'<':b])


                                                  Try it online!



                                                  Explanation / Ungolfed



                                                  Using do-notation saves us a concat, and using infix-notation allows a pointfree function with take, undoing these would give:



                                                  f n = take n $ concat [ [b++">", '<':b] | b <- iterate ('-':) "" ]





                                                  share|improve this answer



















                                                  • 1




                                                    You can shorten the part after do to b<-iterate('-':)"".
                                                    – xnor
                                                    Dec 13 at 5:33















                                                  up vote
                                                  5
                                                  down vote














                                                  Haskell, 51 44 bytes



                                                  -7 bytes thanks to xnor (using iterate over list-comprehension)!





                                                  (`take`do b<-iterate('-':)"";[b++">",'<':b])


                                                  Try it online!



                                                  Explanation / Ungolfed



                                                  Using do-notation saves us a concat, and using infix-notation allows a pointfree function with take, undoing these would give:



                                                  f n = take n $ concat [ [b++">", '<':b] | b <- iterate ('-':) "" ]





                                                  share|improve this answer



















                                                  • 1




                                                    You can shorten the part after do to b<-iterate('-':)"".
                                                    – xnor
                                                    Dec 13 at 5:33













                                                  up vote
                                                  5
                                                  down vote










                                                  up vote
                                                  5
                                                  down vote










                                                  Haskell, 51 44 bytes



                                                  -7 bytes thanks to xnor (using iterate over list-comprehension)!





                                                  (`take`do b<-iterate('-':)"";[b++">",'<':b])


                                                  Try it online!



                                                  Explanation / Ungolfed



                                                  Using do-notation saves us a concat, and using infix-notation allows a pointfree function with take, undoing these would give:



                                                  f n = take n $ concat [ [b++">", '<':b] | b <- iterate ('-':) "" ]





                                                  share|improve this answer















                                                  Haskell, 51 44 bytes



                                                  -7 bytes thanks to xnor (using iterate over list-comprehension)!





                                                  (`take`do b<-iterate('-':)"";[b++">",'<':b])


                                                  Try it online!



                                                  Explanation / Ungolfed



                                                  Using do-notation saves us a concat, and using infix-notation allows a pointfree function with take, undoing these would give:



                                                  f n = take n $ concat [ [b++">", '<':b] | b <- iterate ('-':) "" ]






                                                  share|improve this answer














                                                  share|improve this answer



                                                  share|improve this answer








                                                  edited Dec 13 at 14:04

























                                                  answered Dec 12 at 17:22









                                                  BMO

                                                  11.2k22084




                                                  11.2k22084








                                                  • 1




                                                    You can shorten the part after do to b<-iterate('-':)"".
                                                    – xnor
                                                    Dec 13 at 5:33














                                                  • 1




                                                    You can shorten the part after do to b<-iterate('-':)"".
                                                    – xnor
                                                    Dec 13 at 5:33








                                                  1




                                                  1




                                                  You can shorten the part after do to b<-iterate('-':)"".
                                                  – xnor
                                                  Dec 13 at 5:33




                                                  You can shorten the part after do to b<-iterate('-':)"".
                                                  – xnor
                                                  Dec 13 at 5:33










                                                  up vote
                                                  5
                                                  down vote













                                                  Japt -m, 16 15 13 bytes



                                                  g"><" iUUz ç-


                                                  Test it online



                                                  Explanation:



                                                  -m              // Map the program through [0...Input); U becomes the item
                                                  g"><" iUUz ç-
                                                  "><" // Literal "><"
                                                  g // Get the char at index U (with wrapping)
                                                  i // Insert:
                                                  U // At index U (with wrapping)
                                                  ç- // "-" repeated:
                                                  Uz // U/2 times





                                                  share|improve this answer



























                                                    up vote
                                                    5
                                                    down vote













                                                    Japt -m, 16 15 13 bytes



                                                    g"><" iUUz ç-


                                                    Test it online



                                                    Explanation:



                                                    -m              // Map the program through [0...Input); U becomes the item
                                                    g"><" iUUz ç-
                                                    "><" // Literal "><"
                                                    g // Get the char at index U (with wrapping)
                                                    i // Insert:
                                                    U // At index U (with wrapping)
                                                    ç- // "-" repeated:
                                                    Uz // U/2 times





                                                    share|improve this answer

























                                                      up vote
                                                      5
                                                      down vote










                                                      up vote
                                                      5
                                                      down vote









                                                      Japt -m, 16 15 13 bytes



                                                      g"><" iUUz ç-


                                                      Test it online



                                                      Explanation:



                                                      -m              // Map the program through [0...Input); U becomes the item
                                                      g"><" iUUz ç-
                                                      "><" // Literal "><"
                                                      g // Get the char at index U (with wrapping)
                                                      i // Insert:
                                                      U // At index U (with wrapping)
                                                      ç- // "-" repeated:
                                                      Uz // U/2 times





                                                      share|improve this answer














                                                      Japt -m, 16 15 13 bytes



                                                      g"><" iUUz ç-


                                                      Test it online



                                                      Explanation:



                                                      -m              // Map the program through [0...Input); U becomes the item
                                                      g"><" iUUz ç-
                                                      "><" // Literal "><"
                                                      g // Get the char at index U (with wrapping)
                                                      i // Insert:
                                                      U // At index U (with wrapping)
                                                      ç- // "-" repeated:
                                                      Uz // U/2 times






                                                      share|improve this answer














                                                      share|improve this answer



                                                      share|improve this answer








                                                      edited Dec 14 at 15:24

























                                                      answered Dec 12 at 19:49









                                                      Oliver

                                                      4,7301831




                                                      4,7301831






















                                                          up vote
                                                          4
                                                          down vote














                                                          PowerShell, 62 56 50 bytes





                                                          param($n)(0..$n|%{($j='-'*$_)+'>';"<$j"})[0..--$n]


                                                          Try it online!



                                                          Loops from 0 up to input $n, each iteration creating two arrow strings. Those are then indexed with 0..--$n to pull out the correct number of elements.



                                                          Saved 6 bytes thanks to KGlasier.






                                                          share|improve this answer























                                                          • Messing around with my own solution I found a way to cut a few bytes on yours: Can save 4 bytes by wrapping the loop in brackets and indexing directly. ie param($n)(0..$n|%{($j='-'*$_++)+'>';"<$j"})[0..--$n]. So now you don't have to write $x twice.
                                                            – KGlasier
                                                            Dec 12 at 17:00










                                                          • Also you can save two more bytes by not using ++ in ($j='-'*$_++) as you don't use $_ anywhere else.
                                                            – KGlasier
                                                            Dec 12 at 17:03








                                                          • 1




                                                            @KGlasier Awesome - thanks for the obvious golfs! :)
                                                            – AdmBorkBork
                                                            Dec 12 at 17:16















                                                          up vote
                                                          4
                                                          down vote














                                                          PowerShell, 62 56 50 bytes





                                                          param($n)(0..$n|%{($j='-'*$_)+'>';"<$j"})[0..--$n]


                                                          Try it online!



                                                          Loops from 0 up to input $n, each iteration creating two arrow strings. Those are then indexed with 0..--$n to pull out the correct number of elements.



                                                          Saved 6 bytes thanks to KGlasier.






                                                          share|improve this answer























                                                          • Messing around with my own solution I found a way to cut a few bytes on yours: Can save 4 bytes by wrapping the loop in brackets and indexing directly. ie param($n)(0..$n|%{($j='-'*$_++)+'>';"<$j"})[0..--$n]. So now you don't have to write $x twice.
                                                            – KGlasier
                                                            Dec 12 at 17:00










                                                          • Also you can save two more bytes by not using ++ in ($j='-'*$_++) as you don't use $_ anywhere else.
                                                            – KGlasier
                                                            Dec 12 at 17:03








                                                          • 1




                                                            @KGlasier Awesome - thanks for the obvious golfs! :)
                                                            – AdmBorkBork
                                                            Dec 12 at 17:16













                                                          up vote
                                                          4
                                                          down vote










                                                          up vote
                                                          4
                                                          down vote










                                                          PowerShell, 62 56 50 bytes





                                                          param($n)(0..$n|%{($j='-'*$_)+'>';"<$j"})[0..--$n]


                                                          Try it online!



                                                          Loops from 0 up to input $n, each iteration creating two arrow strings. Those are then indexed with 0..--$n to pull out the correct number of elements.



                                                          Saved 6 bytes thanks to KGlasier.






                                                          share|improve this answer















                                                          PowerShell, 62 56 50 bytes





                                                          param($n)(0..$n|%{($j='-'*$_)+'>';"<$j"})[0..--$n]


                                                          Try it online!



                                                          Loops from 0 up to input $n, each iteration creating two arrow strings. Those are then indexed with 0..--$n to pull out the correct number of elements.



                                                          Saved 6 bytes thanks to KGlasier.







                                                          share|improve this answer














                                                          share|improve this answer



                                                          share|improve this answer








                                                          edited Dec 12 at 17:16

























                                                          answered Dec 12 at 16:34









                                                          AdmBorkBork

                                                          26.1k364226




                                                          26.1k364226












                                                          • Messing around with my own solution I found a way to cut a few bytes on yours: Can save 4 bytes by wrapping the loop in brackets and indexing directly. ie param($n)(0..$n|%{($j='-'*$_++)+'>';"<$j"})[0..--$n]. So now you don't have to write $x twice.
                                                            – KGlasier
                                                            Dec 12 at 17:00










                                                          • Also you can save two more bytes by not using ++ in ($j='-'*$_++) as you don't use $_ anywhere else.
                                                            – KGlasier
                                                            Dec 12 at 17:03








                                                          • 1




                                                            @KGlasier Awesome - thanks for the obvious golfs! :)
                                                            – AdmBorkBork
                                                            Dec 12 at 17:16


















                                                          • Messing around with my own solution I found a way to cut a few bytes on yours: Can save 4 bytes by wrapping the loop in brackets and indexing directly. ie param($n)(0..$n|%{($j='-'*$_++)+'>';"<$j"})[0..--$n]. So now you don't have to write $x twice.
                                                            – KGlasier
                                                            Dec 12 at 17:00










                                                          • Also you can save two more bytes by not using ++ in ($j='-'*$_++) as you don't use $_ anywhere else.
                                                            – KGlasier
                                                            Dec 12 at 17:03








                                                          • 1




                                                            @KGlasier Awesome - thanks for the obvious golfs! :)
                                                            – AdmBorkBork
                                                            Dec 12 at 17:16
















                                                          Messing around with my own solution I found a way to cut a few bytes on yours: Can save 4 bytes by wrapping the loop in brackets and indexing directly. ie param($n)(0..$n|%{($j='-'*$_++)+'>';"<$j"})[0..--$n]. So now you don't have to write $x twice.
                                                          – KGlasier
                                                          Dec 12 at 17:00




                                                          Messing around with my own solution I found a way to cut a few bytes on yours: Can save 4 bytes by wrapping the loop in brackets and indexing directly. ie param($n)(0..$n|%{($j='-'*$_++)+'>';"<$j"})[0..--$n]. So now you don't have to write $x twice.
                                                          – KGlasier
                                                          Dec 12 at 17:00












                                                          Also you can save two more bytes by not using ++ in ($j='-'*$_++) as you don't use $_ anywhere else.
                                                          – KGlasier
                                                          Dec 12 at 17:03






                                                          Also you can save two more bytes by not using ++ in ($j='-'*$_++) as you don't use $_ anywhere else.
                                                          – KGlasier
                                                          Dec 12 at 17:03






                                                          1




                                                          1




                                                          @KGlasier Awesome - thanks for the obvious golfs! :)
                                                          – AdmBorkBork
                                                          Dec 12 at 17:16




                                                          @KGlasier Awesome - thanks for the obvious golfs! :)
                                                          – AdmBorkBork
                                                          Dec 12 at 17:16










                                                          up vote
                                                          4
                                                          down vote














                                                          Jelly, 15 bytes



                                                          ị⁾><;’H”-ẋƲṚ⁸¡)


                                                          Try it online!






                                                          share|improve this answer





















                                                          • -1 byte using tie: TIO.
                                                            – HyperNeutrino
                                                            Dec 14 at 14:29















                                                          up vote
                                                          4
                                                          down vote














                                                          Jelly, 15 bytes



                                                          ị⁾><;’H”-ẋƲṚ⁸¡)


                                                          Try it online!






                                                          share|improve this answer





















                                                          • -1 byte using tie: TIO.
                                                            – HyperNeutrino
                                                            Dec 14 at 14:29













                                                          up vote
                                                          4
                                                          down vote










                                                          up vote
                                                          4
                                                          down vote










                                                          Jelly, 15 bytes



                                                          ị⁾><;’H”-ẋƲṚ⁸¡)


                                                          Try it online!






                                                          share|improve this answer













                                                          Jelly, 15 bytes



                                                          ị⁾><;’H”-ẋƲṚ⁸¡)


                                                          Try it online!







                                                          share|improve this answer












                                                          share|improve this answer



                                                          share|improve this answer










                                                          answered Dec 12 at 17:17









                                                          Erik the Outgolfer

                                                          31.2k429102




                                                          31.2k429102












                                                          • -1 byte using tie: TIO.
                                                            – HyperNeutrino
                                                            Dec 14 at 14:29


















                                                          • -1 byte using tie: TIO.
                                                            – HyperNeutrino
                                                            Dec 14 at 14:29
















                                                          -1 byte using tie: TIO.
                                                          – HyperNeutrino
                                                          Dec 14 at 14:29




                                                          -1 byte using tie: TIO.
                                                          – HyperNeutrino
                                                          Dec 14 at 14:29










                                                          up vote
                                                          4
                                                          down vote














                                                          MathGolf, 17 15 bytes



                                                          Saved 2 bytes thanks to Jo King and Kevin Cruijssen



                                                          {ï½'-*'>ï¥╛Å⌡n


                                                          Try it online!



                                                          Explanation



                                                          The 15-byte approach is different compared to my original solution, I can't take any credit for the implementation.



                                                          {                 start block or arbitrary length
                                                          ï index of current loop, or length of last loop
                                                          ½ pop a : push(a//2 if int else a/2)
                                                          '- push single character "-"
                                                          * pop a, b : push(a*b)
                                                          '> push single character ">"
                                                          ï index of current loop, or length of last loop
                                                          ¥ modulo 2
                                                          ╛ if without else
                                                          Å start block of length 2
                                                          ⌡ decrement twice
                                                          swap top elements
                                                          n newline char, or map array with newlines





                                                          share|improve this answer























                                                          • How does the if/else work in MathGolf? I know how the if-without-else and else-without-if statements work, but how to create an if{ ... } else{ ... } in MathGolf with ¿? (Maybe I should post this in the chat instead of here.. But I might perhaps have a save of 1 byte if I can fix the if-else.)
                                                            – Kevin Cruijssen
                                                            Dec 13 at 10:20








                                                          • 1




                                                            @KevinCruijssen I think it works with the next two commands/blocks. e.g. ¿12 will push 1 if true, else 2, ¿Å3*Å1+ will add one if true else triple the next element
                                                            – Jo King
                                                            Dec 13 at 10:30












                                                          • @KevinCruijssen The if/else pops two operators or blocks from the code. Jo King is correct in his example, but you could also do ¿{"foo"}{"bar"} or ¿1{2}.
                                                            – maxb
                                                            Dec 13 at 10:34










                                                          • @JoKing I'll add a TODO to fix the docs for the slicing operators.
                                                            – maxb
                                                            Dec 13 at 10:35






                                                          • 1




                                                            15 bytes using @KevinCruijssen's solution
                                                            – Jo King
                                                            Dec 13 at 10:46

















                                                          up vote
                                                          4
                                                          down vote














                                                          MathGolf, 17 15 bytes



                                                          Saved 2 bytes thanks to Jo King and Kevin Cruijssen



                                                          {ï½'-*'>ï¥╛Å⌡n


                                                          Try it online!



                                                          Explanation



                                                          The 15-byte approach is different compared to my original solution, I can't take any credit for the implementation.



                                                          {                 start block or arbitrary length
                                                          ï index of current loop, or length of last loop
                                                          ½ pop a : push(a//2 if int else a/2)
                                                          '- push single character "-"
                                                          * pop a, b : push(a*b)
                                                          '> push single character ">"
                                                          ï index of current loop, or length of last loop
                                                          ¥ modulo 2
                                                          ╛ if without else
                                                          Å start block of length 2
                                                          ⌡ decrement twice
                                                          swap top elements
                                                          n newline char, or map array with newlines





                                                          share|improve this answer























                                                          • How does the if/else work in MathGolf? I know how the if-without-else and else-without-if statements work, but how to create an if{ ... } else{ ... } in MathGolf with ¿? (Maybe I should post this in the chat instead of here.. But I might perhaps have a save of 1 byte if I can fix the if-else.)
                                                            – Kevin Cruijssen
                                                            Dec 13 at 10:20








                                                          • 1




                                                            @KevinCruijssen I think it works with the next two commands/blocks. e.g. ¿12 will push 1 if true, else 2, ¿Å3*Å1+ will add one if true else triple the next element
                                                            – Jo King
                                                            Dec 13 at 10:30












                                                          • @KevinCruijssen The if/else pops two operators or blocks from the code. Jo King is correct in his example, but you could also do ¿{"foo"}{"bar"} or ¿1{2}.
                                                            – maxb
                                                            Dec 13 at 10:34










                                                          • @JoKing I'll add a TODO to fix the docs for the slicing operators.
                                                            – maxb
                                                            Dec 13 at 10:35






                                                          • 1




                                                            15 bytes using @KevinCruijssen's solution
                                                            – Jo King
                                                            Dec 13 at 10:46















                                                          up vote
                                                          4
                                                          down vote










                                                          up vote
                                                          4
                                                          down vote










                                                          MathGolf, 17 15 bytes



                                                          Saved 2 bytes thanks to Jo King and Kevin Cruijssen



                                                          {ï½'-*'>ï¥╛Å⌡n


                                                          Try it online!



                                                          Explanation



                                                          The 15-byte approach is different compared to my original solution, I can't take any credit for the implementation.



                                                          {                 start block or arbitrary length
                                                          ï index of current loop, or length of last loop
                                                          ½ pop a : push(a//2 if int else a/2)
                                                          '- push single character "-"
                                                          * pop a, b : push(a*b)
                                                          '> push single character ">"
                                                          ï index of current loop, or length of last loop
                                                          ¥ modulo 2
                                                          ╛ if without else
                                                          Å start block of length 2
                                                          ⌡ decrement twice
                                                          swap top elements
                                                          n newline char, or map array with newlines





                                                          share|improve this answer















                                                          MathGolf, 17 15 bytes



                                                          Saved 2 bytes thanks to Jo King and Kevin Cruijssen



                                                          {ï½'-*'>ï¥╛Å⌡n


                                                          Try it online!



                                                          Explanation



                                                          The 15-byte approach is different compared to my original solution, I can't take any credit for the implementation.



                                                          {                 start block or arbitrary length
                                                          ï index of current loop, or length of last loop
                                                          ½ pop a : push(a//2 if int else a/2)
                                                          '- push single character "-"
                                                          * pop a, b : push(a*b)
                                                          '> push single character ">"
                                                          ï index of current loop, or length of last loop
                                                          ¥ modulo 2
                                                          ╛ if without else
                                                          Å start block of length 2
                                                          ⌡ decrement twice
                                                          swap top elements
                                                          n newline char, or map array with newlines






                                                          share|improve this answer














                                                          share|improve this answer



                                                          share|improve this answer








                                                          edited Dec 13 at 11:47

























                                                          answered Dec 13 at 10:08









                                                          maxb

                                                          2,6331927




                                                          2,6331927












                                                          • How does the if/else work in MathGolf? I know how the if-without-else and else-without-if statements work, but how to create an if{ ... } else{ ... } in MathGolf with ¿? (Maybe I should post this in the chat instead of here.. But I might perhaps have a save of 1 byte if I can fix the if-else.)
                                                            – Kevin Cruijssen
                                                            Dec 13 at 10:20








                                                          • 1




                                                            @KevinCruijssen I think it works with the next two commands/blocks. e.g. ¿12 will push 1 if true, else 2, ¿Å3*Å1+ will add one if true else triple the next element
                                                            – Jo King
                                                            Dec 13 at 10:30












                                                          • @KevinCruijssen The if/else pops two operators or blocks from the code. Jo King is correct in his example, but you could also do ¿{"foo"}{"bar"} or ¿1{2}.
                                                            – maxb
                                                            Dec 13 at 10:34










                                                          • @JoKing I'll add a TODO to fix the docs for the slicing operators.
                                                            – maxb
                                                            Dec 13 at 10:35






                                                          • 1




                                                            15 bytes using @KevinCruijssen's solution
                                                            – Jo King
                                                            Dec 13 at 10:46




















                                                          • How does the if/else work in MathGolf? I know how the if-without-else and else-without-if statements work, but how to create an if{ ... } else{ ... } in MathGolf with ¿? (Maybe I should post this in the chat instead of here.. But I might perhaps have a save of 1 byte if I can fix the if-else.)
                                                            – Kevin Cruijssen
                                                            Dec 13 at 10:20








                                                          • 1




                                                            @KevinCruijssen I think it works with the next two commands/blocks. e.g. ¿12 will push 1 if true, else 2, ¿Å3*Å1+ will add one if true else triple the next element
                                                            – Jo King
                                                            Dec 13 at 10:30












                                                          • @KevinCruijssen The if/else pops two operators or blocks from the code. Jo King is correct in his example, but you could also do ¿{"foo"}{"bar"} or ¿1{2}.
                                                            – maxb
                                                            Dec 13 at 10:34










                                                          • @JoKing I'll add a TODO to fix the docs for the slicing operators.
                                                            – maxb
                                                            Dec 13 at 10:35






                                                          • 1




                                                            15 bytes using @KevinCruijssen's solution
                                                            – Jo King
                                                            Dec 13 at 10:46


















                                                          How does the if/else work in MathGolf? I know how the if-without-else and else-without-if statements work, but how to create an if{ ... } else{ ... } in MathGolf with ¿? (Maybe I should post this in the chat instead of here.. But I might perhaps have a save of 1 byte if I can fix the if-else.)
                                                          – Kevin Cruijssen
                                                          Dec 13 at 10:20






                                                          How does the if/else work in MathGolf? I know how the if-without-else and else-without-if statements work, but how to create an if{ ... } else{ ... } in MathGolf with ¿? (Maybe I should post this in the chat instead of here.. But I might perhaps have a save of 1 byte if I can fix the if-else.)
                                                          – Kevin Cruijssen
                                                          Dec 13 at 10:20






                                                          1




                                                          1




                                                          @KevinCruijssen I think it works with the next two commands/blocks. e.g. ¿12 will push 1 if true, else 2, ¿Å3*Å1+ will add one if true else triple the next element
                                                          – Jo King
                                                          Dec 13 at 10:30






                                                          @KevinCruijssen I think it works with the next two commands/blocks. e.g. ¿12 will push 1 if true, else 2, ¿Å3*Å1+ will add one if true else triple the next element
                                                          – Jo King
                                                          Dec 13 at 10:30














                                                          @KevinCruijssen The if/else pops two operators or blocks from the code. Jo King is correct in his example, but you could also do ¿{"foo"}{"bar"} or ¿1{2}.
                                                          – maxb
                                                          Dec 13 at 10:34




                                                          @KevinCruijssen The if/else pops two operators or blocks from the code. Jo King is correct in his example, but you could also do ¿{"foo"}{"bar"} or ¿1{2}.
                                                          – maxb
                                                          Dec 13 at 10:34












                                                          @JoKing I'll add a TODO to fix the docs for the slicing operators.
                                                          – maxb
                                                          Dec 13 at 10:35




                                                          @JoKing I'll add a TODO to fix the docs for the slicing operators.
                                                          – maxb
                                                          Dec 13 at 10:35




                                                          1




                                                          1




                                                          15 bytes using @KevinCruijssen's solution
                                                          – Jo King
                                                          Dec 13 at 10:46






                                                          15 bytes using @KevinCruijssen's solution
                                                          – Jo King
                                                          Dec 13 at 10:46












                                                          up vote
                                                          4
                                                          down vote














                                                          Japt -m, 14 bytes



                                                          "<>"¬hUUz ç-)q


                                                          Try it online!



                                                          Updated with a completely new method.



                                                          Explanation:



                                                                            #Implicitly map over the range [0..input) as U
                                                          "<>" #The string "<>"
                                                          ¬ #Split into the array ["<",">"]
                                                          hU ) #Replace the element at index U with wrapping:
                                                          - # The character '-'
                                                          ç # Repeated a number of times equal to
                                                          Uz # U integer divided by 2
                                                          q #Join the array to a string





                                                          share|improve this answer



















                                                          • 1




                                                            ç auto-casts its first parameter into a string, so you can drop the '.
                                                            – Oliver
                                                            Dec 13 at 0:21






                                                          • 1




                                                            You don't need the u method thanks to index wrapping so this can be 14 bytes.
                                                            – Shaggy
                                                            Dec 13 at 8:13















                                                          up vote
                                                          4
                                                          down vote














                                                          Japt -m, 14 bytes



                                                          "<>"¬hUUz ç-)q


                                                          Try it online!



                                                          Updated with a completely new method.



                                                          Explanation:



                                                                            #Implicitly map over the range [0..input) as U
                                                          "<>" #The string "<>"
                                                          ¬ #Split into the array ["<",">"]
                                                          hU ) #Replace the element at index U with wrapping:
                                                          - # The character '-'
                                                          ç # Repeated a number of times equal to
                                                          Uz # U integer divided by 2
                                                          q #Join the array to a string





                                                          share|improve this answer



















                                                          • 1




                                                            ç auto-casts its first parameter into a string, so you can drop the '.
                                                            – Oliver
                                                            Dec 13 at 0:21






                                                          • 1




                                                            You don't need the u method thanks to index wrapping so this can be 14 bytes.
                                                            – Shaggy
                                                            Dec 13 at 8:13













                                                          up vote
                                                          4
                                                          down vote










                                                          up vote
                                                          4
                                                          down vote










                                                          Japt -m, 14 bytes



                                                          "<>"¬hUUz ç-)q


                                                          Try it online!



                                                          Updated with a completely new method.



                                                          Explanation:



                                                                            #Implicitly map over the range [0..input) as U
                                                          "<>" #The string "<>"
                                                          ¬ #Split into the array ["<",">"]
                                                          hU ) #Replace the element at index U with wrapping:
                                                          - # The character '-'
                                                          ç # Repeated a number of times equal to
                                                          Uz # U integer divided by 2
                                                          q #Join the array to a string





                                                          share|improve this answer















                                                          Japt -m, 14 bytes



                                                          "<>"¬hUUz ç-)q


                                                          Try it online!



                                                          Updated with a completely new method.



                                                          Explanation:



                                                                            #Implicitly map over the range [0..input) as U
                                                          "<>" #The string "<>"
                                                          ¬ #Split into the array ["<",">"]
                                                          hU ) #Replace the element at index U with wrapping:
                                                          - # The character '-'
                                                          ç # Repeated a number of times equal to
                                                          Uz # U integer divided by 2
                                                          q #Join the array to a string






                                                          share|improve this answer














                                                          share|improve this answer



                                                          share|improve this answer








                                                          edited Dec 13 at 14:07

























                                                          answered Dec 12 at 18:09









                                                          Kamil Drakari

                                                          2,961416




                                                          2,961416








                                                          • 1




                                                            ç auto-casts its first parameter into a string, so you can drop the '.
                                                            – Oliver
                                                            Dec 13 at 0:21






                                                          • 1




                                                            You don't need the u method thanks to index wrapping so this can be 14 bytes.
                                                            – Shaggy
                                                            Dec 13 at 8:13














                                                          • 1




                                                            ç auto-casts its first parameter into a string, so you can drop the '.
                                                            – Oliver
                                                            Dec 13 at 0:21






                                                          • 1




                                                            You don't need the u method thanks to index wrapping so this can be 14 bytes.
                                                            – Shaggy
                                                            Dec 13 at 8:13








                                                          1




                                                          1




                                                          ç auto-casts its first parameter into a string, so you can drop the '.
                                                          – Oliver
                                                          Dec 13 at 0:21




                                                          ç auto-casts its first parameter into a string, so you can drop the '.
                                                          – Oliver
                                                          Dec 13 at 0:21




                                                          1




                                                          1




                                                          You don't need the u method thanks to index wrapping so this can be 14 bytes.
                                                          – Shaggy
                                                          Dec 13 at 8:13




                                                          You don't need the u method thanks to index wrapping so this can be 14 bytes.
                                                          – Shaggy
                                                          Dec 13 at 8:13










                                                          up vote
                                                          3
                                                          down vote













                                                          JavaScript (ES6), 58 bytes



                                                          Returns a space-separated string.





                                                          n=>(g=p=>n--?k++&1?`<${p} `+g(p+'-'):p+'> '+g(p):'')(k='')


                                                          Try it online!






                                                          share|improve this answer

























                                                            up vote
                                                            3
                                                            down vote













                                                            JavaScript (ES6), 58 bytes



                                                            Returns a space-separated string.





                                                            n=>(g=p=>n--?k++&1?`<${p} `+g(p+'-'):p+'> '+g(p):'')(k='')


                                                            Try it online!






                                                            share|improve this answer























                                                              up vote
                                                              3
                                                              down vote










                                                              up vote
                                                              3
                                                              down vote









                                                              JavaScript (ES6), 58 bytes



                                                              Returns a space-separated string.





                                                              n=>(g=p=>n--?k++&1?`<${p} `+g(p+'-'):p+'> '+g(p):'')(k='')


                                                              Try it online!






                                                              share|improve this answer












                                                              JavaScript (ES6), 58 bytes



                                                              Returns a space-separated string.





                                                              n=>(g=p=>n--?k++&1?`<${p} `+g(p+'-'):p+'> '+g(p):'')(k='')


                                                              Try it online!







                                                              share|improve this answer












                                                              share|improve this answer



                                                              share|improve this answer










                                                              answered Dec 12 at 16:30









                                                              Arnauld

                                                              71.7k688300




                                                              71.7k688300






















                                                                  up vote
                                                                  3
                                                                  down vote














                                                                  SNOBOL4 (CSNOBOL4), 123 122 118 bytes



                                                                  	N =INPUT - 1
                                                                  P H =X / 2
                                                                  Y =DUPL('-',H)
                                                                  OUTPUT =EQ(H,X - H) Y '>' :S(I)
                                                                  OUTPUT ='<' Y
                                                                  I X =LT(X,N) X + 1 :S(P)
                                                                  END


                                                                  Try it online!






                                                                  share|improve this answer



























                                                                    up vote
                                                                    3
                                                                    down vote














                                                                    SNOBOL4 (CSNOBOL4), 123 122 118 bytes



                                                                    	N =INPUT - 1
                                                                    P H =X / 2
                                                                    Y =DUPL('-',H)
                                                                    OUTPUT =EQ(H,X - H) Y '>' :S(I)
                                                                    OUTPUT ='<' Y
                                                                    I X =LT(X,N) X + 1 :S(P)
                                                                    END


                                                                    Try it online!






                                                                    share|improve this answer

























                                                                      up vote
                                                                      3
                                                                      down vote










                                                                      up vote
                                                                      3
                                                                      down vote










                                                                      SNOBOL4 (CSNOBOL4), 123 122 118 bytes



                                                                      	N =INPUT - 1
                                                                      P H =X / 2
                                                                      Y =DUPL('-',H)
                                                                      OUTPUT =EQ(H,X - H) Y '>' :S(I)
                                                                      OUTPUT ='<' Y
                                                                      I X =LT(X,N) X + 1 :S(P)
                                                                      END


                                                                      Try it online!






                                                                      share|improve this answer















                                                                      SNOBOL4 (CSNOBOL4), 123 122 118 bytes



                                                                      	N =INPUT - 1
                                                                      P H =X / 2
                                                                      Y =DUPL('-',H)
                                                                      OUTPUT =EQ(H,X - H) Y '>' :S(I)
                                                                      OUTPUT ='<' Y
                                                                      I X =LT(X,N) X + 1 :S(P)
                                                                      END


                                                                      Try it online!







                                                                      share|improve this answer














                                                                      share|improve this answer



                                                                      share|improve this answer








                                                                      edited Dec 12 at 17:23

























                                                                      answered Dec 12 at 16:39









                                                                      Giuseppe

                                                                      16.5k31052




                                                                      16.5k31052






















                                                                          up vote
                                                                          3
                                                                          down vote














                                                                          V, 22 bytes



                                                                          i>
                                                                          <Àñäkjjé-já-ñÀGjdG


                                                                          Try it online!






                                                                          share|improve this answer

















                                                                          • 5




                                                                            This looks like some weird scandinavian language
                                                                            – Pavel
                                                                            Dec 12 at 18:02















                                                                          up vote
                                                                          3
                                                                          down vote














                                                                          V, 22 bytes



                                                                          i>
                                                                          <Àñäkjjé-já-ñÀGjdG


                                                                          Try it online!






                                                                          share|improve this answer

















                                                                          • 5




                                                                            This looks like some weird scandinavian language
                                                                            – Pavel
                                                                            Dec 12 at 18:02













                                                                          up vote
                                                                          3
                                                                          down vote










                                                                          up vote
                                                                          3
                                                                          down vote










                                                                          V, 22 bytes



                                                                          i>
                                                                          <Àñäkjjé-já-ñÀGjdG


                                                                          Try it online!






                                                                          share|improve this answer













                                                                          V, 22 bytes



                                                                          i>
                                                                          <Àñäkjjé-já-ñÀGjdG


                                                                          Try it online!







                                                                          share|improve this answer












                                                                          share|improve this answer



                                                                          share|improve this answer










                                                                          answered Dec 12 at 17:50









                                                                          DJMcMayhem

                                                                          40.8k11145308




                                                                          40.8k11145308








                                                                          • 5




                                                                            This looks like some weird scandinavian language
                                                                            – Pavel
                                                                            Dec 12 at 18:02














                                                                          • 5




                                                                            This looks like some weird scandinavian language
                                                                            – Pavel
                                                                            Dec 12 at 18:02








                                                                          5




                                                                          5




                                                                          This looks like some weird scandinavian language
                                                                          – Pavel
                                                                          Dec 12 at 18:02




                                                                          This looks like some weird scandinavian language
                                                                          – Pavel
                                                                          Dec 12 at 18:02










                                                                          up vote
                                                                          3
                                                                          down vote














                                                                          Charcoal, 16 bytes



                                                                          NθFθ«⊘ι↓>‖T»Fθ‖T


                                                                          Try it online! Link is to verbose version of code. I had three 17-byte solutions before I eventually stumbled over this one. Explanation:



                                                                          Nθ


                                                                          Input n.



                                                                          Fθ«


                                                                          Repeat n times, 0-indexed.



                                                                          ⊘ι


                                                                          Draw a line of -s of length half the index (truncated).



                                                                          ↓>


                                                                          Draw the arrowhead and move to the next line.



                                                                          ‖T»


                                                                          Reflect everything, flipping the arrowheads.



                                                                          Fθ‖T


                                                                          The above loop has n reflections, but we need an even number of reflections, so perform another n reflections.






                                                                          share|improve this answer

























                                                                            up vote
                                                                            3
                                                                            down vote














                                                                            Charcoal, 16 bytes



                                                                            NθFθ«⊘ι↓>‖T»Fθ‖T


                                                                            Try it online! Link is to verbose version of code. I had three 17-byte solutions before I eventually stumbled over this one. Explanation:



                                                                            Nθ


                                                                            Input n.



                                                                            Fθ«


                                                                            Repeat n times, 0-indexed.



                                                                            ⊘ι


                                                                            Draw a line of -s of length half the index (truncated).



                                                                            ↓>


                                                                            Draw the arrowhead and move to the next line.



                                                                            ‖T»


                                                                            Reflect everything, flipping the arrowheads.



                                                                            Fθ‖T


                                                                            The above loop has n reflections, but we need an even number of reflections, so perform another n reflections.






                                                                            share|improve this answer























                                                                              up vote
                                                                              3
                                                                              down vote










                                                                              up vote
                                                                              3
                                                                              down vote










                                                                              Charcoal, 16 bytes



                                                                              NθFθ«⊘ι↓>‖T»Fθ‖T


                                                                              Try it online! Link is to verbose version of code. I had three 17-byte solutions before I eventually stumbled over this one. Explanation:



                                                                              Nθ


                                                                              Input n.



                                                                              Fθ«


                                                                              Repeat n times, 0-indexed.



                                                                              ⊘ι


                                                                              Draw a line of -s of length half the index (truncated).



                                                                              ↓>


                                                                              Draw the arrowhead and move to the next line.



                                                                              ‖T»


                                                                              Reflect everything, flipping the arrowheads.



                                                                              Fθ‖T


                                                                              The above loop has n reflections, but we need an even number of reflections, so perform another n reflections.






                                                                              share|improve this answer













                                                                              Charcoal, 16 bytes



                                                                              NθFθ«⊘ι↓>‖T»Fθ‖T


                                                                              Try it online! Link is to verbose version of code. I had three 17-byte solutions before I eventually stumbled over this one. Explanation:



                                                                              Nθ


                                                                              Input n.



                                                                              Fθ«


                                                                              Repeat n times, 0-indexed.



                                                                              ⊘ι


                                                                              Draw a line of -s of length half the index (truncated).



                                                                              ↓>


                                                                              Draw the arrowhead and move to the next line.



                                                                              ‖T»


                                                                              Reflect everything, flipping the arrowheads.



                                                                              Fθ‖T


                                                                              The above loop has n reflections, but we need an even number of reflections, so perform another n reflections.







                                                                              share|improve this answer












                                                                              share|improve this answer



                                                                              share|improve this answer










                                                                              answered Dec 12 at 20:59









                                                                              Neil

                                                                              78.9k744175




                                                                              78.9k744175






















                                                                                  up vote
                                                                                  3
                                                                                  down vote














                                                                                  Clean, 76 73 bytes



                                                                                  import StdEnv,StdLib
                                                                                  $n=take n[s\i<-inits['--'..],s<-[i++['>'],['<':i]]]


                                                                                  Try it online!



                                                                                  Uses the neat fact that ['-','-'..] is the same as ['--'..] to save a bit.






                                                                                  share|improve this answer

























                                                                                    up vote
                                                                                    3
                                                                                    down vote














                                                                                    Clean, 76 73 bytes



                                                                                    import StdEnv,StdLib
                                                                                    $n=take n[s\i<-inits['--'..],s<-[i++['>'],['<':i]]]


                                                                                    Try it online!



                                                                                    Uses the neat fact that ['-','-'..] is the same as ['--'..] to save a bit.






                                                                                    share|improve this answer























                                                                                      up vote
                                                                                      3
                                                                                      down vote










                                                                                      up vote
                                                                                      3
                                                                                      down vote










                                                                                      Clean, 76 73 bytes



                                                                                      import StdEnv,StdLib
                                                                                      $n=take n[s\i<-inits['--'..],s<-[i++['>'],['<':i]]]


                                                                                      Try it online!



                                                                                      Uses the neat fact that ['-','-'..] is the same as ['--'..] to save a bit.






                                                                                      share|improve this answer













                                                                                      Clean, 76 73 bytes



                                                                                      import StdEnv,StdLib
                                                                                      $n=take n[s\i<-inits['--'..],s<-[i++['>'],['<':i]]]


                                                                                      Try it online!



                                                                                      Uses the neat fact that ['-','-'..] is the same as ['--'..] to save a bit.







                                                                                      share|improve this answer












                                                                                      share|improve this answer



                                                                                      share|improve this answer










                                                                                      answered Dec 12 at 21:35









                                                                                      Οurous

                                                                                      6,31811032




                                                                                      6,31811032






















                                                                                          up vote
                                                                                          3
                                                                                          down vote













                                                                                          JavaScript, 49 bytes





                                                                                          f=n=>--n?f(n,l='')+(n%2?`
                                                                                          <`+l:`
                                                                                          ${l+='-'}>`):'>'


                                                                                          Try it online!






                                                                                          share|improve this answer























                                                                                          • Wow, pretty cool
                                                                                            – Levitator Imbalance
                                                                                            Dec 14 at 10:41










                                                                                          • ...but it throws on 10000, meanwhile my ES6 solution is still works :D Anyway, your solution is very cool)
                                                                                            – Levitator Imbalance
                                                                                            Dec 14 at 10:53

















                                                                                          up vote
                                                                                          3
                                                                                          down vote













                                                                                          JavaScript, 49 bytes





                                                                                          f=n=>--n?f(n,l='')+(n%2?`
                                                                                          <`+l:`
                                                                                          ${l+='-'}>`):'>'


                                                                                          Try it online!






                                                                                          share|improve this answer























                                                                                          • Wow, pretty cool
                                                                                            – Levitator Imbalance
                                                                                            Dec 14 at 10:41










                                                                                          • ...but it throws on 10000, meanwhile my ES6 solution is still works :D Anyway, your solution is very cool)
                                                                                            – Levitator Imbalance
                                                                                            Dec 14 at 10:53















                                                                                          up vote
                                                                                          3
                                                                                          down vote










                                                                                          up vote
                                                                                          3
                                                                                          down vote









                                                                                          JavaScript, 49 bytes





                                                                                          f=n=>--n?f(n,l='')+(n%2?`
                                                                                          <`+l:`
                                                                                          ${l+='-'}>`):'>'


                                                                                          Try it online!






                                                                                          share|improve this answer














                                                                                          JavaScript, 49 bytes





                                                                                          f=n=>--n?f(n,l='')+(n%2?`
                                                                                          <`+l:`
                                                                                          ${l+='-'}>`):'>'


                                                                                          Try it online!







                                                                                          share|improve this answer














                                                                                          share|improve this answer



                                                                                          share|improve this answer








                                                                                          edited Dec 13 at 5:49

























                                                                                          answered Dec 13 at 3:17









                                                                                          tsh

                                                                                          8,31511546




                                                                                          8,31511546












                                                                                          • Wow, pretty cool
                                                                                            – Levitator Imbalance
                                                                                            Dec 14 at 10:41










                                                                                          • ...but it throws on 10000, meanwhile my ES6 solution is still works :D Anyway, your solution is very cool)
                                                                                            – Levitator Imbalance
                                                                                            Dec 14 at 10:53




















                                                                                          • Wow, pretty cool
                                                                                            – Levitator Imbalance
                                                                                            Dec 14 at 10:41










                                                                                          • ...but it throws on 10000, meanwhile my ES6 solution is still works :D Anyway, your solution is very cool)
                                                                                            – Levitator Imbalance
                                                                                            Dec 14 at 10:53


















                                                                                          Wow, pretty cool
                                                                                          – Levitator Imbalance
                                                                                          Dec 14 at 10:41




                                                                                          Wow, pretty cool
                                                                                          – Levitator Imbalance
                                                                                          Dec 14 at 10:41












                                                                                          ...but it throws on 10000, meanwhile my ES6 solution is still works :D Anyway, your solution is very cool)
                                                                                          – Levitator Imbalance
                                                                                          Dec 14 at 10:53






                                                                                          ...but it throws on 10000, meanwhile my ES6 solution is still works :D Anyway, your solution is very cool)
                                                                                          – Levitator Imbalance
                                                                                          Dec 14 at 10:53












                                                                                          up vote
                                                                                          2
                                                                                          down vote














                                                                                          6502 machine code (C64), 49 bytes



                                                                                          00 C0 20 9B B7 A2 00 8A 4A A8 90 05 A9 3C 20 D2 FF A9 2D C0 00 F0 06 20 D2 FF 
                                                                                          88 D0 FA 8A 4A B0 05 A9 3E 20 D2 FF A9 0D 20 D2 FF E8 E4 65 D0 D7 60


                                                                                          Still quite a bit shorter than BASIC ;) This one has a number range only up to 255 because the natural integer size of the machine has only 8 bits.



                                                                                          Online demo



                                                                                          Usage: SYS49152,[n] (e.g. SYS49152,3 for the example from the challenge)



                                                                                          Commented disassembly:



                                                                                                   00 C0       .WORD $C000        ; load address
                                                                                          .C:c000 20 9B B7 JSR $B79B ; get unsigned byte from commandline
                                                                                          .C:c003 A2 00 LDX #$00 ; main loop counter
                                                                                          .C:c005 .loop:
                                                                                          .C:c005 8A TXA ; loop counter to accumulator
                                                                                          .C:c006 4A LSR A ; divide by 2, shift lowest bit to C
                                                                                          .C:c007 A8 TAY ; result to Y
                                                                                          .C:c008 90 05 BCC .toright ; C clear -> counter even, skip '<'
                                                                                          .C:c00a A9 3C LDA #$3C ; load character '<'
                                                                                          .C:c00c 20 D2 FF JSR $FFD2 ; output character
                                                                                          .C:c00f .toright:
                                                                                          .C:c00f A9 2D LDA #$2D ; load character '-'
                                                                                          .C:c011 C0 00 CPY #$00 ; counter/2 == 0 ? then no dashes
                                                                                          .C:c013 F0 06 BEQ .skipdashes
                                                                                          .C:c015 .printdashes:
                                                                                          .C:c015 20 D2 FF JSR $FFD2 ; output character
                                                                                          .C:c018 88 DEY ; decrement Y
                                                                                          .C:c019 D0 FA BNE .printdashes ; not 0 yet -> repeat
                                                                                          .C:c01b .skipdashes:
                                                                                          .C:c01b 8A TXA ; loop counter to accumulator
                                                                                          .C:c01c 4A LSR A ; shift lowest bit to C
                                                                                          .C:c01d B0 05 BCS .toleft ; C set -> counter odd, skip '>'
                                                                                          .C:c01f A9 3E LDA #$3E ; load character '>'
                                                                                          .C:c021 20 D2 FF JSR $FFD2 ; output character
                                                                                          .C:c024 .toleft:
                                                                                          .C:c024 A9 0D LDA #$0D ; load newline character
                                                                                          .C:c026 20 D2 FF JSR $FFD2 ; output character
                                                                                          .C:c029 E8 INX ; next loop iteration
                                                                                          .C:c02a E4 65 CPX $65 ; compare to command line argument
                                                                                          .C:c02c D0 D7 BNE .loop ; not reached yet -> repeat main loop
                                                                                          .C:c02e 60 RTS ; exit





                                                                                          share|improve this answer

























                                                                                            up vote
                                                                                            2
                                                                                            down vote














                                                                                            6502 machine code (C64), 49 bytes



                                                                                            00 C0 20 9B B7 A2 00 8A 4A A8 90 05 A9 3C 20 D2 FF A9 2D C0 00 F0 06 20 D2 FF 
                                                                                            88 D0 FA 8A 4A B0 05 A9 3E 20 D2 FF A9 0D 20 D2 FF E8 E4 65 D0 D7 60


                                                                                            Still quite a bit shorter than BASIC ;) This one has a number range only up to 255 because the natural integer size of the machine has only 8 bits.



                                                                                            Online demo



                                                                                            Usage: SYS49152,[n] (e.g. SYS49152,3 for the example from the challenge)



                                                                                            Commented disassembly:



                                                                                                     00 C0       .WORD $C000        ; load address
                                                                                            .C:c000 20 9B B7 JSR $B79B ; get unsigned byte from commandline
                                                                                            .C:c003 A2 00 LDX #$00 ; main loop counter
                                                                                            .C:c005 .loop:
                                                                                            .C:c005 8A TXA ; loop counter to accumulator
                                                                                            .C:c006 4A LSR A ; divide by 2, shift lowest bit to C
                                                                                            .C:c007 A8 TAY ; result to Y
                                                                                            .C:c008 90 05 BCC .toright ; C clear -> counter even, skip '<'
                                                                                            .C:c00a A9 3C LDA #$3C ; load character '<'
                                                                                            .C:c00c 20 D2 FF JSR $FFD2 ; output character
                                                                                            .C:c00f .toright:
                                                                                            .C:c00f A9 2D LDA #$2D ; load character '-'
                                                                                            .C:c011 C0 00 CPY #$00 ; counter/2 == 0 ? then no dashes
                                                                                            .C:c013 F0 06 BEQ .skipdashes
                                                                                            .C:c015 .printdashes:
                                                                                            .C:c015 20 D2 FF JSR $FFD2 ; output character
                                                                                            .C:c018 88 DEY ; decrement Y
                                                                                            .C:c019 D0 FA BNE .printdashes ; not 0 yet -> repeat
                                                                                            .C:c01b .skipdashes:
                                                                                            .C:c01b 8A TXA ; loop counter to accumulator
                                                                                            .C:c01c 4A LSR A ; shift lowest bit to C
                                                                                            .C:c01d B0 05 BCS .toleft ; C set -> counter odd, skip '>'
                                                                                            .C:c01f A9 3E LDA #$3E ; load character '>'
                                                                                            .C:c021 20 D2 FF JSR $FFD2 ; output character
                                                                                            .C:c024 .toleft:
                                                                                            .C:c024 A9 0D LDA #$0D ; load newline character
                                                                                            .C:c026 20 D2 FF JSR $FFD2 ; output character
                                                                                            .C:c029 E8 INX ; next loop iteration
                                                                                            .C:c02a E4 65 CPX $65 ; compare to command line argument
                                                                                            .C:c02c D0 D7 BNE .loop ; not reached yet -> repeat main loop
                                                                                            .C:c02e 60 RTS ; exit





                                                                                            share|improve this answer























                                                                                              up vote
                                                                                              2
                                                                                              down vote










                                                                                              up vote
                                                                                              2
                                                                                              down vote










                                                                                              6502 machine code (C64), 49 bytes



                                                                                              00 C0 20 9B B7 A2 00 8A 4A A8 90 05 A9 3C 20 D2 FF A9 2D C0 00 F0 06 20 D2 FF 
                                                                                              88 D0 FA 8A 4A B0 05 A9 3E 20 D2 FF A9 0D 20 D2 FF E8 E4 65 D0 D7 60


                                                                                              Still quite a bit shorter than BASIC ;) This one has a number range only up to 255 because the natural integer size of the machine has only 8 bits.



                                                                                              Online demo



                                                                                              Usage: SYS49152,[n] (e.g. SYS49152,3 for the example from the challenge)



                                                                                              Commented disassembly:



                                                                                                       00 C0       .WORD $C000        ; load address
                                                                                              .C:c000 20 9B B7 JSR $B79B ; get unsigned byte from commandline
                                                                                              .C:c003 A2 00 LDX #$00 ; main loop counter
                                                                                              .C:c005 .loop:
                                                                                              .C:c005 8A TXA ; loop counter to accumulator
                                                                                              .C:c006 4A LSR A ; divide by 2, shift lowest bit to C
                                                                                              .C:c007 A8 TAY ; result to Y
                                                                                              .C:c008 90 05 BCC .toright ; C clear -> counter even, skip '<'
                                                                                              .C:c00a A9 3C LDA #$3C ; load character '<'
                                                                                              .C:c00c 20 D2 FF JSR $FFD2 ; output character
                                                                                              .C:c00f .toright:
                                                                                              .C:c00f A9 2D LDA #$2D ; load character '-'
                                                                                              .C:c011 C0 00 CPY #$00 ; counter/2 == 0 ? then no dashes
                                                                                              .C:c013 F0 06 BEQ .skipdashes
                                                                                              .C:c015 .printdashes:
                                                                                              .C:c015 20 D2 FF JSR $FFD2 ; output character
                                                                                              .C:c018 88 DEY ; decrement Y
                                                                                              .C:c019 D0 FA BNE .printdashes ; not 0 yet -> repeat
                                                                                              .C:c01b .skipdashes:
                                                                                              .C:c01b 8A TXA ; loop counter to accumulator
                                                                                              .C:c01c 4A LSR A ; shift lowest bit to C
                                                                                              .C:c01d B0 05 BCS .toleft ; C set -> counter odd, skip '>'
                                                                                              .C:c01f A9 3E LDA #$3E ; load character '>'
                                                                                              .C:c021 20 D2 FF JSR $FFD2 ; output character
                                                                                              .C:c024 .toleft:
                                                                                              .C:c024 A9 0D LDA #$0D ; load newline character
                                                                                              .C:c026 20 D2 FF JSR $FFD2 ; output character
                                                                                              .C:c029 E8 INX ; next loop iteration
                                                                                              .C:c02a E4 65 CPX $65 ; compare to command line argument
                                                                                              .C:c02c D0 D7 BNE .loop ; not reached yet -> repeat main loop
                                                                                              .C:c02e 60 RTS ; exit





                                                                                              share|improve this answer













                                                                                              6502 machine code (C64), 49 bytes



                                                                                              00 C0 20 9B B7 A2 00 8A 4A A8 90 05 A9 3C 20 D2 FF A9 2D C0 00 F0 06 20 D2 FF 
                                                                                              88 D0 FA 8A 4A B0 05 A9 3E 20 D2 FF A9 0D 20 D2 FF E8 E4 65 D0 D7 60


                                                                                              Still quite a bit shorter than BASIC ;) This one has a number range only up to 255 because the natural integer size of the machine has only 8 bits.



                                                                                              Online demo



                                                                                              Usage: SYS49152,[n] (e.g. SYS49152,3 for the example from the challenge)



                                                                                              Commented disassembly:



                                                                                                       00 C0       .WORD $C000        ; load address
                                                                                              .C:c000 20 9B B7 JSR $B79B ; get unsigned byte from commandline
                                                                                              .C:c003 A2 00 LDX #$00 ; main loop counter
                                                                                              .C:c005 .loop:
                                                                                              .C:c005 8A TXA ; loop counter to accumulator
                                                                                              .C:c006 4A LSR A ; divide by 2, shift lowest bit to C
                                                                                              .C:c007 A8 TAY ; result to Y
                                                                                              .C:c008 90 05 BCC .toright ; C clear -> counter even, skip '<'
                                                                                              .C:c00a A9 3C LDA #$3C ; load character '<'
                                                                                              .C:c00c 20 D2 FF JSR $FFD2 ; output character
                                                                                              .C:c00f .toright:
                                                                                              .C:c00f A9 2D LDA #$2D ; load character '-'
                                                                                              .C:c011 C0 00 CPY #$00 ; counter/2 == 0 ? then no dashes
                                                                                              .C:c013 F0 06 BEQ .skipdashes
                                                                                              .C:c015 .printdashes:
                                                                                              .C:c015 20 D2 FF JSR $FFD2 ; output character
                                                                                              .C:c018 88 DEY ; decrement Y
                                                                                              .C:c019 D0 FA BNE .printdashes ; not 0 yet -> repeat
                                                                                              .C:c01b .skipdashes:
                                                                                              .C:c01b 8A TXA ; loop counter to accumulator
                                                                                              .C:c01c 4A LSR A ; shift lowest bit to C
                                                                                              .C:c01d B0 05 BCS .toleft ; C set -> counter odd, skip '>'
                                                                                              .C:c01f A9 3E LDA #$3E ; load character '>'
                                                                                              .C:c021 20 D2 FF JSR $FFD2 ; output character
                                                                                              .C:c024 .toleft:
                                                                                              .C:c024 A9 0D LDA #$0D ; load newline character
                                                                                              .C:c026 20 D2 FF JSR $FFD2 ; output character
                                                                                              .C:c029 E8 INX ; next loop iteration
                                                                                              .C:c02a E4 65 CPX $65 ; compare to command line argument
                                                                                              .C:c02c D0 D7 BNE .loop ; not reached yet -> repeat main loop
                                                                                              .C:c02e 60 RTS ; exit






                                                                                              share|improve this answer












                                                                                              share|improve this answer



                                                                                              share|improve this answer










                                                                                              answered Dec 12 at 21:59









                                                                                              Felix Palmen

                                                                                              3,331525




                                                                                              3,331525






















                                                                                                  up vote
                                                                                                  2
                                                                                                  down vote














                                                                                                  Perl 6, 39 bytes





                                                                                                  {map {'<'x$_%2~'-'x$_/2~'>'x$_%%2},^$_}


                                                                                                  Try it online!



                                                                                                  Anonymous code block that returns a list of lines.






                                                                                                  share|improve this answer

























                                                                                                    up vote
                                                                                                    2
                                                                                                    down vote














                                                                                                    Perl 6, 39 bytes





                                                                                                    {map {'<'x$_%2~'-'x$_/2~'>'x$_%%2},^$_}


                                                                                                    Try it online!



                                                                                                    Anonymous code block that returns a list of lines.






                                                                                                    share|improve this answer























                                                                                                      up vote
                                                                                                      2
                                                                                                      down vote










                                                                                                      up vote
                                                                                                      2
                                                                                                      down vote










                                                                                                      Perl 6, 39 bytes





                                                                                                      {map {'<'x$_%2~'-'x$_/2~'>'x$_%%2},^$_}


                                                                                                      Try it online!



                                                                                                      Anonymous code block that returns a list of lines.






                                                                                                      share|improve this answer













                                                                                                      Perl 6, 39 bytes





                                                                                                      {map {'<'x$_%2~'-'x$_/2~'>'x$_%%2},^$_}


                                                                                                      Try it online!



                                                                                                      Anonymous code block that returns a list of lines.







                                                                                                      share|improve this answer












                                                                                                      share|improve this answer



                                                                                                      share|improve this answer










                                                                                                      answered Dec 13 at 0:02









                                                                                                      Jo King

                                                                                                      20.5k246108




                                                                                                      20.5k246108






















                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote














                                                                                                          K (ngn/k), 31 29 bytes



                                                                                                          {"<->"x#2,x{(1=*x)_1,2-|x}}


                                                                                                          Try it online!



                                                                                                          first we generate lists with 0 instead of "<", 1 instead of "-", and 2 instead of ">":



                                                                                                          { } function with argument x



                                                                                                          x{...} apply the inner function x times, starting with an initial value of 0 and preserving intermediate results



                                                                                                          |x reverse



                                                                                                          2- replace 0 with 2 and vice versa, keep the 1s as they are



                                                                                                          1, prepend a 1



                                                                                                          (1=*x)_ is the first of x equal to 1? if yes, drop one element, otherwise drop 0 elements (do nothing)



                                                                                                          2, prepend a 2 for the initial ">" arrow



                                                                                                          x# we have a little too many lists, so take only the first x of them



                                                                                                          "<->" use the lists' elements (0/1/2) as indices in this string






                                                                                                          share|improve this answer























                                                                                                          • I would like to ask for an explanation (I haven't started learning K yet, I don't know which version to start with...)
                                                                                                            – Galen Ivanov
                                                                                                            Dec 13 at 12:14






                                                                                                          • 1




                                                                                                            @GalenIvanov i tried to write an explanation, i hope it makes sense. thanks for your interest in my favourite language :) there are multiple implementations with different advantages and disadvantages (kx's original, kona, oK and i'm working on my own). would you like to join the apl chat room so i can give you more details?
                                                                                                            – ngn
                                                                                                            Dec 13 at 12:44












                                                                                                          • Thank you, I'm already there
                                                                                                            – Galen Ivanov
                                                                                                            Dec 13 at 12:49















                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote














                                                                                                          K (ngn/k), 31 29 bytes



                                                                                                          {"<->"x#2,x{(1=*x)_1,2-|x}}


                                                                                                          Try it online!



                                                                                                          first we generate lists with 0 instead of "<", 1 instead of "-", and 2 instead of ">":



                                                                                                          { } function with argument x



                                                                                                          x{...} apply the inner function x times, starting with an initial value of 0 and preserving intermediate results



                                                                                                          |x reverse



                                                                                                          2- replace 0 with 2 and vice versa, keep the 1s as they are



                                                                                                          1, prepend a 1



                                                                                                          (1=*x)_ is the first of x equal to 1? if yes, drop one element, otherwise drop 0 elements (do nothing)



                                                                                                          2, prepend a 2 for the initial ">" arrow



                                                                                                          x# we have a little too many lists, so take only the first x of them



                                                                                                          "<->" use the lists' elements (0/1/2) as indices in this string






                                                                                                          share|improve this answer























                                                                                                          • I would like to ask for an explanation (I haven't started learning K yet, I don't know which version to start with...)
                                                                                                            – Galen Ivanov
                                                                                                            Dec 13 at 12:14






                                                                                                          • 1




                                                                                                            @GalenIvanov i tried to write an explanation, i hope it makes sense. thanks for your interest in my favourite language :) there are multiple implementations with different advantages and disadvantages (kx's original, kona, oK and i'm working on my own). would you like to join the apl chat room so i can give you more details?
                                                                                                            – ngn
                                                                                                            Dec 13 at 12:44












                                                                                                          • Thank you, I'm already there
                                                                                                            – Galen Ivanov
                                                                                                            Dec 13 at 12:49













                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          K (ngn/k), 31 29 bytes



                                                                                                          {"<->"x#2,x{(1=*x)_1,2-|x}}


                                                                                                          Try it online!



                                                                                                          first we generate lists with 0 instead of "<", 1 instead of "-", and 2 instead of ">":



                                                                                                          { } function with argument x



                                                                                                          x{...} apply the inner function x times, starting with an initial value of 0 and preserving intermediate results



                                                                                                          |x reverse



                                                                                                          2- replace 0 with 2 and vice versa, keep the 1s as they are



                                                                                                          1, prepend a 1



                                                                                                          (1=*x)_ is the first of x equal to 1? if yes, drop one element, otherwise drop 0 elements (do nothing)



                                                                                                          2, prepend a 2 for the initial ">" arrow



                                                                                                          x# we have a little too many lists, so take only the first x of them



                                                                                                          "<->" use the lists' elements (0/1/2) as indices in this string






                                                                                                          share|improve this answer















                                                                                                          K (ngn/k), 31 29 bytes



                                                                                                          {"<->"x#2,x{(1=*x)_1,2-|x}}


                                                                                                          Try it online!



                                                                                                          first we generate lists with 0 instead of "<", 1 instead of "-", and 2 instead of ">":



                                                                                                          { } function with argument x



                                                                                                          x{...} apply the inner function x times, starting with an initial value of 0 and preserving intermediate results



                                                                                                          |x reverse



                                                                                                          2- replace 0 with 2 and vice versa, keep the 1s as they are



                                                                                                          1, prepend a 1



                                                                                                          (1=*x)_ is the first of x equal to 1? if yes, drop one element, otherwise drop 0 elements (do nothing)



                                                                                                          2, prepend a 2 for the initial ">" arrow



                                                                                                          x# we have a little too many lists, so take only the first x of them



                                                                                                          "<->" use the lists' elements (0/1/2) as indices in this string







                                                                                                          share|improve this answer














                                                                                                          share|improve this answer



                                                                                                          share|improve this answer








                                                                                                          edited Dec 13 at 12:29

























                                                                                                          answered Dec 13 at 11:45









                                                                                                          ngn

                                                                                                          6,76312459




                                                                                                          6,76312459












                                                                                                          • I would like to ask for an explanation (I haven't started learning K yet, I don't know which version to start with...)
                                                                                                            – Galen Ivanov
                                                                                                            Dec 13 at 12:14






                                                                                                          • 1




                                                                                                            @GalenIvanov i tried to write an explanation, i hope it makes sense. thanks for your interest in my favourite language :) there are multiple implementations with different advantages and disadvantages (kx's original, kona, oK and i'm working on my own). would you like to join the apl chat room so i can give you more details?
                                                                                                            – ngn
                                                                                                            Dec 13 at 12:44












                                                                                                          • Thank you, I'm already there
                                                                                                            – Galen Ivanov
                                                                                                            Dec 13 at 12:49


















                                                                                                          • I would like to ask for an explanation (I haven't started learning K yet, I don't know which version to start with...)
                                                                                                            – Galen Ivanov
                                                                                                            Dec 13 at 12:14






                                                                                                          • 1




                                                                                                            @GalenIvanov i tried to write an explanation, i hope it makes sense. thanks for your interest in my favourite language :) there are multiple implementations with different advantages and disadvantages (kx's original, kona, oK and i'm working on my own). would you like to join the apl chat room so i can give you more details?
                                                                                                            – ngn
                                                                                                            Dec 13 at 12:44












                                                                                                          • Thank you, I'm already there
                                                                                                            – Galen Ivanov
                                                                                                            Dec 13 at 12:49
















                                                                                                          I would like to ask for an explanation (I haven't started learning K yet, I don't know which version to start with...)
                                                                                                          – Galen Ivanov
                                                                                                          Dec 13 at 12:14




                                                                                                          I would like to ask for an explanation (I haven't started learning K yet, I don't know which version to start with...)
                                                                                                          – Galen Ivanov
                                                                                                          Dec 13 at 12:14




                                                                                                          1




                                                                                                          1




                                                                                                          @GalenIvanov i tried to write an explanation, i hope it makes sense. thanks for your interest in my favourite language :) there are multiple implementations with different advantages and disadvantages (kx's original, kona, oK and i'm working on my own). would you like to join the apl chat room so i can give you more details?
                                                                                                          – ngn
                                                                                                          Dec 13 at 12:44






                                                                                                          @GalenIvanov i tried to write an explanation, i hope it makes sense. thanks for your interest in my favourite language :) there are multiple implementations with different advantages and disadvantages (kx's original, kona, oK and i'm working on my own). would you like to join the apl chat room so i can give you more details?
                                                                                                          – ngn
                                                                                                          Dec 13 at 12:44














                                                                                                          Thank you, I'm already there
                                                                                                          – Galen Ivanov
                                                                                                          Dec 13 at 12:49




                                                                                                          Thank you, I'm already there
                                                                                                          – Galen Ivanov
                                                                                                          Dec 13 at 12:49










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote














                                                                                                          05AB1E, 23 20 bytes



                                                                                                          FNÉD„><è'-N;∍«s_iR},


                                                                                                          Try it online!



                                                                                                          First time using 05AB1E or any other golfing language for that matter. Any ideas welcome.



                                                                                                          -3 from Kevin Cruijssen






                                                                                                          share|improve this answer



















                                                                                                          • 1




                                                                                                            Welcome to the world of 05AB1E, and nice first answer. +1 from me. :) "><" can be „>< to save a byte. There are builtins for 1, 2, and 3 char strings, being ', , and respectively. Here is a 18 bytes alternative I came up with, but perhaps it could be golfed a bit more. If you haven't seen it yet, we have a tips for golfing in 05AB1E page, and also feel free to ask anything in the chat.
                                                                                                            – Kevin Cruijssen
                                                                                                            Dec 13 at 8:54








                                                                                                          • 1




                                                                                                            @KevinCruijssen Thanks so much for your ideas. I don't feel right just using your code, as it feels fairly different from mine, but I did use the idea of modulo 2 as checking for if a number is odd. I also use the two char string idea. I would not mind at all if you posted the 18 byte version on your own.
                                                                                                            – nedla2004
                                                                                                            Dec 13 at 23:09










                                                                                                          • I've posted my answer in that case. :)
                                                                                                            – Kevin Cruijssen
                                                                                                            Dec 14 at 8:31















                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote














                                                                                                          05AB1E, 23 20 bytes



                                                                                                          FNÉD„><è'-N;∍«s_iR},


                                                                                                          Try it online!



                                                                                                          First time using 05AB1E or any other golfing language for that matter. Any ideas welcome.



                                                                                                          -3 from Kevin Cruijssen






                                                                                                          share|improve this answer



















                                                                                                          • 1




                                                                                                            Welcome to the world of 05AB1E, and nice first answer. +1 from me. :) "><" can be „>< to save a byte. There are builtins for 1, 2, and 3 char strings, being ', , and respectively. Here is a 18 bytes alternative I came up with, but perhaps it could be golfed a bit more. If you haven't seen it yet, we have a tips for golfing in 05AB1E page, and also feel free to ask anything in the chat.
                                                                                                            – Kevin Cruijssen
                                                                                                            Dec 13 at 8:54








                                                                                                          • 1




                                                                                                            @KevinCruijssen Thanks so much for your ideas. I don't feel right just using your code, as it feels fairly different from mine, but I did use the idea of modulo 2 as checking for if a number is odd. I also use the two char string idea. I would not mind at all if you posted the 18 byte version on your own.
                                                                                                            – nedla2004
                                                                                                            Dec 13 at 23:09










                                                                                                          • I've posted my answer in that case. :)
                                                                                                            – Kevin Cruijssen
                                                                                                            Dec 14 at 8:31













                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          05AB1E, 23 20 bytes



                                                                                                          FNÉD„><è'-N;∍«s_iR},


                                                                                                          Try it online!



                                                                                                          First time using 05AB1E or any other golfing language for that matter. Any ideas welcome.



                                                                                                          -3 from Kevin Cruijssen






                                                                                                          share|improve this answer















                                                                                                          05AB1E, 23 20 bytes



                                                                                                          FNÉD„><è'-N;∍«s_iR},


                                                                                                          Try it online!



                                                                                                          First time using 05AB1E or any other golfing language for that matter. Any ideas welcome.



                                                                                                          -3 from Kevin Cruijssen







                                                                                                          share|improve this answer














                                                                                                          share|improve this answer



                                                                                                          share|improve this answer








                                                                                                          edited Dec 13 at 23:05

























                                                                                                          answered Dec 12 at 19:55









                                                                                                          nedla2004

                                                                                                          4011410




                                                                                                          4011410








                                                                                                          • 1




                                                                                                            Welcome to the world of 05AB1E, and nice first answer. +1 from me. :) "><" can be „>< to save a byte. There are builtins for 1, 2, and 3 char strings, being ', , and respectively. Here is a 18 bytes alternative I came up with, but perhaps it could be golfed a bit more. If you haven't seen it yet, we have a tips for golfing in 05AB1E page, and also feel free to ask anything in the chat.
                                                                                                            – Kevin Cruijssen
                                                                                                            Dec 13 at 8:54








                                                                                                          • 1




                                                                                                            @KevinCruijssen Thanks so much for your ideas. I don't feel right just using your code, as it feels fairly different from mine, but I did use the idea of modulo 2 as checking for if a number is odd. I also use the two char string idea. I would not mind at all if you posted the 18 byte version on your own.
                                                                                                            – nedla2004
                                                                                                            Dec 13 at 23:09










                                                                                                          • I've posted my answer in that case. :)
                                                                                                            – Kevin Cruijssen
                                                                                                            Dec 14 at 8:31














                                                                                                          • 1




                                                                                                            Welcome to the world of 05AB1E, and nice first answer. +1 from me. :) "><" can be „>< to save a byte. There are builtins for 1, 2, and 3 char strings, being ', , and respectively. Here is a 18 bytes alternative I came up with, but perhaps it could be golfed a bit more. If you haven't seen it yet, we have a tips for golfing in 05AB1E page, and also feel free to ask anything in the chat.
                                                                                                            – Kevin Cruijssen
                                                                                                            Dec 13 at 8:54








                                                                                                          • 1




                                                                                                            @KevinCruijssen Thanks so much for your ideas. I don't feel right just using your code, as it feels fairly different from mine, but I did use the idea of modulo 2 as checking for if a number is odd. I also use the two char string idea. I would not mind at all if you posted the 18 byte version on your own.
                                                                                                            – nedla2004
                                                                                                            Dec 13 at 23:09










                                                                                                          • I've posted my answer in that case. :)
                                                                                                            – Kevin Cruijssen
                                                                                                            Dec 14 at 8:31








                                                                                                          1




                                                                                                          1




                                                                                                          Welcome to the world of 05AB1E, and nice first answer. +1 from me. :) "><" can be „>< to save a byte. There are builtins for 1, 2, and 3 char strings, being ', , and respectively. Here is a 18 bytes alternative I came up with, but perhaps it could be golfed a bit more. If you haven't seen it yet, we have a tips for golfing in 05AB1E page, and also feel free to ask anything in the chat.
                                                                                                          – Kevin Cruijssen
                                                                                                          Dec 13 at 8:54






                                                                                                          Welcome to the world of 05AB1E, and nice first answer. +1 from me. :) "><" can be „>< to save a byte. There are builtins for 1, 2, and 3 char strings, being ', , and respectively. Here is a 18 bytes alternative I came up with, but perhaps it could be golfed a bit more. If you haven't seen it yet, we have a tips for golfing in 05AB1E page, and also feel free to ask anything in the chat.
                                                                                                          – Kevin Cruijssen
                                                                                                          Dec 13 at 8:54






                                                                                                          1




                                                                                                          1




                                                                                                          @KevinCruijssen Thanks so much for your ideas. I don't feel right just using your code, as it feels fairly different from mine, but I did use the idea of modulo 2 as checking for if a number is odd. I also use the two char string idea. I would not mind at all if you posted the 18 byte version on your own.
                                                                                                          – nedla2004
                                                                                                          Dec 13 at 23:09




                                                                                                          @KevinCruijssen Thanks so much for your ideas. I don't feel right just using your code, as it feels fairly different from mine, but I did use the idea of modulo 2 as checking for if a number is odd. I also use the two char string idea. I would not mind at all if you posted the 18 byte version on your own.
                                                                                                          – nedla2004
                                                                                                          Dec 13 at 23:09












                                                                                                          I've posted my answer in that case. :)
                                                                                                          – Kevin Cruijssen
                                                                                                          Dec 14 at 8:31




                                                                                                          I've posted my answer in that case. :)
                                                                                                          – Kevin Cruijssen
                                                                                                          Dec 14 at 8:31










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote













                                                                                                          ES6, 96 82 79 70 bytes



                                                                                                          Try it online! (Thanks to @Oliver)



                                                                                                          n=>[...Array(n)].map((_,i)=>(i%2?"<":"")+"-".repeat(i/2)+(i%2?"":">"))





                                                                                                          share|improve this answer










                                                                                                          New contributor




                                                                                                          Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                          Check out our Code of Conduct.














                                                                                                          • 1




                                                                                                            Welcome to PPCG! By default, taking input as a variable is disallowed; you have to either make it a function (just stick a i=> in front of your code!) or from a command-line argument or STDIN or something.
                                                                                                            – HyperNeutrino
                                                                                                            Dec 14 at 14:40










                                                                                                          • @HyperNeutrino okay, edited answer. However, the most voted answer contains only the body of the function, but ok. Anyway I'm outsider)
                                                                                                            – Levitator Imbalance
                                                                                                            Dec 14 at 15:09












                                                                                                          • Can you link it? I don't think any of them are invalid, at least not the top few.
                                                                                                            – HyperNeutrino
                                                                                                            Dec 14 at 15:16






                                                                                                          • 1




                                                                                                            A few more bytes: Try it online
                                                                                                            – Oliver
                                                                                                            Dec 14 at 16:15






                                                                                                          • 1




                                                                                                            A few more bytes if you re-arrange that last ternary operator and remove the center parenthesis: Try it online
                                                                                                            – Oliver
                                                                                                            Dec 14 at 16:59















                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote













                                                                                                          ES6, 96 82 79 70 bytes



                                                                                                          Try it online! (Thanks to @Oliver)



                                                                                                          n=>[...Array(n)].map((_,i)=>(i%2?"<":"")+"-".repeat(i/2)+(i%2?"":">"))





                                                                                                          share|improve this answer










                                                                                                          New contributor




                                                                                                          Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                          Check out our Code of Conduct.














                                                                                                          • 1




                                                                                                            Welcome to PPCG! By default, taking input as a variable is disallowed; you have to either make it a function (just stick a i=> in front of your code!) or from a command-line argument or STDIN or something.
                                                                                                            – HyperNeutrino
                                                                                                            Dec 14 at 14:40










                                                                                                          • @HyperNeutrino okay, edited answer. However, the most voted answer contains only the body of the function, but ok. Anyway I'm outsider)
                                                                                                            – Levitator Imbalance
                                                                                                            Dec 14 at 15:09












                                                                                                          • Can you link it? I don't think any of them are invalid, at least not the top few.
                                                                                                            – HyperNeutrino
                                                                                                            Dec 14 at 15:16






                                                                                                          • 1




                                                                                                            A few more bytes: Try it online
                                                                                                            – Oliver
                                                                                                            Dec 14 at 16:15






                                                                                                          • 1




                                                                                                            A few more bytes if you re-arrange that last ternary operator and remove the center parenthesis: Try it online
                                                                                                            – Oliver
                                                                                                            Dec 14 at 16:59













                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote









                                                                                                          ES6, 96 82 79 70 bytes



                                                                                                          Try it online! (Thanks to @Oliver)



                                                                                                          n=>[...Array(n)].map((_,i)=>(i%2?"<":"")+"-".repeat(i/2)+(i%2?"":">"))





                                                                                                          share|improve this answer










                                                                                                          New contributor




                                                                                                          Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                          Check out our Code of Conduct.









                                                                                                          ES6, 96 82 79 70 bytes



                                                                                                          Try it online! (Thanks to @Oliver)



                                                                                                          n=>[...Array(n)].map((_,i)=>(i%2?"<":"")+"-".repeat(i/2)+(i%2?"":">"))






                                                                                                          share|improve this answer










                                                                                                          New contributor




                                                                                                          Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                          Check out our Code of Conduct.









                                                                                                          share|improve this answer



                                                                                                          share|improve this answer








                                                                                                          edited Dec 14 at 17:02





















                                                                                                          New contributor




                                                                                                          Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                          Check out our Code of Conduct.









                                                                                                          answered Dec 14 at 10:35









                                                                                                          Levitator Imbalance

                                                                                                          1213




                                                                                                          1213




                                                                                                          New contributor




                                                                                                          Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                          Check out our Code of Conduct.





                                                                                                          New contributor





                                                                                                          Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                          Check out our Code of Conduct.






                                                                                                          Levitator Imbalance is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                                          Check out our Code of Conduct.








                                                                                                          • 1




                                                                                                            Welcome to PPCG! By default, taking input as a variable is disallowed; you have to either make it a function (just stick a i=> in front of your code!) or from a command-line argument or STDIN or something.
                                                                                                            – HyperNeutrino
                                                                                                            Dec 14 at 14:40










                                                                                                          • @HyperNeutrino okay, edited answer. However, the most voted answer contains only the body of the function, but ok. Anyway I'm outsider)
                                                                                                            – Levitator Imbalance
                                                                                                            Dec 14 at 15:09












                                                                                                          • Can you link it? I don't think any of them are invalid, at least not the top few.
                                                                                                            – HyperNeutrino
                                                                                                            Dec 14 at 15:16






                                                                                                          • 1




                                                                                                            A few more bytes: Try it online
                                                                                                            – Oliver
                                                                                                            Dec 14 at 16:15






                                                                                                          • 1




                                                                                                            A few more bytes if you re-arrange that last ternary operator and remove the center parenthesis: Try it online
                                                                                                            – Oliver
                                                                                                            Dec 14 at 16:59














                                                                                                          • 1




                                                                                                            Welcome to PPCG! By default, taking input as a variable is disallowed; you have to either make it a function (just stick a i=> in front of your code!) or from a command-line argument or STDIN or something.
                                                                                                            – HyperNeutrino
                                                                                                            Dec 14 at 14:40










                                                                                                          • @HyperNeutrino okay, edited answer. However, the most voted answer contains only the body of the function, but ok. Anyway I'm outsider)
                                                                                                            – Levitator Imbalance
                                                                                                            Dec 14 at 15:09












                                                                                                          • Can you link it? I don't think any of them are invalid, at least not the top few.
                                                                                                            – HyperNeutrino
                                                                                                            Dec 14 at 15:16






                                                                                                          • 1




                                                                                                            A few more bytes: Try it online
                                                                                                            – Oliver
                                                                                                            Dec 14 at 16:15






                                                                                                          • 1




                                                                                                            A few more bytes if you re-arrange that last ternary operator and remove the center parenthesis: Try it online
                                                                                                            – Oliver
                                                                                                            Dec 14 at 16:59








                                                                                                          1




                                                                                                          1




                                                                                                          Welcome to PPCG! By default, taking input as a variable is disallowed; you have to either make it a function (just stick a i=> in front of your code!) or from a command-line argument or STDIN or something.
                                                                                                          – HyperNeutrino
                                                                                                          Dec 14 at 14:40




                                                                                                          Welcome to PPCG! By default, taking input as a variable is disallowed; you have to either make it a function (just stick a i=> in front of your code!) or from a command-line argument or STDIN or something.
                                                                                                          – HyperNeutrino
                                                                                                          Dec 14 at 14:40












                                                                                                          @HyperNeutrino okay, edited answer. However, the most voted answer contains only the body of the function, but ok. Anyway I'm outsider)
                                                                                                          – Levitator Imbalance
                                                                                                          Dec 14 at 15:09






                                                                                                          @HyperNeutrino okay, edited answer. However, the most voted answer contains only the body of the function, but ok. Anyway I'm outsider)
                                                                                                          – Levitator Imbalance
                                                                                                          Dec 14 at 15:09














                                                                                                          Can you link it? I don't think any of them are invalid, at least not the top few.
                                                                                                          – HyperNeutrino
                                                                                                          Dec 14 at 15:16




                                                                                                          Can you link it? I don't think any of them are invalid, at least not the top few.
                                                                                                          – HyperNeutrino
                                                                                                          Dec 14 at 15:16




                                                                                                          1




                                                                                                          1




                                                                                                          A few more bytes: Try it online
                                                                                                          – Oliver
                                                                                                          Dec 14 at 16:15




                                                                                                          A few more bytes: Try it online
                                                                                                          – Oliver
                                                                                                          Dec 14 at 16:15




                                                                                                          1




                                                                                                          1




                                                                                                          A few more bytes if you re-arrange that last ternary operator and remove the center parenthesis: Try it online
                                                                                                          – Oliver
                                                                                                          Dec 14 at 16:59




                                                                                                          A few more bytes if you re-arrange that last ternary operator and remove the center parenthesis: Try it online
                                                                                                          – Oliver
                                                                                                          Dec 14 at 16:59










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote














                                                                                                          Red, 109 108 bytes



                                                                                                          -1 byte thanks to NK1406



                                                                                                          func[n][repeat i n[print reduce[pick[pad/with pad/left/with]k: i% 2 + 1
                                                                                                          pick copy"<>"k i / 2 + k - 1 #"-"]]]


                                                                                                          Try it online!






                                                                                                          share|improve this answer



















                                                                                                          • 1




                                                                                                            -1 for removing a space
                                                                                                            – NK1406
                                                                                                            Dec 15 at 18:28










                                                                                                          • @NK1406 Thank you! I didn't know this is valid.
                                                                                                            – Galen Ivanov
                                                                                                            Dec 15 at 19:01















                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote














                                                                                                          Red, 109 108 bytes



                                                                                                          -1 byte thanks to NK1406



                                                                                                          func[n][repeat i n[print reduce[pick[pad/with pad/left/with]k: i% 2 + 1
                                                                                                          pick copy"<>"k i / 2 + k - 1 #"-"]]]


                                                                                                          Try it online!






                                                                                                          share|improve this answer



















                                                                                                          • 1




                                                                                                            -1 for removing a space
                                                                                                            – NK1406
                                                                                                            Dec 15 at 18:28










                                                                                                          • @NK1406 Thank you! I didn't know this is valid.
                                                                                                            – Galen Ivanov
                                                                                                            Dec 15 at 19:01













                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          Red, 109 108 bytes



                                                                                                          -1 byte thanks to NK1406



                                                                                                          func[n][repeat i n[print reduce[pick[pad/with pad/left/with]k: i% 2 + 1
                                                                                                          pick copy"<>"k i / 2 + k - 1 #"-"]]]


                                                                                                          Try it online!






                                                                                                          share|improve this answer















                                                                                                          Red, 109 108 bytes



                                                                                                          -1 byte thanks to NK1406



                                                                                                          func[n][repeat i n[print reduce[pick[pad/with pad/left/with]k: i% 2 + 1
                                                                                                          pick copy"<>"k i / 2 + k - 1 #"-"]]]


                                                                                                          Try it online!







                                                                                                          share|improve this answer














                                                                                                          share|improve this answer



                                                                                                          share|improve this answer








                                                                                                          edited Dec 15 at 19:00

























                                                                                                          answered Dec 13 at 9:18









                                                                                                          Galen Ivanov

                                                                                                          6,21711032




                                                                                                          6,21711032








                                                                                                          • 1




                                                                                                            -1 for removing a space
                                                                                                            – NK1406
                                                                                                            Dec 15 at 18:28










                                                                                                          • @NK1406 Thank you! I didn't know this is valid.
                                                                                                            – Galen Ivanov
                                                                                                            Dec 15 at 19:01














                                                                                                          • 1




                                                                                                            -1 for removing a space
                                                                                                            – NK1406
                                                                                                            Dec 15 at 18:28










                                                                                                          • @NK1406 Thank you! I didn't know this is valid.
                                                                                                            – Galen Ivanov
                                                                                                            Dec 15 at 19:01








                                                                                                          1




                                                                                                          1




                                                                                                          -1 for removing a space
                                                                                                          – NK1406
                                                                                                          Dec 15 at 18:28




                                                                                                          -1 for removing a space
                                                                                                          – NK1406
                                                                                                          Dec 15 at 18:28












                                                                                                          @NK1406 Thank you! I didn't know this is valid.
                                                                                                          – Galen Ivanov
                                                                                                          Dec 15 at 19:01




                                                                                                          @NK1406 Thank you! I didn't know this is valid.
                                                                                                          – Galen Ivanov
                                                                                                          Dec 15 at 19:01










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote














                                                                                                          C (gcc), 127 95 + 26 = 121 bytes





                                                                                                          i,j;f(x){for(i=0;i<x;putchar(10),i+=2){for(j=0;E;printf(">n%c",x-i-1?60:9);for(j=0;x-i-1&&E;}}


                                                                                                          Try it online!



                                                                                                          Compile with -DE=j<i/2;++j)putchar(45)



                                                                                                          -6 bytes from Logern



                                                                                                          Yay mismatched parentheses!



                                                                                                          Ungolfed:





                                                                                                          void f(int x) {
                                                                                                          for (int i = 0; i < x; i += 2) {
                                                                                                          for (int j = 0; j < i/2; ++j) {
                                                                                                          printf("-");
                                                                                                          }
                                                                                                          printf(">n");
                                                                                                          if (x - i - 1) { // Test for last loop: only print <-- if x is even
                                                                                                          printf("<");
                                                                                                          for (int j = 0; j < i/2; ++j) {
                                                                                                          printf("-");
                                                                                                          }
                                                                                                          }
                                                                                                          else {
                                                                                                          printf("t"); // This is the 9 in the x-i-1?60:9
                                                                                                          }
                                                                                                          printf("n");
                                                                                                          }
                                                                                                          }



                                                                                                          Try it online!






                                                                                                          share|improve this answer



















                                                                                                          • 1




                                                                                                            121 bytes with a -D compiler flag instead of #define - Try it online!
                                                                                                            – Logern
                                                                                                            Dec 14 at 17:31










                                                                                                          • Another -3 bytes by taking out the i=0 like this
                                                                                                            – NK1406
                                                                                                            Dec 15 at 18:19










                                                                                                          • @NK1406 Functions have to be reusable, that edit would break this rule. Try it online!
                                                                                                            – pizzapants184
                                                                                                            2 days ago










                                                                                                          • Suggest x+~i instead of x-i-1
                                                                                                            – ceilingcat
                                                                                                            2 days ago










                                                                                                          • @pizzapants184 Sorry, didn't see that!
                                                                                                            – NK1406
                                                                                                            2 days ago















                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote














                                                                                                          C (gcc), 127 95 + 26 = 121 bytes





                                                                                                          i,j;f(x){for(i=0;i<x;putchar(10),i+=2){for(j=0;E;printf(">n%c",x-i-1?60:9);for(j=0;x-i-1&&E;}}


                                                                                                          Try it online!



                                                                                                          Compile with -DE=j<i/2;++j)putchar(45)



                                                                                                          -6 bytes from Logern



                                                                                                          Yay mismatched parentheses!



                                                                                                          Ungolfed:





                                                                                                          void f(int x) {
                                                                                                          for (int i = 0; i < x; i += 2) {
                                                                                                          for (int j = 0; j < i/2; ++j) {
                                                                                                          printf("-");
                                                                                                          }
                                                                                                          printf(">n");
                                                                                                          if (x - i - 1) { // Test for last loop: only print <-- if x is even
                                                                                                          printf("<");
                                                                                                          for (int j = 0; j < i/2; ++j) {
                                                                                                          printf("-");
                                                                                                          }
                                                                                                          }
                                                                                                          else {
                                                                                                          printf("t"); // This is the 9 in the x-i-1?60:9
                                                                                                          }
                                                                                                          printf("n");
                                                                                                          }
                                                                                                          }



                                                                                                          Try it online!






                                                                                                          share|improve this answer



















                                                                                                          • 1




                                                                                                            121 bytes with a -D compiler flag instead of #define - Try it online!
                                                                                                            – Logern
                                                                                                            Dec 14 at 17:31










                                                                                                          • Another -3 bytes by taking out the i=0 like this
                                                                                                            – NK1406
                                                                                                            Dec 15 at 18:19










                                                                                                          • @NK1406 Functions have to be reusable, that edit would break this rule. Try it online!
                                                                                                            – pizzapants184
                                                                                                            2 days ago










                                                                                                          • Suggest x+~i instead of x-i-1
                                                                                                            – ceilingcat
                                                                                                            2 days ago










                                                                                                          • @pizzapants184 Sorry, didn't see that!
                                                                                                            – NK1406
                                                                                                            2 days ago













                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          up vote
                                                                                                          2
                                                                                                          down vote










                                                                                                          C (gcc), 127 95 + 26 = 121 bytes





                                                                                                          i,j;f(x){for(i=0;i<x;putchar(10),i+=2){for(j=0;E;printf(">n%c",x-i-1?60:9);for(j=0;x-i-1&&E;}}


                                                                                                          Try it online!



                                                                                                          Compile with -DE=j<i/2;++j)putchar(45)



                                                                                                          -6 bytes from Logern



                                                                                                          Yay mismatched parentheses!



                                                                                                          Ungolfed:





                                                                                                          void f(int x) {
                                                                                                          for (int i = 0; i < x; i += 2) {
                                                                                                          for (int j = 0; j < i/2; ++j) {
                                                                                                          printf("-");
                                                                                                          }
                                                                                                          printf(">n");
                                                                                                          if (x - i - 1) { // Test for last loop: only print <-- if x is even
                                                                                                          printf("<");
                                                                                                          for (int j = 0; j < i/2; ++j) {
                                                                                                          printf("-");
                                                                                                          }
                                                                                                          }
                                                                                                          else {
                                                                                                          printf("t"); // This is the 9 in the x-i-1?60:9
                                                                                                          }
                                                                                                          printf("n");
                                                                                                          }
                                                                                                          }



                                                                                                          Try it online!






                                                                                                          share|improve this answer















                                                                                                          C (gcc), 127 95 + 26 = 121 bytes





                                                                                                          i,j;f(x){for(i=0;i<x;putchar(10),i+=2){for(j=0;E;printf(">n%c",x-i-1?60:9);for(j=0;x-i-1&&E;}}


                                                                                                          Try it online!



                                                                                                          Compile with -DE=j<i/2;++j)putchar(45)



                                                                                                          -6 bytes from Logern



                                                                                                          Yay mismatched parentheses!



                                                                                                          Ungolfed:





                                                                                                          void f(int x) {
                                                                                                          for (int i = 0; i < x; i += 2) {
                                                                                                          for (int j = 0; j < i/2; ++j) {
                                                                                                          printf("-");
                                                                                                          }
                                                                                                          printf(">n");
                                                                                                          if (x - i - 1) { // Test for last loop: only print <-- if x is even
                                                                                                          printf("<");
                                                                                                          for (int j = 0; j < i/2; ++j) {
                                                                                                          printf("-");
                                                                                                          }
                                                                                                          }
                                                                                                          else {
                                                                                                          printf("t"); // This is the 9 in the x-i-1?60:9
                                                                                                          }
                                                                                                          printf("n");
                                                                                                          }
                                                                                                          }



                                                                                                          Try it online!







                                                                                                          share|improve this answer














                                                                                                          share|improve this answer



                                                                                                          share|improve this answer








                                                                                                          edited 2 days ago

























                                                                                                          answered Dec 14 at 6:23









                                                                                                          pizzapants184

                                                                                                          2,644716




                                                                                                          2,644716








                                                                                                          • 1




                                                                                                            121 bytes with a -D compiler flag instead of #define - Try it online!
                                                                                                            – Logern
                                                                                                            Dec 14 at 17:31










                                                                                                          • Another -3 bytes by taking out the i=0 like this
                                                                                                            – NK1406
                                                                                                            Dec 15 at 18:19










                                                                                                          • @NK1406 Functions have to be reusable, that edit would break this rule. Try it online!
                                                                                                            – pizzapants184
                                                                                                            2 days ago










                                                                                                          • Suggest x+~i instead of x-i-1
                                                                                                            – ceilingcat
                                                                                                            2 days ago










                                                                                                          • @pizzapants184 Sorry, didn't see that!
                                                                                                            – NK1406
                                                                                                            2 days ago














                                                                                                          • 1




                                                                                                            121 bytes with a -D compiler flag instead of #define - Try it online!
                                                                                                            – Logern
                                                                                                            Dec 14 at 17:31










                                                                                                          • Another -3 bytes by taking out the i=0 like this
                                                                                                            – NK1406
                                                                                                            Dec 15 at 18:19










                                                                                                          • @NK1406 Functions have to be reusable, that edit would break this rule. Try it online!
                                                                                                            – pizzapants184
                                                                                                            2 days ago










                                                                                                          • Suggest x+~i instead of x-i-1
                                                                                                            – ceilingcat
                                                                                                            2 days ago










                                                                                                          • @pizzapants184 Sorry, didn't see that!
                                                                                                            – NK1406
                                                                                                            2 days ago








                                                                                                          1




                                                                                                          1




                                                                                                          121 bytes with a -D compiler flag instead of #define - Try it online!
                                                                                                          – Logern
                                                                                                          Dec 14 at 17:31




                                                                                                          121 bytes with a -D compiler flag instead of #define - Try it online!
                                                                                                          – Logern
                                                                                                          Dec 14 at 17:31












                                                                                                          Another -3 bytes by taking out the i=0 like this
                                                                                                          – NK1406
                                                                                                          Dec 15 at 18:19




                                                                                                          Another -3 bytes by taking out the i=0 like this
                                                                                                          – NK1406
                                                                                                          Dec 15 at 18:19












                                                                                                          @NK1406 Functions have to be reusable, that edit would break this rule. Try it online!
                                                                                                          – pizzapants184
                                                                                                          2 days ago




                                                                                                          @NK1406 Functions have to be reusable, that edit would break this rule. Try it online!
                                                                                                          – pizzapants184
                                                                                                          2 days ago












                                                                                                          Suggest x+~i instead of x-i-1
                                                                                                          – ceilingcat
                                                                                                          2 days ago




                                                                                                          Suggest x+~i instead of x-i-1
                                                                                                          – ceilingcat
                                                                                                          2 days ago












                                                                                                          @pizzapants184 Sorry, didn't see that!
                                                                                                          – NK1406
                                                                                                          2 days ago




                                                                                                          @pizzapants184 Sorry, didn't see that!
                                                                                                          – NK1406
                                                                                                          2 days ago










                                                                                                          up vote
                                                                                                          1
                                                                                                          down vote













                                                                                                          Powershell, 51 bytes





                                                                                                          param($n)0..$n|%{'-'*$_+'>';'<'+'-'*$_}|?{$n---gt0}





                                                                                                          share|improve this answer

























                                                                                                            up vote
                                                                                                            1
                                                                                                            down vote













                                                                                                            Powershell, 51 bytes





                                                                                                            param($n)0..$n|%{'-'*$_+'>';'<'+'-'*$_}|?{$n---gt0}





                                                                                                            share|improve this answer























                                                                                                              up vote
                                                                                                              1
                                                                                                              down vote










                                                                                                              up vote
                                                                                                              1
                                                                                                              down vote









                                                                                                              Powershell, 51 bytes





                                                                                                              param($n)0..$n|%{'-'*$_+'>';'<'+'-'*$_}|?{$n---gt0}





                                                                                                              share|improve this answer












                                                                                                              Powershell, 51 bytes





                                                                                                              param($n)0..$n|%{'-'*$_+'>';'<'+'-'*$_}|?{$n---gt0}






                                                                                                              share|improve this answer












                                                                                                              share|improve this answer



                                                                                                              share|improve this answer










                                                                                                              answered Dec 12 at 17:47









                                                                                                              mazzy

                                                                                                              2,0151314




                                                                                                              2,0151314






















                                                                                                                  up vote
                                                                                                                  1
                                                                                                                  down vote














                                                                                                                  Perl 5, 44 bytes





                                                                                                                  map{$_/=2;say'<'x/./,'-'x$_,'>'x!$&}0..<>-1


                                                                                                                  Try it online!






                                                                                                                  share|improve this answer

























                                                                                                                    up vote
                                                                                                                    1
                                                                                                                    down vote














                                                                                                                    Perl 5, 44 bytes





                                                                                                                    map{$_/=2;say'<'x/./,'-'x$_,'>'x!$&}0..<>-1


                                                                                                                    Try it online!






                                                                                                                    share|improve this answer























                                                                                                                      up vote
                                                                                                                      1
                                                                                                                      down vote










                                                                                                                      up vote
                                                                                                                      1
                                                                                                                      down vote










                                                                                                                      Perl 5, 44 bytes





                                                                                                                      map{$_/=2;say'<'x/./,'-'x$_,'>'x!$&}0..<>-1


                                                                                                                      Try it online!






                                                                                                                      share|improve this answer













                                                                                                                      Perl 5, 44 bytes





                                                                                                                      map{$_/=2;say'<'x/./,'-'x$_,'>'x!$&}0..<>-1


                                                                                                                      Try it online!







                                                                                                                      share|improve this answer












                                                                                                                      share|improve this answer



                                                                                                                      share|improve this answer










                                                                                                                      answered Dec 12 at 22:25









                                                                                                                      Xcali

                                                                                                                      5,148520




                                                                                                                      5,148520






















                                                                                                                          1 2
                                                                                                                          next

















                                                                                                                          draft saved

                                                                                                                          draft discarded




















































                                                                                                                          If this is an answer to a challenge…




                                                                                                                          • …Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.


                                                                                                                          • …Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
                                                                                                                            Explanations of your answer make it more interesting to read and are very much encouraged.


                                                                                                                          • …Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.



                                                                                                                          More generally…




                                                                                                                          • …Please make sure to answer the question and provide sufficient detail.


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