Converting a text file to Map<String, List> using lambda
7
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>> by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
7
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>> by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
7
7
7
1
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>> by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am trying to convert the following text input file:
A=groupA1
A=groupA2
A=groupA3
B=groupB1
B=groupB2
into Map<String, List<String>> by splitting each line on "="
So far I manged to get this sort of output:
KEY: A
VALUE: A=groupA1
VALUE: A=groupA2
VALUE: A=groupA3
KEY: B
VALUE: B=groupB1
VALUE: B=groupB2
using such code:
File reqFile = new File("test.config");
try (Stream<String> stream = Files.lines(reqFile.toPath())) {
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0]));
for (Map.Entry<String, List<String>> entry: conf.entrySet()) {
System.out.println("KEY: " + entry.getKey());
for (String value : entry.getValue()) {
System.out.println("VALUE: " + value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
How to tweak the above lambda to get something like this:
KEY: A
VALUE: groupA1
VALUE: groupA2
VALUE: groupA3
KEY: B
VALUE: groupB1
VALUE: groupB2
java java-8 java-stream
java java-8 java-stream
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 hours ago
Deadpool
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 hours ago
Deadpool
5,1822528
edited 3 hours ago
Deadpool
5,1822528
edited 3 hours ago
Deadpool
5,1822528
5,1822528
asked 3 hours ago
BartDBartD
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
BartDBartD
383
asked 3 hours ago
BartDBartD
383
383
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
BartD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
2
2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago
add a comment |
3 Answers
3
active
oldest
votes
3
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
2 hours ago
add a comment |
2
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
0
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 6 mins ago
Donald RaabDonald Raab
4,26112029
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
2 hours ago
add a comment |
3
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
2 hours ago
add a comment |
3
3
3
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
Map and collect:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(HashMap::new,
(map, item) -> map.computeIfAbsent(item.get(0), k -> new ArrayList<>()).add(item.get(1)),
HashMap::putAll);
Or map and group by:
Map<String, List<String>> res = lines.stream()
.map(s -> Arrays.asList(s.split("=")))
.collect(Collectors.groupingBy(s -> s.get(0), Collectors.mapping(v->v.get(1), Collectors.toList())));
Stream.collectdocumentation
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
edited 2 hours ago
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
answered 3 hours ago
Michał ZioberMichał Ziober
12.9k967101
12.9k967101
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
2 hours ago
add a comment |
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
2 hours ago
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
This one also works nicely! Thank you @Michał Ziober
– BartD
3 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
2 hours ago
No problem. Mapping solves problem with splitting items two times. I have also added a version with grouping by collectors. If you think it is helpful for you, please, upvote it.
– Michał Ziober
2 hours ago
add a comment |
2
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
2
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
2
2
2
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
Use Collectors.mapping while groupingBy, for more information look at this doc-with-example
Map<String, List<String>> conf = stream.
collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));
System.out.println(conf); //{A=[groupA1, groupA2, groupA3], B=[groupB1, groupB2]}
answered 3 hours ago
DeadpoolDeadpool
5,1822528
edited 3 hours ago
answered 3 hours ago
DeadpoolDeadpool
5,1822528
answered 3 hours ago
DeadpoolDeadpool
5,1822528
answered 3 hours ago
DeadpoolDeadpool
5,1822528
5,1822528
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
add a comment |
1
That is exactly what I was looking for!Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList())));and the output:KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2
– BartD
3 hours ago
1
1
That is exactly what I was looking for!
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2– BartD
3 hours ago
That is exactly what I was looking for!
Map<String, List<String>> conf = stream.collect(Collectors.groupingBy(s -> s.split("=")[0], Collectors.mapping(v->v.split("=")[1], Collectors.toList()))); and the output: KEY: A VALUE: groupA1 VALUE: groupA2 VALUE: groupA3 KEY: B VALUE: groupB1 VALUE: groupB2– BartD
3 hours ago
add a comment |
0
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 6 mins ago
Donald RaabDonald Raab
4,26112029
add a comment |
0
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 6 mins ago
Donald RaabDonald Raab
4,26112029
add a comment |
0
0
0
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 6 mins ago
Donald RaabDonald Raab
4,26112029
If you are open to using a third-party library, the following will work using Eclipse Collections.
ListMultimap<String, String> strings = stream
.map(s -> s.split("="))
.collect(Collectors2.toListMultimap(a -> a[0], a -> a[1]));
Collectors2.toListMultimap takes a Function to calculate the key and a separate Function to calculate the value. The ListMultimap<K, V> type is equivalent to Map<K, List<V>>.
Note: I am a committer for Eclipse Collections.
answered 6 mins ago
Donald RaabDonald Raab
4,26112029
answered 6 mins ago
Donald RaabDonald Raab
4,26112029
answered 6 mins ago
Donald RaabDonald Raab
4,26112029
answered 6 mins ago
Donald RaabDonald Raab
4,26112029
4,26112029
add a comment |
add a comment |
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BartD is a new contributor. Be nice, and check out our Code of Conduct.
BartD is a new contributor. Be nice, and check out our Code of Conduct.
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2
much like regular expressions, once you decide to solve a problem with lambdas now you have two problems ( if you do not 100% comprehend what you are doing and why you are doing it that way ). Regular non-lambda solution would be far more efficient and more importantly readable and maintainable.
– Jarrod Roberson
3 hours ago