Chemical composition of seawater












4














Is it true that the sea water is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals? The chemical formula of water is $ce{H2O}$ (two hydrogen and one oxgen) that shows that the number of hydrogen is greater than that of oxygen.



If the number of hydrogen is greater, then why does the sea water consist of $11%$ hydrogen and $86%$ oxygen, which is lesser than the oxygen?



The book which I am reading says which is confusing me:




... Seawater is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals, consisting mainly of sodium and chlorine.











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    4














    Is it true that the sea water is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals? The chemical formula of water is $ce{H2O}$ (two hydrogen and one oxgen) that shows that the number of hydrogen is greater than that of oxygen.



    If the number of hydrogen is greater, then why does the sea water consist of $11%$ hydrogen and $86%$ oxygen, which is lesser than the oxygen?



    The book which I am reading says which is confusing me:




    ... Seawater is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals, consisting mainly of sodium and chlorine.











    share|improve this question









    New contributor




    Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      4












      4








      4







      Is it true that the sea water is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals? The chemical formula of water is $ce{H2O}$ (two hydrogen and one oxgen) that shows that the number of hydrogen is greater than that of oxygen.



      If the number of hydrogen is greater, then why does the sea water consist of $11%$ hydrogen and $86%$ oxygen, which is lesser than the oxygen?



      The book which I am reading says which is confusing me:




      ... Seawater is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals, consisting mainly of sodium and chlorine.











      share|improve this question









      New contributor




      Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Is it true that the sea water is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals? The chemical formula of water is $ce{H2O}$ (two hydrogen and one oxgen) that shows that the number of hydrogen is greater than that of oxygen.



      If the number of hydrogen is greater, then why does the sea water consist of $11%$ hydrogen and $86%$ oxygen, which is lesser than the oxygen?



      The book which I am reading says which is confusing me:




      ... Seawater is composed of about $86%$ oxygen, $11%$ hydrogen and $3%$ of minerals, consisting mainly of sodium and chlorine.








      water elements






      share|improve this question









      New contributor




      Ahmed is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









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      edited Dec 17 at 20:32









      andselisk

      13k64598




      13k64598






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      asked Dec 17 at 19:10









      Ahmed

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          2 Answers
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          8














          The book that you're reading is measuring by mass.



          If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.






          share|improve this answer





























            7














            As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:



            begin{array}{llr}
            hline
            text{Element} & rho_i/pu{mg L-1} & omega/% \
            hline
            ce{O} & pu{8.57E5} & 85.8443 \
            ce{H} & pu{1.08E5} & 10.8182 \
            ce{Cl} & pu{1.94E4} & 1.9433 \
            ce{Na} & pu{1.08E4} & 1.0818 \
            ce{Mg} & pu{1.29E3} & 0.1292 \
            ce{S} & pu{9.05E2} & 0.0907 \
            ce{Ca} & pu{4.12E2} & 0.0413 \
            ce{K} & pu{3.99E2} & 0.0400 \
            ce{Br} & pu{6.73E1} & 0.0067 \
            ce{C} & pu{2.80E1} & 0.0028 \
            ce{Sr} & pu{7.9} & 0.0008 \
            ce{B} & pu{4.44} & 0.0004 \
            ce{Si} & pu{2.2} & 0.0002 \
            ce{F} & pu{1.3} & 0.0001 \
            ce{N} & pu{5.00E-1} & 0.0001 \
            hline
            end{array}



            References




            1. Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.






            share|improve this answer























            • You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
              – Mr Lister
              Dec 18 at 10:50











            Your Answer





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            2 Answers
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            2 Answers
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            active

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            8














            The book that you're reading is measuring by mass.



            If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.






            share|improve this answer


























              8














              The book that you're reading is measuring by mass.



              If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.






              share|improve this answer
























                8












                8








                8






                The book that you're reading is measuring by mass.



                If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.






                share|improve this answer












                The book that you're reading is measuring by mass.



                If you have pure water then you would expect oxygen to make up $frac{16}{16 + 2}times 100% approx 89 % $ by mass. Likewise, hydrogen would make up $frac{2}{16 + 2}times 100% approx 11 % $ by mass.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Dec 17 at 19:23









                PJ R

                75111




                75111























                    7














                    As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:



                    begin{array}{llr}
                    hline
                    text{Element} & rho_i/pu{mg L-1} & omega/% \
                    hline
                    ce{O} & pu{8.57E5} & 85.8443 \
                    ce{H} & pu{1.08E5} & 10.8182 \
                    ce{Cl} & pu{1.94E4} & 1.9433 \
                    ce{Na} & pu{1.08E4} & 1.0818 \
                    ce{Mg} & pu{1.29E3} & 0.1292 \
                    ce{S} & pu{9.05E2} & 0.0907 \
                    ce{Ca} & pu{4.12E2} & 0.0413 \
                    ce{K} & pu{3.99E2} & 0.0400 \
                    ce{Br} & pu{6.73E1} & 0.0067 \
                    ce{C} & pu{2.80E1} & 0.0028 \
                    ce{Sr} & pu{7.9} & 0.0008 \
                    ce{B} & pu{4.44} & 0.0004 \
                    ce{Si} & pu{2.2} & 0.0002 \
                    ce{F} & pu{1.3} & 0.0001 \
                    ce{N} & pu{5.00E-1} & 0.0001 \
                    hline
                    end{array}



                    References




                    1. Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.






                    share|improve this answer























                    • You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
                      – Mr Lister
                      Dec 18 at 10:50
















                    7














                    As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:



                    begin{array}{llr}
                    hline
                    text{Element} & rho_i/pu{mg L-1} & omega/% \
                    hline
                    ce{O} & pu{8.57E5} & 85.8443 \
                    ce{H} & pu{1.08E5} & 10.8182 \
                    ce{Cl} & pu{1.94E4} & 1.9433 \
                    ce{Na} & pu{1.08E4} & 1.0818 \
                    ce{Mg} & pu{1.29E3} & 0.1292 \
                    ce{S} & pu{9.05E2} & 0.0907 \
                    ce{Ca} & pu{4.12E2} & 0.0413 \
                    ce{K} & pu{3.99E2} & 0.0400 \
                    ce{Br} & pu{6.73E1} & 0.0067 \
                    ce{C} & pu{2.80E1} & 0.0028 \
                    ce{Sr} & pu{7.9} & 0.0008 \
                    ce{B} & pu{4.44} & 0.0004 \
                    ce{Si} & pu{2.2} & 0.0002 \
                    ce{F} & pu{1.3} & 0.0001 \
                    ce{N} & pu{5.00E-1} & 0.0001 \
                    hline
                    end{array}



                    References




                    1. Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.






                    share|improve this answer























                    • You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
                      – Mr Lister
                      Dec 18 at 10:50














                    7












                    7








                    7






                    As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:



                    begin{array}{llr}
                    hline
                    text{Element} & rho_i/pu{mg L-1} & omega/% \
                    hline
                    ce{O} & pu{8.57E5} & 85.8443 \
                    ce{H} & pu{1.08E5} & 10.8182 \
                    ce{Cl} & pu{1.94E4} & 1.9433 \
                    ce{Na} & pu{1.08E4} & 1.0818 \
                    ce{Mg} & pu{1.29E3} & 0.1292 \
                    ce{S} & pu{9.05E2} & 0.0907 \
                    ce{Ca} & pu{4.12E2} & 0.0413 \
                    ce{K} & pu{3.99E2} & 0.0400 \
                    ce{Br} & pu{6.73E1} & 0.0067 \
                    ce{C} & pu{2.80E1} & 0.0028 \
                    ce{Sr} & pu{7.9} & 0.0008 \
                    ce{B} & pu{4.44} & 0.0004 \
                    ce{Si} & pu{2.2} & 0.0002 \
                    ce{F} & pu{1.3} & 0.0001 \
                    ce{N} & pu{5.00E-1} & 0.0001 \
                    hline
                    end{array}



                    References




                    1. Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.






                    share|improve this answer














                    As it has already been mentioned, these are mass percentages, which are a bit imprecise. For the reference, CRC handbook of chemistry and physics [1, p. 14-17] lists elements' abundances in seawater near the surface in $pu{mg L-1}$, alphabetically. I took 15 (starting with 16th element $omega < 10^{-4}~%$) most abundant elements from that array and calculated mass percentage for each:



                    begin{array}{llr}
                    hline
                    text{Element} & rho_i/pu{mg L-1} & omega/% \
                    hline
                    ce{O} & pu{8.57E5} & 85.8443 \
                    ce{H} & pu{1.08E5} & 10.8182 \
                    ce{Cl} & pu{1.94E4} & 1.9433 \
                    ce{Na} & pu{1.08E4} & 1.0818 \
                    ce{Mg} & pu{1.29E3} & 0.1292 \
                    ce{S} & pu{9.05E2} & 0.0907 \
                    ce{Ca} & pu{4.12E2} & 0.0413 \
                    ce{K} & pu{3.99E2} & 0.0400 \
                    ce{Br} & pu{6.73E1} & 0.0067 \
                    ce{C} & pu{2.80E1} & 0.0028 \
                    ce{Sr} & pu{7.9} & 0.0008 \
                    ce{B} & pu{4.44} & 0.0004 \
                    ce{Si} & pu{2.2} & 0.0002 \
                    ce{F} & pu{1.3} & 0.0001 \
                    ce{N} & pu{5.00E-1} & 0.0001 \
                    hline
                    end{array}



                    References




                    1. Haynes, W. M.; Lide, D. R.; Bruno, T. J. CRC Handbook of Chemistry and Physics: A Ready-Reference Book of Chemical and Physical Data.; 2017; Vol. 97.







                    share|improve this answer














                    share|improve this answer



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                    edited Dec 17 at 22:51

























                    answered Dec 17 at 20:29









                    andselisk

                    13k64598




                    13k64598












                    • You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
                      – Mr Lister
                      Dec 18 at 10:50


















                    • You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
                      – Mr Lister
                      Dec 18 at 10:50
















                    You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
                    – Mr Lister
                    Dec 18 at 10:50




                    You say the numbers are a bit imprecise, but they have to be, because not all seawater is the same!
                    – Mr Lister
                    Dec 18 at 10:50










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