Moving plot label
$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
asked 11 hours ago
rodger_kicksrodger_kicks
365
$endgroup$
add a comment |
$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
asked 11 hours ago
rodger_kicksrodger_kicks
365
$endgroup$
add a comment |
$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
asked 11 hours ago
rodger_kicksrodger_kicks
365
$endgroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
plotting
asked 11 hours ago
rodger_kicksrodger_kicks
365
asked 11 hours ago
rodger_kicksrodger_kicks
365
asked 11 hours ago
rodger_kicksrodger_kicks
365
asked 11 hours ago
rodger_kicksrodger_kicks
365
asked 11 hours ago
rodger_kicksrodger_kicks
365
365
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You can use Inset to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 10 hours ago
Michael E2Michael E2
149k12200479
$endgroup$
add a comment |
$begingroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
Update: An alternative way is to put the label in a dynamic, movable Epilog:
DynamicModule[{pt = Scaled[{.5, 1}]},
Plot[1/(1 + Exp[-x]), {x, -10, 10},
ImagePadding -> {{Automatic, Automatic}, {Automatic, Scaled[.05]}},
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
answered 10 hours ago
kglrkglr
188k10204422
$endgroup$
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
10 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
10 hours ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can use Inset to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 10 hours ago
Michael E2Michael E2
149k12200479
$endgroup$
add a comment |
$begingroup$
You can use Inset to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 10 hours ago
Michael E2Michael E2
149k12200479
$endgroup$
add a comment |
$begingroup$
You can use Inset to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 10 hours ago
Michael E2Michael E2
149k12200479
$endgroup$
You can use Inset to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
{-1.5, 1}, {1, 1}]]
FWIW, I rather prefer the look of TraditionalForm in this:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
{-1.5, 1}, {1, 1}]]
answered 10 hours ago
Michael E2Michael E2
149k12200479
answered 10 hours ago
Michael E2Michael E2
149k12200479
answered 10 hours ago
Michael E2Michael E2
149k12200479
answered 10 hours ago
Michael E2Michael E2
149k12200479
149k12200479
add a comment |
add a comment |
$begingroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
Update: An alternative way is to put the label in a dynamic, movable Epilog:
DynamicModule[{pt = Scaled[{.5, 1}]},
Plot[1/(1 + Exp[-x]), {x, -10, 10},
ImagePadding -> {{Automatic, Automatic}, {Automatic, Scaled[.05]}},
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
answered 10 hours ago
kglrkglr
188k10204422
$endgroup$
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
10 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
10 hours ago
add a comment |
$begingroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
Update: An alternative way is to put the label in a dynamic, movable Epilog:
DynamicModule[{pt = Scaled[{.5, 1}]},
Plot[1/(1 + Exp[-x]), {x, -10, 10},
ImagePadding -> {{Automatic, Automatic}, {Automatic, Scaled[.05]}},
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
answered 10 hours ago
kglrkglr
188k10204422
$endgroup$
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
10 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
10 hours ago
add a comment |
$begingroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
Update: An alternative way is to put the label in a dynamic, movable Epilog:
DynamicModule[{pt = Scaled[{.5, 1}]},
Plot[1/(1 + Exp[-x]), {x, -10, 10},
ImagePadding -> {{Automatic, Automatic}, {Automatic, Scaled[.05]}},
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
answered 10 hours ago
kglrkglr
188k10204422
$endgroup$
You can wrap your label with another Framed with the options FrameStyle -> None and FrameMargins -> {{0, rightmargin}, {0,0}} with your choice of rightmargin:
Plot[1/(1 + Exp[-x]), {x, -10, 10},
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> {{0, Scaled[.1]}, {0, 0}}]]
Use FrameMargins -> {{0, Scaled[.14]}, {0, Scaled[.05]}} to get
Update: An alternative way is to put the label in a dynamic, movable Epilog:
DynamicModule[{pt = Scaled[{.5, 1}]},
Plot[1/(1 + Exp[-x]), {x, -10, 10},
ImagePadding -> {{Automatic, Automatic}, {Automatic, Scaled[.05]}},
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
answered 10 hours ago
kglrkglr
188k10204422
edited 10 hours ago
answered 10 hours ago
kglrkglr
188k10204422
answered 10 hours ago
kglrkglr
188k10204422
answered 10 hours ago
kglrkglr
188k10204422
188k10204422
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
10 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
10 hours ago
add a comment |
$begingroup$
Isn't theTraditionalFormunnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
10 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
10 hours ago
$begingroup$
Isn't the
TraditionalForm unnecessary? (It's applied by default here, I think.)$endgroup$
– Michael E2
10 hours ago
$begingroup$
Isn't the
TraditionalForm unnecessary? (It's applied by default here, I think.)$endgroup$
– Michael E2
10 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
10 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
10 hours ago
add a comment |
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