Relationship between strut and baselineskip
Here, it is said that a strut is defined as:
rule[-.3baselineskip]{0pt}{baselineskip}
However, if I do:
newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}
It prints:
8.39996pt 12.0pt
8.39996 is equal to 0.7*12. However, what I don't understand is that according to its definition the height of the strut should be baselineskip, because -.3baselineskip only refers to a vertical alignment offset. Why does settoheight on a strut produces this behaviour?
vertical-alignment baseline calc strut
add a comment |
Here, it is said that a strut is defined as:
rule[-.3baselineskip]{0pt}{baselineskip}
However, if I do:
newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}
It prints:
8.39996pt 12.0pt
8.39996 is equal to 0.7*12. However, what I don't understand is that according to its definition the height of the strut should be baselineskip, because -.3baselineskip only refers to a vertical alignment offset. Why does settoheight on a strut produces this behaviour?
vertical-alignment baseline calc strut
add a comment |
Here, it is said that a strut is defined as:
rule[-.3baselineskip]{0pt}{baselineskip}
However, if I do:
newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}
It prints:
8.39996pt 12.0pt
8.39996 is equal to 0.7*12. However, what I don't understand is that according to its definition the height of the strut should be baselineskip, because -.3baselineskip only refers to a vertical alignment offset. Why does settoheight on a strut produces this behaviour?
vertical-alignment baseline calc strut
Here, it is said that a strut is defined as:
rule[-.3baselineskip]{0pt}{baselineskip}
However, if I do:
newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}
It prints:
8.39996pt 12.0pt
8.39996 is equal to 0.7*12. However, what I don't understand is that according to its definition the height of the strut should be baselineskip, because -.3baselineskip only refers to a vertical alignment offset. Why does settoheight on a strut produces this behaviour?
vertical-alignment baseline calc strut
vertical-alignment baseline calc strut
asked 2 hours ago
VincentVincent
1,70421939
1,70421939
add a comment |
add a comment |
                                2 Answers
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The height of the whole strut is baselineskip, however it is lowered by 0.3baselineskip form the baseline. Its depth plus its height totals baselineskip:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight you get only the height of the box, not the total height.
You can draw the strut and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
add a comment |
Well, the definition of strut is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip} is a less efficient way to say unhcopystrutbox, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p or y.
The strutbox is updated whenever a fontsize command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
    @defaultunits@tempdimb#2ptrelax@nnil
    edeff@size{strip@pt@tempdimb}%
    @defaultunits@tempskipa#3ptrelax@nnil
    edeff@baselineskip{the@tempskipa}%
    edeff@linespread{#1}%
    letbaselinestretchf@linespread
      defsize@update{%
        baselineskipf@baselineskiprelax
        baselineskipf@linespreadbaselineskip
        normalbaselineskipbaselineskip
        setboxstrutboxhbox{%
          vrule@height.7baselineskip
                @depth.3baselineskip
                @widthz@}%
        letsize@updaterelax}%
  }
So the strutbox is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox and dpstrutbox:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}

add a comment |
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                                2 Answers
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active
oldest
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                                2 Answers
                            2
                        
active
oldest
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active
oldest
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active
oldest
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The height of the whole strut is baselineskip, however it is lowered by 0.3baselineskip form the baseline. Its depth plus its height totals baselineskip:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight you get only the height of the box, not the total height.
You can draw the strut and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
add a comment |
The height of the whole strut is baselineskip, however it is lowered by 0.3baselineskip form the baseline. Its depth plus its height totals baselineskip:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight you get only the height of the box, not the total height.
You can draw the strut and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
add a comment |
The height of the whole strut is baselineskip, however it is lowered by 0.3baselineskip form the baseline. Its depth plus its height totals baselineskip:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight you get only the height of the box, not the total height.
You can draw the strut and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
The height of the whole strut is baselineskip, however it is lowered by 0.3baselineskip form the baseline. Its depth plus its height totals baselineskip:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight you get only the height of the box, not the total height.
You can draw the strut and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
answered 2 hours ago
Phelype OleinikPhelype Oleinik
26.2k54791
26.2k54791
add a comment |
add a comment |
Well, the definition of strut is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip} is a less efficient way to say unhcopystrutbox, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p or y.
The strutbox is updated whenever a fontsize command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
    @defaultunits@tempdimb#2ptrelax@nnil
    edeff@size{strip@pt@tempdimb}%
    @defaultunits@tempskipa#3ptrelax@nnil
    edeff@baselineskip{the@tempskipa}%
    edeff@linespread{#1}%
    letbaselinestretchf@linespread
      defsize@update{%
        baselineskipf@baselineskiprelax
        baselineskipf@linespreadbaselineskip
        normalbaselineskipbaselineskip
        setboxstrutboxhbox{%
          vrule@height.7baselineskip
                @depth.3baselineskip
                @widthz@}%
        letsize@updaterelax}%
  }
So the strutbox is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox and dpstrutbox:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}

add a comment |
Well, the definition of strut is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip} is a less efficient way to say unhcopystrutbox, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p or y.
The strutbox is updated whenever a fontsize command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
    @defaultunits@tempdimb#2ptrelax@nnil
    edeff@size{strip@pt@tempdimb}%
    @defaultunits@tempskipa#3ptrelax@nnil
    edeff@baselineskip{the@tempskipa}%
    edeff@linespread{#1}%
    letbaselinestretchf@linespread
      defsize@update{%
        baselineskipf@baselineskiprelax
        baselineskipf@linespreadbaselineskip
        normalbaselineskipbaselineskip
        setboxstrutboxhbox{%
          vrule@height.7baselineskip
                @depth.3baselineskip
                @widthz@}%
        letsize@updaterelax}%
  }
So the strutbox is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox and dpstrutbox:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}

add a comment |
Well, the definition of strut is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip} is a less efficient way to say unhcopystrutbox, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p or y.
The strutbox is updated whenever a fontsize command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
    @defaultunits@tempdimb#2ptrelax@nnil
    edeff@size{strip@pt@tempdimb}%
    @defaultunits@tempskipa#3ptrelax@nnil
    edeff@baselineskip{the@tempskipa}%
    edeff@linespread{#1}%
    letbaselinestretchf@linespread
      defsize@update{%
        baselineskipf@baselineskiprelax
        baselineskipf@linespreadbaselineskip
        normalbaselineskipbaselineskip
        setboxstrutboxhbox{%
          vrule@height.7baselineskip
                @depth.3baselineskip
                @widthz@}%
        letsize@updaterelax}%
  }
So the strutbox is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox and dpstrutbox:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}

Well, the definition of strut is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip} is a less efficient way to say unhcopystrutbox, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p or y.
The strutbox is updated whenever a fontsize command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
    @defaultunits@tempdimb#2ptrelax@nnil
    edeff@size{strip@pt@tempdimb}%
    @defaultunits@tempskipa#3ptrelax@nnil
    edeff@baselineskip{the@tempskipa}%
    edeff@linespread{#1}%
    letbaselinestretchf@linespread
      defsize@update{%
        baselineskipf@baselineskiprelax
        baselineskipf@linespreadbaselineskip
        normalbaselineskipbaselineskip
        setboxstrutboxhbox{%
          vrule@height.7baselineskip
                @depth.3baselineskip
                @widthz@}%
        letsize@updaterelax}%
  }
So the strutbox is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox and dpstrutbox:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}

answered 1 hour ago
egregegreg
737k8919373265
737k8919373265
add a comment |
add a comment |
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