Relationship between strut and baselineskip
Here, it is said that a strut
is defined as:
rule[-.3baselineskip]{0pt}{baselineskip}
However, if I do:
newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}
It prints:
8.39996pt 12.0pt
8.39996
is equal to 0.7*12
. However, what I don't understand is that according to its definition the height of the strut should be baselineskip
, because -.3baselineskip
only refers to a vertical alignment offset. Why does settoheight
on a strut
produces this behaviour?
vertical-alignment baseline calc strut
add a comment |
Here, it is said that a strut
is defined as:
rule[-.3baselineskip]{0pt}{baselineskip}
However, if I do:
newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}
It prints:
8.39996pt 12.0pt
8.39996
is equal to 0.7*12
. However, what I don't understand is that according to its definition the height of the strut should be baselineskip
, because -.3baselineskip
only refers to a vertical alignment offset. Why does settoheight
on a strut
produces this behaviour?
vertical-alignment baseline calc strut
add a comment |
Here, it is said that a strut
is defined as:
rule[-.3baselineskip]{0pt}{baselineskip}
However, if I do:
newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}
It prints:
8.39996pt 12.0pt
8.39996
is equal to 0.7*12
. However, what I don't understand is that according to its definition the height of the strut should be baselineskip
, because -.3baselineskip
only refers to a vertical alignment offset. Why does settoheight
on a strut
produces this behaviour?
vertical-alignment baseline calc strut
Here, it is said that a strut
is defined as:
rule[-.3baselineskip]{0pt}{baselineskip}
However, if I do:
newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}
It prints:
8.39996pt 12.0pt
8.39996
is equal to 0.7*12
. However, what I don't understand is that according to its definition the height of the strut should be baselineskip
, because -.3baselineskip
only refers to a vertical alignment offset. Why does settoheight
on a strut
produces this behaviour?
vertical-alignment baseline calc strut
vertical-alignment baseline calc strut
asked 2 hours ago
VincentVincent
1,70421939
1,70421939
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The height of the whole strut
is baselineskip
, however it is lowered by 0.3baselineskip
form the baseline. Its depth plus its height totals baselineskip
:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt
.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight
you get only the height of the box, not the total height.
You can draw the strut
and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
add a comment |
Well, the definition of strut
is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip}
is a less efficient way to say unhcopystrutbox
, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p
or y
.
The strutbox
is updated whenever a fontsize
command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
@defaultunits@tempdimb#2ptrelax@nnil
edeff@size{strip@pt@tempdimb}%
@defaultunits@tempskipa#3ptrelax@nnil
edeff@baselineskip{the@tempskipa}%
edeff@linespread{#1}%
letbaselinestretchf@linespread
defsize@update{%
baselineskipf@baselineskiprelax
baselineskipf@linespreadbaselineskip
normalbaselineskipbaselineskip
setboxstrutboxhbox{%
vrule@height.7baselineskip
@depth.3baselineskip
@widthz@}%
letsize@updaterelax}%
}
So the strutbox
is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox
and dpstrutbox
:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The height of the whole strut
is baselineskip
, however it is lowered by 0.3baselineskip
form the baseline. Its depth plus its height totals baselineskip
:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt
.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight
you get only the height of the box, not the total height.
You can draw the strut
and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
add a comment |
The height of the whole strut
is baselineskip
, however it is lowered by 0.3baselineskip
form the baseline. Its depth plus its height totals baselineskip
:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt
.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight
you get only the height of the box, not the total height.
You can draw the strut
and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
add a comment |
The height of the whole strut
is baselineskip
, however it is lowered by 0.3baselineskip
form the baseline. Its depth plus its height totals baselineskip
:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt
.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight
you get only the height of the box, not the total height.
You can draw the strut
and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
The height of the whole strut
is baselineskip
, however it is lowered by 0.3baselineskip
form the baseline. Its depth plus its height totals baselineskip
:
documentclass{article}
begin{document}
newlength{strutheight}
newlength{strutdepth}
settoheight{strutheight}{strut}
settodepth{strutdepth}{strut}
$thestrutheight+thestrutdepth=thebaselineskip$
end{document}
this prints 8.39996pt + 3.60004pt = 12.0pt
.
In TeX, the “height” of a box is not its total height, but the height above the baseline, and the “depth” is the amount that box goes below that baseline. And when you do settoheight
you get only the height of the box, not the total height.
You can draw the strut
and its height and depth to see:
documentclass{article}
begin{document}
fboxsep0pt
fboxrule0.1pt
fbox{strut}
fbox{rule{0pt}{0.7baselineskip}}
fbox{rule[-0.3baselineskip]{0pt}{0.3baselineskip}}
end{document}
answered 2 hours ago
Phelype OleinikPhelype Oleinik
26.2k54791
26.2k54791
add a comment |
add a comment |
Well, the definition of strut
is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip}
is a less efficient way to say unhcopystrutbox
, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p
or y
.
The strutbox
is updated whenever a fontsize
command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
@defaultunits@tempdimb#2ptrelax@nnil
edeff@size{strip@pt@tempdimb}%
@defaultunits@tempskipa#3ptrelax@nnil
edeff@baselineskip{the@tempskipa}%
edeff@linespread{#1}%
letbaselinestretchf@linespread
defsize@update{%
baselineskipf@baselineskiprelax
baselineskipf@linespreadbaselineskip
normalbaselineskipbaselineskip
setboxstrutboxhbox{%
vrule@height.7baselineskip
@depth.3baselineskip
@widthz@}%
letsize@updaterelax}%
}
So the strutbox
is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox
and dpstrutbox
:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}
add a comment |
Well, the definition of strut
is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip}
is a less efficient way to say unhcopystrutbox
, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p
or y
.
The strutbox
is updated whenever a fontsize
command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
@defaultunits@tempdimb#2ptrelax@nnil
edeff@size{strip@pt@tempdimb}%
@defaultunits@tempskipa#3ptrelax@nnil
edeff@baselineskip{the@tempskipa}%
edeff@linespread{#1}%
letbaselinestretchf@linespread
defsize@update{%
baselineskipf@baselineskiprelax
baselineskipf@linespreadbaselineskip
normalbaselineskipbaselineskip
setboxstrutboxhbox{%
vrule@height.7baselineskip
@depth.3baselineskip
@widthz@}%
letsize@updaterelax}%
}
So the strutbox
is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox
and dpstrutbox
:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}
add a comment |
Well, the definition of strut
is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip}
is a less efficient way to say unhcopystrutbox
, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p
or y
.
The strutbox
is updated whenever a fontsize
command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
@defaultunits@tempdimb#2ptrelax@nnil
edeff@size{strip@pt@tempdimb}%
@defaultunits@tempskipa#3ptrelax@nnil
edeff@baselineskip{the@tempskipa}%
edeff@linespread{#1}%
letbaselinestretchf@linespread
defsize@update{%
baselineskipf@baselineskiprelax
baselineskipf@linespreadbaselineskip
normalbaselineskipbaselineskip
setboxstrutboxhbox{%
vrule@height.7baselineskip
@depth.3baselineskip
@widthz@}%
letsize@updaterelax}%
}
So the strutbox
is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox
and dpstrutbox
:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}
Well, the definition of strut
is
% latex.ltx, line 594:
defstrut{relaxifmmodecopystrutboxelseunhcopystrutboxfi}
The code rule[-0.3baselineskip]{0pt}{baselineskip}
is a less efficient way to say unhcopystrutbox
, but amounts to essentially the same. Part of the strut is below the baseline, to cope with characters with descenders like p
or y
.
The strutbox
is updated whenever a fontsize
command is processed:
% latex.ltx, line 2808:
defset@fontsize#1#2#3{%
@defaultunits@tempdimb#2ptrelax@nnil
edeff@size{strip@pt@tempdimb}%
@defaultunits@tempskipa#3ptrelax@nnil
edeff@baselineskip{the@tempskipa}%
edeff@linespread{#1}%
letbaselinestretchf@linespread
defsize@update{%
baselineskipf@baselineskiprelax
baselineskipf@linespreadbaselineskip
normalbaselineskipbaselineskip
setboxstrutboxhbox{%
vrule@height.7baselineskip
@depth.3baselineskip
@widthz@}%
letsize@updaterelax}%
}
So the strutbox
is a box containing a zero width rule, with height 70% of the baseline skip and depth 30% of the baseline skip.
You can access the current dimensions as htstrutbox
and dpstrutbox
:
documentclass{article}
begin{document}
thehtstrutbox (height)
thedpstrutbox (depth)
thedimexprhtstrutbox+dpstrutbox (total)
thebaselineskip (baselineskip)
end{document}
answered 1 hour ago
egregegreg
737k8919373265
737k8919373265
add a comment |
add a comment |
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