use for loop variable inside a sed command
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
I have based my script on the following quesstion
Find and replace text within a file using commands
I have a lot of files named test_xxx_01.sql in which i need to replace a text testoriginal with testoriginal_xxx
so I wrote the following command
for i in {220,630,1000}; do sed -i 's/testoriginal/testoriginal_${i}/g' test_${i}_01.sql; done
the expected output is that in the file test_221_01.sql, i should now have 'testoriginal_221'.
but instead i have testoriginal_${i}
how can i fix this command?
command-line sed
add a comment |
I have based my script on the following quesstion
Find and replace text within a file using commands
I have a lot of files named test_xxx_01.sql in which i need to replace a text testoriginal with testoriginal_xxx
so I wrote the following command
for i in {220,630,1000}; do sed -i 's/testoriginal/testoriginal_${i}/g' test_${i}_01.sql; done
the expected output is that in the file test_221_01.sql, i should now have 'testoriginal_221'.
but instead i have testoriginal_${i}
how can i fix this command?
command-line sed
5
It's basically a matter of using the right quotes - but be careful of metacharacters. See How can I use variables in the LHS and RHS of a sed substitution?
– steeldriver
Apr 5 at 12:06
1
You need to use double quotes for the expression.
– pa4080
Apr 5 at 12:12
add a comment |
I have based my script on the following quesstion
Find and replace text within a file using commands
I have a lot of files named test_xxx_01.sql in which i need to replace a text testoriginal with testoriginal_xxx
so I wrote the following command
for i in {220,630,1000}; do sed -i 's/testoriginal/testoriginal_${i}/g' test_${i}_01.sql; done
the expected output is that in the file test_221_01.sql, i should now have 'testoriginal_221'.
but instead i have testoriginal_${i}
how can i fix this command?
command-line sed
I have based my script on the following quesstion
Find and replace text within a file using commands
I have a lot of files named test_xxx_01.sql in which i need to replace a text testoriginal with testoriginal_xxx
so I wrote the following command
for i in {220,630,1000}; do sed -i 's/testoriginal/testoriginal_${i}/g' test_${i}_01.sql; done
the expected output is that in the file test_221_01.sql, i should now have 'testoriginal_221'.
but instead i have testoriginal_${i}
how can i fix this command?
command-line sed
command-line sed
asked Apr 5 at 12:04
AnandAnand
1062
1062
5
It's basically a matter of using the right quotes - but be careful of metacharacters. See How can I use variables in the LHS and RHS of a sed substitution?
– steeldriver
Apr 5 at 12:06
1
You need to use double quotes for the expression.
– pa4080
Apr 5 at 12:12
add a comment |
5
It's basically a matter of using the right quotes - but be careful of metacharacters. See How can I use variables in the LHS and RHS of a sed substitution?
– steeldriver
Apr 5 at 12:06
1
You need to use double quotes for the expression.
– pa4080
Apr 5 at 12:12
5
5
It's basically a matter of using the right quotes - but be careful of metacharacters. See How can I use variables in the LHS and RHS of a sed substitution?
– steeldriver
Apr 5 at 12:06
It's basically a matter of using the right quotes - but be careful of metacharacters. See How can I use variables in the LHS and RHS of a sed substitution?
– steeldriver
Apr 5 at 12:06
1
1
You need to use double quotes for the expression.
– pa4080
Apr 5 at 12:12
You need to use double quotes for the expression.
– pa4080
Apr 5 at 12:12
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "89"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2faskubuntu.com%2fquestions%2f1131420%2fuse-for-loop-variable-inside-a-sed-command%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Ask Ubuntu!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2faskubuntu.com%2fquestions%2f1131420%2fuse-for-loop-variable-inside-a-sed-command%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
5
It's basically a matter of using the right quotes - but be careful of metacharacters. See How can I use variables in the LHS and RHS of a sed substitution?
– steeldriver
Apr 5 at 12:06
1
You need to use double quotes for the expression.
– pa4080
Apr 5 at 12:12