Empty elements as dots in matrix











up vote
6
down vote

favorite












I need to create a determinant (vmatrix) as shown in this picture.enter image description here So, I wrote a simple LaTEX file for testing purposes as follows:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot                                      &cdot &cdot &cdot \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot                                      &cdot &cdot &cdot \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}


When the above file gets compiled with TeXLive on a Linux desktop computer, it produces the following ugly result:enter image description here I thought using hdotsfor{} for the horizontal line, but the spacing between the dots is too close. If there is a simple way to tell hdotsfor{} to skip every dot, I believe that would do. However, perhaps someone here knows a much better way.






matrices







share|improve this question






















  • hdotsfor has an optional argument which is a multiplier for the amount of space between consecutive dots, so you could try hdotsfor[2]{<number of rows>}. I'm not sure if it'd look good though, since they wouldn't align with the dots in your first row.
    – Circumscribe
    Dec 8 at 21:47















up vote
6
down vote

favorite












I need to create a determinant (vmatrix) as shown in this picture.enter image description here So, I wrote a simple LaTEX file for testing purposes as follows:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot                                      &cdot &cdot &cdot \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot                                      &cdot &cdot &cdot \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}


When the above file gets compiled with TeXLive on a Linux desktop computer, it produces the following ugly result:enter image description here I thought using hdotsfor{} for the horizontal line, but the spacing between the dots is too close. If there is a simple way to tell hdotsfor{} to skip every dot, I believe that would do. However, perhaps someone here knows a much better way.






matrices







share|improve this question






















  • hdotsfor has an optional argument which is a multiplier for the amount of space between consecutive dots, so you could try hdotsfor[2]{<number of rows>}. I'm not sure if it'd look good though, since they wouldn't align with the dots in your first row.
    – Circumscribe
    Dec 8 at 21:47













up vote
6
down vote

favorite









up vote
6
down vote

favorite











I need to create a determinant (vmatrix) as shown in this picture.enter image description here So, I wrote a simple LaTEX file for testing purposes as follows:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot                                      &cdot &cdot &cdot \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot                                      &cdot &cdot &cdot \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}


When the above file gets compiled with TeXLive on a Linux desktop computer, it produces the following ugly result:enter image description here I thought using hdotsfor{} for the horizontal line, but the spacing between the dots is too close. If there is a simple way to tell hdotsfor{} to skip every dot, I believe that would do. However, perhaps someone here knows a much better way.






matrices







share|improve this question













I need to create a determinant (vmatrix) as shown in this picture.enter image description here So, I wrote a simple LaTEX file for testing purposes as follows:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot                                      &cdot &cdot &cdot \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot                                      &cdot &cdot &cdot \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}


When the above file gets compiled with TeXLive on a Linux desktop computer, it produces the following ugly result:enter image description here I thought using hdotsfor{} for the horizontal line, but the spacing between the dots is too close. If there is a simple way to tell hdotsfor{} to skip every dot, I believe that would do. However, perhaps someone here knows a much better way.






matrices




matrices






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Dec 8 at 21:18









user91822

1354




1354












  • hdotsfor has an optional argument which is a multiplier for the amount of space between consecutive dots, so you could try hdotsfor[2]{<number of rows>}. I'm not sure if it'd look good though, since they wouldn't align with the dots in your first row.
    – Circumscribe
    Dec 8 at 21:47


















  • hdotsfor has an optional argument which is a multiplier for the amount of space between consecutive dots, so you could try hdotsfor[2]{<number of rows>}. I'm not sure if it'd look good though, since they wouldn't align with the dots in your first row.
    – Circumscribe
    Dec 8 at 21:47
















hdotsfor has an optional argument which is a multiplier for the amount of space between consecutive dots, so you could try hdotsfor[2]{<number of rows>}. I'm not sure if it'd look good though, since they wouldn't align with the dots in your first row.
– Circumscribe
Dec 8 at 21:47




hdotsfor has an optional argument which is a multiplier for the amount of space between consecutive dots, so you could try hdotsfor[2]{<number of rows>}. I'm not sure if it'd look good though, since they wouldn't align with the dots in your first row.
– Circumscribe
Dec 8 at 21:47










4 Answers
4






active

oldest

votes

















up vote
8
down vote



accepted










This seems a good approximation:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

begin{vmatrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

-1 & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & -1 & alpha_{n}     & . & . & kappa_{n}

end{vmatrix}

end{equation*}



end{document}


enter image description here



The value 14tabcolsep has been determined by first looking at the entries at their natural width.



Even better than the original if we make -1 to hide its width.



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

newcommand{?}{makebox[0pt]{$-1$}}

begin{vmatrix}mspace{8mu}

begin{matrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

? & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & ? & alpha_{n}     & . & . & kappa_{n}

end{matrix}mspace{3mu}

end{vmatrix}

end{equation*}



end{document}


enter image description here



With dots and hdotsfor:



begin{equation*}

newcommand{ak}[2]{a_{#2}#1_1+dots+k_{#2}#1_n}

begin{vmatrix}

 0 & dots &  0 & ak{alpha}{1} & dots & ak{kappa}{1} \

hdotsfor{6} \

 0 & dots &  0 & ak{alpha}{n} & dots & ak{kappa}{n} \

-1 & dots &  0 & alpha_{1}     & dots & kappa_{1}     \

hdotsfor{6} \

 0 & dots & -1 & alpha_{n}     & dots & kappa_{n}

end{vmatrix}

end{equation*}


enter image description here






share|improve this answer























  • Although I may not be able to decipher how your code works, it looks like the one with the capability of hiding the with of -1 fits my need. I have a feeling after perusing your code, I will understand better. Thank you.
    – user91822
    Dec 9 at 0:18


















up vote
4
down vote













One way is to manually put dots with some horizontal space.



enter image description here



documentclass[a4paper,10pt]{article}

usepackage{amsmath}

begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                               &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                                      &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}





share|improve this answer





















  • Honestly, I had never thought of using 'hfil'. Thank you for the pointer.
    – user91822
    Dec 9 at 0:20


















up vote
3
down vote













Defining two newcommands twodts and fivedts for empty columns and rows can simplify the table. 



documentclass[a4paper,10pt]{article}

usepackage{amsmath}



begin{document}



newcommand{twodts}{begin{tabular}{@{}cc@{}}$cdot$&$cdot$end{tabular}}

newcommand{fivedts}{begin{tabular}{@{}*5{c}@{}}$cdot$&$cdot$&$cdot$&$cdot$&$cdot$end{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here




Update:



You can easily adapt my answer to add six dots instead of five like this:



documentclass[a4paper,10pt]{article}

usepackage{amsmath,array}



begin{document}



deftwocdots{$cdot$&$cdot$}

newcommand{twodts}{begin{tabular}{@{}cc@{}}twocdotsend{tabular}}

newcommand{sixdts}{begin{tabular}{@{}*6{c}@{}}twocdots&twocdots&twocdotsend{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here







share|improve this answer























  • This looks pretty simple and good solution. Since there is still some gaps that seems to be able to put one more dot when using the `fivedts' command, I wonder if this command can be modded to accommodate the gap. I tried to modify with a "sixdots" and it does not work, unfortunately. Anyway, thank you too.
    – user91822
    Dec 9 at 0:24










  • Please see my update for doing this.
    – AboAmmar
    Dec 9 at 16:31


















up vote
1
down vote













Would this be acceptable?



enter image description here



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

           begin{vmatrix}

            0     &cdots &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdots     &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

            vdots &ddots &vdots &vdots &ddots  &vdots \

            0     &cdots & 0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdots  &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

            -1    &cdots &0     &alpha_{1}  &cdots &kappa_{1} \

            vdots &ddots &vdots &vdots   &ddots &vdots \

            0     &cdots & -1    &alpha_{n}  &cdots &kappa_{n}

    end{vmatrix}

end{equation*}



end{document}





share|improve this answer

















  • 1




    This is I usually do and I don't think it will do for me. Sorry and I try to stick closer to the example I posted above. Anyway, thank you.
    – user91822
    Dec 9 at 0:25













Your Answer








StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "85"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f463868%2fempty-elements-as-dots-in-matrix%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























4 Answers
4






active

oldest

votes








4 Answers
4






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
8
down vote



accepted










This seems a good approximation:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

begin{vmatrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

-1 & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & -1 & alpha_{n}     & . & . & kappa_{n}

end{vmatrix}

end{equation*}



end{document}


enter image description here



The value 14tabcolsep has been determined by first looking at the entries at their natural width.



Even better than the original if we make -1 to hide its width.



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

newcommand{?}{makebox[0pt]{$-1$}}

begin{vmatrix}mspace{8mu}

begin{matrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

? & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & ? & alpha_{n}     & . & . & kappa_{n}

end{matrix}mspace{3mu}

end{vmatrix}

end{equation*}



end{document}


enter image description here



With dots and hdotsfor:



begin{equation*}

newcommand{ak}[2]{a_{#2}#1_1+dots+k_{#2}#1_n}

begin{vmatrix}

 0 & dots &  0 & ak{alpha}{1} & dots & ak{kappa}{1} \

hdotsfor{6} \

 0 & dots &  0 & ak{alpha}{n} & dots & ak{kappa}{n} \

-1 & dots &  0 & alpha_{1}     & dots & kappa_{1}     \

hdotsfor{6} \

 0 & dots & -1 & alpha_{n}     & dots & kappa_{n}

end{vmatrix}

end{equation*}


enter image description here






share|improve this answer























  • Although I may not be able to decipher how your code works, it looks like the one with the capability of hiding the with of -1 fits my need. I have a feeling after perusing your code, I will understand better. Thank you.
    – user91822
    Dec 9 at 0:18















up vote
8
down vote



accepted










This seems a good approximation:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

begin{vmatrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

-1 & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & -1 & alpha_{n}     & . & . & kappa_{n}

end{vmatrix}

end{equation*}



end{document}


enter image description here



The value 14tabcolsep has been determined by first looking at the entries at their natural width.



Even better than the original if we make -1 to hide its width.



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

newcommand{?}{makebox[0pt]{$-1$}}

begin{vmatrix}mspace{8mu}

begin{matrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

? & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & ? & alpha_{n}     & . & . & kappa_{n}

end{matrix}mspace{3mu}

end{vmatrix}

end{equation*}



end{document}


enter image description here



With dots and hdotsfor:



begin{equation*}

newcommand{ak}[2]{a_{#2}#1_1+dots+k_{#2}#1_n}

begin{vmatrix}

 0 & dots &  0 & ak{alpha}{1} & dots & ak{kappa}{1} \

hdotsfor{6} \

 0 & dots &  0 & ak{alpha}{n} & dots & ak{kappa}{n} \

-1 & dots &  0 & alpha_{1}     & dots & kappa_{1}     \

hdotsfor{6} \

 0 & dots & -1 & alpha_{n}     & dots & kappa_{n}

end{vmatrix}

end{equation*}


enter image description here






share|improve this answer























  • Although I may not be able to decipher how your code works, it looks like the one with the capability of hiding the with of -1 fits my need. I have a feeling after perusing your code, I will understand better. Thank you.
    – user91822
    Dec 9 at 0:18













up vote
8
down vote



accepted







up vote
8
down vote



accepted






This seems a good approximation:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

begin{vmatrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

-1 & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & -1 & alpha_{n}     & . & . & kappa_{n}

end{vmatrix}

end{equation*}



end{document}


enter image description here



The value 14tabcolsep has been determined by first looking at the entries at their natural width.



Even better than the original if we make -1 to hide its width.



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

newcommand{?}{makebox[0pt]{$-1$}}

begin{vmatrix}mspace{8mu}

begin{matrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

? & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & ? & alpha_{n}     & . & . & kappa_{n}

end{matrix}mspace{3mu}

end{vmatrix}

end{equation*}



end{document}


enter image description here



With dots and hdotsfor:



begin{equation*}

newcommand{ak}[2]{a_{#2}#1_1+dots+k_{#2}#1_n}

begin{vmatrix}

 0 & dots &  0 & ak{alpha}{1} & dots & ak{kappa}{1} \

hdotsfor{6} \

 0 & dots &  0 & ak{alpha}{n} & dots & ak{kappa}{n} \

-1 & dots &  0 & alpha_{1}     & dots & kappa_{1}     \

hdotsfor{6} \

 0 & dots & -1 & alpha_{n}     & dots & kappa_{n}

end{vmatrix}

end{equation*}


enter image description here






share|improve this answer














This seems a good approximation:



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

begin{vmatrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

-1 & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & -1 & alpha_{n}     & . & . & kappa_{n}

end{vmatrix}

end{equation*}



end{document}


enter image description here



The value 14tabcolsep has been determined by first looking at the entries at their natural width.



Even better than the original if we make -1 to hide its width.



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



newcommand{widedots}{%

  .cleadershbox to 2tabcolsep{hss.hss}hfill.%

  hspace*{0pt}%

}



begin{document}



begin{equation*}

newcommand{ak}[2]{%

  makebox[14tabcolsep][s]{$displaystyle a_{#2}#1_1+dots+k_{#2}#1_n$}%

}

newcommand{?}{makebox[0pt]{$-1$}}

begin{vmatrix}mspace{8mu}

begin{matrix}

 0 & . & . &  0 & ak{alpha}{1} & . & . & ak{kappa}{1} \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . &  0 & ak{alpha}{n} & . & . & ak{kappa}{n} \

? & . & . &  0 & alpha_{1}     & . & . & kappa_{1}     \

 . & . & . &  . & widedots      & . & . & widedots      \

 0 & . & . & ? & alpha_{n}     & . & . & kappa_{n}

end{matrix}mspace{3mu}

end{vmatrix}

end{equation*}



end{document}


enter image description here



With dots and hdotsfor:



begin{equation*}

newcommand{ak}[2]{a_{#2}#1_1+dots+k_{#2}#1_n}

begin{vmatrix}

 0 & dots &  0 & ak{alpha}{1} & dots & ak{kappa}{1} \

hdotsfor{6} \

 0 & dots &  0 & ak{alpha}{n} & dots & ak{kappa}{n} \

-1 & dots &  0 & alpha_{1}     & dots & kappa_{1}     \

hdotsfor{6} \

 0 & dots & -1 & alpha_{n}     & dots & kappa_{n}

end{vmatrix}

end{equation*}


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 8 at 22:05

























answered Dec 8 at 21:53









egreg

704k8618763155




704k8618763155












  • Although I may not be able to decipher how your code works, it looks like the one with the capability of hiding the with of -1 fits my need. I have a feeling after perusing your code, I will understand better. Thank you.
    – user91822
    Dec 9 at 0:18


















  • Although I may not be able to decipher how your code works, it looks like the one with the capability of hiding the with of -1 fits my need. I have a feeling after perusing your code, I will understand better. Thank you.
    – user91822
    Dec 9 at 0:18
















Although I may not be able to decipher how your code works, it looks like the one with the capability of hiding the with of -1 fits my need. I have a feeling after perusing your code, I will understand better. Thank you.
– user91822
Dec 9 at 0:18




Although I may not be able to decipher how your code works, it looks like the one with the capability of hiding the with of -1 fits my need. I have a feeling after perusing your code, I will understand better. Thank you.
– user91822
Dec 9 at 0:18










up vote
4
down vote













One way is to manually put dots with some horizontal space.



enter image description here



documentclass[a4paper,10pt]{article}

usepackage{amsmath}

begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                               &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                                      &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}





share|improve this answer





















  • Honestly, I had never thought of using 'hfil'. Thank you for the pointer.
    – user91822
    Dec 9 at 0:20















up vote
4
down vote













One way is to manually put dots with some horizontal space.



enter image description here



documentclass[a4paper,10pt]{article}

usepackage{amsmath}

begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                               &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                                      &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}





share|improve this answer





















  • Honestly, I had never thought of using 'hfil'. Thank you for the pointer.
    – user91822
    Dec 9 at 0:20













up vote
4
down vote










up vote
4
down vote









One way is to manually put dots with some horizontal space.



enter image description here



documentclass[a4paper,10pt]{article}

usepackage{amsmath}

begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                               &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                                      &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}





share|improve this answer












One way is to manually put dots with some horizontal space.



enter image description here



documentclass[a4paper,10pt]{article}

usepackage{amsmath}

begin{document}



begin{equation*}

        begin{vmatrix}

                0     &cdot &cdot &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdot &cdot &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                               &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdot &cdot &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

                -1    &cdot &cdot &0     &alpha_{1}                                 &cdot &cdot &kappa_{1} \

                cdot &cdot &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot                                      &cdot &cdot &cdot hfil hfil cdot hfil cdot hfil cdot hfil cdot  \

                0     &cdot &cdot &-1    &alpha_{n}                                 &cdot &cdot &kappa_{n}

        end{vmatrix}

end{equation*}



end{document}






share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 8 at 21:33









nidhin

3,279927




3,279927












  • Honestly, I had never thought of using 'hfil'. Thank you for the pointer.
    – user91822
    Dec 9 at 0:20


















  • Honestly, I had never thought of using 'hfil'. Thank you for the pointer.
    – user91822
    Dec 9 at 0:20
















Honestly, I had never thought of using 'hfil'. Thank you for the pointer.
– user91822
Dec 9 at 0:20




Honestly, I had never thought of using 'hfil'. Thank you for the pointer.
– user91822
Dec 9 at 0:20










up vote
3
down vote













Defining two newcommands twodts and fivedts for empty columns and rows can simplify the table. 



documentclass[a4paper,10pt]{article}

usepackage{amsmath}



begin{document}



newcommand{twodts}{begin{tabular}{@{}cc@{}}$cdot$&$cdot$end{tabular}}

newcommand{fivedts}{begin{tabular}{@{}*5{c}@{}}$cdot$&$cdot$&$cdot$&$cdot$&$cdot$end{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here




Update:



You can easily adapt my answer to add six dots instead of five like this:



documentclass[a4paper,10pt]{article}

usepackage{amsmath,array}



begin{document}



deftwocdots{$cdot$&$cdot$}

newcommand{twodts}{begin{tabular}{@{}cc@{}}twocdotsend{tabular}}

newcommand{sixdts}{begin{tabular}{@{}*6{c}@{}}twocdots&twocdots&twocdotsend{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here







share|improve this answer























  • This looks pretty simple and good solution. Since there is still some gaps that seems to be able to put one more dot when using the `fivedts' command, I wonder if this command can be modded to accommodate the gap. I tried to modify with a "sixdots" and it does not work, unfortunately. Anyway, thank you too.
    – user91822
    Dec 9 at 0:24










  • Please see my update for doing this.
    – AboAmmar
    Dec 9 at 16:31















up vote
3
down vote













Defining two newcommands twodts and fivedts for empty columns and rows can simplify the table. 



documentclass[a4paper,10pt]{article}

usepackage{amsmath}



begin{document}



newcommand{twodts}{begin{tabular}{@{}cc@{}}$cdot$&$cdot$end{tabular}}

newcommand{fivedts}{begin{tabular}{@{}*5{c}@{}}$cdot$&$cdot$&$cdot$&$cdot$&$cdot$end{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here




Update:



You can easily adapt my answer to add six dots instead of five like this:



documentclass[a4paper,10pt]{article}

usepackage{amsmath,array}



begin{document}



deftwocdots{$cdot$&$cdot$}

newcommand{twodts}{begin{tabular}{@{}cc@{}}twocdotsend{tabular}}

newcommand{sixdts}{begin{tabular}{@{}*6{c}@{}}twocdots&twocdots&twocdotsend{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here







share|improve this answer























  • This looks pretty simple and good solution. Since there is still some gaps that seems to be able to put one more dot when using the `fivedts' command, I wonder if this command can be modded to accommodate the gap. I tried to modify with a "sixdots" and it does not work, unfortunately. Anyway, thank you too.
    – user91822
    Dec 9 at 0:24










  • Please see my update for doing this.
    – AboAmmar
    Dec 9 at 16:31













up vote
3
down vote










up vote
3
down vote









Defining two newcommands twodts and fivedts for empty columns and rows can simplify the table. 



documentclass[a4paper,10pt]{article}

usepackage{amsmath}



begin{document}



newcommand{twodts}{begin{tabular}{@{}cc@{}}$cdot$&$cdot$end{tabular}}

newcommand{fivedts}{begin{tabular}{@{}*5{c}@{}}$cdot$&$cdot$&$cdot$&$cdot$&$cdot$end{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here




Update:



You can easily adapt my answer to add six dots instead of five like this:



documentclass[a4paper,10pt]{article}

usepackage{amsmath,array}



begin{document}



deftwocdots{$cdot$&$cdot$}

newcommand{twodts}{begin{tabular}{@{}cc@{}}twocdotsend{tabular}}

newcommand{sixdts}{begin{tabular}{@{}*6{c}@{}}twocdots&twocdots&twocdotsend{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here







share|improve this answer














Defining two newcommands twodts and fivedts for empty columns and rows can simplify the table. 



documentclass[a4paper,10pt]{article}

usepackage{amsmath}



begin{document}



newcommand{twodts}{begin{tabular}{@{}cc@{}}$cdot$&$cdot$end{tabular}}

newcommand{fivedts}{begin{tabular}{@{}*5{c}@{}}$cdot$&$cdot$&$cdot$&$cdot$&$cdot$end{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & fivedts                           & twodts & fivedts                           \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here




Update:



You can easily adapt my answer to add six dots instead of five like this:



documentclass[a4paper,10pt]{article}

usepackage{amsmath,array}



begin{document}



deftwocdots{$cdot$&$cdot$}

newcommand{twodts}{begin{tabular}{@{}cc@{}}twocdotsend{tabular}}

newcommand{sixdts}{begin{tabular}{@{}*6{c}@{}}twocdots&twocdots&twocdotsend{tabular}}



begin{equation*}

  begin{array}{|cccccc|}

    0     & twodts & 0     & a_1 alpha_1+ cdots +k_1 alpha_n & twodts & a_1 kappa_1+ cdots +k_1 kappa_n \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & 0     & a_n alpha_1+ cdots +k_n alpha_n & twodts & a_n kappa_1+ cdots +k_n kappa_n \

    -1    & twodts & 0     & alpha_1                           & twodts & kappa_1                           \

    cdot & twodts & cdot & sixdts                            & twodts & sixdts                            \

    0     & twodts & -1    & alpha_n                           & twodts & kappa_n

  end{array}

end{equation*}



end{document}



enter image description here








share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 9 at 16:29

























answered Dec 8 at 22:19









AboAmmar

32.1k22781




32.1k22781












  • This looks pretty simple and good solution. Since there is still some gaps that seems to be able to put one more dot when using the `fivedts' command, I wonder if this command can be modded to accommodate the gap. I tried to modify with a "sixdots" and it does not work, unfortunately. Anyway, thank you too.
    – user91822
    Dec 9 at 0:24










  • Please see my update for doing this.
    – AboAmmar
    Dec 9 at 16:31


















  • This looks pretty simple and good solution. Since there is still some gaps that seems to be able to put one more dot when using the `fivedts' command, I wonder if this command can be modded to accommodate the gap. I tried to modify with a "sixdots" and it does not work, unfortunately. Anyway, thank you too.
    – user91822
    Dec 9 at 0:24










  • Please see my update for doing this.
    – AboAmmar
    Dec 9 at 16:31
















This looks pretty simple and good solution. Since there is still some gaps that seems to be able to put one more dot when using the `fivedts' command, I wonder if this command can be modded to accommodate the gap. I tried to modify with a "sixdots" and it does not work, unfortunately. Anyway, thank you too.
– user91822
Dec 9 at 0:24




This looks pretty simple and good solution. Since there is still some gaps that seems to be able to put one more dot when using the `fivedts' command, I wonder if this command can be modded to accommodate the gap. I tried to modify with a "sixdots" and it does not work, unfortunately. Anyway, thank you too.
– user91822
Dec 9 at 0:24












Please see my update for doing this.
– AboAmmar
Dec 9 at 16:31




Please see my update for doing this.
– AboAmmar
Dec 9 at 16:31










up vote
1
down vote













Would this be acceptable?



enter image description here



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

           begin{vmatrix}

            0     &cdots &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdots     &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

            vdots &ddots &vdots &vdots &ddots  &vdots \

            0     &cdots & 0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdots  &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

            -1    &cdots &0     &alpha_{1}  &cdots &kappa_{1} \

            vdots &ddots &vdots &vdots   &ddots &vdots \

            0     &cdots & -1    &alpha_{n}  &cdots &kappa_{n}

    end{vmatrix}

end{equation*}



end{document}





share|improve this answer

















  • 1




    This is I usually do and I don't think it will do for me. Sorry and I try to stick closer to the example I posted above. Anyway, thank you.
    – user91822
    Dec 9 at 0:25

















up vote
1
down vote













Would this be acceptable?



enter image description here



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

           begin{vmatrix}

            0     &cdots &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdots     &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

            vdots &ddots &vdots &vdots &ddots  &vdots \

            0     &cdots & 0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdots  &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

            -1    &cdots &0     &alpha_{1}  &cdots &kappa_{1} \

            vdots &ddots &vdots &vdots   &ddots &vdots \

            0     &cdots & -1    &alpha_{n}  &cdots &kappa_{n}

    end{vmatrix}

end{equation*}



end{document}





share|improve this answer

















  • 1




    This is I usually do and I don't think it will do for me. Sorry and I try to stick closer to the example I posted above. Anyway, thank you.
    – user91822
    Dec 9 at 0:25















up vote
1
down vote










up vote
1
down vote









Would this be acceptable?



enter image description here



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

           begin{vmatrix}

            0     &cdots &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdots     &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

            vdots &ddots &vdots &vdots &ddots  &vdots \

            0     &cdots & 0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdots  &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

            -1    &cdots &0     &alpha_{1}  &cdots &kappa_{1} \

            vdots &ddots &vdots &vdots   &ddots &vdots \

            0     &cdots & -1    &alpha_{n}  &cdots &kappa_{n}

    end{vmatrix}

end{equation*}



end{document}





share|improve this answer












Would this be acceptable?



enter image description here



documentclass[a4paper,10pt]{article}



usepackage{amsmath}



begin{document}



begin{equation*}

           begin{vmatrix}

            0     &cdots &0     &a_{1} alpha_{1}+ cdots +k_{1} alpha_{n} &cdots     &a_{1} kappa_{1}+ cdots +k_{1} kappa_{n} \

            vdots &ddots &vdots &vdots &ddots  &vdots \

            0     &cdots & 0     &a_{n} alpha_{1}+ cdots +k_{n} alpha_{n} &cdots  &a_{n} kappa_{1}+ cdots +k_{n} kappa_{n} \

            -1    &cdots &0     &alpha_{1}  &cdots &kappa_{1} \

            vdots &ddots &vdots &vdots   &ddots &vdots \

            0     &cdots & -1    &alpha_{n}  &cdots &kappa_{n}

    end{vmatrix}

end{equation*}



end{document}






share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 8 at 21:52









prt13463

765




765








  • 1




    This is I usually do and I don't think it will do for me. Sorry and I try to stick closer to the example I posted above. Anyway, thank you.
    – user91822
    Dec 9 at 0:25
















  • 1




    This is I usually do and I don't think it will do for me. Sorry and I try to stick closer to the example I posted above. Anyway, thank you.
    – user91822
    Dec 9 at 0:25










1




1




This is I usually do and I don't think it will do for me. Sorry and I try to stick closer to the example I posted above. Anyway, thank you.
– user91822
Dec 9 at 0:25






This is I usually do and I don't think it will do for me. Sorry and I try to stick closer to the example I posted above. Anyway, thank you.
– user91822
Dec 9 at 0:25




















draft saved

draft discarded




















































Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid …



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.





Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


Please pay close attention to the following guidance:


  • Please be sure to answer the question. Provide details and share your research!

But avoid …



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f463868%2fempty-elements-as-dots-in-matrix%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







-

Popular posts from this blog

數位音樂下載

Image
數位音樂下載 為非以「實體」方式來販賣音樂的相關產品，而使用數位格式如mp3、AAC等文件格式來進行銷售販賣的一种音乐产业形式。著名的數位音樂下載服務商有iTunes Store、RecoChoku、Google Play音乐和微软Zune等。数字音乐下载在二十一世纪初一度风靡全球， [1] [2] 使得传统唱片产业走向衰落，但其自身也在2010年代流媒体音乐服务如Apple Music、Spotify等的挤压下迅速失去市场份额。 [3] [4] 数字音乐下载有便于携带、传播迅速、制作简单成本低等优点，与流媒体音乐相比也能更好保障音乐人权益； [5] 但它同时很可能带来侵犯版权和滥用的情形， [6] 也给音乐产业带来了诸多不利影响。数字音乐下载为音乐人和乐迷提供了更加便捷直接的交流渠道，也一定程度上推动了网络音乐人的出现和独立音乐的迅速发展。 [7] 目录 1 历史 1.1 技术积淀（1987-2000） 1.2 出现与兴起（2000-2004） 1.3 唱片市场的颠覆者（2004-2007） 1.4 巅峰和衰落（2005-2013） 1.5 摇摇欲坠的现状与不可预知的明天（2014至今） 2 主要文件格式 2.1 PCM编码格式 2.1.1 WAV 2.1.2 APE 2.1.3 FLAC 2.2 苹果推出的无损文件格式 2.2.1 AIFF 2.2.2 ALAC 2.3 有损压缩格式 2.3.1 MP3 2.3.2 AAC 3 主要市场 3.1 iTunes Store 3.2 Google Play音乐商店 3.3 亚马逊音乐商店 3.4 部分其他音乐商店 4 影响与评价 4.1 对音乐产业的影响 4.2 对科技行业的影响 4.3 正面评价 4.4 负面评价 4.4.1 侵权问题 4.4.2 经营模式不明晰 4.4.3 不适应移动时代 4.5 文化现象 5 延伸阅读 6 参考资料 历史 苹果iTunes+iPod的软硬件搭配让数字音
Read more

格利澤436b

Image
格利泽436b 太陽系外行星 太陽系外行星列表 艺术家笔下的格利泽436b 母恆星 母恆星 Gliese 436 星座 獅子座 赤經 ( α ) 11 h  42 m  11.0941 s [1] 赤緯 ( δ ) +26° 42′ 23.652″ [1] 距離 33.4 ly (10.2 pc) 光譜類型 M2.5 V [1] 軌道參數 半长轴 ( a ) 0.0291±0.0004 [2] AU 軌道離心率 ( e ) 0.150±0.012 [2] 公轉週期 ( P ) 2.643904±0.000005 [3] d (0.00723849 y) 軌道傾角 ( i ) 85.8 +0.21 −0.25 [3] ° 角距 ( θ ) 2.794 mas 近星點時間 ( T 0 ) 2,451,551.716 ±0.01 JD 半振幅 ( K ) 18.68±0.8 m/s 物理性质 质量 ( m ) 22.2±1.0 [2] M ⊕ 半徑 ( r ) 4.327±0.183 [2] [4] R ⊕ 密度 ( ρ ) 1.51 g cm -3 表面重力 ( g ) 1.18 g 溫度 ( T ) 712±36 [2] K 發現 發現時間 2004 發現者 巴特勒、沃格特、 馬西 et al. 發現方法 徑向速度、凌日法 發現地點 美國加利福尼亞州 發表論文 出版 其他名稱 Ross 905 b, GJ 436 b, [5] LTT 13213 b, GCTP 2704.10 b, LHS 310, AC+27:28217 b, Vyssotsky 616 b, HIP 57087 b, GEN# +9.80120068 b, LP 319-75 b, G 121-7 b, LSPM J1142+2642 b, 1RXS J114211.9+264328 b, ASCC 683818 b, G 147-68 b, UCAC2 41198281 b, BP
Read more

When can things happen in Etherscan, such as the picture below?

Image
2 I don't know why balance of the address is 0. when can this situation? etherscan balances share | improve this question asked yesterday Ru Hi Ru Hi 11 1 New contributor Ru Hi is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct. add a comment  | 
Read more