Encode the date in Christmas Eve format












9














The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be 



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.






code-golf string date







share|improve this question
























  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 3




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    3 hours ago
















9














The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be 



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.






code-golf string date







share|improve this question
























  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 3




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    3 hours ago














9












9








9







The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be 



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.






code-golf string date







share|improve this question















The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be 



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.






code-golf string date




code-golf string date






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago

























asked 5 hours ago









PyRulez

3,35742054




3,35742054












  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 3




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    3 hours ago


















  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 3




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    3 hours ago
















Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
– Black Owl Kai
4 hours ago




Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
– Black Owl Kai
4 hours ago












@BlackOwlKai what cartoon?
– PyRulez
4 hours ago




@BlackOwlKai what cartoon?
– PyRulez
4 hours ago




3




3




A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
– Black Owl Kai
4 hours ago




A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
– Black Owl Kai
4 hours ago












@BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
– PyRulez
4 hours ago




@BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
– PyRulez
4 hours ago












You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
– Sparr
3 hours ago




You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
– Sparr
3 hours ago










2 Answers
2






active

oldest

votes


















3















R, 112 106 bytes





function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


Try it online!



Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



Pick the non-negative one and cat "Christmas" with that many "Eves".






share|improve this answer























  • You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    2 hours ago










  • Also would z[z>=0][1] work instead of min?
    – Giuseppe
    2 hours ago



















1















Perl 6, 61 bytes



say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


Try it online!



Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






share|improve this answer





















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    2 Answers
    2






    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer























    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      2 hours ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      2 hours ago
















    3















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer























    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      2 hours ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      2 hours ago














    3












    3








    3







    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 hours ago

























    answered 2 hours ago









    ngm

    3,22924




    3,22924












    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      2 hours ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      2 hours ago


















    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      2 hours ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      2 hours ago
















    You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    2 hours ago




    You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    2 hours ago












    Also would z[z>=0][1] work instead of min?
    – Giuseppe
    2 hours ago




    Also would z[z>=0][1] work instead of min?
    – Giuseppe
    2 hours ago











    1















    Perl 6, 61 bytes



    say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


    Try it online!



    Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






    share|improve this answer


























      1















      Perl 6, 61 bytes



      say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


      Try it online!



      Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






      share|improve this answer
























        1












        1








        1







        Perl 6, 61 bytes



        say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


        Try it online!



        Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






        share|improve this answer













        Perl 6, 61 bytes



        say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


        Try it online!



        Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 1 hour ago









        Sean

        3,29636




        3,29636






























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            數位音樂下載 為非以「實體」方式來販賣音樂的相關產品，而使用數位格式如mp3、AAC等文件格式來進行銷售販賣的一种音乐产业形式。著名的數位音樂下載服務商有iTunes Store、RecoChoku、Google Play音乐和微软Zune等。数字音乐下载在二十一世纪初一度风靡全球， [1] [2] 使得传统唱片产业走向衰落，但其自身也在2010年代流媒体音乐服务如Apple Music、Spotify等的挤压下迅速失去市场份额。 [3] [4] 数字音乐下载有便于携带、传播迅速、制作简单成本低等优点，与流媒体音乐相比也能更好保障音乐人权益； [5] 但它同时很可能带来侵犯版权和滥用的情形， [6] 也给音乐产业带来了诸多不利影响。数字音乐下载为音乐人和乐迷提供了更加便捷直接的交流渠道，也一定程度上推动了网络音乐人的出现和独立音乐的迅速发展。 [7] 目录 1 历史 1.1 技术积淀（1987-2000） 1.2 出现与兴起（2000-2004） 1.3 唱片市场的颠覆者（2004-2007） 1.4 巅峰和衰落（2005-2013） 1.5 摇摇欲坠的现状与不可预知的明天（2014至今） 2 主要文件格式 2.1 PCM编码格式 2.1.1 WAV 2.1.2 APE 2.1.3 FLAC 2.2 苹果推出的无损文件格式 2.2.1 AIFF 2.2.2 ALAC 2.3 有损压缩格式 2.3.1 MP3 2.3.2 AAC 3 主要市场 3.1 iTunes Store 3.2 Google Play音乐商店 3.3 亚马逊音乐商店 3.4 部分其他音乐商店 4 影响与评价 4.1 对音乐产业的影响 4.2 对科技行业的影响 4.3 正面评价 4.4 负面评价 4.4.1 侵权问题 4.4.2 经营模式不明晰 4.4.3 不适应移动时代 4.5 文化现象 5 延伸阅读 6 参考资料 历史 苹果iTunes+iPod的软硬件搭配让数字音...
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            When can things happen in Etherscan, such as the picture below?

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            2 I don't know why balance of the address is 0. when can this situation? etherscan balances share | improve this question asked yesterday Ru Hi Ru Hi 11 1 New contributor Ru Hi is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct. add a comment  |  ...
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            格利澤436b

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            格利泽436b 太陽系外行星 太陽系外行星列表 艺术家笔下的格利泽436b 母恆星 母恆星 Gliese 436 星座 獅子座 赤經 ( α ) 11 h  42 m  11.0941 s [1] 赤緯 ( δ ) +26° 42′ 23.652″ [1] 距離 33.4 ly (10.2 pc) 光譜類型 M2.5 V [1] 軌道參數 半长轴 ( a ) 0.0291±0.0004 [2] AU 軌道離心率 ( e ) 0.150±0.012 [2] 公轉週期 ( P ) 2.643904±0.000005 [3] d (0.00723849 y) 軌道傾角 ( i ) 85.8 +0.21 −0.25 [3] ° 角距 ( θ ) 2.794 mas 近星點時間 ( T 0 ) 2,451,551.716 ±0.01 JD 半振幅 ( K ) 18.68±0.8 m/s 物理性质 质量 ( m ) 22.2±1.0 [2] M ⊕ 半徑 ( r ) 4.327±0.183 [2] [4] R ⊕ 密度 ( ρ ) 1.51 g cm -3 表面重力 ( g ) 1.18 g 溫度 ( T ) 712±36 [2] K 發現 發現時間 2004 發現者 巴特勒、沃格特、 馬西 et al. 發現方法 徑向速度、凌日法 發現地點 美國加利福尼亞州 發表論文 出版 其他名稱 Ross 905 b, GJ 436 b, [5] LTT 13213 b, GCTP 2704.10 b, LHS 310, AC+27:28217 b, Vyssotsky 616 b, HIP 57087 b, GEN# +9.80120068 b, LP 319-75 b, G 121-7 b, LSPM J1142+2642 b, 1RXS J114211.9+264328 b, ASCC 683818 b, G 147-68 b, UCAC2 41198281 b, BP...
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