How can I add a directory to PATH in a script so that it affects the calling shell and the rest of the...
I am new to Ubuntu.
I wrote a script to add a dir to the PATH environment. When I run the script it runs fine and the dir is added to the PATH. But it seems that the change only lasts until the script exits instead of lasting for the length of the session. When I look at the PATH after the script is ran the dir is no longer there. Any suggestions?
command-line bash scripts environment-variables
add a comment |
I am new to Ubuntu.
I wrote a script to add a dir to the PATH environment. When I run the script it runs fine and the dir is added to the PATH. But it seems that the change only lasts until the script exits instead of lasting for the length of the session. When I look at the PATH after the script is ran the dir is no longer there. Any suggestions?
command-line bash scripts environment-variables
There are no "Images below", only tags. Your question is clear and doesn't really need any screenshots to explain your situation further. However, FYI, information on inserting images into posts can be found at: meta.stackexchange.com/questions/75491/…
– CentaurusA
Sep 9 at 21:22
2
Please don't post photos of text. Copy the text here and apply code formatting: askubuntu.com/editing-help#code
– muru
Sep 10 at 8:30
add a comment |
I am new to Ubuntu.
I wrote a script to add a dir to the PATH environment. When I run the script it runs fine and the dir is added to the PATH. But it seems that the change only lasts until the script exits instead of lasting for the length of the session. When I look at the PATH after the script is ran the dir is no longer there. Any suggestions?
command-line bash scripts environment-variables
I am new to Ubuntu.
I wrote a script to add a dir to the PATH environment. When I run the script it runs fine and the dir is added to the PATH. But it seems that the change only lasts until the script exits instead of lasting for the length of the session. When I look at the PATH after the script is ran the dir is no longer there. Any suggestions?
command-line bash scripts environment-variables
command-line bash scripts environment-variables
edited Sep 10 at 7:35
Zanna
50k13131238
50k13131238
asked Sep 9 at 20:51
JP JP
134
134
There are no "Images below", only tags. Your question is clear and doesn't really need any screenshots to explain your situation further. However, FYI, information on inserting images into posts can be found at: meta.stackexchange.com/questions/75491/…
– CentaurusA
Sep 9 at 21:22
2
Please don't post photos of text. Copy the text here and apply code formatting: askubuntu.com/editing-help#code
– muru
Sep 10 at 8:30
add a comment |
There are no "Images below", only tags. Your question is clear and doesn't really need any screenshots to explain your situation further. However, FYI, information on inserting images into posts can be found at: meta.stackexchange.com/questions/75491/…
– CentaurusA
Sep 9 at 21:22
2
Please don't post photos of text. Copy the text here and apply code formatting: askubuntu.com/editing-help#code
– muru
Sep 10 at 8:30
There are no "Images below", only tags. Your question is clear and doesn't really need any screenshots to explain your situation further. However, FYI, information on inserting images into posts can be found at: meta.stackexchange.com/questions/75491/…
– CentaurusA
Sep 9 at 21:22
There are no "Images below", only tags. Your question is clear and doesn't really need any screenshots to explain your situation further. However, FYI, information on inserting images into posts can be found at: meta.stackexchange.com/questions/75491/…
– CentaurusA
Sep 9 at 21:22
2
2
Please don't post photos of text. Copy the text here and apply code formatting: askubuntu.com/editing-help#code
– muru
Sep 10 at 8:30
Please don't post photos of text. Copy the text here and apply code formatting: askubuntu.com/editing-help#code
– muru
Sep 10 at 8:30
add a comment |
2 Answers
2
active
oldest
votes
There's two things to remember:
Commands, including scripts, keep their environment for the duration of the command running
Commands inherit environment from parent process. For commands started via shell, they'll inherit from the shell.
So if you do PATH=$PATH:/my/dir
that'll last only for the scripts duration. To make it permanent, the parent shell needs to be aware of the change. Proper way to do that would be to write to ~/.bashrc
if you're using bash or appropriate rc file for your shell. Thus we can use >> to append to file
echo PATH=$PATH:/my/dir >> ~/.bashrc
And when the script exits, run
source ~/.bashrc
so that the shell rereads the config and will be aware of the changes. Now every command you run in shell and every new interactive shell started will inherit new PATH variable
The two steps can be put together into a function since ( at least for bash ) functions run in current shell environment, so unlike a script when you do source
part, calling source
from a function will affect the current shell.
add a comment |
Sergiy Kolodyazhnyy's answer identifies the problem here: scripts are executed in a separate child shell of the shell that calls them, and commands that affect the shell itself, such as assigning to variables or changing working directory, do not affect the calling shell at all, only the child shell and (if they export
variables to the environment) its children.
You can play with this using humble shell variables...
$ foo=bar
$ echo $foo
bar
$ echo -e "foo=baz n"'echo $foo' > script
$ cat script
foo=baz
echo $foo
$ bash script
baz
$ echo $foo
bar
Although as Eliah Kagan shows in this answer it's easier to do so with subshells.
I am writing this answer in case you do not want to permanently add the directory to your PATH, but only to the current shell session.
To do this you simply need to run the script in the current shell. This is done with the source
command which is abbreviated to .
(dot).
Given this slightly simplified version of your script...
read -rp "What did you want to add to PATH? "
[ -d "$REPLY" ] &&
PATH="$PATH:$(readlink -m $REPLY)" &&
echo "OK, adding $REPLY to PATH" &&
echo "$PATH" ||
echo "seems like $REPLY is not a directory"
Notice that I get the same result as you when I run the script in the usual way:
$ ./add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games
But when I source
the script it works as expected:
$ . add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
I will add three asides:
- I recommend adding PATH assignments to
~/.profile
rather than~/.bashrc
because~/.bashrc
is sourced by every interactive Bash shell, including shells started from the current shell - this means child shells could end up with really long PATHs, as they inherit PATH as well as appending to it when they source~/.bashrc
. In contrast,~/.profile
is usually only sourced at login (or by login shells). - You don't need to
export
when you assign to PATH because it's already an environment variable: in a sense it is already exported and will remain so: an assignment to PATH will always be inherited by child processes (though not of parent processes, as you discovered!) without being explicitlyexport
ed.
I have quoted the variables
REPLY
andPATH
throughout. This is a good idea because either may have spaces or other characters that trigger shell expansions. However, a side effect of this is that~
is not expanded, so the script is apt to return things like
looks like ~/some-existing-dir is not a directory
which is true (taking
~
literally) but not very helpful. Maybe the script should warn the user of this...
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
There's two things to remember:
Commands, including scripts, keep their environment for the duration of the command running
Commands inherit environment from parent process. For commands started via shell, they'll inherit from the shell.
So if you do PATH=$PATH:/my/dir
that'll last only for the scripts duration. To make it permanent, the parent shell needs to be aware of the change. Proper way to do that would be to write to ~/.bashrc
if you're using bash or appropriate rc file for your shell. Thus we can use >> to append to file
echo PATH=$PATH:/my/dir >> ~/.bashrc
And when the script exits, run
source ~/.bashrc
so that the shell rereads the config and will be aware of the changes. Now every command you run in shell and every new interactive shell started will inherit new PATH variable
The two steps can be put together into a function since ( at least for bash ) functions run in current shell environment, so unlike a script when you do source
part, calling source
from a function will affect the current shell.
add a comment |
There's two things to remember:
Commands, including scripts, keep their environment for the duration of the command running
Commands inherit environment from parent process. For commands started via shell, they'll inherit from the shell.
So if you do PATH=$PATH:/my/dir
that'll last only for the scripts duration. To make it permanent, the parent shell needs to be aware of the change. Proper way to do that would be to write to ~/.bashrc
if you're using bash or appropriate rc file for your shell. Thus we can use >> to append to file
echo PATH=$PATH:/my/dir >> ~/.bashrc
And when the script exits, run
source ~/.bashrc
so that the shell rereads the config and will be aware of the changes. Now every command you run in shell and every new interactive shell started will inherit new PATH variable
The two steps can be put together into a function since ( at least for bash ) functions run in current shell environment, so unlike a script when you do source
part, calling source
from a function will affect the current shell.
add a comment |
There's two things to remember:
Commands, including scripts, keep their environment for the duration of the command running
Commands inherit environment from parent process. For commands started via shell, they'll inherit from the shell.
So if you do PATH=$PATH:/my/dir
that'll last only for the scripts duration. To make it permanent, the parent shell needs to be aware of the change. Proper way to do that would be to write to ~/.bashrc
if you're using bash or appropriate rc file for your shell. Thus we can use >> to append to file
echo PATH=$PATH:/my/dir >> ~/.bashrc
And when the script exits, run
source ~/.bashrc
so that the shell rereads the config and will be aware of the changes. Now every command you run in shell and every new interactive shell started will inherit new PATH variable
The two steps can be put together into a function since ( at least for bash ) functions run in current shell environment, so unlike a script when you do source
part, calling source
from a function will affect the current shell.
There's two things to remember:
Commands, including scripts, keep their environment for the duration of the command running
Commands inherit environment from parent process. For commands started via shell, they'll inherit from the shell.
So if you do PATH=$PATH:/my/dir
that'll last only for the scripts duration. To make it permanent, the parent shell needs to be aware of the change. Proper way to do that would be to write to ~/.bashrc
if you're using bash or appropriate rc file for your shell. Thus we can use >> to append to file
echo PATH=$PATH:/my/dir >> ~/.bashrc
And when the script exits, run
source ~/.bashrc
so that the shell rereads the config and will be aware of the changes. Now every command you run in shell and every new interactive shell started will inherit new PATH variable
The two steps can be put together into a function since ( at least for bash ) functions run in current shell environment, so unlike a script when you do source
part, calling source
from a function will affect the current shell.
edited Sep 9 at 21:09
answered Sep 9 at 20:58
Sergiy Kolodyazhnyy
69.3k9144304
69.3k9144304
add a comment |
add a comment |
Sergiy Kolodyazhnyy's answer identifies the problem here: scripts are executed in a separate child shell of the shell that calls them, and commands that affect the shell itself, such as assigning to variables or changing working directory, do not affect the calling shell at all, only the child shell and (if they export
variables to the environment) its children.
You can play with this using humble shell variables...
$ foo=bar
$ echo $foo
bar
$ echo -e "foo=baz n"'echo $foo' > script
$ cat script
foo=baz
echo $foo
$ bash script
baz
$ echo $foo
bar
Although as Eliah Kagan shows in this answer it's easier to do so with subshells.
I am writing this answer in case you do not want to permanently add the directory to your PATH, but only to the current shell session.
To do this you simply need to run the script in the current shell. This is done with the source
command which is abbreviated to .
(dot).
Given this slightly simplified version of your script...
read -rp "What did you want to add to PATH? "
[ -d "$REPLY" ] &&
PATH="$PATH:$(readlink -m $REPLY)" &&
echo "OK, adding $REPLY to PATH" &&
echo "$PATH" ||
echo "seems like $REPLY is not a directory"
Notice that I get the same result as you when I run the script in the usual way:
$ ./add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games
But when I source
the script it works as expected:
$ . add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
I will add three asides:
- I recommend adding PATH assignments to
~/.profile
rather than~/.bashrc
because~/.bashrc
is sourced by every interactive Bash shell, including shells started from the current shell - this means child shells could end up with really long PATHs, as they inherit PATH as well as appending to it when they source~/.bashrc
. In contrast,~/.profile
is usually only sourced at login (or by login shells). - You don't need to
export
when you assign to PATH because it's already an environment variable: in a sense it is already exported and will remain so: an assignment to PATH will always be inherited by child processes (though not of parent processes, as you discovered!) without being explicitlyexport
ed.
I have quoted the variables
REPLY
andPATH
throughout. This is a good idea because either may have spaces or other characters that trigger shell expansions. However, a side effect of this is that~
is not expanded, so the script is apt to return things like
looks like ~/some-existing-dir is not a directory
which is true (taking
~
literally) but not very helpful. Maybe the script should warn the user of this...
add a comment |
Sergiy Kolodyazhnyy's answer identifies the problem here: scripts are executed in a separate child shell of the shell that calls them, and commands that affect the shell itself, such as assigning to variables or changing working directory, do not affect the calling shell at all, only the child shell and (if they export
variables to the environment) its children.
You can play with this using humble shell variables...
$ foo=bar
$ echo $foo
bar
$ echo -e "foo=baz n"'echo $foo' > script
$ cat script
foo=baz
echo $foo
$ bash script
baz
$ echo $foo
bar
Although as Eliah Kagan shows in this answer it's easier to do so with subshells.
I am writing this answer in case you do not want to permanently add the directory to your PATH, but only to the current shell session.
To do this you simply need to run the script in the current shell. This is done with the source
command which is abbreviated to .
(dot).
Given this slightly simplified version of your script...
read -rp "What did you want to add to PATH? "
[ -d "$REPLY" ] &&
PATH="$PATH:$(readlink -m $REPLY)" &&
echo "OK, adding $REPLY to PATH" &&
echo "$PATH" ||
echo "seems like $REPLY is not a directory"
Notice that I get the same result as you when I run the script in the usual way:
$ ./add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games
But when I source
the script it works as expected:
$ . add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
I will add three asides:
- I recommend adding PATH assignments to
~/.profile
rather than~/.bashrc
because~/.bashrc
is sourced by every interactive Bash shell, including shells started from the current shell - this means child shells could end up with really long PATHs, as they inherit PATH as well as appending to it when they source~/.bashrc
. In contrast,~/.profile
is usually only sourced at login (or by login shells). - You don't need to
export
when you assign to PATH because it's already an environment variable: in a sense it is already exported and will remain so: an assignment to PATH will always be inherited by child processes (though not of parent processes, as you discovered!) without being explicitlyexport
ed.
I have quoted the variables
REPLY
andPATH
throughout. This is a good idea because either may have spaces or other characters that trigger shell expansions. However, a side effect of this is that~
is not expanded, so the script is apt to return things like
looks like ~/some-existing-dir is not a directory
which is true (taking
~
literally) but not very helpful. Maybe the script should warn the user of this...
add a comment |
Sergiy Kolodyazhnyy's answer identifies the problem here: scripts are executed in a separate child shell of the shell that calls them, and commands that affect the shell itself, such as assigning to variables or changing working directory, do not affect the calling shell at all, only the child shell and (if they export
variables to the environment) its children.
You can play with this using humble shell variables...
$ foo=bar
$ echo $foo
bar
$ echo -e "foo=baz n"'echo $foo' > script
$ cat script
foo=baz
echo $foo
$ bash script
baz
$ echo $foo
bar
Although as Eliah Kagan shows in this answer it's easier to do so with subshells.
I am writing this answer in case you do not want to permanently add the directory to your PATH, but only to the current shell session.
To do this you simply need to run the script in the current shell. This is done with the source
command which is abbreviated to .
(dot).
Given this slightly simplified version of your script...
read -rp "What did you want to add to PATH? "
[ -d "$REPLY" ] &&
PATH="$PATH:$(readlink -m $REPLY)" &&
echo "OK, adding $REPLY to PATH" &&
echo "$PATH" ||
echo "seems like $REPLY is not a directory"
Notice that I get the same result as you when I run the script in the usual way:
$ ./add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games
But when I source
the script it works as expected:
$ . add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
I will add three asides:
- I recommend adding PATH assignments to
~/.profile
rather than~/.bashrc
because~/.bashrc
is sourced by every interactive Bash shell, including shells started from the current shell - this means child shells could end up with really long PATHs, as they inherit PATH as well as appending to it when they source~/.bashrc
. In contrast,~/.profile
is usually only sourced at login (or by login shells). - You don't need to
export
when you assign to PATH because it's already an environment variable: in a sense it is already exported and will remain so: an assignment to PATH will always be inherited by child processes (though not of parent processes, as you discovered!) without being explicitlyexport
ed.
I have quoted the variables
REPLY
andPATH
throughout. This is a good idea because either may have spaces or other characters that trigger shell expansions. However, a side effect of this is that~
is not expanded, so the script is apt to return things like
looks like ~/some-existing-dir is not a directory
which is true (taking
~
literally) but not very helpful. Maybe the script should warn the user of this...
Sergiy Kolodyazhnyy's answer identifies the problem here: scripts are executed in a separate child shell of the shell that calls them, and commands that affect the shell itself, such as assigning to variables or changing working directory, do not affect the calling shell at all, only the child shell and (if they export
variables to the environment) its children.
You can play with this using humble shell variables...
$ foo=bar
$ echo $foo
bar
$ echo -e "foo=baz n"'echo $foo' > script
$ cat script
foo=baz
echo $foo
$ bash script
baz
$ echo $foo
bar
Although as Eliah Kagan shows in this answer it's easier to do so with subshells.
I am writing this answer in case you do not want to permanently add the directory to your PATH, but only to the current shell session.
To do this you simply need to run the script in the current shell. This is done with the source
command which is abbreviated to .
(dot).
Given this slightly simplified version of your script...
read -rp "What did you want to add to PATH? "
[ -d "$REPLY" ] &&
PATH="$PATH:$(readlink -m $REPLY)" &&
echo "OK, adding $REPLY to PATH" &&
echo "$PATH" ||
echo "seems like $REPLY is not a directory"
Notice that I get the same result as you when I run the script in the usual way:
$ ./add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games
But when I source
the script it works as expected:
$ . add-to-path
What did you want to add to PATH? /home/zanna/playground
OK, adding /home/zanna/playground to PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
$ echo $PATH
/home/zanna/bin:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/home/zanna/playground
I will add three asides:
- I recommend adding PATH assignments to
~/.profile
rather than~/.bashrc
because~/.bashrc
is sourced by every interactive Bash shell, including shells started from the current shell - this means child shells could end up with really long PATHs, as they inherit PATH as well as appending to it when they source~/.bashrc
. In contrast,~/.profile
is usually only sourced at login (or by login shells). - You don't need to
export
when you assign to PATH because it's already an environment variable: in a sense it is already exported and will remain so: an assignment to PATH will always be inherited by child processes (though not of parent processes, as you discovered!) without being explicitlyexport
ed.
I have quoted the variables
REPLY
andPATH
throughout. This is a good idea because either may have spaces or other characters that trigger shell expansions. However, a side effect of this is that~
is not expanded, so the script is apt to return things like
looks like ~/some-existing-dir is not a directory
which is true (taking
~
literally) but not very helpful. Maybe the script should warn the user of this...
edited Sep 10 at 8:26
answered Sep 10 at 8:15
Zanna
50k13131238
50k13131238
add a comment |
add a comment |
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There are no "Images below", only tags. Your question is clear and doesn't really need any screenshots to explain your situation further. However, FYI, information on inserting images into posts can be found at: meta.stackexchange.com/questions/75491/…
– CentaurusA
Sep 9 at 21:22
2
Please don't post photos of text. Copy the text here and apply code formatting: askubuntu.com/editing-help#code
– muru
Sep 10 at 8:30