Portable check empty directory
With Bash and Dash, you can check for an empty directory using just the shell
(ignore dotfiles to keep things simple):
set *
if [ -e "$1" ]
then
echo 'not empty'
else
echo 'empty'
fi
However I recently learned that Zsh fails spectacularly in this case:
% set *
zsh: no matches found: *
% echo "$? $#"
1 0
So not only does the set
command fail, but it doesn't even set $@
. I suppose
I could test if $#
is 0
, but it appears that Zsh even stops execution:
% { set *; echo 2; }
zsh: no matches found: *
Compare with Bash and Dash:
$ { set *; echo 2; }
2
Can this be done in a way that works in bash, dash and zsh?
bash zsh wildcards portability dash
New contributor
add a comment |
With Bash and Dash, you can check for an empty directory using just the shell
(ignore dotfiles to keep things simple):
set *
if [ -e "$1" ]
then
echo 'not empty'
else
echo 'empty'
fi
However I recently learned that Zsh fails spectacularly in this case:
% set *
zsh: no matches found: *
% echo "$? $#"
1 0
So not only does the set
command fail, but it doesn't even set $@
. I suppose
I could test if $#
is 0
, but it appears that Zsh even stops execution:
% { set *; echo 2; }
zsh: no matches found: *
Compare with Bash and Dash:
$ { set *; echo 2; }
2
Can this be done in a way that works in bash, dash and zsh?
bash zsh wildcards portability dash
New contributor
add a comment |
With Bash and Dash, you can check for an empty directory using just the shell
(ignore dotfiles to keep things simple):
set *
if [ -e "$1" ]
then
echo 'not empty'
else
echo 'empty'
fi
However I recently learned that Zsh fails spectacularly in this case:
% set *
zsh: no matches found: *
% echo "$? $#"
1 0
So not only does the set
command fail, but it doesn't even set $@
. I suppose
I could test if $#
is 0
, but it appears that Zsh even stops execution:
% { set *; echo 2; }
zsh: no matches found: *
Compare with Bash and Dash:
$ { set *; echo 2; }
2
Can this be done in a way that works in bash, dash and zsh?
bash zsh wildcards portability dash
New contributor
With Bash and Dash, you can check for an empty directory using just the shell
(ignore dotfiles to keep things simple):
set *
if [ -e "$1" ]
then
echo 'not empty'
else
echo 'empty'
fi
However I recently learned that Zsh fails spectacularly in this case:
% set *
zsh: no matches found: *
% echo "$? $#"
1 0
So not only does the set
command fail, but it doesn't even set $@
. I suppose
I could test if $#
is 0
, but it appears that Zsh even stops execution:
% { set *; echo 2; }
zsh: no matches found: *
Compare with Bash and Dash:
$ { set *; echo 2; }
2
Can this be done in a way that works in bash, dash and zsh?
bash zsh wildcards portability dash
bash zsh wildcards portability dash
New contributor
New contributor
edited 1 hour ago
terdon♦
128k31252427
128k31252427
New contributor
asked 1 hour ago
Three
262
262
New contributor
New contributor
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
While zsh's default behaviour is to give an error, this is controlled by the nomatch
option. You can unset the option to leave the *
in place the way that bash and dash do:
setopt -o nonomatch
While that command won't work in either of the others, you can just ignore that:
setopt -o nonomatch 2>/dev/null || true ; set *
This runs setopt
on zsh, and suppresses the error output (2>/dev/null
) and return code (|| true
) of the failed command on the others.
As written it's problematic if there is a file, for example, -e
: then you will run set -e
and change the shell options to terminate whenever a command fails; there are worse outcomes if you're creative. set -- *
will be safer and prevent the option changes.
If a file is named*
, then$1
equals*
and[ -e "$1" ]
passes, meaning the example in the question still works
– Three
47 mins ago
@Three Fair point! It's conceptually iffy but it does actually work, since if there is a file there then... there is a file there.
– Michael Homer
45 mins ago
add a comment |
Most portable way would be via set
and globstar for all POSIX-compliant shells. This has been shown in Gilles's answer on a related question. I've adapted the method slightly into a function:
mkdir empty_dir
pwd
cd empty_dir
pwd
dir_empty(){
# https://stackoverflow.com/a/9911082/3701431
if [ -n "$ZSH_VERSION" ]; then
# https://unix.stackexchange.com/a/310553/85039
setopt +o nomatch
fi
set -- *
echo
if [ $# -ne 1 ] || [ -e "$1" ]; then
echo "directory not empty"
else
echo "directory empty"
fi
}
dir_empty
touch '*'
dir_empty
The way it works is by using set
to set items in current working directory as positional parameters ( $1
, $2
, and so on ). If glob doesn't expand to any existing files, there shall only be one, literal *
as $1
, .
as $2
and $3
, so we also account for hidden files here.
Of course, it's a possibility that *
could be a real filename, which is why we also perform [ -e "$1" ]
check. If you want to use the function silently, we could rewrite it to return
a value as in return 0
if success instead of echo
Try it online!
1
This fails on Zsh for reasons detailed in the question - the function halts execution after the set command - so neither echo is ever reached
– Three
40 mins ago
@Three I've adapted the answer to check forzsh
. Unfortunatelly for uszsh
decided to go the weird way instead of similar behavior tobash
or other shells, since according to POSIX: "If the pattern does not match any pathnames, the returned number of matched paths is set to 0, and the contents of pglob->gl_pathv are implementation-defined." source
– Sergiy Kolodyazhnyy
22 mins ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
While zsh's default behaviour is to give an error, this is controlled by the nomatch
option. You can unset the option to leave the *
in place the way that bash and dash do:
setopt -o nonomatch
While that command won't work in either of the others, you can just ignore that:
setopt -o nonomatch 2>/dev/null || true ; set *
This runs setopt
on zsh, and suppresses the error output (2>/dev/null
) and return code (|| true
) of the failed command on the others.
As written it's problematic if there is a file, for example, -e
: then you will run set -e
and change the shell options to terminate whenever a command fails; there are worse outcomes if you're creative. set -- *
will be safer and prevent the option changes.
If a file is named*
, then$1
equals*
and[ -e "$1" ]
passes, meaning the example in the question still works
– Three
47 mins ago
@Three Fair point! It's conceptually iffy but it does actually work, since if there is a file there then... there is a file there.
– Michael Homer
45 mins ago
add a comment |
While zsh's default behaviour is to give an error, this is controlled by the nomatch
option. You can unset the option to leave the *
in place the way that bash and dash do:
setopt -o nonomatch
While that command won't work in either of the others, you can just ignore that:
setopt -o nonomatch 2>/dev/null || true ; set *
This runs setopt
on zsh, and suppresses the error output (2>/dev/null
) and return code (|| true
) of the failed command on the others.
As written it's problematic if there is a file, for example, -e
: then you will run set -e
and change the shell options to terminate whenever a command fails; there are worse outcomes if you're creative. set -- *
will be safer and prevent the option changes.
If a file is named*
, then$1
equals*
and[ -e "$1" ]
passes, meaning the example in the question still works
– Three
47 mins ago
@Three Fair point! It's conceptually iffy but it does actually work, since if there is a file there then... there is a file there.
– Michael Homer
45 mins ago
add a comment |
While zsh's default behaviour is to give an error, this is controlled by the nomatch
option. You can unset the option to leave the *
in place the way that bash and dash do:
setopt -o nonomatch
While that command won't work in either of the others, you can just ignore that:
setopt -o nonomatch 2>/dev/null || true ; set *
This runs setopt
on zsh, and suppresses the error output (2>/dev/null
) and return code (|| true
) of the failed command on the others.
As written it's problematic if there is a file, for example, -e
: then you will run set -e
and change the shell options to terminate whenever a command fails; there are worse outcomes if you're creative. set -- *
will be safer and prevent the option changes.
While zsh's default behaviour is to give an error, this is controlled by the nomatch
option. You can unset the option to leave the *
in place the way that bash and dash do:
setopt -o nonomatch
While that command won't work in either of the others, you can just ignore that:
setopt -o nonomatch 2>/dev/null || true ; set *
This runs setopt
on zsh, and suppresses the error output (2>/dev/null
) and return code (|| true
) of the failed command on the others.
As written it's problematic if there is a file, for example, -e
: then you will run set -e
and change the shell options to terminate whenever a command fails; there are worse outcomes if you're creative. set -- *
will be safer and prevent the option changes.
edited 45 mins ago
answered 52 mins ago
Michael Homer
46.3k8121161
46.3k8121161
If a file is named*
, then$1
equals*
and[ -e "$1" ]
passes, meaning the example in the question still works
– Three
47 mins ago
@Three Fair point! It's conceptually iffy but it does actually work, since if there is a file there then... there is a file there.
– Michael Homer
45 mins ago
add a comment |
If a file is named*
, then$1
equals*
and[ -e "$1" ]
passes, meaning the example in the question still works
– Three
47 mins ago
@Three Fair point! It's conceptually iffy but it does actually work, since if there is a file there then... there is a file there.
– Michael Homer
45 mins ago
If a file is named
*
, then $1
equals *
and [ -e "$1" ]
passes, meaning the example in the question still works– Three
47 mins ago
If a file is named
*
, then $1
equals *
and [ -e "$1" ]
passes, meaning the example in the question still works– Three
47 mins ago
@Three Fair point! It's conceptually iffy but it does actually work, since if there is a file there then... there is a file there.
– Michael Homer
45 mins ago
@Three Fair point! It's conceptually iffy but it does actually work, since if there is a file there then... there is a file there.
– Michael Homer
45 mins ago
add a comment |
Most portable way would be via set
and globstar for all POSIX-compliant shells. This has been shown in Gilles's answer on a related question. I've adapted the method slightly into a function:
mkdir empty_dir
pwd
cd empty_dir
pwd
dir_empty(){
# https://stackoverflow.com/a/9911082/3701431
if [ -n "$ZSH_VERSION" ]; then
# https://unix.stackexchange.com/a/310553/85039
setopt +o nomatch
fi
set -- *
echo
if [ $# -ne 1 ] || [ -e "$1" ]; then
echo "directory not empty"
else
echo "directory empty"
fi
}
dir_empty
touch '*'
dir_empty
The way it works is by using set
to set items in current working directory as positional parameters ( $1
, $2
, and so on ). If glob doesn't expand to any existing files, there shall only be one, literal *
as $1
, .
as $2
and $3
, so we also account for hidden files here.
Of course, it's a possibility that *
could be a real filename, which is why we also perform [ -e "$1" ]
check. If you want to use the function silently, we could rewrite it to return
a value as in return 0
if success instead of echo
Try it online!
1
This fails on Zsh for reasons detailed in the question - the function halts execution after the set command - so neither echo is ever reached
– Three
40 mins ago
@Three I've adapted the answer to check forzsh
. Unfortunatelly for uszsh
decided to go the weird way instead of similar behavior tobash
or other shells, since according to POSIX: "If the pattern does not match any pathnames, the returned number of matched paths is set to 0, and the contents of pglob->gl_pathv are implementation-defined." source
– Sergiy Kolodyazhnyy
22 mins ago
add a comment |
Most portable way would be via set
and globstar for all POSIX-compliant shells. This has been shown in Gilles's answer on a related question. I've adapted the method slightly into a function:
mkdir empty_dir
pwd
cd empty_dir
pwd
dir_empty(){
# https://stackoverflow.com/a/9911082/3701431
if [ -n "$ZSH_VERSION" ]; then
# https://unix.stackexchange.com/a/310553/85039
setopt +o nomatch
fi
set -- *
echo
if [ $# -ne 1 ] || [ -e "$1" ]; then
echo "directory not empty"
else
echo "directory empty"
fi
}
dir_empty
touch '*'
dir_empty
The way it works is by using set
to set items in current working directory as positional parameters ( $1
, $2
, and so on ). If glob doesn't expand to any existing files, there shall only be one, literal *
as $1
, .
as $2
and $3
, so we also account for hidden files here.
Of course, it's a possibility that *
could be a real filename, which is why we also perform [ -e "$1" ]
check. If you want to use the function silently, we could rewrite it to return
a value as in return 0
if success instead of echo
Try it online!
1
This fails on Zsh for reasons detailed in the question - the function halts execution after the set command - so neither echo is ever reached
– Three
40 mins ago
@Three I've adapted the answer to check forzsh
. Unfortunatelly for uszsh
decided to go the weird way instead of similar behavior tobash
or other shells, since according to POSIX: "If the pattern does not match any pathnames, the returned number of matched paths is set to 0, and the contents of pglob->gl_pathv are implementation-defined." source
– Sergiy Kolodyazhnyy
22 mins ago
add a comment |
Most portable way would be via set
and globstar for all POSIX-compliant shells. This has been shown in Gilles's answer on a related question. I've adapted the method slightly into a function:
mkdir empty_dir
pwd
cd empty_dir
pwd
dir_empty(){
# https://stackoverflow.com/a/9911082/3701431
if [ -n "$ZSH_VERSION" ]; then
# https://unix.stackexchange.com/a/310553/85039
setopt +o nomatch
fi
set -- *
echo
if [ $# -ne 1 ] || [ -e "$1" ]; then
echo "directory not empty"
else
echo "directory empty"
fi
}
dir_empty
touch '*'
dir_empty
The way it works is by using set
to set items in current working directory as positional parameters ( $1
, $2
, and so on ). If glob doesn't expand to any existing files, there shall only be one, literal *
as $1
, .
as $2
and $3
, so we also account for hidden files here.
Of course, it's a possibility that *
could be a real filename, which is why we also perform [ -e "$1" ]
check. If you want to use the function silently, we could rewrite it to return
a value as in return 0
if success instead of echo
Try it online!
Most portable way would be via set
and globstar for all POSIX-compliant shells. This has been shown in Gilles's answer on a related question. I've adapted the method slightly into a function:
mkdir empty_dir
pwd
cd empty_dir
pwd
dir_empty(){
# https://stackoverflow.com/a/9911082/3701431
if [ -n "$ZSH_VERSION" ]; then
# https://unix.stackexchange.com/a/310553/85039
setopt +o nomatch
fi
set -- *
echo
if [ $# -ne 1 ] || [ -e "$1" ]; then
echo "directory not empty"
else
echo "directory empty"
fi
}
dir_empty
touch '*'
dir_empty
The way it works is by using set
to set items in current working directory as positional parameters ( $1
, $2
, and so on ). If glob doesn't expand to any existing files, there shall only be one, literal *
as $1
, .
as $2
and $3
, so we also account for hidden files here.
Of course, it's a possibility that *
could be a real filename, which is why we also perform [ -e "$1" ]
check. If you want to use the function silently, we could rewrite it to return
a value as in return 0
if success instead of echo
Try it online!
edited 17 mins ago
answered 45 mins ago
Sergiy Kolodyazhnyy
8,39212152
8,39212152
1
This fails on Zsh for reasons detailed in the question - the function halts execution after the set command - so neither echo is ever reached
– Three
40 mins ago
@Three I've adapted the answer to check forzsh
. Unfortunatelly for uszsh
decided to go the weird way instead of similar behavior tobash
or other shells, since according to POSIX: "If the pattern does not match any pathnames, the returned number of matched paths is set to 0, and the contents of pglob->gl_pathv are implementation-defined." source
– Sergiy Kolodyazhnyy
22 mins ago
add a comment |
1
This fails on Zsh for reasons detailed in the question - the function halts execution after the set command - so neither echo is ever reached
– Three
40 mins ago
@Three I've adapted the answer to check forzsh
. Unfortunatelly for uszsh
decided to go the weird way instead of similar behavior tobash
or other shells, since according to POSIX: "If the pattern does not match any pathnames, the returned number of matched paths is set to 0, and the contents of pglob->gl_pathv are implementation-defined." source
– Sergiy Kolodyazhnyy
22 mins ago
1
1
This fails on Zsh for reasons detailed in the question - the function halts execution after the set command - so neither echo is ever reached
– Three
40 mins ago
This fails on Zsh for reasons detailed in the question - the function halts execution after the set command - so neither echo is ever reached
– Three
40 mins ago
@Three I've adapted the answer to check for
zsh
. Unfortunatelly for us zsh
decided to go the weird way instead of similar behavior to bash
or other shells, since according to POSIX: "If the pattern does not match any pathnames, the returned number of matched paths is set to 0, and the contents of pglob->gl_pathv are implementation-defined." source– Sergiy Kolodyazhnyy
22 mins ago
@Three I've adapted the answer to check for
zsh
. Unfortunatelly for us zsh
decided to go the weird way instead of similar behavior to bash
or other shells, since according to POSIX: "If the pattern does not match any pathnames, the returned number of matched paths is set to 0, and the contents of pglob->gl_pathv are implementation-defined." source– Sergiy Kolodyazhnyy
22 mins ago
add a comment |
Three is a new contributor. Be nice, and check out our Code of Conduct.
Three is a new contributor. Be nice, and check out our Code of Conduct.
Three is a new contributor. Be nice, and check out our Code of Conduct.
Three is a new contributor. Be nice, and check out our Code of Conduct.
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