Convert an array to list with specific range in Java 8












6














I want to convert one string array to list with specific range. In my case I always want from index 1 to last index. I don't need the index 0 value included in the list. Is there any direct method that I can use to filter and convert to the list as I need ?



public class test1 {



    public static void main(String args) {

        String optArr = {"start", "map1", "map2", "map3"};

        List<String> list = Arrays.stream(optArr).collect(Collectors.toList());

        System.out.println(list);

    }

}





java java-8







share|improve this question


















  • 1




    ArrayList class have a subList method, which can be used to slice the list.
    – raviraja
    1 hour ago






  • 1




    Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
    – nullpointer
    1 hour ago


















6














I want to convert one string array to list with specific range. In my case I always want from index 1 to last index. I don't need the index 0 value included in the list. Is there any direct method that I can use to filter and convert to the list as I need ?



public class test1 {



    public static void main(String args) {

        String optArr = {"start", "map1", "map2", "map3"};

        List<String> list = Arrays.stream(optArr).collect(Collectors.toList());

        System.out.println(list);

    }

}





java java-8







share|improve this question


















  • 1




    ArrayList class have a subList method, which can be used to slice the list.
    – raviraja
    1 hour ago






  • 1




    Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
    – nullpointer
    1 hour ago
















6












6








6


3





I want to convert one string array to list with specific range. In my case I always want from index 1 to last index. I don't need the index 0 value included in the list. Is there any direct method that I can use to filter and convert to the list as I need ?



public class test1 {



    public static void main(String args) {

        String optArr = {"start", "map1", "map2", "map3"};

        List<String> list = Arrays.stream(optArr).collect(Collectors.toList());

        System.out.println(list);

    }

}





java java-8







share|improve this question













I want to convert one string array to list with specific range. In my case I always want from index 1 to last index. I don't need the index 0 value included in the list. Is there any direct method that I can use to filter and convert to the list as I need ?



public class test1 {



    public static void main(String args) {

        String optArr = {"start", "map1", "map2", "map3"};

        List<String> list = Arrays.stream(optArr).collect(Collectors.toList());

        System.out.println(list);

    }

}





java java-8




java java-8






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 1 hour ago









manjunath ramigani

501415




501415








  • 1




    ArrayList class have a subList method, which can be used to slice the list.
    – raviraja
    1 hour ago






  • 1




    Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
    – nullpointer
    1 hour ago
















  • 1




    ArrayList class have a subList method, which can be used to slice the list.
    – raviraja
    1 hour ago






  • 1




    Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
    – nullpointer
    1 hour ago










1




1




ArrayList class have a subList method, which can be used to slice the list.
– raviraja
1 hour ago




ArrayList class have a subList method, which can be used to slice the list.
– raviraja
1 hour ago




1




1




Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
– nullpointer
1 hour ago






Aside: rename your class/variables to follow proper naming conventions and have meaningful names. e.g. ArrayToListConversionTest is also a better name
– nullpointer
1 hour ago














7 Answers
7






active

oldest

votes


















6














You can use Stream.skip():



List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());





share|improve this answer





















  • the only challenge with skip would be selecting initial elements instead of skipping
    – nullpointer
    1 hour ago






  • 1




    @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
    – Robby Cornelissen
    1 hour ago



















6














You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



List<String> list = Arrays.stream(optArr, 1, optArr.length)

                          .collect(Collectors.toList());



Returns a sequential Stream with the specified range of the specified
array as its source.





Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



List<String> list = Arrays.asList(optArr).subList(1, optArr.length);





share|improve this answer































    1














    One non Java 8 option might be to just create a view on top of your current list which omits the first element:



    List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
    
List<String> viewList = list.subList(1, list.size());


    This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.






    share|improve this answer























    • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
      – Tim Biegeleisen
      1 hour ago



















    0














    List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


    I think it must work.



    See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html






    share|improve this answer








    New contributor




    Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.


























      0














      One method use List.sublist(int,int)



      List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
      
System.out.println(list);


      Second method use Stream



      List<String> list = Arrays.stream(optArr)
      
    .skip(1)
      
    .collect(Collectors.toList());
      
System.out.println(list);





      share|improve this answer





























        0














        It should be like this.



        List<String> al = new ArrayList<>(Arrays.asList(optArr));
        
List actualList = list.subList(1, al.size());





        share|improve this answer





























          0














          Looking at your data you might consider :



          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


          But if you just want to filter the first index sublist is the way to go.
          You do not need to use stream whatever of are you can.






          share|improve this answer



















          • 1




            not content based, but index based
            – nullpointer
            1 hour ago











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          7 Answers
          7






          active

          oldest

          votes








          7 Answers
          7






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          6














          You can use Stream.skip():



          List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());





          share|improve this answer





















          • the only challenge with skip would be selecting initial elements instead of skipping
            – nullpointer
            1 hour ago






          • 1




            @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
            – Robby Cornelissen
            1 hour ago
















          6














          You can use Stream.skip():



          List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());





          share|improve this answer





















          • the only challenge with skip would be selecting initial elements instead of skipping
            – nullpointer
            1 hour ago






          • 1




            @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
            – Robby Cornelissen
            1 hour ago














          6












          6








          6






          You can use Stream.skip():



          List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());





          share|improve this answer












          You can use Stream.skip():



          List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 1 hour ago









          Robby Cornelissen

          43.2k126789




          43.2k126789












          • the only challenge with skip would be selecting initial elements instead of skipping
            – nullpointer
            1 hour ago






          • 1




            @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
            – Robby Cornelissen
            1 hour ago


















          • the only challenge with skip would be selecting initial elements instead of skipping
            – nullpointer
            1 hour ago






          • 1




            @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
            – Robby Cornelissen
            1 hour ago
















          the only challenge with skip would be selecting initial elements instead of skipping
          – nullpointer
          1 hour ago




          the only challenge with skip would be selecting initial elements instead of skipping
          – nullpointer
          1 hour ago




          1




          1




          @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
          – Robby Cornelissen
          1 hour ago




          @nullpointer I think we can all safely agree that for the given use case, your answer is the superior one. Have an upvote.
          – Robby Cornelissen
          1 hour ago













          6














          You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



          List<String> list = Arrays.stream(optArr, 1, optArr.length)
          
                          .collect(Collectors.toList());



          Returns a sequential Stream with the specified range of the specified
          array as its source          .





          Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



          List<String> list = Arrays.asList(optArr).subList(1, optArr.length);





          share|improve this answer




























            6














            You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



            List<String> list = Arrays.stream(optArr, 1, optArr.length)
            
                          .collect(Collectors.toList());



            Returns a sequential Stream with the specified range of the specified
            array as its source            .





            Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



            List<String> list = Arrays.asList(optArr).subList(1, optArr.length);





            share|improve this answer


























              6












              6








              6






              You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



              List<String> list = Arrays.stream(optArr, 1, optArr.length)
              
                          .collect(Collectors.toList());



              Returns a sequential Stream with the specified range of the specified
              array as its source              .





              Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



              List<String> list = Arrays.asList(optArr).subList(1, optArr.length);





              share|improve this answer














              You can also use the overloaded method Arrays.stream​(T array, int startInclusive, int endExclusive) as :



              List<String> list = Arrays.stream(optArr, 1, optArr.length)
              
                          .collect(Collectors.toList());



              Returns a sequential Stream with the specified range of the specified
              array as its source              .





              Alternatively(non Java-8), using the subList is an option, but I would prefer chaining it in one-line instead of creating a new object as:



              List<String> list = Arrays.asList(optArr).subList(1, optArr.length);






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 1 hour ago

























              answered 1 hour ago









              nullpointer

              41.2k1086173




              41.2k1086173























                  1














                  One non Java 8 option might be to just create a view on top of your current list which omits the first element:



                  List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
                  
List<String> viewList = list.subList(1, list.size());


                  This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.






                  share|improve this answer























                  • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                    – Tim Biegeleisen
                    1 hour ago
















                  1














                  One non Java 8 option might be to just create a view on top of your current list which omits the first element:



                  List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
                  
List<String> viewList = list.subList(1, list.size());


                  This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.






                  share|improve this answer























                  • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                    – Tim Biegeleisen
                    1 hour ago














                  1












                  1








                  1






                  One non Java 8 option might be to just create a view on top of your current list which omits the first element:



                  List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
                  
List<String> viewList = list.subList(1, list.size());


                  This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.






                  share|improve this answer














                  One non Java 8 option might be to just create a view on top of your current list which omits the first element:



                  List<String> list = Arrays.stream(optArr).collect(Collectors.toList());
                  
List<String> viewList = list.subList(1, list.size());


                  This would mean though that the underlying data structure is still the original list, but one extra element in memory does not seem like a big penalty.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 1 hour ago

























                  answered 1 hour ago









                  Tim Biegeleisen

                  216k1386139




                  216k1386139












                  • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                    – Tim Biegeleisen
                    1 hour ago


















                  • @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                    – Tim Biegeleisen
                    1 hour ago
















                  @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                  – Tim Biegeleisen
                  1 hour ago




                  @nullpointer Um...I am suggesting to just run the original stream, and then view it however you want.
                  – Tim Biegeleisen
                  1 hour ago











                  0














                  List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


                  I think it must work.



                  See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html






                  share|improve this answer








                  New contributor




                  Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.























                    0














                    List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


                    I think it must work.



                    See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html






                    share|improve this answer








                    New contributor




                    Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.





















                      0












                      0








                      0






                      List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


                      I think it must work.



                      See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html






                      share|improve this answer








                      New contributor




                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct. 









                      List<String> list = Arrays.stream(optArr).skip(1).collect(Collectors.toList());


                      I think it must work.



                      See docs here : https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html







                      share|improve this answer








                      New contributor




                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.









                      share|improve this answer



                      share|improve this answer






                      New contributor




                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.









                      answered 1 hour ago









                      Crutch Master

                      313




                      313




                      New contributor




                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.





                      New contributor





                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      Crutch Master is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.























                          0














                          One method use List.sublist(int,int)



                          List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
                          
System.out.println(list);


                          Second method use Stream



                          List<String> list = Arrays.stream(optArr)
                          
    .skip(1)
                          
    .collect(Collectors.toList());
                          
System.out.println(list);





                          share|improve this answer


























                            0














                            One method use List.sublist(int,int)



                            List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
                            
System.out.println(list);


                            Second method use Stream



                            List<String> list = Arrays.stream(optArr)
                            
    .skip(1)
                            
    .collect(Collectors.toList());
                            
System.out.println(list);





                            share|improve this answer
























                              0












                              0








                              0






                              One method use List.sublist(int,int)



                              List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
                              
System.out.println(list);


                              Second method use Stream



                              List<String> list = Arrays.stream(optArr)
                              
    .skip(1)
                              
    .collect(Collectors.toList());
                              
System.out.println(list);





                              share|improve this answer












                              One method use List.sublist(int,int)



                              List<String> list = Arrays.asList(optArr).subList(1,optArr.length);
                              
System.out.println(list);


                              Second method use Stream



                              List<String> list = Arrays.stream(optArr)
                              
    .skip(1)
                              
    .collect(Collectors.toList());
                              
System.out.println(list);






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered 1 hour ago









                              TongChen

                              1046




                              1046























                                  0














                                  It should be like this.



                                  List<String> al = new ArrayList<>(Arrays.asList(optArr));
                                  
List actualList = list.subList(1, al.size());





                                  share|improve this answer


























                                    0














                                    It should be like this.



                                    List<String> al = new ArrayList<>(Arrays.asList(optArr));
                                    
List actualList = list.subList(1, al.size());





                                    share|improve this answer
























                                      0












                                      0








                                      0






                                      It should be like this.



                                      List<String> al = new ArrayList<>(Arrays.asList(optArr));
                                      
List actualList = list.subList(1, al.size());





                                      share|improve this answer












                                      It should be like this.



                                      List<String> al = new ArrayList<>(Arrays.asList(optArr));
                                      
List actualList = list.subList(1, al.size());






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered 1 hour ago









                                      TheSprinter

                                      244110




                                      244110























                                          0














                                          Looking at your data you might consider :



                                          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


                                          But if you just want to filter the first index sublist is the way to go.
                                          You do not need to use stream whatever of are you can.






                                          share|improve this answer



















                                          • 1




                                            not content based, but index based
                                            – nullpointer
                                            1 hour ago
















                                          0














                                          Looking at your data you might consider :



                                          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


                                          But if you just want to filter the first index sublist is the way to go.
                                          You do not need to use stream whatever of are you can.






                                          share|improve this answer



















                                          • 1




                                            not content based, but index based
                                            – nullpointer
                                            1 hour ago














                                          0












                                          0








                                          0






                                          Looking at your data you might consider :



                                          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


                                          But if you just want to filter the first index sublist is the way to go.
                                          You do not need to use stream whatever of are you can.






                                          share|improve this answer














                                          Looking at your data you might consider :



                                          List<String> list = Stream.of(optArr).filter(s -> s.startsWith("map")).collect(toList());


                                          But if you just want to filter the first index sublist is the way to go.
                                          You do not need to use stream whatever of are you can.







                                          share|improve this answer














                                          share|improve this answer



                                          share|improve this answer








                                          edited 1 hour ago

























                                          answered 1 hour ago









                                          fastcodejava

                                          23.8k19109161




                                          23.8k19109161








                                          • 1




                                            not content based, but index based
                                            – nullpointer
                                            1 hour ago














                                          • 1




                                            not content based, but index based
                                            – nullpointer
                                            1 hour ago








                                          1




                                          1




                                          not content based, but index based
                                          – nullpointer
                                          1 hour ago




                                          not content based, but index based
                                          – nullpointer
                                          1 hour ago


















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                                          數位音樂下載

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                                          數位音樂下載 為非以「實體」方式來販賣音樂的相關產品，而使用數位格式如mp3、AAC等文件格式來進行銷售販賣的一种音乐产业形式。著名的數位音樂下載服務商有iTunes Store、RecoChoku、Google Play音乐和微软Zune等。数字音乐下载在二十一世纪初一度风靡全球， [1] [2] 使得传统唱片产业走向衰落，但其自身也在2010年代流媒体音乐服务如Apple Music、Spotify等的挤压下迅速失去市场份额。 [3] [4] 数字音乐下载有便于携带、传播迅速、制作简单成本低等优点，与流媒体音乐相比也能更好保障音乐人权益； [5] 但它同时很可能带来侵犯版权和滥用的情形， [6] 也给音乐产业带来了诸多不利影响。数字音乐下载为音乐人和乐迷提供了更加便捷直接的交流渠道，也一定程度上推动了网络音乐人的出现和独立音乐的迅速发展。 [7] 目录 1 历史 1.1 技术积淀（1987-2000） 1.2 出现与兴起（2000-2004） 1.3 唱片市场的颠覆者（2004-2007） 1.4 巅峰和衰落（2005-2013） 1.5 摇摇欲坠的现状与不可预知的明天（2014至今） 2 主要文件格式 2.1 PCM编码格式 2.1.1 WAV 2.1.2 APE 2.1.3 FLAC 2.2 苹果推出的无损文件格式 2.2.1 AIFF 2.2.2 ALAC 2.3 有损压缩格式 2.3.1 MP3 2.3.2 AAC 3 主要市场 3.1 iTunes Store 3.2 Google Play音乐商店 3.3 亚马逊音乐商店 3.4 部分其他音乐商店 4 影响与评价 4.1 对音乐产业的影响 4.2 对科技行业的影响 4.3 正面评价 4.4 负面评价 4.4.1 侵权问题 4.4.2 经营模式不明晰 4.4.3 不适应移动时代 4.5 文化现象 5 延伸阅读 6 参考资料 历史 苹果iTunes+iPod的软硬件搭配让数字音...
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                                          When can things happen in Etherscan, such as the picture below?

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                                          2 I don't know why balance of the address is 0. when can this situation? etherscan balances share | improve this question asked yesterday Ru Hi Ru Hi 11 1 New contributor Ru Hi is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct. add a comment  |  ...
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                                          格利澤436b

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                                          格利泽436b 太陽系外行星 太陽系外行星列表 艺术家笔下的格利泽436b 母恆星 母恆星 Gliese 436 星座 獅子座 赤經 ( α ) 11 h  42 m  11.0941 s [1] 赤緯 ( δ ) +26° 42′ 23.652″ [1] 距離 33.4 ly (10.2 pc) 光譜類型 M2.5 V [1] 軌道參數 半长轴 ( a ) 0.0291±0.0004 [2] AU 軌道離心率 ( e ) 0.150±0.012 [2] 公轉週期 ( P ) 2.643904±0.000005 [3] d (0.00723849 y) 軌道傾角 ( i ) 85.8 +0.21 −0.25 [3] ° 角距 ( θ ) 2.794 mas 近星點時間 ( T 0 ) 2,451,551.716 ±0.01 JD 半振幅 ( K ) 18.68±0.8 m/s 物理性质 质量 ( m ) 22.2±1.0 [2] M ⊕ 半徑 ( r ) 4.327±0.183 [2] [4] R ⊕ 密度 ( ρ ) 1.51 g cm -3 表面重力 ( g ) 1.18 g 溫度 ( T ) 712±36 [2] K 發現 發現時間 2004 發現者 巴特勒、沃格特、 馬西 et al. 發現方法 徑向速度、凌日法 發現地點 美國加利福尼亞州 發表論文 出版 其他名稱 Ross 905 b, GJ 436 b, [5] LTT 13213 b, GCTP 2704.10 b, LHS 310, AC+27:28217 b, Vyssotsky 616 b, HIP 57087 b, GEN# +9.80120068 b, LP 319-75 b, G 121-7 b, LSPM J1142+2642 b, 1RXS J114211.9+264328 b, ASCC 683818 b, G 147-68 b, UCAC2 41198281 b, BP...
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