Can I use a list of file names that I saved to file to have each file on the list copied/moved/deleted?












0















How can I use cp rm or mv commands to manipulate files saved to a list, for example one made like so:



ls Downloads/ | grep example > example.tmp


The point is to be able to view/edit the file list in a file editor before making a final manipulation, and then deleting the tmp.



So for example, the following does not work:



mkdir example_dir && cp -t example_dir < example.tmp 


Is there a way that I could make this work?



Once I get that down, I'd like to simplify the whole process into fewer commands, but... I'm just trying to make it work (and see how it will work at this individual step) first.










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    0















    How can I use cp rm or mv commands to manipulate files saved to a list, for example one made like so:



    ls Downloads/ | grep example > example.tmp


    The point is to be able to view/edit the file list in a file editor before making a final manipulation, and then deleting the tmp.



    So for example, the following does not work:



    mkdir example_dir && cp -t example_dir < example.tmp 


    Is there a way that I could make this work?



    Once I get that down, I'd like to simplify the whole process into fewer commands, but... I'm just trying to make it work (and see how it will work at this individual step) first.










    share|improve this question







    New contributor




    Rulent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0


      1






      How can I use cp rm or mv commands to manipulate files saved to a list, for example one made like so:



      ls Downloads/ | grep example > example.tmp


      The point is to be able to view/edit the file list in a file editor before making a final manipulation, and then deleting the tmp.



      So for example, the following does not work:



      mkdir example_dir && cp -t example_dir < example.tmp 


      Is there a way that I could make this work?



      Once I get that down, I'd like to simplify the whole process into fewer commands, but... I'm just trying to make it work (and see how it will work at this individual step) first.










      share|improve this question







      New contributor




      Rulent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      How can I use cp rm or mv commands to manipulate files saved to a list, for example one made like so:



      ls Downloads/ | grep example > example.tmp


      The point is to be able to view/edit the file list in a file editor before making a final manipulation, and then deleting the tmp.



      So for example, the following does not work:



      mkdir example_dir && cp -t example_dir < example.tmp 


      Is there a way that I could make this work?



      Once I get that down, I'd like to simplify the whole process into fewer commands, but... I'm just trying to make it work (and see how it will work at this individual step) first.







      command-line rm mv cp batch






      share|improve this question







      New contributor




      Rulent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Rulent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






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      asked Jan 19 at 9:10









      RulentRulent

      83




      83




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      New contributor





      Rulent is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      Check out our Code of Conduct.






















          1 Answer
          1






          active

          oldest

          votes


















          1














          Use bash's command substitution:



          $ ls -1
          1
          2
          3
          a
          b
          c


          Put only a, b, c into a list file.



          $ ls -1 | grep -E "^[a-z]$" > list
          $ cat list
          a
          b
          c


          Edit the list file if you like, then copy the files:



          $ mkdir foo
          $ cp $(cat list) -t foo
          $ ls foo/
          a b c





          share|improve this answer


























          • would you mind if I asked you what the syntax "^[a-z]$" refers to specifically with what each part means? I understand all of the rest of your solution. Thank you.

            – Rulent
            yesterday













          • We are looking for a set of characters, ^ means started with, [a-z] means from a to z (any of them), $: ended with the same character. It looks for all lines containing a character from a to z.

            – Ravexina
            yesterday











          Your Answer








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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Use bash's command substitution:



          $ ls -1
          1
          2
          3
          a
          b
          c


          Put only a, b, c into a list file.



          $ ls -1 | grep -E "^[a-z]$" > list
          $ cat list
          a
          b
          c


          Edit the list file if you like, then copy the files:



          $ mkdir foo
          $ cp $(cat list) -t foo
          $ ls foo/
          a b c





          share|improve this answer


























          • would you mind if I asked you what the syntax "^[a-z]$" refers to specifically with what each part means? I understand all of the rest of your solution. Thank you.

            – Rulent
            yesterday













          • We are looking for a set of characters, ^ means started with, [a-z] means from a to z (any of them), $: ended with the same character. It looks for all lines containing a character from a to z.

            – Ravexina
            yesterday
















          1














          Use bash's command substitution:



          $ ls -1
          1
          2
          3
          a
          b
          c


          Put only a, b, c into a list file.



          $ ls -1 | grep -E "^[a-z]$" > list
          $ cat list
          a
          b
          c


          Edit the list file if you like, then copy the files:



          $ mkdir foo
          $ cp $(cat list) -t foo
          $ ls foo/
          a b c





          share|improve this answer


























          • would you mind if I asked you what the syntax "^[a-z]$" refers to specifically with what each part means? I understand all of the rest of your solution. Thank you.

            – Rulent
            yesterday













          • We are looking for a set of characters, ^ means started with, [a-z] means from a to z (any of them), $: ended with the same character. It looks for all lines containing a character from a to z.

            – Ravexina
            yesterday














          1












          1








          1







          Use bash's command substitution:



          $ ls -1
          1
          2
          3
          a
          b
          c


          Put only a, b, c into a list file.



          $ ls -1 | grep -E "^[a-z]$" > list
          $ cat list
          a
          b
          c


          Edit the list file if you like, then copy the files:



          $ mkdir foo
          $ cp $(cat list) -t foo
          $ ls foo/
          a b c





          share|improve this answer















          Use bash's command substitution:



          $ ls -1
          1
          2
          3
          a
          b
          c


          Put only a, b, c into a list file.



          $ ls -1 | grep -E "^[a-z]$" > list
          $ cat list
          a
          b
          c


          Edit the list file if you like, then copy the files:



          $ mkdir foo
          $ cp $(cat list) -t foo
          $ ls foo/
          a b c






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 19 at 10:00

























          answered Jan 19 at 9:54









          RavexinaRavexina

          32.1k1482112




          32.1k1482112













          • would you mind if I asked you what the syntax "^[a-z]$" refers to specifically with what each part means? I understand all of the rest of your solution. Thank you.

            – Rulent
            yesterday













          • We are looking for a set of characters, ^ means started with, [a-z] means from a to z (any of them), $: ended with the same character. It looks for all lines containing a character from a to z.

            – Ravexina
            yesterday



















          • would you mind if I asked you what the syntax "^[a-z]$" refers to specifically with what each part means? I understand all of the rest of your solution. Thank you.

            – Rulent
            yesterday













          • We are looking for a set of characters, ^ means started with, [a-z] means from a to z (any of them), $: ended with the same character. It looks for all lines containing a character from a to z.

            – Ravexina
            yesterday

















          would you mind if I asked you what the syntax "^[a-z]$" refers to specifically with what each part means? I understand all of the rest of your solution. Thank you.

          – Rulent
          yesterday







          would you mind if I asked you what the syntax "^[a-z]$" refers to specifically with what each part means? I understand all of the rest of your solution. Thank you.

          – Rulent
          yesterday















          We are looking for a set of characters, ^ means started with, [a-z] means from a to z (any of them), $: ended with the same character. It looks for all lines containing a character from a to z.

          – Ravexina
          yesterday





          We are looking for a set of characters, ^ means started with, [a-z] means from a to z (any of them), $: ended with the same character. It looks for all lines containing a character from a to z.

          – Ravexina
          yesterday










          Rulent is a new contributor. Be nice, and check out our Code of Conduct.










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          Rulent is a new contributor. Be nice, and check out our Code of Conduct.













          Rulent is a new contributor. Be nice, and check out our Code of Conduct.












          Rulent is a new contributor. Be nice, and check out our Code of Conduct.
















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