Make a longer lenguage program












8












$begingroup$


Lenguage is a brainfuck dialect that is notorious for breaking source restriction challenges. That is because Lenguage cares only about the length of it's source and not the contents.



First, the length of the program is calculated. Then, said length is converted to binary and left-padded by zeroes to a multiple of 3. The resulting binary string is split into chunks of 3 bits each of which is translated into a brainfuck command as such:



000 -> +

001 -> -

010 -> >

011 -> <

100 -> .

101 -> ,

110 -> [

111 -> ]


Finally the program is run as brainfuck1.



From here the challenge is pretty simple, write a lenguage program that takes no input and produces an output consisting of one byte repeated $n$ times, where $n$ is strictly greater than the length of your program.



Answers will be scored in bytes with fewer bytes being better.



Here's a hacky program to calculate lenguage from brainfuck




1: For this challenge we will use wrapping cells and a non-wrapping tape.






code-golf quine brainfuck







share|improve this question









$endgroup$








  • 1




    $begingroup$
    +[.] Do I win? :P
    $endgroup$
    – Quintec
    4 hours ago






  • 1




    $begingroup$
    Perhaps it might be more interesting to score on the length of the output?
    $endgroup$
    – Jo King
    4 hours ago










  • $begingroup$
    @JoKing That's a good idea. Unfortunately it appears to be a bit late for that.
    $endgroup$
    – TRITICIMAGVS
    3 hours ago










  • $begingroup$
    @JoKing Actually since you are the only answerer do you mind if I change it?
    $endgroup$
    – TRITICIMAGVS
    3 hours ago










  • $begingroup$
    sure, i'll change my answer up
    $endgroup$
    – Jo King
    2 hours ago
















8












$begingroup$


Lenguage is a brainfuck dialect that is notorious for breaking source restriction challenges. That is because Lenguage cares only about the length of it's source and not the contents.



First, the length of the program is calculated. Then, said length is converted to binary and left-padded by zeroes to a multiple of 3. The resulting binary string is split into chunks of 3 bits each of which is translated into a brainfuck command as such:



000 -> +

001 -> -

010 -> >

011 -> <

100 -> .

101 -> ,

110 -> [

111 -> ]


Finally the program is run as brainfuck1.



From here the challenge is pretty simple, write a lenguage program that takes no input and produces an output consisting of one byte repeated $n$ times, where $n$ is strictly greater than the length of your program.



Answers will be scored in bytes with fewer bytes being better.



Here's a hacky program to calculate lenguage from brainfuck




1: For this challenge we will use wrapping cells and a non-wrapping tape.






code-golf quine brainfuck







share|improve this question









$endgroup$








  • 1




    $begingroup$
    +[.] Do I win? :P
    $endgroup$
    – Quintec
    4 hours ago






  • 1




    $begingroup$
    Perhaps it might be more interesting to score on the length of the output?
    $endgroup$
    – Jo King
    4 hours ago










  • $begingroup$
    @JoKing That's a good idea. Unfortunately it appears to be a bit late for that.
    $endgroup$
    – TRITICIMAGVS
    3 hours ago










  • $begingroup$
    @JoKing Actually since you are the only answerer do you mind if I change it?
    $endgroup$
    – TRITICIMAGVS
    3 hours ago










  • $begingroup$
    sure, i'll change my answer up
    $endgroup$
    – Jo King
    2 hours ago














8












8








8


1



$begingroup$


Lenguage is a brainfuck dialect that is notorious for breaking source restriction challenges. That is because Lenguage cares only about the length of it's source and not the contents.



First, the length of the program is calculated. Then, said length is converted to binary and left-padded by zeroes to a multiple of 3. The resulting binary string is split into chunks of 3 bits each of which is translated into a brainfuck command as such:



000 -> +

001 -> -

010 -> >

011 -> <

100 -> .

101 -> ,

110 -> [

111 -> ]


Finally the program is run as brainfuck1.



From here the challenge is pretty simple, write a lenguage program that takes no input and produces an output consisting of one byte repeated $n$ times, where $n$ is strictly greater than the length of your program.



Answers will be scored in bytes with fewer bytes being better.



Here's a hacky program to calculate lenguage from brainfuck




1: For this challenge we will use wrapping cells and a non-wrapping tape.






code-golf quine brainfuck







share|improve this question









$endgroup$




Lenguage is a brainfuck dialect that is notorious for breaking source restriction challenges. That is because Lenguage cares only about the length of it's source and not the contents.



First, the length of the program is calculated. Then, said length is converted to binary and left-padded by zeroes to a multiple of 3. The resulting binary string is split into chunks of 3 bits each of which is translated into a brainfuck command as such:



000 -> +

001 -> -

010 -> >

011 -> <

100 -> .

101 -> ,

110 -> [

111 -> ]


Finally the program is run as brainfuck1.



From here the challenge is pretty simple, write a lenguage program that takes no input and produces an output consisting of one byte repeated $n$ times, where $n$ is strictly greater than the length of your program.



Answers will be scored in bytes with fewer bytes being better.



Here's a hacky program to calculate lenguage from brainfuck




1: For this challenge we will use wrapping cells and a non-wrapping tape.






code-golf quine brainfuck




code-golf quine brainfuck






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 6 hours ago









TRITICIMAGVSTRITICIMAGVS

34.2k10156366




34.2k10156366








  • 1




    $begingroup$
    +[.] Do I win? :P
    $endgroup$
    – Quintec
    4 hours ago






  • 1




    $begingroup$
    Perhaps it might be more interesting to score on the length of the output?
    $endgroup$
    – Jo King
    4 hours ago










  • $begingroup$
    @JoKing That's a good idea. Unfortunately it appears to be a bit late for that.
    $endgroup$
    – TRITICIMAGVS
    3 hours ago










  • $begingroup$
    @JoKing Actually since you are the only answerer do you mind if I change it?
    $endgroup$
    – TRITICIMAGVS
    3 hours ago










  • $begingroup$
    sure, i'll change my answer up
    $endgroup$
    – Jo King
    2 hours ago














  • 1




    $begingroup$
    +[.] Do I win? :P
    $endgroup$
    – Quintec
    4 hours ago






  • 1




    $begingroup$
    Perhaps it might be more interesting to score on the length of the output?
    $endgroup$
    – Jo King
    4 hours ago










  • $begingroup$
    @JoKing That's a good idea. Unfortunately it appears to be a bit late for that.
    $endgroup$
    – TRITICIMAGVS
    3 hours ago










  • $begingroup$
    @JoKing Actually since you are the only answerer do you mind if I change it?
    $endgroup$
    – TRITICIMAGVS
    3 hours ago










  • $begingroup$
    sure, i'll change my answer up
    $endgroup$
    – Jo King
    2 hours ago








1




1




$begingroup$
+[.] Do I win? :P
$endgroup$
– Quintec
4 hours ago




$begingroup$
+[.] Do I win? :P
$endgroup$
– Quintec
4 hours ago




1




1




$begingroup$
Perhaps it might be more interesting to score on the length of the output?
$endgroup$
– Jo King
4 hours ago




$begingroup$
Perhaps it might be more interesting to score on the length of the output?
$endgroup$
– Jo King
4 hours ago












$begingroup$
@JoKing That's a good idea. Unfortunately it appears to be a bit late for that.
$endgroup$
– TRITICIMAGVS
3 hours ago




$begingroup$
@JoKing That's a good idea. Unfortunately it appears to be a bit late for that.
$endgroup$
– TRITICIMAGVS
3 hours ago












$begingroup$
@JoKing Actually since you are the only answerer do you mind if I change it?
$endgroup$
– TRITICIMAGVS
3 hours ago




$begingroup$
@JoKing Actually since you are the only answerer do you mind if I change it?
$endgroup$
– TRITICIMAGVS
3 hours ago












$begingroup$
sure, i'll change my answer up
$endgroup$
– Jo King
2 hours ago




$begingroup$
sure, i'll change my answer up
$endgroup$
– Jo King
2 hours ago










1 Answer
1






active

oldest

votes


















5












$begingroup$

8437495638205698686671 bytes



This translates to the brainfuck program:



-[>>[>]+[->[>]+.[<]+<]<-]


Which prints exactly $231584178474632390847141970017375815706539969331281128078915168015826259279614$ SOH bytes.



This is calculated by the function



f(n)=2*f(n-1)+n

f(0)=0


(submission pending change from code-golf to the shortest output)



664613997892457936451903530140172168 bytes



The program is $190096884071251415869242504183037647$ bytes long, which translates to the brainfuck program:



----[>+++++<--]>[>>[>]+[->[>]+.[<]+<]<-]


This is calculated by the function



f(n)=2*f(n-1)+n

f(0)=0


With an input of 118.






share|improve this answer











$endgroup$













    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "200"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodegolf.stackexchange.com%2fquestions%2f179325%2fmake-a-longer-lenguage-program%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    5












    $begingroup$

    8437495638205698686671 bytes



    This translates to the brainfuck program:



    -[>>[>]+[->[>]+.[<]+<]<-]


    Which prints exactly $231584178474632390847141970017375815706539969331281128078915168015826259279614$ SOH bytes.



    This is calculated by the function



    f(n)=2*f(n-1)+n
    
f(0)=0


    (submission pending change from code-golf to the shortest output)



    664613997892457936451903530140172168 bytes



    The program is $190096884071251415869242504183037647$ bytes long, which translates to the brainfuck program:



    ----[>+++++<--]>[>>[>]+[->[>]+.[<]+<]<-]


    This is calculated by the function



    f(n)=2*f(n-1)+n
    
f(0)=0


    With an input of 118.






    share|improve this answer











    $endgroup$


















      5












      $begingroup$

      8437495638205698686671 bytes



      This translates to the brainfuck program:



      -[>>[>]+[->[>]+.[<]+<]<-]


      Which prints exactly $231584178474632390847141970017375815706539969331281128078915168015826259279614$ SOH bytes.



      This is calculated by the function



      f(n)=2*f(n-1)+n
      
f(0)=0


      (submission pending change from code-golf to the shortest output)



      664613997892457936451903530140172168 bytes



      The program is $190096884071251415869242504183037647$ bytes long, which translates to the brainfuck program:



      ----[>+++++<--]>[>>[>]+[->[>]+.[<]+<]<-]


      This is calculated by the function



      f(n)=2*f(n-1)+n
      
f(0)=0


      With an input of 118.






      share|improve this answer











      $endgroup$
















        5












        5








        5





        $begingroup$

        8437495638205698686671 bytes



        This translates to the brainfuck program:



        -[>>[>]+[->[>]+.[<]+<]<-]


        Which prints exactly $231584178474632390847141970017375815706539969331281128078915168015826259279614$ SOH bytes.



        This is calculated by the function



        f(n)=2*f(n-1)+n
        
f(0)=0


        (submission pending change from code-golf to the shortest output)



        664613997892457936451903530140172168 bytes



        The program is $190096884071251415869242504183037647$ bytes long, which translates to the brainfuck program:



        ----[>+++++<--]>[>>[>]+[->[>]+.[<]+<]<-]


        This is calculated by the function



        f(n)=2*f(n-1)+n
        
f(0)=0


        With an input of 118.






        share|improve this answer











        $endgroup$



        8437495638205698686671 bytes



        This translates to the brainfuck program:



        -[>>[>]+[->[>]+.[<]+<]<-]


        Which prints exactly $231584178474632390847141970017375815706539969331281128078915168015826259279614$ SOH bytes.



        This is calculated by the function



        f(n)=2*f(n-1)+n
        
f(0)=0


        (submission pending change from code-golf to the shortest output)



        664613997892457936451903530140172168 bytes



        The program is $190096884071251415869242504183037647$ bytes long, which translates to the brainfuck program:



        ----[>+++++<--]>[>>[>]+[->[>]+.[<]+<]<-]


        This is calculated by the function



        f(n)=2*f(n-1)+n
        
f(0)=0


        With an input of 118.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 2 hours ago

























        answered 3 hours ago









        Jo KingJo King

        21.9k249113




        21.9k249113






























            draft saved

            draft discarded




















































            If this is an answer to a challenge…




            • …Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.


            • …Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
              Explanations of your answer make it more interesting to read and are very much encouraged.


            • …Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.



            More generally…




            • …Please make sure to answer the question and provide sufficient detail.


            • …Avoid asking for help, clarification or responding to other answers (use comments instead).





            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodegolf.stackexchange.com%2fquestions%2f179325%2fmake-a-longer-lenguage-program%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            -

            Popular posts from this blog

            數位音樂下載

            Image
            數位音樂下載 為非以「實體」方式來販賣音樂的相關產品，而使用數位格式如mp3、AAC等文件格式來進行銷售販賣的一种音乐产业形式。著名的數位音樂下載服務商有iTunes Store、RecoChoku、Google Play音乐和微软Zune等。数字音乐下载在二十一世纪初一度风靡全球， [1] [2] 使得传统唱片产业走向衰落，但其自身也在2010年代流媒体音乐服务如Apple Music、Spotify等的挤压下迅速失去市场份额。 [3] [4] 数字音乐下载有便于携带、传播迅速、制作简单成本低等优点，与流媒体音乐相比也能更好保障音乐人权益； [5] 但它同时很可能带来侵犯版权和滥用的情形， [6] 也给音乐产业带来了诸多不利影响。数字音乐下载为音乐人和乐迷提供了更加便捷直接的交流渠道，也一定程度上推动了网络音乐人的出现和独立音乐的迅速发展。 [7] 目录 1 历史 1.1 技术积淀（1987-2000） 1.2 出现与兴起（2000-2004） 1.3 唱片市场的颠覆者（2004-2007） 1.4 巅峰和衰落（2005-2013） 1.5 摇摇欲坠的现状与不可预知的明天（2014至今） 2 主要文件格式 2.1 PCM编码格式 2.1.1 WAV 2.1.2 APE 2.1.3 FLAC 2.2 苹果推出的无损文件格式 2.2.1 AIFF 2.2.2 ALAC 2.3 有损压缩格式 2.3.1 MP3 2.3.2 AAC 3 主要市场 3.1 iTunes Store 3.2 Google Play音乐商店 3.3 亚马逊音乐商店 3.4 部分其他音乐商店 4 影响与评价 4.1 对音乐产业的影响 4.2 对科技行业的影响 4.3 正面评价 4.4 负面评价 4.4.1 侵权问题 4.4.2 经营模式不明晰 4.4.3 不适应移动时代 4.5 文化现象 5 延伸阅读 6 参考资料 历史 苹果iTunes+iPod的软硬件搭配让数字音...
            Read more

            When can things happen in Etherscan, such as the picture below?

            Image
            2 I don't know why balance of the address is 0. when can this situation? etherscan balances share | improve this question asked yesterday Ru Hi Ru Hi 11 1 New contributor Ru Hi is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct. add a comment  |  ...
            Read more

            格利澤436b

            Image
            格利泽436b 太陽系外行星 太陽系外行星列表 艺术家笔下的格利泽436b 母恆星 母恆星 Gliese 436 星座 獅子座 赤經 ( α ) 11 h  42 m  11.0941 s [1] 赤緯 ( δ ) +26° 42′ 23.652″ [1] 距離 33.4 ly (10.2 pc) 光譜類型 M2.5 V [1] 軌道參數 半长轴 ( a ) 0.0291±0.0004 [2] AU 軌道離心率 ( e ) 0.150±0.012 [2] 公轉週期 ( P ) 2.643904±0.000005 [3] d (0.00723849 y) 軌道傾角 ( i ) 85.8 +0.21 −0.25 [3] ° 角距 ( θ ) 2.794 mas 近星點時間 ( T 0 ) 2,451,551.716 ±0.01 JD 半振幅 ( K ) 18.68±0.8 m/s 物理性质 质量 ( m ) 22.2±1.0 [2] M ⊕ 半徑 ( r ) 4.327±0.183 [2] [4] R ⊕ 密度 ( ρ ) 1.51 g cm -3 表面重力 ( g ) 1.18 g 溫度 ( T ) 712±36 [2] K 發現 發現時間 2004 發現者 巴特勒、沃格特、 馬西 et al. 發現方法 徑向速度、凌日法 發現地點 美國加利福尼亞州 發表論文 出版 其他名稱 Ross 905 b, GJ 436 b, [5] LTT 13213 b, GCTP 2704.10 b, LHS 310, AC+27:28217 b, Vyssotsky 616 b, HIP 57087 b, GEN# +9.80120068 b, LP 319-75 b, G 121-7 b, LSPM J1142+2642 b, 1RXS J114211.9+264328 b, ASCC 683818 b, G 147-68 b, UCAC2 41198281 b, BP...
            Read more