Count all outgoing http/s requests
I would like to know how many http/s requests i make in a month with my computer (Ubuntu 18.10)
Does ubuntu have any command to see that?
monitoring https
add a comment |
I would like to know how many http/s requests i make in a month with my computer (Ubuntu 18.10)
Does ubuntu have any command to see that?
monitoring https
add a comment |
I would like to know how many http/s requests i make in a month with my computer (Ubuntu 18.10)
Does ubuntu have any command to see that?
monitoring https
I would like to know how many http/s requests i make in a month with my computer (Ubuntu 18.10)
Does ubuntu have any command to see that?
monitoring https
monitoring https
asked Mar 18 at 14:47
FrakyDaleFrakyDale
797
797
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The short answer is: No.
You would have to run a packet tracer, such as tcpdump or wireshark, and count them from that.
OR:
Make some iptables rule that makes a log entry for each connection (which might not be be the same number as requests, if multiple can be done per connection.
However, because HTTPS is encrypted, there isn't a good way to isolate "HTTPS: GET" from the rest of the traffic, as can be done for unencrypted HTTP. For example, I was able to extract this from my tcpdump logs for one computer and HTTP only on my network:
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-01-" | wc -l
29835
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-02-" | wc -l
69684
Meaning it did 29835 HTTP requests in January and 69684 in February.
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "89"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2faskubuntu.com%2fquestions%2f1126645%2fcount-all-outgoing-http-s-requests%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The short answer is: No.
You would have to run a packet tracer, such as tcpdump or wireshark, and count them from that.
OR:
Make some iptables rule that makes a log entry for each connection (which might not be be the same number as requests, if multiple can be done per connection.
However, because HTTPS is encrypted, there isn't a good way to isolate "HTTPS: GET" from the rest of the traffic, as can be done for unencrypted HTTP. For example, I was able to extract this from my tcpdump logs for one computer and HTTP only on my network:
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-01-" | wc -l
29835
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-02-" | wc -l
69684
Meaning it did 29835 HTTP requests in January and 69684 in February.
add a comment |
The short answer is: No.
You would have to run a packet tracer, such as tcpdump or wireshark, and count them from that.
OR:
Make some iptables rule that makes a log entry for each connection (which might not be be the same number as requests, if multiple can be done per connection.
However, because HTTPS is encrypted, there isn't a good way to isolate "HTTPS: GET" from the rest of the traffic, as can be done for unencrypted HTTP. For example, I was able to extract this from my tcpdump logs for one computer and HTTP only on my network:
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-01-" | wc -l
29835
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-02-" | wc -l
69684
Meaning it did 29835 HTTP requests in January and 69684 in February.
add a comment |
The short answer is: No.
You would have to run a packet tracer, such as tcpdump or wireshark, and count them from that.
OR:
Make some iptables rule that makes a log entry for each connection (which might not be be the same number as requests, if multiple can be done per connection.
However, because HTTPS is encrypted, there isn't a good way to isolate "HTTPS: GET" from the rest of the traffic, as can be done for unencrypted HTTP. For example, I was able to extract this from my tcpdump logs for one computer and HTTP only on my network:
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-01-" | wc -l
29835
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-02-" | wc -l
69684
Meaning it did 29835 HTTP requests in January and 69684 in February.
The short answer is: No.
You would have to run a packet tracer, such as tcpdump or wireshark, and count them from that.
OR:
Make some iptables rule that makes a log entry for each connection (which might not be be the same number as requests, if multiple can be done per connection.
However, because HTTPS is encrypted, there isn't a good way to isolate "HTTPS: GET" from the rest of the traffic, as can be done for unencrypted HTTP. For example, I was able to extract this from my tcpdump logs for one computer and HTTP only on my network:
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-01-" | wc -l
29835
doug@DOUG-64:~/tcpdump/104$ gunzip -c all0.txt.gz | grep "IP 192.168.111.101." | grep ".80:" | grep "HTTP: GET" | grep "^2019-02-" | wc -l
69684
Meaning it did 29835 HTTP requests in January and 69684 in February.
answered Mar 18 at 22:00
Doug SmythiesDoug Smythies
7,41131631
7,41131631
add a comment |
add a comment |
Thanks for contributing an answer to Ask Ubuntu!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2faskubuntu.com%2fquestions%2f1126645%2fcount-all-outgoing-http-s-requests%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown