Overhead brace in tikz
up vote
4
down vote
favorite
I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.
Here is a template:
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
add a comment |
up vote
4
down vote
favorite
I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.
Here is a template:
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
add a comment |
up vote
4
down vote
favorite
up vote
4
down vote
favorite
I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.
Here is a template:
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.
Here is a template:
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
asked 56 mins ago
wonderich
627618
627618
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
4
down vote
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
35 mins ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
32 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
35 mins ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
32 mins ago
add a comment |
up vote
4
down vote
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
35 mins ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
32 mins ago
add a comment |
up vote
4
down vote
up vote
4
down vote
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
edited 34 mins ago
answered 37 mins ago
AndréC
7,12211340
7,12211340
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
35 mins ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
32 mins ago
add a comment |
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
35 mins ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
32 mins ago
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
35 mins ago
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
35 mins ago
You can use the
graphs
library in several different ways to make this graph (see page 257)– AndréC
32 mins ago
You can use the
graphs
library in several different ways to make this graph (see page 257)– AndréC
32 mins ago
add a comment |
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