Cfxtrjtrk

I have to print a pyramid of numbers with this rule:

odd index: 1 to index,
even index: index to 1:

1

21

123

4321

12345

654321

1234567

87654321

123456789

I wrote this code:

def printFigure(rows):

    if rows > 0:

        if rows%2 == 0:

            printFigure(rows-1)

            while(rows>0):

                print(str(rows)[::-1], end = '')

                rows -= 1

            print('')



        if rows%2 == 1:

            printFigure(rows-1)

            while (rows>0):

                print(str(rows),end = '')

                rows -= 1

            print('')

but the output is:

1

21

321,

4321

54321

654321

7654321

87654321

987654321

I'm a beginner with recursion, I'll be glad for your explanations too.
thanks.

You have two major problems with your current code. First, the check on whether the rows is even or odd should be happening after the recursive call to printFigure. The reason for this is that it is after backing out from the recursive call that you want to decide to print the line in order or backwards.

The second problem was with the logic in the else printing condition. You need to print starting at 1, up to the number of rows. I used a dummy variable to achieve this, though there are probably a few other ways of doing it.

def printFigure(rows):

    if rows > 0:

        printFigure(rows-1)

        if rows%2 == 0:

            while(rows>0):

                print(str(rows)[::-1], end='')

                rows -= 1

            print('')

        else:

            i = 1

            while (i <= rows):

                print(str(i), end='')

                i += 1

            print('')



printFigure(9)



1

21

123

4321

12345

654321

1234567

87654321

123456789

if you don't need to use recursivion, other simple solution is:

def printFigure(rows): 

    for x in range(rows): 

        items = [str(i) for i in range(1, x + 1)] 

        if x % 2 == 0: 

            items = items[::-1] 

        print(''.join(items))

You could use an inner function that prints from bottom to top, and the call this function from an outer function, for instance:

def print_rows(n, limit):

    if n < limit:

        numbers = range(1, n + 1) if n % 2 == 1 else reversed(range(1, n + 1))

        print(''.join(map(str, numbers)))

        print_rows(n + 1, limit)





def print_pyramid_recursive(n):

    if n > 0:

        print_rows(1, n)





print_pyramid_recursive(10)

Output

1

21

123

4321

12345

654321

1234567

87654321

123456789

In this case the inner function is print_rows and the outer function is print_pyramid_recursive. Note, that this problem has a very simple non-recursive solution, for example:

def print_pyramid(n):

    for i in range(1, n + 1):

        numbers = range(1, i + 1) if i % 2 == 1 else reversed(range(1, i + 1))

        print(''.join(map(str, numbers)))

Here's the simplest loop version:

is_reversed = False

for i in range(1, 10):

    step = -1 if is_reversed else 1

    print(''.join(map(str, range(1, i + 1)))[::step])

    is_reversed = not is_reversed

This regenerates a string every iteration. We can also store the value of the previous result and build on that:

s = ''

is_reversed = False

for i in range(1, 10):

    s += str(i)

    step = -1 if is_reversed else 1

    print(s[::step])

    is_reversed = not is_reversed

And of course, this can easily (and pointlessly) be converted to a tail-recursive function by just passing along the stack:

def f(s, i, max_i, is_reversed):

    if i == max_i:

        return

    s += str(i)

    step = -1 if is_reversed else 1

    print(s[::step])

    is_reversed = not is_reversed

    i += 1

    f(s, i, max_i, is_reversed)



f('', 1, 10, False)

The results for each of these increasingly weird looking pieces of code:

1

21

123

4321

12345

654321

1234567

87654321

123456789

You can use simple recursion:

def print_pyramid(_count = 1):

  if _count < 10:

    print((lambda x:x[::-1] if not _count%2 else x)(''.join(map(str, range(1, _count+1)))))

    print_pyramid(_count+1)





print_pyramid()

Output:

1

21

123

4321

12345

654321

1234567

87654321

123456789