How to combine similar characters in a list?












7















I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



test = 'hello###_world###test#test123##'

splitter = re.split("(#)", test)

splitter = filter(None, splitter)


Which returns this in the splitter variable:



['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


I'm trying to combine the hashes so the list turns into this:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


Thanks for any help!






python







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    7















    I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



    test = 'hello###_world###test#test123##'
    
splitter = re.split("(#)", test)
    
splitter = filter(None, splitter)


    Which returns this in the splitter variable:



    ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


    I'm trying to combine the hashes so the list turns into this:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


    Thanks for any help!






    python







    share|improve this question









    New contributor




    Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      7












      7








      7








      I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



      test = 'hello###_world###test#test123##'
      
splitter = re.split("(#)", test)
      
splitter = filter(None, splitter)


      Which returns this in the splitter variable:



      ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


      I'm trying to combine the hashes so the list turns into this:



      ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


      Thanks for any help!






      python







      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



      test = 'hello###_world###test#test123##'
      
splitter = re.split("(#)", test)
      
splitter = filter(None, splitter)


      Which returns this in the splitter variable:



      ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


      I'm trying to combine the hashes so the list turns into this:



      ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


      Thanks for any help!






      python




      python






      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|improve this question




      share|improve this question








      edited 1 hour ago









      Ajax1234

      41.4k42853




      41.4k42853






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      asked 1 hour ago









      GregGreg

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      362




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          3 Answers
          3






          active

          oldest

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          6














          Try:



          splitter = re.split("(#+)", test)





          share|improve this answer



















          • 1





            It gives an empty string at the end.

            – AkshayNevrekar
            48 mins ago






          • 2





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            45 mins ago











          • This works for me. Thanks for the help!

            – Greg
            39 mins ago



















          2














          You can use itertools.groupby:



          import itertools
          
test = 'hello###_world###test#test123##'
          
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


          Output:



          ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


          You can also use re.findall:



          import re
          
result = re.findall('#+|[^#]+', test)


          Output:



          ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





          share|improve this answer


























          • This one also does the job. Thanks for the help!

            – Greg
            37 mins ago



















          1














          Add + at the end of the regular expression and filtering None values will do the trick



          >>> import re
          
>>> test = 'hello###_world###test#test123##'
          
>>> splitter = re.split("(#+)", test)
          
>>> splitter
          
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
          
>>> splitter = list(filter(None, splitter))
          
>>> splitter
          
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
          
>>>





          share|improve this answer























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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            6














            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer



















            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              48 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              45 mins ago











            • This works for me. Thanks for the help!

              – Greg
              39 mins ago
















            6














            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer



















            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              48 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              45 mins ago











            • This works for me. Thanks for the help!

              – Greg
              39 mins ago














            6












            6








            6







            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer













            Try:



            splitter = re.split("(#+)", test)






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 53 mins ago









            mingganzmingganz

            3086




            3086








            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              48 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              45 mins ago











            • This works for me. Thanks for the help!

              – Greg
              39 mins ago














            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              48 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              45 mins ago











            • This works for me. Thanks for the help!

              – Greg
              39 mins ago








            1




            1





            It gives an empty string at the end.

            – AkshayNevrekar
            48 mins ago





            It gives an empty string at the end.

            – AkshayNevrekar
            48 mins ago




            2




            2





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            45 mins ago





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            45 mins ago













            This works for me. Thanks for the help!

            – Greg
            39 mins ago





            This works for me. Thanks for the help!

            – Greg
            39 mins ago













            2














            You can use itertools.groupby:



            import itertools
            
test = 'hello###_world###test#test123##'
            
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


            You can also use re.findall:



            import re
            
result = re.findall('#+|[^#]+', test)


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





            share|improve this answer


























            • This one also does the job. Thanks for the help!

              – Greg
              37 mins ago
















            2














            You can use itertools.groupby:



            import itertools
            
test = 'hello###_world###test#test123##'
            
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


            You can also use re.findall:



            import re
            
result = re.findall('#+|[^#]+', test)


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





            share|improve this answer


























            • This one also does the job. Thanks for the help!

              – Greg
              37 mins ago














            2












            2








            2







            You can use itertools.groupby:



            import itertools
            
test = 'hello###_world###test#test123##'
            
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


            You can also use re.findall:



            import re
            
result = re.findall('#+|[^#]+', test)


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





            share|improve this answer















            You can use itertools.groupby:



            import itertools
            
test = 'hello###_world###test#test123##'
            
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


            You can also use re.findall:



            import re
            
result = re.findall('#+|[^#]+', test)


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 34 mins ago

























            answered 1 hour ago









            Ajax1234Ajax1234

            41.4k42853




            41.4k42853













            • This one also does the job. Thanks for the help!

              – Greg
              37 mins ago



















            • This one also does the job. Thanks for the help!

              – Greg
              37 mins ago

















            This one also does the job. Thanks for the help!

            – Greg
            37 mins ago





            This one also does the job. Thanks for the help!

            – Greg
            37 mins ago











            1














            Add + at the end of the regular expression and filtering None values will do the trick



            >>> import re
            
>>> test = 'hello###_world###test#test123##'
            
>>> splitter = re.split("(#+)", test)
            
>>> splitter
            
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
            
>>> splitter = list(filter(None, splitter))
            
>>> splitter
            
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
            
>>>





            share|improve this answer




























              1














              Add + at the end of the regular expression and filtering None values will do the trick



              >>> import re
              
>>> test = 'hello###_world###test#test123##'
              
>>> splitter = re.split("(#+)", test)
              
>>> splitter
              
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
              
>>> splitter = list(filter(None, splitter))
              
>>> splitter
              
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
              
>>>





              share|improve this answer


























                1












                1








                1







                Add + at the end of the regular expression and filtering None values will do the trick



                >>> import re
                
>>> test = 'hello###_world###test#test123##'
                
>>> splitter = re.split("(#+)", test)
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
                
>>> splitter = list(filter(None, splitter))
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
                
>>>





                share|improve this answer













                Add + at the end of the regular expression and filtering None values will do the trick



                >>> import re
                
>>> test = 'hello###_world###test#test123##'
                
>>> splitter = re.split("(#+)", test)
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
                
>>> splitter = list(filter(None, splitter))
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
                
>>>






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 42 mins ago









                Bodhi94Bodhi94

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