Python: next in for loop
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I want to use next
to skip one or more items returned from a generator. Here is a simplified example designed to skip one item per loop (in actual use, I'd test n
and depending on the result, may repeat the next()
and the generator is from a package I don't control):
def gen():
for i in range(10):
yield i
for g in gen():
n = next(gen())
print(g, n)
I expected the result to be
0 1
2 3
etc.
Instead I got
0 0
1 0
etc.
What am I doing wrong?
python generator next
add a comment |
I want to use next
to skip one or more items returned from a generator. Here is a simplified example designed to skip one item per loop (in actual use, I'd test n
and depending on the result, may repeat the next()
and the generator is from a package I don't control):
def gen():
for i in range(10):
yield i
for g in gen():
n = next(gen())
print(g, n)
I expected the result to be
0 1
2 3
etc.
Instead I got
0 0
1 0
etc.
What am I doing wrong?
python generator next
add a comment |
I want to use next
to skip one or more items returned from a generator. Here is a simplified example designed to skip one item per loop (in actual use, I'd test n
and depending on the result, may repeat the next()
and the generator is from a package I don't control):
def gen():
for i in range(10):
yield i
for g in gen():
n = next(gen())
print(g, n)
I expected the result to be
0 1
2 3
etc.
Instead I got
0 0
1 0
etc.
What am I doing wrong?
python generator next
I want to use next
to skip one or more items returned from a generator. Here is a simplified example designed to skip one item per loop (in actual use, I'd test n
and depending on the result, may repeat the next()
and the generator is from a package I don't control):
def gen():
for i in range(10):
yield i
for g in gen():
n = next(gen())
print(g, n)
I expected the result to be
0 1
2 3
etc.
Instead I got
0 0
1 0
etc.
What am I doing wrong?
python generator next
python generator next
asked Apr 6 at 22:08
foosionfoosion
3,340144990
3,340144990
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You're making a new generator each time you call gen()
. Each new generator starts from 0.
Instead, you can call it once and capture the return value.
def gen():
for i in range(10):
yield i
x = gen()
for g in x:
n = next(x)
print(g, n)
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You're making a new generator each time you call gen()
. Each new generator starts from 0.
Instead, you can call it once and capture the return value.
def gen():
for i in range(10):
yield i
x = gen()
for g in x:
n = next(x)
print(g, n)
add a comment |
You're making a new generator each time you call gen()
. Each new generator starts from 0.
Instead, you can call it once and capture the return value.
def gen():
for i in range(10):
yield i
x = gen()
for g in x:
n = next(x)
print(g, n)
add a comment |
You're making a new generator each time you call gen()
. Each new generator starts from 0.
Instead, you can call it once and capture the return value.
def gen():
for i in range(10):
yield i
x = gen()
for g in x:
n = next(x)
print(g, n)
You're making a new generator each time you call gen()
. Each new generator starts from 0.
Instead, you can call it once and capture the return value.
def gen():
for i in range(10):
yield i
x = gen()
for g in x:
n = next(x)
print(g, n)
answered Apr 6 at 22:12
khelwoodkhelwood
32.3k74465
32.3k74465
add a comment |
add a comment |
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