Self-referential multiple-choice question [duplicate]
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This question already has an answer here:
Multiple-choice question about the probability of a random answer to itself being correct
6 answers
I came across this question, which I believe cannot be satisfactorily answered, but I'm not completely sure. Can you tell me if it has a answer?
If you choose the answer to this question at random,
what is the chance that you will be correct?
a) 25%
b) 50%
c) 60%
d) 25%
logic paradoxes
edited 2 days ago
Bernard
124k741117
asked Apr 7 at 6:39
Ricardo MagallanesRicardo Magallanes
244
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marked as duplicate by Martin R, Community♦ 2 days ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
$begingroup$
This question already has an answer here:
Multiple-choice question about the probability of a random answer to itself being correct
6 answers
I came across this question, which I believe cannot be satisfactorily answered, but I'm not completely sure. Can you tell me if it has a answer?
If you choose the answer to this question at random,
what is the chance that you will be correct?
a) 25%
b) 50%
c) 60%
d) 25%
logic paradoxes
edited 2 days ago
Bernard
124k741117
asked Apr 7 at 6:39
Ricardo MagallanesRicardo Magallanes
244
$endgroup$
marked as duplicate by Martin R, Community♦ 2 days ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
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Possible duplicate of Multiple-choice question about the probability of a random answer to itself being correct (for reviewers: only option (c) is different from the duplicating target, but 60% clearly doesn't make more sense than 0%)
$endgroup$
– YuiTo Cheng
2 days ago
add a comment |
$begingroup$
This question already has an answer here:
Multiple-choice question about the probability of a random answer to itself being correct
6 answers
I came across this question, which I believe cannot be satisfactorily answered, but I'm not completely sure. Can you tell me if it has a answer?
If you choose the answer to this question at random,
what is the chance that you will be correct?
a) 25%
b) 50%
c) 60%
d) 25%
logic paradoxes
edited 2 days ago
Bernard
124k741117
asked Apr 7 at 6:39
Ricardo MagallanesRicardo Magallanes
244
$endgroup$
This question already has an answer here:
Multiple-choice question about the probability of a random answer to itself being correct
6 answers
I came across this question, which I believe cannot be satisfactorily answered, but I'm not completely sure. Can you tell me if it has a answer?
If you choose the answer to this question at random,
what is the chance that you will be correct?
a) 25%
b) 50%
c) 60%
d) 25%
This question already has an answer here:
Multiple-choice question about the probability of a random answer to itself being correct
6 answers
logic paradoxes
logic paradoxes
edited 2 days ago
Bernard
124k741117
asked Apr 7 at 6:39
Ricardo MagallanesRicardo Magallanes
244
edited 2 days ago
Bernard
124k741117
asked Apr 7 at 6:39
Ricardo MagallanesRicardo Magallanes
244
edited 2 days ago
Bernard
124k741117
edited 2 days ago
Bernard
124k741117
edited 2 days ago
Bernard
124k741117
124k741117
asked Apr 7 at 6:39
Ricardo MagallanesRicardo Magallanes
244
asked Apr 7 at 6:39
Ricardo MagallanesRicardo Magallanes
244
asked Apr 7 at 6:39
Ricardo MagallanesRicardo Magallanes
244
244
marked as duplicate by Martin R, Community♦ 2 days ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Martin R, Community♦ 2 days ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
$begingroup$
Possible duplicate of Multiple-choice question about the probability of a random answer to itself being correct (for reviewers: only option (c) is different from the duplicating target, but 60% clearly doesn't make more sense than 0%)
$endgroup$
– YuiTo Cheng
2 days ago
add a comment |
1
$begingroup$
Possible duplicate of Multiple-choice question about the probability of a random answer to itself being correct (for reviewers: only option (c) is different from the duplicating target, but 60% clearly doesn't make more sense than 0%)
$endgroup$
– YuiTo Cheng
2 days ago
1
1
$begingroup$
Possible duplicate of Multiple-choice question about the probability of a random answer to itself being correct (for reviewers: only option (c) is different from the duplicating target, but 60% clearly doesn't make more sense than 0%)
$endgroup$
– YuiTo Cheng
2 days ago
$begingroup$
Possible duplicate of Multiple-choice question about the probability of a random answer to itself being correct (for reviewers: only option (c) is different from the duplicating target, but 60% clearly doesn't make more sense than 0%)
$endgroup$
– YuiTo Cheng
2 days ago
add a comment |
1 Answer
1
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Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.
Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.
So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.
$60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.
So as it is posed, there is no correct answer.
answered Apr 7 at 6:47
Eevee TrainerEevee Trainer
10.3k31742
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add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.
Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.
So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.
$60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.
So as it is posed, there is no correct answer.
answered Apr 7 at 6:47
Eevee TrainerEevee Trainer
10.3k31742
$endgroup$
add a comment |
$begingroup$
Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.
Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.
So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.
$60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.
So as it is posed, there is no correct answer.
answered Apr 7 at 6:47
Eevee TrainerEevee Trainer
10.3k31742
$endgroup$
add a comment |
$begingroup$
Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.
Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.
So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.
$60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.
So as it is posed, there is no correct answer.
answered Apr 7 at 6:47
Eevee TrainerEevee Trainer
10.3k31742
$endgroup$
Correct (on the typical assumptions we can only pick one answer, that the selection is uniformly random, etc.). The question is actually a fairly common paradox. The cause is the sort of self-referential nature of the question.
Typically for multiple-choice questions with four answers, at random there is a $25%$ chance to get it right. But two answers have that choice.
So logically it would be $50%$, but only one choice corresponds to that. So you're damned if you pick either one: if $50%$ is correct, the odds are $25%$ and if $25%$ is correct the odds are $50%$.
$60%$ simply makes no sense, being not a multiple of $25%$, and can be ruled out outright.
So as it is posed, there is no correct answer.
answered Apr 7 at 6:47
Eevee TrainerEevee Trainer
10.3k31742
answered Apr 7 at 6:47
Eevee TrainerEevee Trainer
10.3k31742
answered Apr 7 at 6:47
Eevee TrainerEevee Trainer
10.3k31742
answered Apr 7 at 6:47
Eevee TrainerEevee Trainer
10.3k31742
10.3k31742
add a comment |
add a comment |
1
$begingroup$
Possible duplicate of Multiple-choice question about the probability of a random answer to itself being correct (for reviewers: only option (c) is different from the duplicating target, but 60% clearly doesn't make more sense than 0%)
$endgroup$
– YuiTo Cheng
2 days ago