Unlock my phone! March 2018
$begingroup$
New month, new password, but I've already forgotten! Help!
What is my phone's password this month?
Hint #1:
As per usual, my password is pretty long (maybe around 40 digits?)
Hint #2:
In March I took up an interest in analytical number theory
mathematics knowledge visual
asked Apr 3 at 14:54
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
New month, new password, but I've already forgotten! Help!
What is my phone's password this month?
Hint #1:
As per usual, my password is pretty long (maybe around 40 digits?)
Hint #2:
In March I took up an interest in analytical number theory
mathematics knowledge visual
asked Apr 3 at 14:54
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
2
$begingroup$
Really March? Really 2018?
$endgroup$
– Gareth McCaughan♦
Apr 3 at 15:26
1
$begingroup$
If you look at my other puzzles you’ll see I’m starting January of 2018 and going month by month to the present day. Sorry for confusion!
$endgroup$
– Tyler22Alex
Apr 3 at 15:59
$begingroup$
Ah, OK. Fair enough.
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
add a comment |
$begingroup$
New month, new password, but I've already forgotten! Help!
What is my phone's password this month?
Hint #1:
As per usual, my password is pretty long (maybe around 40 digits?)
Hint #2:
In March I took up an interest in analytical number theory
mathematics knowledge visual
asked Apr 3 at 14:54
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
New month, new password, but I've already forgotten! Help!
What is my phone's password this month?
Hint #1:
As per usual, my password is pretty long (maybe around 40 digits?)
Hint #2:
In March I took up an interest in analytical number theory
mathematics knowledge visual
mathematics knowledge visual
asked Apr 3 at 14:54
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Apr 3 at 14:54
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Apr 3 at 14:54
Tyler22AlexTyler22Alex
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Apr 3 at 14:54
Tyler22AlexTyler22Alex
316212
asked Apr 3 at 14:54
Tyler22AlexTyler22Alex
316212
316212
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
$begingroup$
Really March? Really 2018?
$endgroup$
– Gareth McCaughan♦
Apr 3 at 15:26
1
$begingroup$
If you look at my other puzzles you’ll see I’m starting January of 2018 and going month by month to the present day. Sorry for confusion!
$endgroup$
– Tyler22Alex
Apr 3 at 15:59
$begingroup$
Ah, OK. Fair enough.
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
add a comment |
2
$begingroup$
Really March? Really 2018?
$endgroup$
– Gareth McCaughan♦
Apr 3 at 15:26
1
$begingroup$
If you look at my other puzzles you’ll see I’m starting January of 2018 and going month by month to the present day. Sorry for confusion!
$endgroup$
– Tyler22Alex
Apr 3 at 15:59
$begingroup$
Ah, OK. Fair enough.
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
2
2
$begingroup$
Really March? Really 2018?
$endgroup$
– Gareth McCaughan♦
Apr 3 at 15:26
$begingroup$
Really March? Really 2018?
$endgroup$
– Gareth McCaughan♦
Apr 3 at 15:26
1
1
$begingroup$
If you look at my other puzzles you’ll see I’m starting January of 2018 and going month by month to the present day. Sorry for confusion!
$endgroup$
– Tyler22Alex
Apr 3 at 15:59
$begingroup$
If you look at my other puzzles you’ll see I’m starting January of 2018 and going month by month to the present day. Sorry for confusion!
$endgroup$
– Tyler22Alex
Apr 3 at 15:59
$begingroup$
Ah, OK. Fair enough.
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
Ah, OK. Fair enough.
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Your password is
the first 40 digits, or perhaps decimal places, of the Euler-Mascheroni constant, sometimes denoted $gamma$.
So it will begin
either 5772 or 05772 or 0.5772.
Since
to 41 decimal places the constant's value is 0.57721566490153286060651209008240243104215, the last digit will (if you've used 40 decimal places rather than 40 digits including the leading zero) depend on how you've chosen to round it.
Explanation in case the above doesn't make it clear:
the harmonic series is $1+frac12+frac13+frac14+cdots$ and the sum of its first $n$ terms is $log n+gamma+varepsilon(n)$ where $varepsilon(n)rightarrow0$ as $nrightarrowinfty$. So the limiting difference between the harmonic series and the natural logarithm is $gamma$.
answered Apr 3 at 15:22
Gareth McCaughan♦Gareth McCaughan
66.6k3169260
$endgroup$
1
$begingroup$
That was fast! Nice job!
$endgroup$
– Tyler22Alex
Apr 3 at 16:00
$begingroup$
The second hint made it pretty hard not to get :-).
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
(Though I think I'd probably have got it quickly even without.)
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "559"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81362%2funlock-my-phone-march-2018%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Your password is
the first 40 digits, or perhaps decimal places, of the Euler-Mascheroni constant, sometimes denoted $gamma$.
So it will begin
either 5772 or 05772 or 0.5772.
Since
to 41 decimal places the constant's value is 0.57721566490153286060651209008240243104215, the last digit will (if you've used 40 decimal places rather than 40 digits including the leading zero) depend on how you've chosen to round it.
Explanation in case the above doesn't make it clear:
the harmonic series is $1+frac12+frac13+frac14+cdots$ and the sum of its first $n$ terms is $log n+gamma+varepsilon(n)$ where $varepsilon(n)rightarrow0$ as $nrightarrowinfty$. So the limiting difference between the harmonic series and the natural logarithm is $gamma$.
answered Apr 3 at 15:22
Gareth McCaughan♦Gareth McCaughan
66.6k3169260
$endgroup$
1
$begingroup$
That was fast! Nice job!
$endgroup$
– Tyler22Alex
Apr 3 at 16:00
$begingroup$
The second hint made it pretty hard not to get :-).
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
(Though I think I'd probably have got it quickly even without.)
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
add a comment |
$begingroup$
Your password is
the first 40 digits, or perhaps decimal places, of the Euler-Mascheroni constant, sometimes denoted $gamma$.
So it will begin
either 5772 or 05772 or 0.5772.
Since
to 41 decimal places the constant's value is 0.57721566490153286060651209008240243104215, the last digit will (if you've used 40 decimal places rather than 40 digits including the leading zero) depend on how you've chosen to round it.
Explanation in case the above doesn't make it clear:
the harmonic series is $1+frac12+frac13+frac14+cdots$ and the sum of its first $n$ terms is $log n+gamma+varepsilon(n)$ where $varepsilon(n)rightarrow0$ as $nrightarrowinfty$. So the limiting difference between the harmonic series and the natural logarithm is $gamma$.
answered Apr 3 at 15:22
Gareth McCaughan♦Gareth McCaughan
66.6k3169260
$endgroup$
1
$begingroup$
That was fast! Nice job!
$endgroup$
– Tyler22Alex
Apr 3 at 16:00
$begingroup$
The second hint made it pretty hard not to get :-).
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
(Though I think I'd probably have got it quickly even without.)
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
add a comment |
$begingroup$
Your password is
the first 40 digits, or perhaps decimal places, of the Euler-Mascheroni constant, sometimes denoted $gamma$.
So it will begin
either 5772 or 05772 or 0.5772.
Since
to 41 decimal places the constant's value is 0.57721566490153286060651209008240243104215, the last digit will (if you've used 40 decimal places rather than 40 digits including the leading zero) depend on how you've chosen to round it.
Explanation in case the above doesn't make it clear:
the harmonic series is $1+frac12+frac13+frac14+cdots$ and the sum of its first $n$ terms is $log n+gamma+varepsilon(n)$ where $varepsilon(n)rightarrow0$ as $nrightarrowinfty$. So the limiting difference between the harmonic series and the natural logarithm is $gamma$.
answered Apr 3 at 15:22
Gareth McCaughan♦Gareth McCaughan
66.6k3169260
$endgroup$
Your password is
the first 40 digits, or perhaps decimal places, of the Euler-Mascheroni constant, sometimes denoted $gamma$.
So it will begin
either 5772 or 05772 or 0.5772.
Since
to 41 decimal places the constant's value is 0.57721566490153286060651209008240243104215, the last digit will (if you've used 40 decimal places rather than 40 digits including the leading zero) depend on how you've chosen to round it.
Explanation in case the above doesn't make it clear:
the harmonic series is $1+frac12+frac13+frac14+cdots$ and the sum of its first $n$ terms is $log n+gamma+varepsilon(n)$ where $varepsilon(n)rightarrow0$ as $nrightarrowinfty$. So the limiting difference between the harmonic series and the natural logarithm is $gamma$.
answered Apr 3 at 15:22
Gareth McCaughan♦Gareth McCaughan
66.6k3169260
answered Apr 3 at 15:22
Gareth McCaughan♦Gareth McCaughan
66.6k3169260
answered Apr 3 at 15:22
Gareth McCaughan♦Gareth McCaughan
66.6k3169260
answered Apr 3 at 15:22
Gareth McCaughan♦Gareth McCaughan
66.6k3169260
66.6k3169260
1
$begingroup$
That was fast! Nice job!
$endgroup$
– Tyler22Alex
Apr 3 at 16:00
$begingroup$
The second hint made it pretty hard not to get :-).
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
(Though I think I'd probably have got it quickly even without.)
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
add a comment |
1
$begingroup$
That was fast! Nice job!
$endgroup$
– Tyler22Alex
Apr 3 at 16:00
$begingroup$
The second hint made it pretty hard not to get :-).
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
(Though I think I'd probably have got it quickly even without.)
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
1
1
$begingroup$
That was fast! Nice job!
$endgroup$
– Tyler22Alex
Apr 3 at 16:00
$begingroup$
That was fast! Nice job!
$endgroup$
– Tyler22Alex
Apr 3 at 16:00
$begingroup$
The second hint made it pretty hard not to get :-).
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
The second hint made it pretty hard not to get :-).
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
(Though I think I'd probably have got it quickly even without.)
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
$begingroup$
(Though I think I'd probably have got it quickly even without.)
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44
add a comment |
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81362%2funlock-my-phone-march-2018%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
$begingroup$
Really March? Really 2018?
$endgroup$
– Gareth McCaughan♦
Apr 3 at 15:26
1
$begingroup$
If you look at my other puzzles you’ll see I’m starting January of 2018 and going month by month to the present day. Sorry for confusion!
$endgroup$
– Tyler22Alex
Apr 3 at 15:59
$begingroup$
Ah, OK. Fair enough.
$endgroup$
– Gareth McCaughan♦
Apr 3 at 16:44