Why do lower f-stop numbers mean larger apertures? [duplicate]











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  • What does f-stop mean?

    4 answers




I thought this would have been asked before but it seems not.



I don't understand how f-stops are numbered. From what I read, the lower the f-stop number, the larger the aperture. That is, f/2 is larger than f/22.



This seems odd to me. The maximum aperture width is (at least theoretically) infinite, while the minimum is 0 (i.e. the lens is completely closed and not letting in any light).



The way the numbering system is set up, it allows for infinitely tiny apertures but a limit on how large they can be (i.e. I guess the largest is f/0)



Can someone clarify why the aperture is numbered in this way?










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marked as duplicate by scottbb, xiota, Philip Kendall, Rafael, Hueco yesterday


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • Also see photo.stackexchange.com/questions/12072/…
    – Tetsujin
    yesterday










  • There may be limits on how large an aperture can be, but practical considerations make lenses faster than f/1 very, very, very rare. The fastest I have ever heard of is f/0.7.
    – Jim MacKenzie
    yesterday










  • There are many measuring systems where a larger numerical value means a smaller physical size.
    – whatsisname
    yesterday















up vote
2
down vote

favorite













This question already has an answer here:




  • What does f-stop mean?

    4 answers




I thought this would have been asked before but it seems not.



I don't understand how f-stops are numbered. From what I read, the lower the f-stop number, the larger the aperture. That is, f/2 is larger than f/22.



This seems odd to me. The maximum aperture width is (at least theoretically) infinite, while the minimum is 0 (i.e. the lens is completely closed and not letting in any light).



The way the numbering system is set up, it allows for infinitely tiny apertures but a limit on how large they can be (i.e. I guess the largest is f/0)



Can someone clarify why the aperture is numbered in this way?










share|improve this question













marked as duplicate by scottbb, xiota, Philip Kendall, Rafael, Hueco yesterday


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • Also see photo.stackexchange.com/questions/12072/…
    – Tetsujin
    yesterday










  • There may be limits on how large an aperture can be, but practical considerations make lenses faster than f/1 very, very, very rare. The fastest I have ever heard of is f/0.7.
    – Jim MacKenzie
    yesterday










  • There are many measuring systems where a larger numerical value means a smaller physical size.
    – whatsisname
    yesterday













up vote
2
down vote

favorite









up vote
2
down vote

favorite












This question already has an answer here:




  • What does f-stop mean?

    4 answers




I thought this would have been asked before but it seems not.



I don't understand how f-stops are numbered. From what I read, the lower the f-stop number, the larger the aperture. That is, f/2 is larger than f/22.



This seems odd to me. The maximum aperture width is (at least theoretically) infinite, while the minimum is 0 (i.e. the lens is completely closed and not letting in any light).



The way the numbering system is set up, it allows for infinitely tiny apertures but a limit on how large they can be (i.e. I guess the largest is f/0)



Can someone clarify why the aperture is numbered in this way?










share|improve this question














This question already has an answer here:




  • What does f-stop mean?

    4 answers




I thought this would have been asked before but it seems not.



I don't understand how f-stops are numbered. From what I read, the lower the f-stop number, the larger the aperture. That is, f/2 is larger than f/22.



This seems odd to me. The maximum aperture width is (at least theoretically) infinite, while the minimum is 0 (i.e. the lens is completely closed and not letting in any light).



The way the numbering system is set up, it allows for infinitely tiny apertures but a limit on how large they can be (i.e. I guess the largest is f/0)



Can someone clarify why the aperture is numbered in this way?





This question already has an answer here:




  • What does f-stop mean?

    4 answers








aperture f-stop






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share|improve this question










asked yesterday









CodyBugstein

2742416




2742416




marked as duplicate by scottbb, xiota, Philip Kendall, Rafael, Hueco yesterday


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by scottbb, xiota, Philip Kendall, Rafael, Hueco yesterday


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • Also see photo.stackexchange.com/questions/12072/…
    – Tetsujin
    yesterday










  • There may be limits on how large an aperture can be, but practical considerations make lenses faster than f/1 very, very, very rare. The fastest I have ever heard of is f/0.7.
    – Jim MacKenzie
    yesterday










  • There are many measuring systems where a larger numerical value means a smaller physical size.
    – whatsisname
    yesterday


















  • Also see photo.stackexchange.com/questions/12072/…
    – Tetsujin
    yesterday










  • There may be limits on how large an aperture can be, but practical considerations make lenses faster than f/1 very, very, very rare. The fastest I have ever heard of is f/0.7.
    – Jim MacKenzie
    yesterday










  • There are many measuring systems where a larger numerical value means a smaller physical size.
    – whatsisname
    yesterday
















Also see photo.stackexchange.com/questions/12072/…
– Tetsujin
yesterday




Also see photo.stackexchange.com/questions/12072/…
– Tetsujin
yesterday












There may be limits on how large an aperture can be, but practical considerations make lenses faster than f/1 very, very, very rare. The fastest I have ever heard of is f/0.7.
– Jim MacKenzie
yesterday




There may be limits on how large an aperture can be, but practical considerations make lenses faster than f/1 very, very, very rare. The fastest I have ever heard of is f/0.7.
– Jim MacKenzie
yesterday












There are many measuring systems where a larger numerical value means a smaller physical size.
– whatsisname
yesterday




There are many measuring systems where a larger numerical value means a smaller physical size.
– whatsisname
yesterday










5 Answers
5






active

oldest

votes

















up vote
5
down vote













The f stop is a comparison between the physical size of the focal length and the aperture.



If the aperture is 25mm and the focal length is 100mm, then you'd have f/4 because the aperture value is 1/4 the focal length.



So, the f stop is the fractional representation of this comparison. As with fractions, 1/2 is bigger than 1/22.






share|improve this answer






























    up vote
    3
    down vote













    / is division.



    A number divided by 22 (f/22) is smaller than the same number divided by 2 (f/2).
    As simple as that.



    Now, WHY?



    f is the focal length. Describing the aperture as a fraction of the focal length has one advantage: it immediately reveals the image brightness.



    Example:



    20mm aperture can be...




    • Telephoto lens, 200mm f/10 - pretty dark

    • Wide angle lens, 30mm f/1.5 - pretty bright






    share|improve this answer



















    • 1




      Aha didn't realize that we were dividing f. So what is f ? What does f/1 equal?
      – CodyBugstein
      yesterday










    • Aha So aperture of f/6 means something very different on a 30mm lens and a 200mm lens?
      – CodyBugstein
      yesterday










    • f/1 would be aperture equal to the focal length (which means quite big aperture and bright lens but otherwise not a special case of any kind. it is always possible to push a little harder and make lens a bit bigger and more expensive)
      – szulat
      yesterday






    • 2




      f/6 means the physical diameter would be different but they produce the same brightness.
      – szulat
      yesterday










    • So the maximum aperture is always equal to the length of the lens? In other words, longer lenses must be fatter too?
      – CodyBugstein
      yesterday


















    up vote
    2
    down vote













    It's no accident that f-stops are written with a "division" slash.



    You say, "f/2 is larger than f/22". Here, "f" stands for the focal length, and the result of the expression gives the physical size of the aperture opening. So, let's take a 50mm lens... At f/2, the aperture opening measures 25mm. At f/22, the aperture opening measures ~2.3mm. Obviously an opening measuring 25mm is going to let in more light than one that measures ~2.3mm.



    You say, "I guess the largest is f/0". No. You can't divide by zero. Or in other words, there is no lens such that the ratio of the focal length to the size of the aperture is f:∞.






    share|improve this answer























    • I always say... photography is the art for mathematicians :-P
      – osullic
      yesterday








    • 1




      I have literally been told, you're about the science and I'm more about the art, when trying to teach darkroom principals. Le sigh.
      – Hueco
      yesterday


















    up vote
    0
    down vote













    Because the lens operates much like a funnel in that it gathers light, the greater the working diameter of the lens, the brighter the projected image. How bright this image will be is dependent on the brightness of the scene and the magnification realized by the lens. The longer the focal length, the more the lens magnifies. The deed of magnifying to produce an image, takes its toll on image brightness. In other words, the longer the focal length, the more the lens magnifies. This higher magnification result is a larger but dimmer image of objects.



    Another way to say this, image brightness intertwines the working diameter and the focal length. Because these two factors are so interwoven, gauging image brightness is demanding. We are forced to fall back on a mathematical ratio that will take the chaos out of figuring out image brightness. This is true because a ratio is dimensionless. If I tell you the ratio of boys to girls in a 6th grade class is 3 boys for every 4 girls, I have given you a ratio that works independent of the number of students. For example if the class consist of 28 kids, then 12 boys to 16 girls is the breakdown (ratio is dimensionless).



    For the camera lens: if the working diameter is 4 inches and the focal length is 4 inches, then the focal ratio (f-number) = 4 ÷ 4 = 1 (written as f/1 (f/1 is produces a very bright image). If the working diameter is 2 inches and the focal length is 4 inches, then the f-number is 4 ÷ 2 = 2 (written as f/2.).



    The splendor of using a ratio is, any lens operating at the same f-number as another lens, yields the same image brightness regardless of the dimensions (diameter or focal length), for an identical scene. It’s complicated; but the f-number system actually takes away the chaos.






    share|improve this answer




























      up vote
      0
      down vote













      The "why" is that f/stop number is focal length / aperture diameter.



      So a 100 mm lens at f/4 has an effective aperture of 25 mm. This is not exactly the physical diameter opening, but is the effective diameter, specifically the front entrance pupil, as seen by the magnification of the front lens elements.



      Because of this definition, as aperture diameter becomes larger (and exposure increases), f/stop number becomes smaller. f/2.8 is wide, and f/22 is narrow.



      It may seem backwards at first, but we get over it easily, and the huge advantage of the f/stop number system is that it applies for any lens, of any size and focal length and aperture, so then we all know what we mean when we say f/8. f/8 is f/8 exposure on any lens. This is a plus. It wasn't that way in the early beginning. And of course, light meters meter with the same meanings.



      My site has more about this at https://www.scantips.com/lights/fstop.html






      share|improve this answer






























        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes








        up vote
        5
        down vote













        The f stop is a comparison between the physical size of the focal length and the aperture.



        If the aperture is 25mm and the focal length is 100mm, then you'd have f/4 because the aperture value is 1/4 the focal length.



        So, the f stop is the fractional representation of this comparison. As with fractions, 1/2 is bigger than 1/22.






        share|improve this answer



























          up vote
          5
          down vote













          The f stop is a comparison between the physical size of the focal length and the aperture.



          If the aperture is 25mm and the focal length is 100mm, then you'd have f/4 because the aperture value is 1/4 the focal length.



          So, the f stop is the fractional representation of this comparison. As with fractions, 1/2 is bigger than 1/22.






          share|improve this answer

























            up vote
            5
            down vote










            up vote
            5
            down vote









            The f stop is a comparison between the physical size of the focal length and the aperture.



            If the aperture is 25mm and the focal length is 100mm, then you'd have f/4 because the aperture value is 1/4 the focal length.



            So, the f stop is the fractional representation of this comparison. As with fractions, 1/2 is bigger than 1/22.






            share|improve this answer














            The f stop is a comparison between the physical size of the focal length and the aperture.



            If the aperture is 25mm and the focal length is 100mm, then you'd have f/4 because the aperture value is 1/4 the focal length.



            So, the f stop is the fractional representation of this comparison. As with fractions, 1/2 is bigger than 1/22.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited yesterday

























            answered yesterday









            Hueco

            9,80732346




            9,80732346
























                up vote
                3
                down vote













                / is division.



                A number divided by 22 (f/22) is smaller than the same number divided by 2 (f/2).
                As simple as that.



                Now, WHY?



                f is the focal length. Describing the aperture as a fraction of the focal length has one advantage: it immediately reveals the image brightness.



                Example:



                20mm aperture can be...




                • Telephoto lens, 200mm f/10 - pretty dark

                • Wide angle lens, 30mm f/1.5 - pretty bright






                share|improve this answer



















                • 1




                  Aha didn't realize that we were dividing f. So what is f ? What does f/1 equal?
                  – CodyBugstein
                  yesterday










                • Aha So aperture of f/6 means something very different on a 30mm lens and a 200mm lens?
                  – CodyBugstein
                  yesterday










                • f/1 would be aperture equal to the focal length (which means quite big aperture and bright lens but otherwise not a special case of any kind. it is always possible to push a little harder and make lens a bit bigger and more expensive)
                  – szulat
                  yesterday






                • 2




                  f/6 means the physical diameter would be different but they produce the same brightness.
                  – szulat
                  yesterday










                • So the maximum aperture is always equal to the length of the lens? In other words, longer lenses must be fatter too?
                  – CodyBugstein
                  yesterday















                up vote
                3
                down vote













                / is division.



                A number divided by 22 (f/22) is smaller than the same number divided by 2 (f/2).
                As simple as that.



                Now, WHY?



                f is the focal length. Describing the aperture as a fraction of the focal length has one advantage: it immediately reveals the image brightness.



                Example:



                20mm aperture can be...




                • Telephoto lens, 200mm f/10 - pretty dark

                • Wide angle lens, 30mm f/1.5 - pretty bright






                share|improve this answer



















                • 1




                  Aha didn't realize that we were dividing f. So what is f ? What does f/1 equal?
                  – CodyBugstein
                  yesterday










                • Aha So aperture of f/6 means something very different on a 30mm lens and a 200mm lens?
                  – CodyBugstein
                  yesterday










                • f/1 would be aperture equal to the focal length (which means quite big aperture and bright lens but otherwise not a special case of any kind. it is always possible to push a little harder and make lens a bit bigger and more expensive)
                  – szulat
                  yesterday






                • 2




                  f/6 means the physical diameter would be different but they produce the same brightness.
                  – szulat
                  yesterday










                • So the maximum aperture is always equal to the length of the lens? In other words, longer lenses must be fatter too?
                  – CodyBugstein
                  yesterday













                up vote
                3
                down vote










                up vote
                3
                down vote









                / is division.



                A number divided by 22 (f/22) is smaller than the same number divided by 2 (f/2).
                As simple as that.



                Now, WHY?



                f is the focal length. Describing the aperture as a fraction of the focal length has one advantage: it immediately reveals the image brightness.



                Example:



                20mm aperture can be...




                • Telephoto lens, 200mm f/10 - pretty dark

                • Wide angle lens, 30mm f/1.5 - pretty bright






                share|improve this answer














                / is division.



                A number divided by 22 (f/22) is smaller than the same number divided by 2 (f/2).
                As simple as that.



                Now, WHY?



                f is the focal length. Describing the aperture as a fraction of the focal length has one advantage: it immediately reveals the image brightness.



                Example:



                20mm aperture can be...




                • Telephoto lens, 200mm f/10 - pretty dark

                • Wide angle lens, 30mm f/1.5 - pretty bright







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited yesterday

























                answered yesterday









                szulat

                3,58711126




                3,58711126








                • 1




                  Aha didn't realize that we were dividing f. So what is f ? What does f/1 equal?
                  – CodyBugstein
                  yesterday










                • Aha So aperture of f/6 means something very different on a 30mm lens and a 200mm lens?
                  – CodyBugstein
                  yesterday










                • f/1 would be aperture equal to the focal length (which means quite big aperture and bright lens but otherwise not a special case of any kind. it is always possible to push a little harder and make lens a bit bigger and more expensive)
                  – szulat
                  yesterday






                • 2




                  f/6 means the physical diameter would be different but they produce the same brightness.
                  – szulat
                  yesterday










                • So the maximum aperture is always equal to the length of the lens? In other words, longer lenses must be fatter too?
                  – CodyBugstein
                  yesterday














                • 1




                  Aha didn't realize that we were dividing f. So what is f ? What does f/1 equal?
                  – CodyBugstein
                  yesterday










                • Aha So aperture of f/6 means something very different on a 30mm lens and a 200mm lens?
                  – CodyBugstein
                  yesterday










                • f/1 would be aperture equal to the focal length (which means quite big aperture and bright lens but otherwise not a special case of any kind. it is always possible to push a little harder and make lens a bit bigger and more expensive)
                  – szulat
                  yesterday






                • 2




                  f/6 means the physical diameter would be different but they produce the same brightness.
                  – szulat
                  yesterday










                • So the maximum aperture is always equal to the length of the lens? In other words, longer lenses must be fatter too?
                  – CodyBugstein
                  yesterday








                1




                1




                Aha didn't realize that we were dividing f. So what is f ? What does f/1 equal?
                – CodyBugstein
                yesterday




                Aha didn't realize that we were dividing f. So what is f ? What does f/1 equal?
                – CodyBugstein
                yesterday












                Aha So aperture of f/6 means something very different on a 30mm lens and a 200mm lens?
                – CodyBugstein
                yesterday




                Aha So aperture of f/6 means something very different on a 30mm lens and a 200mm lens?
                – CodyBugstein
                yesterday












                f/1 would be aperture equal to the focal length (which means quite big aperture and bright lens but otherwise not a special case of any kind. it is always possible to push a little harder and make lens a bit bigger and more expensive)
                – szulat
                yesterday




                f/1 would be aperture equal to the focal length (which means quite big aperture and bright lens but otherwise not a special case of any kind. it is always possible to push a little harder and make lens a bit bigger and more expensive)
                – szulat
                yesterday




                2




                2




                f/6 means the physical diameter would be different but they produce the same brightness.
                – szulat
                yesterday




                f/6 means the physical diameter would be different but they produce the same brightness.
                – szulat
                yesterday












                So the maximum aperture is always equal to the length of the lens? In other words, longer lenses must be fatter too?
                – CodyBugstein
                yesterday




                So the maximum aperture is always equal to the length of the lens? In other words, longer lenses must be fatter too?
                – CodyBugstein
                yesterday










                up vote
                2
                down vote













                It's no accident that f-stops are written with a "division" slash.



                You say, "f/2 is larger than f/22". Here, "f" stands for the focal length, and the result of the expression gives the physical size of the aperture opening. So, let's take a 50mm lens... At f/2, the aperture opening measures 25mm. At f/22, the aperture opening measures ~2.3mm. Obviously an opening measuring 25mm is going to let in more light than one that measures ~2.3mm.



                You say, "I guess the largest is f/0". No. You can't divide by zero. Or in other words, there is no lens such that the ratio of the focal length to the size of the aperture is f:∞.






                share|improve this answer























                • I always say... photography is the art for mathematicians :-P
                  – osullic
                  yesterday








                • 1




                  I have literally been told, you're about the science and I'm more about the art, when trying to teach darkroom principals. Le sigh.
                  – Hueco
                  yesterday















                up vote
                2
                down vote













                It's no accident that f-stops are written with a "division" slash.



                You say, "f/2 is larger than f/22". Here, "f" stands for the focal length, and the result of the expression gives the physical size of the aperture opening. So, let's take a 50mm lens... At f/2, the aperture opening measures 25mm. At f/22, the aperture opening measures ~2.3mm. Obviously an opening measuring 25mm is going to let in more light than one that measures ~2.3mm.



                You say, "I guess the largest is f/0". No. You can't divide by zero. Or in other words, there is no lens such that the ratio of the focal length to the size of the aperture is f:∞.






                share|improve this answer























                • I always say... photography is the art for mathematicians :-P
                  – osullic
                  yesterday








                • 1




                  I have literally been told, you're about the science and I'm more about the art, when trying to teach darkroom principals. Le sigh.
                  – Hueco
                  yesterday













                up vote
                2
                down vote










                up vote
                2
                down vote









                It's no accident that f-stops are written with a "division" slash.



                You say, "f/2 is larger than f/22". Here, "f" stands for the focal length, and the result of the expression gives the physical size of the aperture opening. So, let's take a 50mm lens... At f/2, the aperture opening measures 25mm. At f/22, the aperture opening measures ~2.3mm. Obviously an opening measuring 25mm is going to let in more light than one that measures ~2.3mm.



                You say, "I guess the largest is f/0". No. You can't divide by zero. Or in other words, there is no lens such that the ratio of the focal length to the size of the aperture is f:∞.






                share|improve this answer














                It's no accident that f-stops are written with a "division" slash.



                You say, "f/2 is larger than f/22". Here, "f" stands for the focal length, and the result of the expression gives the physical size of the aperture opening. So, let's take a 50mm lens... At f/2, the aperture opening measures 25mm. At f/22, the aperture opening measures ~2.3mm. Obviously an opening measuring 25mm is going to let in more light than one that measures ~2.3mm.



                You say, "I guess the largest is f/0". No. You can't divide by zero. Or in other words, there is no lens such that the ratio of the focal length to the size of the aperture is f:∞.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited yesterday

























                answered yesterday









                osullic

                5,56311021




                5,56311021












                • I always say... photography is the art for mathematicians :-P
                  – osullic
                  yesterday








                • 1




                  I have literally been told, you're about the science and I'm more about the art, when trying to teach darkroom principals. Le sigh.
                  – Hueco
                  yesterday


















                • I always say... photography is the art for mathematicians :-P
                  – osullic
                  yesterday








                • 1




                  I have literally been told, you're about the science and I'm more about the art, when trying to teach darkroom principals. Le sigh.
                  – Hueco
                  yesterday
















                I always say... photography is the art for mathematicians :-P
                – osullic
                yesterday






                I always say... photography is the art for mathematicians :-P
                – osullic
                yesterday






                1




                1




                I have literally been told, you're about the science and I'm more about the art, when trying to teach darkroom principals. Le sigh.
                – Hueco
                yesterday




                I have literally been told, you're about the science and I'm more about the art, when trying to teach darkroom principals. Le sigh.
                – Hueco
                yesterday










                up vote
                0
                down vote













                Because the lens operates much like a funnel in that it gathers light, the greater the working diameter of the lens, the brighter the projected image. How bright this image will be is dependent on the brightness of the scene and the magnification realized by the lens. The longer the focal length, the more the lens magnifies. The deed of magnifying to produce an image, takes its toll on image brightness. In other words, the longer the focal length, the more the lens magnifies. This higher magnification result is a larger but dimmer image of objects.



                Another way to say this, image brightness intertwines the working diameter and the focal length. Because these two factors are so interwoven, gauging image brightness is demanding. We are forced to fall back on a mathematical ratio that will take the chaos out of figuring out image brightness. This is true because a ratio is dimensionless. If I tell you the ratio of boys to girls in a 6th grade class is 3 boys for every 4 girls, I have given you a ratio that works independent of the number of students. For example if the class consist of 28 kids, then 12 boys to 16 girls is the breakdown (ratio is dimensionless).



                For the camera lens: if the working diameter is 4 inches and the focal length is 4 inches, then the focal ratio (f-number) = 4 ÷ 4 = 1 (written as f/1 (f/1 is produces a very bright image). If the working diameter is 2 inches and the focal length is 4 inches, then the f-number is 4 ÷ 2 = 2 (written as f/2.).



                The splendor of using a ratio is, any lens operating at the same f-number as another lens, yields the same image brightness regardless of the dimensions (diameter or focal length), for an identical scene. It’s complicated; but the f-number system actually takes away the chaos.






                share|improve this answer

























                  up vote
                  0
                  down vote













                  Because the lens operates much like a funnel in that it gathers light, the greater the working diameter of the lens, the brighter the projected image. How bright this image will be is dependent on the brightness of the scene and the magnification realized by the lens. The longer the focal length, the more the lens magnifies. The deed of magnifying to produce an image, takes its toll on image brightness. In other words, the longer the focal length, the more the lens magnifies. This higher magnification result is a larger but dimmer image of objects.



                  Another way to say this, image brightness intertwines the working diameter and the focal length. Because these two factors are so interwoven, gauging image brightness is demanding. We are forced to fall back on a mathematical ratio that will take the chaos out of figuring out image brightness. This is true because a ratio is dimensionless. If I tell you the ratio of boys to girls in a 6th grade class is 3 boys for every 4 girls, I have given you a ratio that works independent of the number of students. For example if the class consist of 28 kids, then 12 boys to 16 girls is the breakdown (ratio is dimensionless).



                  For the camera lens: if the working diameter is 4 inches and the focal length is 4 inches, then the focal ratio (f-number) = 4 ÷ 4 = 1 (written as f/1 (f/1 is produces a very bright image). If the working diameter is 2 inches and the focal length is 4 inches, then the f-number is 4 ÷ 2 = 2 (written as f/2.).



                  The splendor of using a ratio is, any lens operating at the same f-number as another lens, yields the same image brightness regardless of the dimensions (diameter or focal length), for an identical scene. It’s complicated; but the f-number system actually takes away the chaos.






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                    up vote
                    0
                    down vote









                    Because the lens operates much like a funnel in that it gathers light, the greater the working diameter of the lens, the brighter the projected image. How bright this image will be is dependent on the brightness of the scene and the magnification realized by the lens. The longer the focal length, the more the lens magnifies. The deed of magnifying to produce an image, takes its toll on image brightness. In other words, the longer the focal length, the more the lens magnifies. This higher magnification result is a larger but dimmer image of objects.



                    Another way to say this, image brightness intertwines the working diameter and the focal length. Because these two factors are so interwoven, gauging image brightness is demanding. We are forced to fall back on a mathematical ratio that will take the chaos out of figuring out image brightness. This is true because a ratio is dimensionless. If I tell you the ratio of boys to girls in a 6th grade class is 3 boys for every 4 girls, I have given you a ratio that works independent of the number of students. For example if the class consist of 28 kids, then 12 boys to 16 girls is the breakdown (ratio is dimensionless).



                    For the camera lens: if the working diameter is 4 inches and the focal length is 4 inches, then the focal ratio (f-number) = 4 ÷ 4 = 1 (written as f/1 (f/1 is produces a very bright image). If the working diameter is 2 inches and the focal length is 4 inches, then the f-number is 4 ÷ 2 = 2 (written as f/2.).



                    The splendor of using a ratio is, any lens operating at the same f-number as another lens, yields the same image brightness regardless of the dimensions (diameter or focal length), for an identical scene. It’s complicated; but the f-number system actually takes away the chaos.






                    share|improve this answer












                    Because the lens operates much like a funnel in that it gathers light, the greater the working diameter of the lens, the brighter the projected image. How bright this image will be is dependent on the brightness of the scene and the magnification realized by the lens. The longer the focal length, the more the lens magnifies. The deed of magnifying to produce an image, takes its toll on image brightness. In other words, the longer the focal length, the more the lens magnifies. This higher magnification result is a larger but dimmer image of objects.



                    Another way to say this, image brightness intertwines the working diameter and the focal length. Because these two factors are so interwoven, gauging image brightness is demanding. We are forced to fall back on a mathematical ratio that will take the chaos out of figuring out image brightness. This is true because a ratio is dimensionless. If I tell you the ratio of boys to girls in a 6th grade class is 3 boys for every 4 girls, I have given you a ratio that works independent of the number of students. For example if the class consist of 28 kids, then 12 boys to 16 girls is the breakdown (ratio is dimensionless).



                    For the camera lens: if the working diameter is 4 inches and the focal length is 4 inches, then the focal ratio (f-number) = 4 ÷ 4 = 1 (written as f/1 (f/1 is produces a very bright image). If the working diameter is 2 inches and the focal length is 4 inches, then the f-number is 4 ÷ 2 = 2 (written as f/2.).



                    The splendor of using a ratio is, any lens operating at the same f-number as another lens, yields the same image brightness regardless of the dimensions (diameter or focal length), for an identical scene. It’s complicated; but the f-number system actually takes away the chaos.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered yesterday









                    Alan Marcus

                    24.2k12858




                    24.2k12858






















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                        down vote













                        The "why" is that f/stop number is focal length / aperture diameter.



                        So a 100 mm lens at f/4 has an effective aperture of 25 mm. This is not exactly the physical diameter opening, but is the effective diameter, specifically the front entrance pupil, as seen by the magnification of the front lens elements.



                        Because of this definition, as aperture diameter becomes larger (and exposure increases), f/stop number becomes smaller. f/2.8 is wide, and f/22 is narrow.



                        It may seem backwards at first, but we get over it easily, and the huge advantage of the f/stop number system is that it applies for any lens, of any size and focal length and aperture, so then we all know what we mean when we say f/8. f/8 is f/8 exposure on any lens. This is a plus. It wasn't that way in the early beginning. And of course, light meters meter with the same meanings.



                        My site has more about this at https://www.scantips.com/lights/fstop.html






                        share|improve this answer



























                          up vote
                          0
                          down vote













                          The "why" is that f/stop number is focal length / aperture diameter.



                          So a 100 mm lens at f/4 has an effective aperture of 25 mm. This is not exactly the physical diameter opening, but is the effective diameter, specifically the front entrance pupil, as seen by the magnification of the front lens elements.



                          Because of this definition, as aperture diameter becomes larger (and exposure increases), f/stop number becomes smaller. f/2.8 is wide, and f/22 is narrow.



                          It may seem backwards at first, but we get over it easily, and the huge advantage of the f/stop number system is that it applies for any lens, of any size and focal length and aperture, so then we all know what we mean when we say f/8. f/8 is f/8 exposure on any lens. This is a plus. It wasn't that way in the early beginning. And of course, light meters meter with the same meanings.



                          My site has more about this at https://www.scantips.com/lights/fstop.html






                          share|improve this answer

























                            up vote
                            0
                            down vote










                            up vote
                            0
                            down vote









                            The "why" is that f/stop number is focal length / aperture diameter.



                            So a 100 mm lens at f/4 has an effective aperture of 25 mm. This is not exactly the physical diameter opening, but is the effective diameter, specifically the front entrance pupil, as seen by the magnification of the front lens elements.



                            Because of this definition, as aperture diameter becomes larger (and exposure increases), f/stop number becomes smaller. f/2.8 is wide, and f/22 is narrow.



                            It may seem backwards at first, but we get over it easily, and the huge advantage of the f/stop number system is that it applies for any lens, of any size and focal length and aperture, so then we all know what we mean when we say f/8. f/8 is f/8 exposure on any lens. This is a plus. It wasn't that way in the early beginning. And of course, light meters meter with the same meanings.



                            My site has more about this at https://www.scantips.com/lights/fstop.html






                            share|improve this answer














                            The "why" is that f/stop number is focal length / aperture diameter.



                            So a 100 mm lens at f/4 has an effective aperture of 25 mm. This is not exactly the physical diameter opening, but is the effective diameter, specifically the front entrance pupil, as seen by the magnification of the front lens elements.



                            Because of this definition, as aperture diameter becomes larger (and exposure increases), f/stop number becomes smaller. f/2.8 is wide, and f/22 is narrow.



                            It may seem backwards at first, but we get over it easily, and the huge advantage of the f/stop number system is that it applies for any lens, of any size and focal length and aperture, so then we all know what we mean when we say f/8. f/8 is f/8 exposure on any lens. This is a plus. It wasn't that way in the early beginning. And of course, light meters meter with the same meanings.



                            My site has more about this at https://www.scantips.com/lights/fstop.html







                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited yesterday

























                            answered yesterday









                            WayneF

                            9,5611924




                            9,5611924















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