How to color a curve












4












$begingroup$


How does one color the interior of the elongated circular region in the following figure:



ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]









share|improve this question











$endgroup$

















    4












    $begingroup$


    How does one color the interior of the elongated circular region in the following figure:



    ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]









    share|improve this question











    $endgroup$















      4












      4








      4


      0



      $begingroup$


      How does one color the interior of the elongated circular region in the following figure:



      ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]









      share|improve this question











      $endgroup$




      How does one color the interior of the elongated circular region in the following figure:



      ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]






      plotting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 days ago









      J. M. is slightly pensive

      98.5k10309466




      98.5k10309466










      asked 2 days ago









      Sara yaqobSara yaqob

      234




      234






















          2 Answers
          2






          active

          oldest

          votes


















          2












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]


          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            2 days ago



















          3












          $begingroup$

          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            2 days ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            2 days ago






          • 2




            $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            2 days ago










          • $begingroup$
            That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using ContourPlot.
            $endgroup$
            – mjw
            8 hours ago











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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]


          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            2 days ago
















          2












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]


          enter image description here






          share|improve this answer









          $endgroup$













          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            2 days ago














          2












          2








          2





          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]


          enter image description here






          share|improve this answer









          $endgroup$



          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 days ago









          XminerXminer

          33818




          33818












          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            2 days ago


















          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            2 days ago
















          $begingroup$
          But I need only the curve not the surface
          $endgroup$
          – Sara yaqob
          2 days ago




          $begingroup$
          But I need only the curve not the surface
          $endgroup$
          – Sara yaqob
          2 days ago











          3












          $begingroup$

          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            2 days ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            2 days ago






          • 2




            $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            2 days ago










          • $begingroup$
            That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using ContourPlot.
            $endgroup$
            – mjw
            8 hours ago
















          3












          $begingroup$

          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            2 days ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            2 days ago






          • 2




            $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            2 days ago










          • $begingroup$
            That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using ContourPlot.
            $endgroup$
            – mjw
            8 hours ago














          3












          3








          3





          $begingroup$

          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 2 days ago

























          answered 2 days ago









          mjwmjw

          1,03710




          1,03710








          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            2 days ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            2 days ago






          • 2




            $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            2 days ago










          • $begingroup$
            That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using ContourPlot.
            $endgroup$
            – mjw
            8 hours ago














          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            2 days ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            2 days ago






          • 2




            $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            2 days ago










          • $begingroup$
            That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using ContourPlot.
            $endgroup$
            – mjw
            8 hours ago








          1




          1




          $begingroup$
          Thank you so so much sir. That's what I need.
          $endgroup$
          – Sara yaqob
          2 days ago




          $begingroup$
          Thank you so so much sir. That's what I need.
          $endgroup$
          – Sara yaqob
          2 days ago












          $begingroup$
          @Sara, You are welcome!
          $endgroup$
          – mjw
          2 days ago




          $begingroup$
          @Sara, You are welcome!
          $endgroup$
          – mjw
          2 days ago




          2




          2




          $begingroup$
          @Sarayaqob you mistakenly accepted my answer
          $endgroup$
          – Xminer
          2 days ago




          $begingroup$
          @Sarayaqob you mistakenly accepted my answer
          $endgroup$
          – Xminer
          2 days ago












          $begingroup$
          That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using ContourPlot.
          $endgroup$
          – mjw
          8 hours ago




          $begingroup$
          That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using ContourPlot.
          $endgroup$
          – mjw
          8 hours ago


















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