How to color a curve
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
plotting
$endgroup$
add a comment |
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
plotting
$endgroup$
add a comment |
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
plotting
$endgroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
plotting
plotting
edited 2 days ago
J. M. is slightly pensive♦
98.5k10309466
98.5k10309466
asked 2 days ago
Sara yaqobSara yaqob
234
234
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 days ago
add a comment |
$begingroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 days ago
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 days ago
$begingroup$
That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only usingContourPlot
.
$endgroup$
– mjw
8 hours ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 days ago
add a comment |
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 days ago
add a comment |
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
$endgroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
answered 2 days ago
XminerXminer
33818
33818
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 days ago
add a comment |
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 days ago
add a comment |
$begingroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 days ago
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 days ago
$begingroup$
That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only usingContourPlot
.
$endgroup$
– mjw
8 hours ago
add a comment |
$begingroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 days ago
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 days ago
$begingroup$
That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only usingContourPlot
.
$endgroup$
– mjw
8 hours ago
add a comment |
$begingroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
$endgroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
edited 2 days ago
answered 2 days ago
mjwmjw
1,03710
1,03710
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 days ago
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 days ago
$begingroup$
That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only usingContourPlot
.
$endgroup$
– mjw
8 hours ago
add a comment |
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 days ago
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 days ago
$begingroup$
That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only usingContourPlot
.
$endgroup$
– mjw
8 hours ago
1
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 days ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 days ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 days ago
2
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 days ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 days ago
$begingroup$
That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using
ContourPlot
.$endgroup$
– mjw
8 hours ago
$begingroup$
That's okay. Anyway, your answer works. One question is whether or not we can color in the round area only using
ContourPlot
.$endgroup$
– mjw
8 hours ago
add a comment |
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