Magento 1 : each() function is deprecated
In Magento 1, I have been getting this error:
Deprecated: The each() function is deprecated. This message will be suppressed on further calls in /var/www/html/test/app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php on line 757
Code:
if (is_array($table)) {
list($tableAlias, $tableName) = each($table);
} else {
$tableName = $table;
}
How to solve this?
Any help would be much appreciated.
magento-1.9 php-7 deprecated
asked Mar 19 at 10:15
AnsumanAnsuman
446
add a comment |
In Magento 1, I have been getting this error:
Deprecated: The each() function is deprecated. This message will be suppressed on further calls in /var/www/html/test/app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php on line 757
Code:
if (is_array($table)) {
list($tableAlias, $tableName) = each($table);
} else {
$tableName = $table;
}
How to solve this?
Any help would be much appreciated.
magento-1.9 php-7 deprecated
asked Mar 19 at 10:15
AnsumanAnsuman
446
It's too much different question which you duplicated. First of all, please read it :)
– Ansuman
Mar 19 at 10:20
apologies for the inconvenience. +1 for your question
– Shoaib Munir
Mar 19 at 10:23
add a comment |
In Magento 1, I have been getting this error:
Deprecated: The each() function is deprecated. This message will be suppressed on further calls in /var/www/html/test/app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php on line 757
Code:
if (is_array($table)) {
list($tableAlias, $tableName) = each($table);
} else {
$tableName = $table;
}
How to solve this?
Any help would be much appreciated.
magento-1.9 php-7 deprecated
asked Mar 19 at 10:15
AnsumanAnsuman
446
In Magento 1, I have been getting this error:
Deprecated: The each() function is deprecated. This message will be suppressed on further calls in /var/www/html/test/app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php on line 757
Code:
if (is_array($table)) {
list($tableAlias, $tableName) = each($table);
} else {
$tableName = $table;
}
How to solve this?
Any help would be much appreciated.
magento-1.9 php-7 deprecated
magento-1.9 php-7 deprecated
asked Mar 19 at 10:15
AnsumanAnsuman
446
asked Mar 19 at 10:15
AnsumanAnsuman
446
edited Mar 19 at 10:19
Ansuman
asked Mar 19 at 10:15
AnsumanAnsuman
446
asked Mar 19 at 10:15
AnsumanAnsuman
446
asked Mar 19 at 10:15
AnsumanAnsuman
446
446
It's too much different question which you duplicated. First of all, please read it :)
– Ansuman
Mar 19 at 10:20
apologies for the inconvenience. +1 for your question
– Shoaib Munir
Mar 19 at 10:23
add a comment |
It's too much different question which you duplicated. First of all, please read it :)
– Ansuman
Mar 19 at 10:20
apologies for the inconvenience. +1 for your question
– Shoaib Munir
Mar 19 at 10:23
It's too much different question which you duplicated. First of all, please read it :)
– Ansuman
Mar 19 at 10:20
It's too much different question which you duplicated. First of all, please read it :)
– Ansuman
Mar 19 at 10:20
apologies for the inconvenience. +1 for your question
– Shoaib Munir
Mar 19 at 10:23
apologies for the inconvenience. +1 for your question
– Shoaib Munir
Mar 19 at 10:23
add a comment |
1 Answer
1
active
oldest
votes
You should replace this below code in if condition :
list($tableAlias, $tableName) = [key($table), current($table)];
As like :
if (is_array($table)) {
list($tableAlias, $tableName) = [key($table), current($table)];
} else {
$tableName = $table;
}
answered Mar 19 at 10:16
Rohan HapaniRohan Hapani
6,79731865
Thanks ..!! It's working.
– Ansuman
Mar 19 at 10:22
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should replace this below code in if condition :
list($tableAlias, $tableName) = [key($table), current($table)];
As like :
if (is_array($table)) {
list($tableAlias, $tableName) = [key($table), current($table)];
} else {
$tableName = $table;
}
answered Mar 19 at 10:16
Rohan HapaniRohan Hapani
6,79731865
Thanks ..!! It's working.
– Ansuman
Mar 19 at 10:22
add a comment |
You should replace this below code in if condition :
list($tableAlias, $tableName) = [key($table), current($table)];
As like :
if (is_array($table)) {
list($tableAlias, $tableName) = [key($table), current($table)];
} else {
$tableName = $table;
}
answered Mar 19 at 10:16
Rohan HapaniRohan Hapani
6,79731865
Thanks ..!! It's working.
– Ansuman
Mar 19 at 10:22
add a comment |
You should replace this below code in if condition :
list($tableAlias, $tableName) = [key($table), current($table)];
As like :
if (is_array($table)) {
list($tableAlias, $tableName) = [key($table), current($table)];
} else {
$tableName = $table;
}
answered Mar 19 at 10:16
Rohan HapaniRohan Hapani
6,79731865
You should replace this below code in if condition :
list($tableAlias, $tableName) = [key($table), current($table)];
As like :
if (is_array($table)) {
list($tableAlias, $tableName) = [key($table), current($table)];
} else {
$tableName = $table;
}
answered Mar 19 at 10:16
Rohan HapaniRohan Hapani
6,79731865
answered Mar 19 at 10:16
Rohan HapaniRohan Hapani
6,79731865
answered Mar 19 at 10:16
Rohan HapaniRohan Hapani
6,79731865
answered Mar 19 at 10:16
Rohan HapaniRohan Hapani
6,79731865
6,79731865
Thanks ..!! It's working.
– Ansuman
Mar 19 at 10:22
add a comment |
Thanks ..!! It's working.
– Ansuman
Mar 19 at 10:22
Thanks ..!! It's working.
– Ansuman
Mar 19 at 10:22
Thanks ..!! It's working.
– Ansuman
Mar 19 at 10:22
add a comment |
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It's too much different question which you duplicated. First of all, please read it :)
– Ansuman
Mar 19 at 10:20
apologies for the inconvenience. +1 for your question
– Shoaib Munir
Mar 19 at 10:23