What expression will give age in years in QGIS?
I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
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I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
New contributor
add a comment |
I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
New contributor
I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
qgis-plugins
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New contributor
edited Mar 29 at 18:16
Vince
14.8k32849
14.8k32849
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asked Mar 29 at 17:07
TraineeGISTraineeGIS
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2 Answers
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Or use the age
function
year(age(now() ,"yourdatefield"))
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
Mar 29 at 18:25
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From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Or use the age
function
year(age(now() ,"yourdatefield"))
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
Mar 29 at 18:25
add a comment |
Or use the age
function
year(age(now() ,"yourdatefield"))
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
Mar 29 at 18:25
add a comment |
Or use the age
function
year(age(now() ,"yourdatefield"))
Or use the age
function
year(age(now() ,"yourdatefield"))
answered Mar 29 at 18:21
cskcsk
9,5751035
9,5751035
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
Mar 29 at 18:25
add a comment |
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
Mar 29 at 18:25
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
Mar 29 at 18:25
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
Mar 29 at 18:25
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
answered Mar 29 at 18:19
Gabriel C.Gabriel C.
1,342320
1,342320
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add a comment |
TraineeGIS is a new contributor. Be nice, and check out our Code of Conduct.
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