Grep remove line with 0 but not 0.2?












1















I have a file similar to this:



0

0

0.02

0

0

0

0


I want to remove all the lines with a single zero.



I was thinking to use something like:



grep -v "0"


But this also removes the instances of 0.2.



I also saw there is a whole word option -w but this doesn't seem to work either.



How can I remove all lines which are just a single 0 but keep lines which may contain a 0?






grep







share|improve this question



























    1















    I have a file similar to this:



    0
    
0
    
0.02
    
0
    
0
    
0
    
0


    I want to remove all the lines with a single zero.



    I was thinking to use something like:



    grep -v "0"


    But this also removes the instances of 0.2.



    I also saw there is a whole word option -w but this doesn't seem to work either.



    How can I remove all lines which are just a single 0 but keep lines which may contain a 0?






    grep







    share|improve this question

























      1












      1








      1








      I have a file similar to this:



      0
      
0
      
0.02
      
0
      
0
      
0
      
0


      I want to remove all the lines with a single zero.



      I was thinking to use something like:



      grep -v "0"


      But this also removes the instances of 0.2.



      I also saw there is a whole word option -w but this doesn't seem to work either.



      How can I remove all lines which are just a single 0 but keep lines which may contain a 0?






      grep







      share|improve this question














      I have a file similar to this:



      0
      
0
      
0.02
      
0
      
0
      
0
      
0


      I want to remove all the lines with a single zero.



      I was thinking to use something like:



      grep -v "0"


      But this also removes the instances of 0.2.



      I also saw there is a whole word option -w but this doesn't seem to work either.



      How can I remove all lines which are just a single 0 but keep lines which may contain a 0?






      grep




      grep






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 35 mins ago









      Philip KirkbridePhilip Kirkbride

      2,47313084




      2,47313084






















          5 Answers
          5






          active

          oldest

          votes


















          3














          grep -vx 0


          From man grep:



          -x, --line-regexp
          
       Select only those matches that exactly match the whole line.
          
       For a regular expression pattern, this is like parenthesizing
          
       the pattern and then surrounding it with ^ and $.


          -w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".






          share|improve this answer































            2














            With grep:



            grep -v "^0$" file


            ^ means beginning of the line, $ means end of the line.






            share|improve this answer































              0















              • b - word border


              grep -v "b0b"




              • match beginning of line, your pattern and end of line


              grep -v "^0$"




              • or as @Sparhawk suggested -vx lineregexp


              -w works, but in your case 0.2 are two words because dot character is a word separator.






              share|improve this answer
























              • grep -v "b0b" doesn't really work here. What version of grep do you use?

                – Arkadiusz Drabczyk
                20 mins ago



















              0














              grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.



              Using sed is a bit easy in this context to just remove the whole words that match 



              sed '/^0$/d' file





              share|improve this answer































                0














                When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:



                grep "^0$"


                This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.



                I hope this helps!






                share|improve this answer

























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                  5 Answers
                  5






                  active

                  oldest

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                  5 Answers
                  5






                  active

                  oldest

                  votes









                  active

                  oldest

                  votes






                  active

                  oldest

                  votes









                  3














                  grep -vx 0


                  From man grep:



                  -x, --line-regexp
                  
       Select only those matches that exactly match the whole line.
                  
       For a regular expression pattern, this is like parenthesizing
                  
       the pattern and then surrounding it with ^ and $.


                  -w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".






                  share|improve this answer




























                    3














                    grep -vx 0


                    From man grep:



                    -x, --line-regexp
                    
       Select only those matches that exactly match the whole line.
                    
       For a regular expression pattern, this is like parenthesizing
                    
       the pattern and then surrounding it with ^ and $.


                    -w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".






                    share|improve this answer


























                      3












                      3








                      3







                      grep -vx 0


                      From man grep:



                      -x, --line-regexp
                      
       Select only those matches that exactly match the whole line.
                      
       For a regular expression pattern, this is like parenthesizing
                      
       the pattern and then surrounding it with ^ and $.


                      -w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".






                      share|improve this answer













                      grep -vx 0


                      From man grep:



                      -x, --line-regexp
                      
       Select only those matches that exactly match the whole line.
                      
       For a regular expression pattern, this is like parenthesizing
                      
       the pattern and then surrounding it with ^ and $.


                      -w fails because the first 0 in 0.02 is considered a "word", and hence this line is matched. This is because it is followed by a "non-word" character. You can see this if you run the original command without -v, i.e. grep -w "0".







                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered 26 mins ago









                      SparhawkSparhawk

                      9,74264094




                      9,74264094

























                          2














                          With grep:



                          grep -v "^0$" file


                          ^ means beginning of the line, $ means end of the line.






                          share|improve this answer




























                            2














                            With grep:



                            grep -v "^0$" file


                            ^ means beginning of the line, $ means end of the line.






                            share|improve this answer


























                              2












                              2








                              2







                              With grep:



                              grep -v "^0$" file


                              ^ means beginning of the line, $ means end of the line.






                              share|improve this answer













                              With grep:



                              grep -v "^0$" file


                              ^ means beginning of the line, $ means end of the line.







                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered 25 mins ago









                              Arkadiusz DrabczykArkadiusz Drabczyk

                              7,95521734




                              7,95521734























                                  0















                                  • b - word border


                                  grep -v "b0b"




                                  • match beginning of line, your pattern and end of line


                                  grep -v "^0$"




                                  • or as @Sparhawk suggested -vx lineregexp


                                  -w works, but in your case 0.2 are two words because dot character is a word separator.






                                  share|improve this answer
























                                  • grep -v "b0b" doesn't really work here. What version of grep do you use?

                                    – Arkadiusz Drabczyk
                                    20 mins ago
















                                  0















                                  • b - word border


                                  grep -v "b0b"




                                  • match beginning of line, your pattern and end of line


                                  grep -v "^0$"




                                  • or as @Sparhawk suggested -vx lineregexp


                                  -w works, but in your case 0.2 are two words because dot character is a word separator.






                                  share|improve this answer
























                                  • grep -v "b0b" doesn't really work here. What version of grep do you use?

                                    – Arkadiusz Drabczyk
                                    20 mins ago














                                  0












                                  0








                                  0








                                  • b - word border


                                  grep -v "b0b"




                                  • match beginning of line, your pattern and end of line


                                  grep -v "^0$"




                                  • or as @Sparhawk suggested -vx lineregexp


                                  -w works, but in your case 0.2 are two words because dot character is a word separator.






                                  share|improve this answer














                                  • b - word border


                                  grep -v "b0b"




                                  • match beginning of line, your pattern and end of line


                                  grep -v "^0$"




                                  • or as @Sparhawk suggested -vx lineregexp


                                  -w works, but in your case 0.2 are two words because dot character is a word separator.







                                  share|improve this answer












                                  share|improve this answer



                                  share|improve this answer










                                  answered 22 mins ago









                                  Jakub JindraJakub Jindra

                                  817




                                  817













                                  • grep -v "b0b" doesn't really work here. What version of grep do you use?

                                    – Arkadiusz Drabczyk
                                    20 mins ago



















                                  • grep -v "b0b" doesn't really work here. What version of grep do you use?

                                    – Arkadiusz Drabczyk
                                    20 mins ago

















                                  grep -v "b0b" doesn't really work here. What version of grep do you use?

                                  – Arkadiusz Drabczyk
                                  20 mins ago





                                  grep -v "b0b" doesn't really work here. What version of grep do you use?

                                  – Arkadiusz Drabczyk
                                  20 mins ago











                                  0














                                  grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.



                                  Using sed is a bit easy in this context to just remove the whole words that match 



                                  sed '/^0$/d' file





                                  share|improve this answer




























                                    0














                                    grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.



                                    Using sed is a bit easy in this context to just remove the whole words that match 



                                    sed '/^0$/d' file





                                    share|improve this answer


























                                      0












                                      0








                                      0







                                      grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.



                                      Using sed is a bit easy in this context to just remove the whole words that match 



                                      sed '/^0$/d' file





                                      share|improve this answer













                                      grep's -w is a bit convoluted in a way that it splits up the original string into word and non-word constituents (anything except letters, digits or underscore) . Since it has already encountered a a valid word constituent 0 in 0.02 it had asserted the negation logic to remove the line.



                                      Using sed is a bit easy in this context to just remove the whole words that match 



                                      sed '/^0$/d' file






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered 11 mins ago









                                      InianInian

                                      4,4851025




                                      4,4851025























                                          0














                                          When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:



                                          grep "^0$"


                                          This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.



                                          I hope this helps!






                                          share|improve this answer






























                                            0














                                            When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:



                                            grep "^0$"


                                            This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.



                                            I hope this helps!






                                            share|improve this answer




























                                              0












                                              0








                                              0







                                              When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:



                                              grep "^0$"


                                              This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.



                                              I hope this helps!






                                              share|improve this answer















                                              When the lines you want to delete only contain a 0 followed by the next line you can select those lines by issuing the following command:



                                              grep "^0$"


                                              This will only print the occurrences of 0 that are at the end of a line and at the beginning of a line at the same time.



                                              I hope this helps!







                                              share|improve this answer














                                              share|improve this answer



                                              share|improve this answer








                                              edited 5 mins ago

























                                              answered 11 mins ago









                                              majesticLSDmajesticLSD

                                              423




                                              423






























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