Using only 1s, make 29 with the minimum number of digits
$begingroup$
Operations permitted:
- Standard operations: +, −, ×, ÷
- Negation: −
- Exponentiation of two numbers: x^y
- Square root of a number: √
- Factorial: !
- Concatenation of the original digits: dd
mathematics calculation-puzzle formation-of-numbers
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add a comment |
$begingroup$
Operations permitted:
- Standard operations: +, −, ×, ÷
- Negation: −
- Exponentiation of two numbers: x^y
- Square root of a number: √
- Factorial: !
- Concatenation of the original digits: dd
mathematics calculation-puzzle formation-of-numbers
New contributor
$endgroup$
add a comment |
$begingroup$
Operations permitted:
- Standard operations: +, −, ×, ÷
- Negation: −
- Exponentiation of two numbers: x^y
- Square root of a number: √
- Factorial: !
- Concatenation of the original digits: dd
mathematics calculation-puzzle formation-of-numbers
New contributor
$endgroup$
Operations permitted:
- Standard operations: +, −, ×, ÷
- Negation: −
- Exponentiation of two numbers: x^y
- Square root of a number: √
- Factorial: !
- Concatenation of the original digits: dd
mathematics calculation-puzzle formation-of-numbers
mathematics calculation-puzzle formation-of-numbers
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New contributor
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asked 1 hour ago
Allan CaoAllan Cao
1063
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2 Answers
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$begingroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
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$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
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– Allan Cao
30 mins ago
$begingroup$
Do you mean that allowing concatenations should reduce it from 7 to 6? Or are the constraints the same in the paper you cite as in the question above?
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– Dr Xorile
27 mins ago
$begingroup$
The paper uses different rules.
$endgroup$
– Allan Cao
17 mins ago
add a comment |
$begingroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
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add a comment |
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2 Answers
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2 Answers
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active
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active
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votes
$begingroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
$endgroup$
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
30 mins ago
$begingroup$
Do you mean that allowing concatenations should reduce it from 7 to 6? Or are the constraints the same in the paper you cite as in the question above?
$endgroup$
– Dr Xorile
27 mins ago
$begingroup$
The paper uses different rules.
$endgroup$
– Allan Cao
17 mins ago
add a comment |
$begingroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
$endgroup$
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
30 mins ago
$begingroup$
Do you mean that allowing concatenations should reduce it from 7 to 6? Or are the constraints the same in the paper you cite as in the question above?
$endgroup$
– Dr Xorile
27 mins ago
$begingroup$
The paper uses different rules.
$endgroup$
– Allan Cao
17 mins ago
add a comment |
$begingroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
$endgroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
answered 40 mins ago
Dr XorileDr Xorile
12.9k22569
12.9k22569
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
30 mins ago
$begingroup$
Do you mean that allowing concatenations should reduce it from 7 to 6? Or are the constraints the same in the paper you cite as in the question above?
$endgroup$
– Dr Xorile
27 mins ago
$begingroup$
The paper uses different rules.
$endgroup$
– Allan Cao
17 mins ago
add a comment |
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
30 mins ago
$begingroup$
Do you mean that allowing concatenations should reduce it from 7 to 6? Or are the constraints the same in the paper you cite as in the question above?
$endgroup$
– Dr Xorile
27 mins ago
$begingroup$
The paper uses different rules.
$endgroup$
– Allan Cao
17 mins ago
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
30 mins ago
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
30 mins ago
$begingroup$
Do you mean that allowing concatenations should reduce it from 7 to 6? Or are the constraints the same in the paper you cite as in the question above?
$endgroup$
– Dr Xorile
27 mins ago
$begingroup$
Do you mean that allowing concatenations should reduce it from 7 to 6? Or are the constraints the same in the paper you cite as in the question above?
$endgroup$
– Dr Xorile
27 mins ago
$begingroup$
The paper uses different rules.
$endgroup$
– Allan Cao
17 mins ago
$begingroup$
The paper uses different rules.
$endgroup$
– Allan Cao
17 mins ago
add a comment |
$begingroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
$endgroup$
add a comment |
$begingroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
$endgroup$
add a comment |
$begingroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
$endgroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
edited 42 mins ago
answered 50 mins ago
simonzacksimonzack
267110
267110
add a comment |
add a comment |
Allan Cao is a new contributor. Be nice, and check out our Code of Conduct.
Allan Cao is a new contributor. Be nice, and check out our Code of Conduct.
Allan Cao is a new contributor. Be nice, and check out our Code of Conduct.
Allan Cao is a new contributor. Be nice, and check out our Code of Conduct.
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