Filter any system log file by date or date range





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9















What I want to achieve:



I'd like to filter a system log file by date, i.e. when I do:



$ cat /var/log/syslog | grep -i "error|warn|kernel" 


it prints lines like these for the three last days let say:



(...)
Apr 3 06:17:38 computer_name kernel: [517239.805470] IPv6: ADDRCONF(NETDEV_CHANGE): wlp3s0: link becomes ready
(...)
Apr 4 19:34:21 computer_name kernel: [517242.523165] e1000e: enp0s25 NIC Link is Up 1000 Mbps Full Duplex, Flow Control: None
(...)
Apr 5 09:00:52 computer_name kernel: [517242.523217] IPv6: ADDRCONF(NETDEV_CHANGE): enp0s25: link becomes ready


How to grep (select, or filter):




  • by date?

  • by date+hour?


What I tried:



$ cat /var/log/syslog | grep -i "Apr  5" | grep -i "error|warn|kernel" 


It works as expected on the syslog file, but not on the kern.log file for example, which only returns: Binary file (standard input) matches. And when I tail this particular file I can see the same starting date format than in the syslog file.



Question:



How to achieve the same on other logs like the kern.log file?



In addition, is it possible to filter:




  • by date range?

  • by date+hour range?


Hint: if possible, with "easy-to-remember commands".










share|improve this question































    9















    What I want to achieve:



    I'd like to filter a system log file by date, i.e. when I do:



    $ cat /var/log/syslog | grep -i "error|warn|kernel" 


    it prints lines like these for the three last days let say:



    (...)
    Apr 3 06:17:38 computer_name kernel: [517239.805470] IPv6: ADDRCONF(NETDEV_CHANGE): wlp3s0: link becomes ready
    (...)
    Apr 4 19:34:21 computer_name kernel: [517242.523165] e1000e: enp0s25 NIC Link is Up 1000 Mbps Full Duplex, Flow Control: None
    (...)
    Apr 5 09:00:52 computer_name kernel: [517242.523217] IPv6: ADDRCONF(NETDEV_CHANGE): enp0s25: link becomes ready


    How to grep (select, or filter):




    • by date?

    • by date+hour?


    What I tried:



    $ cat /var/log/syslog | grep -i "Apr  5" | grep -i "error|warn|kernel" 


    It works as expected on the syslog file, but not on the kern.log file for example, which only returns: Binary file (standard input) matches. And when I tail this particular file I can see the same starting date format than in the syslog file.



    Question:



    How to achieve the same on other logs like the kern.log file?



    In addition, is it possible to filter:




    • by date range?

    • by date+hour range?


    Hint: if possible, with "easy-to-remember commands".










    share|improve this question



























      9












      9








      9


      1






      What I want to achieve:



      I'd like to filter a system log file by date, i.e. when I do:



      $ cat /var/log/syslog | grep -i "error|warn|kernel" 


      it prints lines like these for the three last days let say:



      (...)
      Apr 3 06:17:38 computer_name kernel: [517239.805470] IPv6: ADDRCONF(NETDEV_CHANGE): wlp3s0: link becomes ready
      (...)
      Apr 4 19:34:21 computer_name kernel: [517242.523165] e1000e: enp0s25 NIC Link is Up 1000 Mbps Full Duplex, Flow Control: None
      (...)
      Apr 5 09:00:52 computer_name kernel: [517242.523217] IPv6: ADDRCONF(NETDEV_CHANGE): enp0s25: link becomes ready


      How to grep (select, or filter):




      • by date?

      • by date+hour?


      What I tried:



      $ cat /var/log/syslog | grep -i "Apr  5" | grep -i "error|warn|kernel" 


      It works as expected on the syslog file, but not on the kern.log file for example, which only returns: Binary file (standard input) matches. And when I tail this particular file I can see the same starting date format than in the syslog file.



      Question:



      How to achieve the same on other logs like the kern.log file?



      In addition, is it possible to filter:




      • by date range?

      • by date+hour range?


      Hint: if possible, with "easy-to-remember commands".










      share|improve this question
















      What I want to achieve:



      I'd like to filter a system log file by date, i.e. when I do:



      $ cat /var/log/syslog | grep -i "error|warn|kernel" 


      it prints lines like these for the three last days let say:



      (...)
      Apr 3 06:17:38 computer_name kernel: [517239.805470] IPv6: ADDRCONF(NETDEV_CHANGE): wlp3s0: link becomes ready
      (...)
      Apr 4 19:34:21 computer_name kernel: [517242.523165] e1000e: enp0s25 NIC Link is Up 1000 Mbps Full Duplex, Flow Control: None
      (...)
      Apr 5 09:00:52 computer_name kernel: [517242.523217] IPv6: ADDRCONF(NETDEV_CHANGE): enp0s25: link becomes ready


      How to grep (select, or filter):




      • by date?

      • by date+hour?


      What I tried:



      $ cat /var/log/syslog | grep -i "Apr  5" | grep -i "error|warn|kernel" 


      It works as expected on the syslog file, but not on the kern.log file for example, which only returns: Binary file (standard input) matches. And when I tail this particular file I can see the same starting date format than in the syslog file.



      Question:



      How to achieve the same on other logs like the kern.log file?



      In addition, is it possible to filter:




      • by date range?

      • by date+hour range?


      Hint: if possible, with "easy-to-remember commands".







      command-line log systemd-journald






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited yesterday









      Community

      1




      1










      asked 2 days ago









      s.ks.k

      218212




      218212






















          2 Answers
          2






          active

          oldest

          votes


















          12














          With systemd we got journalctl which easily allows fine grained filtering like this:



          sudo journalctl --since "2 days ago"   
          sudo journalctl --since "2019-03-10" --until "2019-03-11 03:00"
          sudo journalctl -b # last boot
          sudo journalctl -k # kernel messages
          sudo journalctl -p er # by priority (emerg|alert|crit|err|warning|info|debug)
          sudo journalctl -u sshd # by unit
          sudo journalctl _UID=1000 # by user id



          Examples can be combined together!






          share|improve this answer





















          • 3





            Ok now this is so cool!

            – George Udosen
            2 days ago






          • 1





            Often not even sudo is required (in particular if the user is member of the adm group, which the "main" user usually is).

            – PerlDuck
            2 days ago





















          4














          In general, the kern.log is a text file. But sometimes it happens that it contains some binary data, especially when the system has crashed before and the system could not close the file properly. You may then notice lines containing text like ^@^@^@^@^@^@^@^@^@ and such.



          If grep notices its input is binary, it usually stops further processing and prints ... binary file ... instead. But there's a switch to change this behaviour. From the manpage:




          [...]
          File and Directory Selection
          -a, --text
          Process a binary file as if it were text;
          this is equivalent to the --binary-files=text option.
          [...]



          You can try the following:



          $ grep -a -i "Apr  5" /var/log/kern.log  | grep -i "error|warn|kernel"


          (But I would actually prefer the journalctl solution given in another answer.)






          share|improve this answer
























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            12














            With systemd we got journalctl which easily allows fine grained filtering like this:



            sudo journalctl --since "2 days ago"   
            sudo journalctl --since "2019-03-10" --until "2019-03-11 03:00"
            sudo journalctl -b # last boot
            sudo journalctl -k # kernel messages
            sudo journalctl -p er # by priority (emerg|alert|crit|err|warning|info|debug)
            sudo journalctl -u sshd # by unit
            sudo journalctl _UID=1000 # by user id



            Examples can be combined together!






            share|improve this answer





















            • 3





              Ok now this is so cool!

              – George Udosen
              2 days ago






            • 1





              Often not even sudo is required (in particular if the user is member of the adm group, which the "main" user usually is).

              – PerlDuck
              2 days ago


















            12














            With systemd we got journalctl which easily allows fine grained filtering like this:



            sudo journalctl --since "2 days ago"   
            sudo journalctl --since "2019-03-10" --until "2019-03-11 03:00"
            sudo journalctl -b # last boot
            sudo journalctl -k # kernel messages
            sudo journalctl -p er # by priority (emerg|alert|crit|err|warning|info|debug)
            sudo journalctl -u sshd # by unit
            sudo journalctl _UID=1000 # by user id



            Examples can be combined together!






            share|improve this answer





















            • 3





              Ok now this is so cool!

              – George Udosen
              2 days ago






            • 1





              Often not even sudo is required (in particular if the user is member of the adm group, which the "main" user usually is).

              – PerlDuck
              2 days ago
















            12












            12








            12







            With systemd we got journalctl which easily allows fine grained filtering like this:



            sudo journalctl --since "2 days ago"   
            sudo journalctl --since "2019-03-10" --until "2019-03-11 03:00"
            sudo journalctl -b # last boot
            sudo journalctl -k # kernel messages
            sudo journalctl -p er # by priority (emerg|alert|crit|err|warning|info|debug)
            sudo journalctl -u sshd # by unit
            sudo journalctl _UID=1000 # by user id



            Examples can be combined together!






            share|improve this answer















            With systemd we got journalctl which easily allows fine grained filtering like this:



            sudo journalctl --since "2 days ago"   
            sudo journalctl --since "2019-03-10" --until "2019-03-11 03:00"
            sudo journalctl -b # last boot
            sudo journalctl -k # kernel messages
            sudo journalctl -p er # by priority (emerg|alert|crit|err|warning|info|debug)
            sudo journalctl -u sshd # by unit
            sudo journalctl _UID=1000 # by user id



            Examples can be combined together!







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 2 days ago

























            answered 2 days ago









            tomodachitomodachi

            9,61742243




            9,61742243








            • 3





              Ok now this is so cool!

              – George Udosen
              2 days ago






            • 1





              Often not even sudo is required (in particular if the user is member of the adm group, which the "main" user usually is).

              – PerlDuck
              2 days ago
















            • 3





              Ok now this is so cool!

              – George Udosen
              2 days ago






            • 1





              Often not even sudo is required (in particular if the user is member of the adm group, which the "main" user usually is).

              – PerlDuck
              2 days ago










            3




            3





            Ok now this is so cool!

            – George Udosen
            2 days ago





            Ok now this is so cool!

            – George Udosen
            2 days ago




            1




            1





            Often not even sudo is required (in particular if the user is member of the adm group, which the "main" user usually is).

            – PerlDuck
            2 days ago







            Often not even sudo is required (in particular if the user is member of the adm group, which the "main" user usually is).

            – PerlDuck
            2 days ago















            4














            In general, the kern.log is a text file. But sometimes it happens that it contains some binary data, especially when the system has crashed before and the system could not close the file properly. You may then notice lines containing text like ^@^@^@^@^@^@^@^@^@ and such.



            If grep notices its input is binary, it usually stops further processing and prints ... binary file ... instead. But there's a switch to change this behaviour. From the manpage:




            [...]
            File and Directory Selection
            -a, --text
            Process a binary file as if it were text;
            this is equivalent to the --binary-files=text option.
            [...]



            You can try the following:



            $ grep -a -i "Apr  5" /var/log/kern.log  | grep -i "error|warn|kernel"


            (But I would actually prefer the journalctl solution given in another answer.)






            share|improve this answer




























              4














              In general, the kern.log is a text file. But sometimes it happens that it contains some binary data, especially when the system has crashed before and the system could not close the file properly. You may then notice lines containing text like ^@^@^@^@^@^@^@^@^@ and such.



              If grep notices its input is binary, it usually stops further processing and prints ... binary file ... instead. But there's a switch to change this behaviour. From the manpage:




              [...]
              File and Directory Selection
              -a, --text
              Process a binary file as if it were text;
              this is equivalent to the --binary-files=text option.
              [...]



              You can try the following:



              $ grep -a -i "Apr  5" /var/log/kern.log  | grep -i "error|warn|kernel"


              (But I would actually prefer the journalctl solution given in another answer.)






              share|improve this answer


























                4












                4








                4







                In general, the kern.log is a text file. But sometimes it happens that it contains some binary data, especially when the system has crashed before and the system could not close the file properly. You may then notice lines containing text like ^@^@^@^@^@^@^@^@^@ and such.



                If grep notices its input is binary, it usually stops further processing and prints ... binary file ... instead. But there's a switch to change this behaviour. From the manpage:




                [...]
                File and Directory Selection
                -a, --text
                Process a binary file as if it were text;
                this is equivalent to the --binary-files=text option.
                [...]



                You can try the following:



                $ grep -a -i "Apr  5" /var/log/kern.log  | grep -i "error|warn|kernel"


                (But I would actually prefer the journalctl solution given in another answer.)






                share|improve this answer













                In general, the kern.log is a text file. But sometimes it happens that it contains some binary data, especially when the system has crashed before and the system could not close the file properly. You may then notice lines containing text like ^@^@^@^@^@^@^@^@^@ and such.



                If grep notices its input is binary, it usually stops further processing and prints ... binary file ... instead. But there's a switch to change this behaviour. From the manpage:




                [...]
                File and Directory Selection
                -a, --text
                Process a binary file as if it were text;
                this is equivalent to the --binary-files=text option.
                [...]



                You can try the following:



                $ grep -a -i "Apr  5" /var/log/kern.log  | grep -i "error|warn|kernel"


                (But I would actually prefer the journalctl solution given in another answer.)







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 2 days ago









                PerlDuckPerlDuck

                8,00611636




                8,00611636






























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