How can an equation having ColorDistance function be solved?
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I wish to extract the colors on the L axis in the CIELab color space such that the CIE2000 distance between a corresponding color and LABColor[0., 0., 0.] will be gradually increasing by a factor 0.01. For example, {LABColor[0, 0, 0], LABColor[0.01733965, 0, 0], LABColor[0.0344219, 0, 0], LABColor[0.0512525, 0, 0], LABColor[0.0678371, 0, 0], LABColor[0.0841806, 0, 0], LABColor[0.100288, 0, 0]} are the first few colors in this series. I have got these values by manually checking. However, to automate this, when I tried the following (to get the second element in the series)
Solve[ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0],
DistanceFunction -> "CIE2000"] == 0.01, l]
I got an error message.
How can I automate this process to complete the series.
list-manipulation equation-solving color
asked 2 days ago
MajisMajis
1,477415
$endgroup$
add a comment |
$begingroup$
I wish to extract the colors on the L axis in the CIELab color space such that the CIE2000 distance between a corresponding color and LABColor[0., 0., 0.] will be gradually increasing by a factor 0.01. For example, {LABColor[0, 0, 0], LABColor[0.01733965, 0, 0], LABColor[0.0344219, 0, 0], LABColor[0.0512525, 0, 0], LABColor[0.0678371, 0, 0], LABColor[0.0841806, 0, 0], LABColor[0.100288, 0, 0]} are the first few colors in this series. I have got these values by manually checking. However, to automate this, when I tried the following (to get the second element in the series)
Solve[ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0],
DistanceFunction -> "CIE2000"] == 0.01, l]
I got an error message.
How can I automate this process to complete the series.
list-manipulation equation-solving color
asked 2 days ago
MajisMajis
1,477415
$endgroup$
add a comment |
$begingroup$
I wish to extract the colors on the L axis in the CIELab color space such that the CIE2000 distance between a corresponding color and LABColor[0., 0., 0.] will be gradually increasing by a factor 0.01. For example, {LABColor[0, 0, 0], LABColor[0.01733965, 0, 0], LABColor[0.0344219, 0, 0], LABColor[0.0512525, 0, 0], LABColor[0.0678371, 0, 0], LABColor[0.0841806, 0, 0], LABColor[0.100288, 0, 0]} are the first few colors in this series. I have got these values by manually checking. However, to automate this, when I tried the following (to get the second element in the series)
Solve[ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0],
DistanceFunction -> "CIE2000"] == 0.01, l]
I got an error message.
How can I automate this process to complete the series.
list-manipulation equation-solving color
asked 2 days ago
MajisMajis
1,477415
$endgroup$
I wish to extract the colors on the L axis in the CIELab color space such that the CIE2000 distance between a corresponding color and LABColor[0., 0., 0.] will be gradually increasing by a factor 0.01. For example, {LABColor[0, 0, 0], LABColor[0.01733965, 0, 0], LABColor[0.0344219, 0, 0], LABColor[0.0512525, 0, 0], LABColor[0.0678371, 0, 0], LABColor[0.0841806, 0, 0], LABColor[0.100288, 0, 0]} are the first few colors in this series. I have got these values by manually checking. However, to automate this, when I tried the following (to get the second element in the series)
Solve[ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0],
DistanceFunction -> "CIE2000"] == 0.01, l]
I got an error message.
How can I automate this process to complete the series.
list-manipulation equation-solving color
list-manipulation equation-solving color
asked 2 days ago
MajisMajis
1,477415
asked 2 days ago
MajisMajis
1,477415
asked 2 days ago
MajisMajis
1,477415
asked 2 days ago
MajisMajis
1,477415
asked 2 days ago
MajisMajis
1,477415
1,477415
add a comment |
add a comment |
1 Answer
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$begingroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 2 days ago
SzabolcsSzabolcs
163k14448945
$endgroup$
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
2 days ago
add a comment |
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1 Answer
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1 Answer
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$begingroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 2 days ago
SzabolcsSzabolcs
163k14448945
$endgroup$
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
2 days ago
add a comment |
$begingroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 2 days ago
SzabolcsSzabolcs
163k14448945
$endgroup$
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
2 days ago
add a comment |
$begingroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 2 days ago
SzabolcsSzabolcs
163k14448945
$endgroup$
f[l_?NumericQ] :=
ColorDistance[LABColor[0, 0, 0], LABColor[l, 0, 0], DistanceFunction -> "CIE2000"]
FindRoot[f[l] == 0.01, {l, .5}]
(* {l -> 0.0173396} *)
ColorDistance does not work with symbolic inputs. Write a function that evaluates with numeric inputs only.
Solve is meant for exact symbolic computations. Use FindRoot instead.
answered 2 days ago
SzabolcsSzabolcs
163k14448945
answered 2 days ago
SzabolcsSzabolcs
163k14448945
answered 2 days ago
SzabolcsSzabolcs
163k14448945
answered 2 days ago
SzabolcsSzabolcs
163k14448945
163k14448945
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
2 days ago
add a comment |
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
2 days ago
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
2 days ago
$begingroup$
Perfect. Now I can get the complete list. Thanks.
$endgroup$
– Majis
2 days ago
add a comment |
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