Why is the BSI not using powers of two?












6












$begingroup$


In their Technical Guideline TR-02102-2 Cryptographic Mechanisms: Recommendations and Key Lengths the BSI is giving minimal key lengths for - e.g. the TLS handshake protocol. All of these are not integers that are a power of two. I always thought, that it was the norm to give key lengths as powers of two. Is it not?



Recommended minimum key lenghts for the TLS handshake protoco










share|improve this question











$endgroup$

















    6












    $begingroup$


    In their Technical Guideline TR-02102-2 Cryptographic Mechanisms: Recommendations and Key Lengths the BSI is giving minimal key lengths for - e.g. the TLS handshake protocol. All of these are not integers that are a power of two. I always thought, that it was the norm to give key lengths as powers of two. Is it not?



    Recommended minimum key lenghts for the TLS handshake protoco










    share|improve this question











    $endgroup$















      6












      6








      6





      $begingroup$


      In their Technical Guideline TR-02102-2 Cryptographic Mechanisms: Recommendations and Key Lengths the BSI is giving minimal key lengths for - e.g. the TLS handshake protocol. All of these are not integers that are a power of two. I always thought, that it was the norm to give key lengths as powers of two. Is it not?



      Recommended minimum key lenghts for the TLS handshake protoco










      share|improve this question











      $endgroup$




      In their Technical Guideline TR-02102-2 Cryptographic Mechanisms: Recommendations and Key Lengths the BSI is giving minimal key lengths for - e.g. the TLS handshake protocol. All of these are not integers that are a power of two. I always thought, that it was the norm to give key lengths as powers of two. Is it not?



      Recommended minimum key lenghts for the TLS handshake protoco







      notation






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 17 hours ago









      AleksanderRas

      2,7671835




      2,7671835










      asked 17 hours ago









      Tom K.Tom K.

      1486




      1486






















          1 Answer
          1






          active

          oldest

          votes


















          11












          $begingroup$

          My guess is that it is stated a round decimal number (e.g. 2000) of bits in order not to disqualify solutions using keys that can be up to the next round binary number (e.g. 2048) of bits, but are occasionally slightly less.



          In particular, in RSA, when we make the product of two 1024-bit primes, the result is 2047 or 2048-bit. This scenario happens with some versions of PGP/GPG, and some SSH software. Contrast with FIPS 186-4, which wants 2048-bit moduli to be exactly 2048-bit, and towards that goal generates 1024-bit primes at least $2^{1023.5}$. TR-02102-2 is slightly more lenient, in a way that does not practically compromise security.






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            On the subject of "occasionally slightly less," cf. the recent silliness around "64-bit" certificate serial numbers that were really 63 bits. That was an example of a standard specifying an exact power of two, and then when software inevitably went off-by-one (in this case, to preserve the sign bit of a 64-bit integer), it counted as noncompliance-with-the-standard and provoked extreme reactions. If the standard had said "serial numbers must have at least 60 bits," or "100 bits," there'd have been no problem.
            $endgroup$
            – Quuxplusone
            7 hours ago











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "281"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcrypto.stackexchange.com%2fquestions%2f68034%2fwhy-is-the-bsi-not-using-powers-of-two%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          11












          $begingroup$

          My guess is that it is stated a round decimal number (e.g. 2000) of bits in order not to disqualify solutions using keys that can be up to the next round binary number (e.g. 2048) of bits, but are occasionally slightly less.



          In particular, in RSA, when we make the product of two 1024-bit primes, the result is 2047 or 2048-bit. This scenario happens with some versions of PGP/GPG, and some SSH software. Contrast with FIPS 186-4, which wants 2048-bit moduli to be exactly 2048-bit, and towards that goal generates 1024-bit primes at least $2^{1023.5}$. TR-02102-2 is slightly more lenient, in a way that does not practically compromise security.






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            On the subject of "occasionally slightly less," cf. the recent silliness around "64-bit" certificate serial numbers that were really 63 bits. That was an example of a standard specifying an exact power of two, and then when software inevitably went off-by-one (in this case, to preserve the sign bit of a 64-bit integer), it counted as noncompliance-with-the-standard and provoked extreme reactions. If the standard had said "serial numbers must have at least 60 bits," or "100 bits," there'd have been no problem.
            $endgroup$
            – Quuxplusone
            7 hours ago
















          11












          $begingroup$

          My guess is that it is stated a round decimal number (e.g. 2000) of bits in order not to disqualify solutions using keys that can be up to the next round binary number (e.g. 2048) of bits, but are occasionally slightly less.



          In particular, in RSA, when we make the product of two 1024-bit primes, the result is 2047 or 2048-bit. This scenario happens with some versions of PGP/GPG, and some SSH software. Contrast with FIPS 186-4, which wants 2048-bit moduli to be exactly 2048-bit, and towards that goal generates 1024-bit primes at least $2^{1023.5}$. TR-02102-2 is slightly more lenient, in a way that does not practically compromise security.






          share|improve this answer











          $endgroup$









          • 1




            $begingroup$
            On the subject of "occasionally slightly less," cf. the recent silliness around "64-bit" certificate serial numbers that were really 63 bits. That was an example of a standard specifying an exact power of two, and then when software inevitably went off-by-one (in this case, to preserve the sign bit of a 64-bit integer), it counted as noncompliance-with-the-standard and provoked extreme reactions. If the standard had said "serial numbers must have at least 60 bits," or "100 bits," there'd have been no problem.
            $endgroup$
            – Quuxplusone
            7 hours ago














          11












          11








          11





          $begingroup$

          My guess is that it is stated a round decimal number (e.g. 2000) of bits in order not to disqualify solutions using keys that can be up to the next round binary number (e.g. 2048) of bits, but are occasionally slightly less.



          In particular, in RSA, when we make the product of two 1024-bit primes, the result is 2047 or 2048-bit. This scenario happens with some versions of PGP/GPG, and some SSH software. Contrast with FIPS 186-4, which wants 2048-bit moduli to be exactly 2048-bit, and towards that goal generates 1024-bit primes at least $2^{1023.5}$. TR-02102-2 is slightly more lenient, in a way that does not practically compromise security.






          share|improve this answer











          $endgroup$



          My guess is that it is stated a round decimal number (e.g. 2000) of bits in order not to disqualify solutions using keys that can be up to the next round binary number (e.g. 2048) of bits, but are occasionally slightly less.



          In particular, in RSA, when we make the product of two 1024-bit primes, the result is 2047 or 2048-bit. This scenario happens with some versions of PGP/GPG, and some SSH software. Contrast with FIPS 186-4, which wants 2048-bit moduli to be exactly 2048-bit, and towards that goal generates 1024-bit primes at least $2^{1023.5}$. TR-02102-2 is slightly more lenient, in a way that does not practically compromise security.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 9 hours ago

























          answered 15 hours ago









          fgrieufgrieu

          81.6k7175347




          81.6k7175347








          • 1




            $begingroup$
            On the subject of "occasionally slightly less," cf. the recent silliness around "64-bit" certificate serial numbers that were really 63 bits. That was an example of a standard specifying an exact power of two, and then when software inevitably went off-by-one (in this case, to preserve the sign bit of a 64-bit integer), it counted as noncompliance-with-the-standard and provoked extreme reactions. If the standard had said "serial numbers must have at least 60 bits," or "100 bits," there'd have been no problem.
            $endgroup$
            – Quuxplusone
            7 hours ago














          • 1




            $begingroup$
            On the subject of "occasionally slightly less," cf. the recent silliness around "64-bit" certificate serial numbers that were really 63 bits. That was an example of a standard specifying an exact power of two, and then when software inevitably went off-by-one (in this case, to preserve the sign bit of a 64-bit integer), it counted as noncompliance-with-the-standard and provoked extreme reactions. If the standard had said "serial numbers must have at least 60 bits," or "100 bits," there'd have been no problem.
            $endgroup$
            – Quuxplusone
            7 hours ago








          1




          1




          $begingroup$
          On the subject of "occasionally slightly less," cf. the recent silliness around "64-bit" certificate serial numbers that were really 63 bits. That was an example of a standard specifying an exact power of two, and then when software inevitably went off-by-one (in this case, to preserve the sign bit of a 64-bit integer), it counted as noncompliance-with-the-standard and provoked extreme reactions. If the standard had said "serial numbers must have at least 60 bits," or "100 bits," there'd have been no problem.
          $endgroup$
          – Quuxplusone
          7 hours ago




          $begingroup$
          On the subject of "occasionally slightly less," cf. the recent silliness around "64-bit" certificate serial numbers that were really 63 bits. That was an example of a standard specifying an exact power of two, and then when software inevitably went off-by-one (in this case, to preserve the sign bit of a 64-bit integer), it counted as noncompliance-with-the-standard and provoked extreme reactions. If the standard had said "serial numbers must have at least 60 bits," or "100 bits," there'd have been no problem.
          $endgroup$
          – Quuxplusone
          7 hours ago


















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Cryptography Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcrypto.stackexchange.com%2fquestions%2f68034%2fwhy-is-the-bsi-not-using-powers-of-two%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          How did Captain America manage to do this?

          迪纳利

          南乌拉尔铁路局