How to draw the diamond structure using `chains`?












2















I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
2nd-iso-wiki



The code and the resulting figure is shown as follows.



How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



2nd-iso



documentclass[tikz]{standalone}
usetikzlibrary{chains, scopes}

begin{document}
begin{tikzpicture}[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
{
[start chain = G going below] % G chain
node (g) [on chain] {$G$};
node (hn) [on chain, below = 0.50cm of g] {$HN$};
{ [start branch = H going below left] % H branch
node (h) [on chain] {$H$};
}
{ [start branch = N going below right] % N branch
node [on chain] {$N$};
}
node [on chain] {}; % dummy node % continue G chain
node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] {$H cap N$};
node (e) [on chain, below = 0.50cm of hcapn] {${ e }$};
}
end{tikzpicture}
end{document}









share|improve this question



























    2















    I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
    2nd-iso-wiki



    The code and the resulting figure is shown as follows.



    How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



    2nd-iso



    documentclass[tikz]{standalone}
    usetikzlibrary{chains, scopes}

    begin{document}
    begin{tikzpicture}[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
    {
    [start chain = G going below] % G chain
    node (g) [on chain] {$G$};
    node (hn) [on chain, below = 0.50cm of g] {$HN$};
    { [start branch = H going below left] % H branch
    node (h) [on chain] {$H$};
    }
    { [start branch = N going below right] % N branch
    node [on chain] {$N$};
    }
    node [on chain] {}; % dummy node % continue G chain
    node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] {$H cap N$};
    node (e) [on chain, below = 0.50cm of hcapn] {${ e }$};
    }
    end{tikzpicture}
    end{document}









    share|improve this question

























      2












      2








      2








      I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
      2nd-iso-wiki



      The code and the resulting figure is shown as follows.



      How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



      2nd-iso



      documentclass[tikz]{standalone}
      usetikzlibrary{chains, scopes}

      begin{document}
      begin{tikzpicture}[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
      {
      [start chain = G going below] % G chain
      node (g) [on chain] {$G$};
      node (hn) [on chain, below = 0.50cm of g] {$HN$};
      { [start branch = H going below left] % H branch
      node (h) [on chain] {$H$};
      }
      { [start branch = N going below right] % N branch
      node [on chain] {$N$};
      }
      node [on chain] {}; % dummy node % continue G chain
      node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] {$H cap N$};
      node (e) [on chain, below = 0.50cm of hcapn] {${ e }$};
      }
      end{tikzpicture}
      end{document}









      share|improve this question














      I am using chains to re-draw the structure (shown below) in Second isomorphism theorem(wiki).
      2nd-iso-wiki



      The code and the resulting figure is shown as follows.



      How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?



      2nd-iso



      documentclass[tikz]{standalone}
      usetikzlibrary{chains, scopes}

      begin{document}
      begin{tikzpicture}[every on chain/.style = join, every join/.style = -, node distance = 0.8cm and 1.0cm]
      {
      [start chain = G going below] % G chain
      node (g) [on chain] {$G$};
      node (hn) [on chain, below = 0.50cm of g] {$HN$};
      { [start branch = H going below left] % H branch
      node (h) [on chain] {$H$};
      }
      { [start branch = N going below right] % N branch
      node [on chain] {$N$};
      }
      node [on chain] {}; % dummy node % continue G chain
      node (hcapn) [on chain, join = with G/H-end, join = with G/N-end] {$H cap N$};
      node (e) [on chain, below = 0.50cm of hcapn] {${ e }$};
      }
      end{tikzpicture}
      end{document}






      tikz-pgf tikz-chains






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 2 days ago









      hengxinhengxin

      1,0282926




      1,0282926






















          2 Answers
          2






          active

          oldest

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          3














          with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



          documentclass[tikz, margin=3mm]{standalone}
          usetikzlibrary{chains, positioning, shapes.geometric}
          makeatletter
          tikzset{suspend join/.code={deftikz@after@path{}}}
          makeatother

          begin{document}
          begin{tikzpicture}[
          node distance = 8mm and 10 mm,
          start chain = going below,
          N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
          node (g) [N] {$G$};
          node (hn) [N] {$HN$};
          node (h) [N, below left=of hn] {$H$};
          node (hcapn) [N, below=of h -| hn] {$H cap N$};
          node (e) [N] {${ e }$};
          %
          node (n) [N,suspend join,
          below right=of hn] {$N$};
          node [below=of hn] {$cong$};
          draw (hn) -- (n) (n) -- (hcapn);
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer


























          • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            2 days ago













          • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            2 days ago











          • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            2 days ago











          • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            2 days ago



















          5














          If you want to replicate the linked picture, I propose this



          documentclass[tikz]{standalone}
          usetikzlibrary{shapes,fit}
          usepackage{mathptmx}
          begin{document}
          begin{tikzpicture}[x=1.75cm,y=1.75cm]
          begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
          node (g) at (0,2) {$G$};
          node (sn) at (0,1) {$SN$};
          node (n) at (-1,0) {$N$};
          node (s) at (1,0) {$S$};
          node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
          node (e) at (0,-2) {${e}$};
          end{scope}
          draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
          node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
          node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
          node {$cong$};
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer
























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]{standalone}
            usetikzlibrary{chains, positioning, shapes.geometric}
            makeatletter
            tikzset{suspend join/.code={deftikz@after@path{}}}
            makeatother

            begin{document}
            begin{tikzpicture}[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
            node (g) [N] {$G$};
            node (hn) [N] {$HN$};
            node (h) [N, below left=of hn] {$H$};
            node (hcapn) [N, below=of h -| hn] {$H cap N$};
            node (e) [N] {${ e }$};
            %
            node (n) [N,suspend join,
            below right=of hn] {$N$};
            node [below=of hn] {$cong$};
            draw (hn) -- (n) (n) -- (hcapn);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              2 days ago













            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              2 days ago











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              2 days ago











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              2 days ago
















            3














            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]{standalone}
            usetikzlibrary{chains, positioning, shapes.geometric}
            makeatletter
            tikzset{suspend join/.code={deftikz@after@path{}}}
            makeatother

            begin{document}
            begin{tikzpicture}[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
            node (g) [N] {$G$};
            node (hn) [N] {$HN$};
            node (h) [N, below left=of hn] {$H$};
            node (hcapn) [N, below=of h -| hn] {$H cap N$};
            node (e) [N] {${ e }$};
            %
            node (n) [N,suspend join,
            below right=of hn] {$N$};
            node [below=of hn] {$cong$};
            draw (hn) -- (n) (n) -- (hcapn);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              2 days ago













            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              2 days ago











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              2 days ago











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              2 days ago














            3












            3








            3







            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]{standalone}
            usetikzlibrary{chains, positioning, shapes.geometric}
            makeatletter
            tikzset{suspend join/.code={deftikz@after@path{}}}
            makeatother

            begin{document}
            begin{tikzpicture}[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
            node (g) [N] {$G$};
            node (hn) [N] {$HN$};
            node (h) [N, below left=of hn] {$H$};
            node (hcapn) [N, below=of h -| hn] {$H cap N$};
            node (e) [N] {${ e }$};
            %
            node (n) [N,suspend join,
            below right=of hn] {$N$};
            node [below=of hn] {$cong$};
            draw (hn) -- (n) (n) -- (hcapn);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer















            with chain, but two nodes are excluded in join macro and for it the connection is drawn separately:



            documentclass[tikz, margin=3mm]{standalone}
            usetikzlibrary{chains, positioning, shapes.geometric}
            makeatletter
            tikzset{suspend join/.code={deftikz@after@path{}}}
            makeatother

            begin{document}
            begin{tikzpicture}[
            node distance = 8mm and 10 mm,
            start chain = going below,
            N/.style = {ellipse, draw, inner sep=2pt, on chain, join=by -}]
            node (g) [N] {$G$};
            node (hn) [N] {$HN$};
            node (h) [N, below left=of hn] {$H$};
            node (hcapn) [N, below=of h -| hn] {$H cap N$};
            node (e) [N] {${ e }$};
            %
            node (n) [N,suspend join,
            below right=of hn] {$N$};
            node [below=of hn] {$cong$};
            draw (hn) -- (n) (n) -- (hcapn);
            end{tikzpicture}
            end{document}


            enter image description here







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 2 days ago

























            answered 2 days ago









            ZarkoZarko

            129k868169




            129k868169













            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              2 days ago













            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              2 days ago











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              2 days ago











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              2 days ago



















            • Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

              – marmot
              2 days ago













            • i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

              – Zarko
              2 days ago











            • What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

              – marmot
              2 days ago











            • @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

              – Zarko
              2 days ago

















            Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            2 days ago







            Why is it that an identical definition of suspend join can be found e.g. in Heiko Oberdiek's answer?

            – marmot
            2 days ago















            i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            2 days ago





            i didn't invent this definition. i obtained it from some Ulrike Fisher answer (many) years ago. what you like to tel me with your comment?

            – Zarko
            2 days ago













            What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            2 days ago





            What I want to say is: imagine you had invented this definition, and someone else, let's say I, would use it to answer a question that reads "How to get rid of the dummy node (added for alignment) and the unnecessary join lines between it and the node hn and hcapn, respectively?". Wouldn't you like it much better if the other user, let's say I, would say "I am going to use a definition invented by Zarko..." better?

            – marmot
            2 days ago













            @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            2 days ago





            @marmot, no, i'm not sensitive to do this. and on the another hand, to give credits to all where i find some interesting solution is almost impossible. how do i should remember all answers which i read (few thousands till now) ? i store in my latex corner only some of attractive (to me) solutions, but my evidence, where i find them is very poor :-(. best regards!

            – Zarko
            2 days ago











            5














            If you want to replicate the linked picture, I propose this



            documentclass[tikz]{standalone}
            usetikzlibrary{shapes,fit}
            usepackage{mathptmx}
            begin{document}
            begin{tikzpicture}[x=1.75cm,y=1.75cm]
            begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
            node (g) at (0,2) {$G$};
            node (sn) at (0,1) {$SN$};
            node (n) at (-1,0) {$N$};
            node (s) at (1,0) {$S$};
            node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
            node (e) at (0,-2) {${e}$};
            end{scope}
            draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
            node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
            node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
            node {$cong$};
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer




























              5














              If you want to replicate the linked picture, I propose this



              documentclass[tikz]{standalone}
              usetikzlibrary{shapes,fit}
              usepackage{mathptmx}
              begin{document}
              begin{tikzpicture}[x=1.75cm,y=1.75cm]
              begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
              node (g) at (0,2) {$G$};
              node (sn) at (0,1) {$SN$};
              node (n) at (-1,0) {$N$};
              node (s) at (1,0) {$S$};
              node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
              node (e) at (0,-2) {${e}$};
              end{scope}
              draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
              node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
              node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
              node {$cong$};
              end{tikzpicture}
              end{document}


              enter image description here






              share|improve this answer


























                5












                5








                5







                If you want to replicate the linked picture, I propose this



                documentclass[tikz]{standalone}
                usetikzlibrary{shapes,fit}
                usepackage{mathptmx}
                begin{document}
                begin{tikzpicture}[x=1.75cm,y=1.75cm]
                begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
                node (g) at (0,2) {$G$};
                node (sn) at (0,1) {$SN$};
                node (n) at (-1,0) {$N$};
                node (s) at (1,0) {$S$};
                node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
                node (e) at (0,-2) {${e}$};
                end{scope}
                draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
                node {$cong$};
                end{tikzpicture}
                end{document}


                enter image description here






                share|improve this answer













                If you want to replicate the linked picture, I propose this



                documentclass[tikz]{standalone}
                usetikzlibrary{shapes,fit}
                usepackage{mathptmx}
                begin{document}
                begin{tikzpicture}[x=1.75cm,y=1.75cm]
                begin{scope}[every node/.style={draw,circle,minimum size=1cm}]
                node (g) at (0,2) {$G$};
                node (sn) at (0,1) {$SN$};
                node (n) at (-1,0) {$N$};
                node (s) at (1,0) {$S$};
                node[ellipse,draw,minimum height=1cm] (scn) at (0,-1) {$Scap N$};
                node (e) at (0,-2) {${e}$};
                end{scope}
                draw (g)--(sn)--(n)--(scn)--(e) (scn)--(s)--(sn);
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-7mm,inner ysep=-1mm,fit=(sn)(n)] {};
                node[rotate=-45,ellipse,draw,dashed,inner xsep=-9mm,inner ysep=1mm,fit=(scn)(s)] {};
                node {$cong$};
                end{tikzpicture}
                end{document}


                enter image description here







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                answered 2 days ago









                JouleVJouleV

                9,91322558




                9,91322558






























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