Write a regular expression which catches user $HOME in shellscripting





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I'd like to write a regex in shellscript which would compare the user input path to user$HOME. Then it would raise an error in case the user input path contains the user $HOME. The home folder normally starts with /ort/home but /ort part is not a must. When I run it always gives a valid path although I clearly enter an invalid path. What am I doing wrong? Thanks. Please refer following link[1] if necessary to see how regex are used in shellscript



My attempt is as follows



#!/bin/bash

function user_input () {

read -p "Type the path for project1:" user_path

string1="${HOME}"
echo "$string1"

if [ "$user_path" = "$string1 | /ort/home/+.* | .*+/home/+.*" ]; then
echo "Not a valid path, contains $HOME directory"
else
echo "valid path"
fi
}

function main() {

user_input
}

main


Terminal output



Please note first entry is a valid path and other two are invalid paths.



jenny@server32:~$ ./test.sh 
Type the path for project1:/scratch/random
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh
Type the path for project1:/ort/home/j/jen
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh
Type the path for project1:/ort/home
/ort/home/j/jen
valid path


[1]https://stackoverflow.com/questions/2237080/how-to-compare-strings-in-bash










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  • 2





    Regular expression comparison and string (glob pattern) comparison are different things, with different operators in bash (=~ versus == or =); additionally, =~ is only supported within extended test brackets [[ ... ]] afaik

    – steeldriver
    Apr 1 at 22:32


















-1















I'd like to write a regex in shellscript which would compare the user input path to user$HOME. Then it would raise an error in case the user input path contains the user $HOME. The home folder normally starts with /ort/home but /ort part is not a must. When I run it always gives a valid path although I clearly enter an invalid path. What am I doing wrong? Thanks. Please refer following link[1] if necessary to see how regex are used in shellscript



My attempt is as follows



#!/bin/bash

function user_input () {

read -p "Type the path for project1:" user_path

string1="${HOME}"
echo "$string1"

if [ "$user_path" = "$string1 | /ort/home/+.* | .*+/home/+.*" ]; then
echo "Not a valid path, contains $HOME directory"
else
echo "valid path"
fi
}

function main() {

user_input
}

main


Terminal output



Please note first entry is a valid path and other two are invalid paths.



jenny@server32:~$ ./test.sh 
Type the path for project1:/scratch/random
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh
Type the path for project1:/ort/home/j/jen
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh
Type the path for project1:/ort/home
/ort/home/j/jen
valid path


[1]https://stackoverflow.com/questions/2237080/how-to-compare-strings-in-bash










share|improve this question


















  • 2





    Regular expression comparison and string (glob pattern) comparison are different things, with different operators in bash (=~ versus == or =); additionally, =~ is only supported within extended test brackets [[ ... ]] afaik

    – steeldriver
    Apr 1 at 22:32














-1












-1








-1








I'd like to write a regex in shellscript which would compare the user input path to user$HOME. Then it would raise an error in case the user input path contains the user $HOME. The home folder normally starts with /ort/home but /ort part is not a must. When I run it always gives a valid path although I clearly enter an invalid path. What am I doing wrong? Thanks. Please refer following link[1] if necessary to see how regex are used in shellscript



My attempt is as follows



#!/bin/bash

function user_input () {

read -p "Type the path for project1:" user_path

string1="${HOME}"
echo "$string1"

if [ "$user_path" = "$string1 | /ort/home/+.* | .*+/home/+.*" ]; then
echo "Not a valid path, contains $HOME directory"
else
echo "valid path"
fi
}

function main() {

user_input
}

main


Terminal output



Please note first entry is a valid path and other two are invalid paths.



jenny@server32:~$ ./test.sh 
Type the path for project1:/scratch/random
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh
Type the path for project1:/ort/home/j/jen
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh
Type the path for project1:/ort/home
/ort/home/j/jen
valid path


[1]https://stackoverflow.com/questions/2237080/how-to-compare-strings-in-bash










share|improve this question














I'd like to write a regex in shellscript which would compare the user input path to user$HOME. Then it would raise an error in case the user input path contains the user $HOME. The home folder normally starts with /ort/home but /ort part is not a must. When I run it always gives a valid path although I clearly enter an invalid path. What am I doing wrong? Thanks. Please refer following link[1] if necessary to see how regex are used in shellscript



My attempt is as follows



#!/bin/bash

function user_input () {

read -p "Type the path for project1:" user_path

string1="${HOME}"
echo "$string1"

if [ "$user_path" = "$string1 | /ort/home/+.* | .*+/home/+.*" ]; then
echo "Not a valid path, contains $HOME directory"
else
echo "valid path"
fi
}

function main() {

user_input
}

main


Terminal output



Please note first entry is a valid path and other two are invalid paths.



jenny@server32:~$ ./test.sh 
Type the path for project1:/scratch/random
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh
Type the path for project1:/ort/home/j/jen
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh
Type the path for project1:/ort/home
/ort/home/j/jen
valid path


[1]https://stackoverflow.com/questions/2237080/how-to-compare-strings-in-bash







command-line bash scripts regex






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asked Apr 1 at 22:21









JennyJenny

1018




1018








  • 2





    Regular expression comparison and string (glob pattern) comparison are different things, with different operators in bash (=~ versus == or =); additionally, =~ is only supported within extended test brackets [[ ... ]] afaik

    – steeldriver
    Apr 1 at 22:32














  • 2





    Regular expression comparison and string (glob pattern) comparison are different things, with different operators in bash (=~ versus == or =); additionally, =~ is only supported within extended test brackets [[ ... ]] afaik

    – steeldriver
    Apr 1 at 22:32








2




2





Regular expression comparison and string (glob pattern) comparison are different things, with different operators in bash (=~ versus == or =); additionally, =~ is only supported within extended test brackets [[ ... ]] afaik

– steeldriver
Apr 1 at 22:32





Regular expression comparison and string (glob pattern) comparison are different things, with different operators in bash (=~ versus == or =); additionally, =~ is only supported within extended test brackets [[ ... ]] afaik

– steeldriver
Apr 1 at 22:32










1 Answer
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The case command uses glob wildcards which are pretty easy to work with:



case "$user_path" in
"$HOME"*) echo "Error: path cannot be in your HOME" ;;
*/home/*) echo "Error: cannot have 'home' in the path" ;;
*) echo "Thank you, valid path" ;;
esac





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    The case command uses glob wildcards which are pretty easy to work with:



    case "$user_path" in
    "$HOME"*) echo "Error: path cannot be in your HOME" ;;
    */home/*) echo "Error: cannot have 'home' in the path" ;;
    *) echo "Thank you, valid path" ;;
    esac





    share|improve this answer




























      2














      The case command uses glob wildcards which are pretty easy to work with:



      case "$user_path" in
      "$HOME"*) echo "Error: path cannot be in your HOME" ;;
      */home/*) echo "Error: cannot have 'home' in the path" ;;
      *) echo "Thank you, valid path" ;;
      esac





      share|improve this answer


























        2












        2








        2







        The case command uses glob wildcards which are pretty easy to work with:



        case "$user_path" in
        "$HOME"*) echo "Error: path cannot be in your HOME" ;;
        */home/*) echo "Error: cannot have 'home' in the path" ;;
        *) echo "Thank you, valid path" ;;
        esac





        share|improve this answer













        The case command uses glob wildcards which are pretty easy to work with:



        case "$user_path" in
        "$HOME"*) echo "Error: path cannot be in your HOME" ;;
        */home/*) echo "Error: cannot have 'home' in the path" ;;
        *) echo "Thank you, valid path" ;;
        esac






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Apr 1 at 22:40









        glenn jackmanglenn jackman

        12.8k2545




        12.8k2545






























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