How to align my equation to left?
I want to display four equations which have different length. I want they align left like this.
But my code give this
The following are my code:
$$begin{aligned} p(a) &=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a) \
&={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}
end{aligned}$$
$$begin{aligned} p(b) &=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b) \
&={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}} end{aligned}$$
$$begin{aligned} p(c) &=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}} end{aligned}$$
$$begin{aligned} p(d) &=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}} end{aligned}$$
Can anyone tell me what I can do?
math-mode align
New contributor
add a comment |
I want to display four equations which have different length. I want they align left like this.
But my code give this
The following are my code:
$$begin{aligned} p(a) &=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a) \
&={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}
end{aligned}$$
$$begin{aligned} p(b) &=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b) \
&={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}} end{aligned}$$
$$begin{aligned} p(c) &=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}} end{aligned}$$
$$begin{aligned} p(d) &=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}} end{aligned}$$
Can anyone tell me what I can do?
math-mode align
New contributor
never use$$
in latex, use[
and then thefleqn
option will left align equations.
– David Carlisle
yesterday
add a comment |
I want to display four equations which have different length. I want they align left like this.
But my code give this
The following are my code:
$$begin{aligned} p(a) &=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a) \
&={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}
end{aligned}$$
$$begin{aligned} p(b) &=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b) \
&={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}} end{aligned}$$
$$begin{aligned} p(c) &=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}} end{aligned}$$
$$begin{aligned} p(d) &=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}} end{aligned}$$
Can anyone tell me what I can do?
math-mode align
New contributor
I want to display four equations which have different length. I want they align left like this.
But my code give this
The following are my code:
$$begin{aligned} p(a) &=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a) \
&={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}
end{aligned}$$
$$begin{aligned} p(b) &=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b) \
&={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}} end{aligned}$$
$$begin{aligned} p(c) &=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}} end{aligned}$$
$$begin{aligned} p(d) &=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}} end{aligned}$$
Can anyone tell me what I can do?
math-mode align
math-mode align
New contributor
New contributor
edited yesterday
JouleV
7,41221952
7,41221952
New contributor
asked yesterday
cholechole
411
411
New contributor
New contributor
never use$$
in latex, use[
and then thefleqn
option will left align equations.
– David Carlisle
yesterday
add a comment |
never use$$
in latex, use[
and then thefleqn
option will left align equations.
– David Carlisle
yesterday
never use
$$
in latex, use [
and then the fleqn
option will left align equations.– David Carlisle
yesterday
never use
$$
in latex, use [
and then the fleqn
option will left align equations.– David Carlisle
yesterday
add a comment |
2 Answers
2
active
oldest
votes
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle
? It is very hard to read the fractions! Use tfrac
instead!
You should remove ;
in the &;={scriptstyle...
lines to align the =
s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
yesterday
1
@chole Then you should usetfrac
instead ofscriptstylefrac
.
– JouleV
yesterday
2
+1 for recommendingtfrac
in place ofscriptstylefrac
.
– Mico
yesterday
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
yesterday
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$
but If I had answered I would also have suggestedalign*
rather than[begin{aligned}
:-)
– David Carlisle
yesterday
|
show 1 more comment
I propose this layout, using the fleqn
environment and, as in my opinion, medium sized fractions will look best, I also use the medmath
and mfrac
commands, each from nccmath
:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
add a comment |
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2 Answers
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votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle
? It is very hard to read the fractions! Use tfrac
instead!
You should remove ;
in the &;={scriptstyle...
lines to align the =
s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
yesterday
1
@chole Then you should usetfrac
instead ofscriptstylefrac
.
– JouleV
yesterday
2
+1 for recommendingtfrac
in place ofscriptstylefrac
.
– Mico
yesterday
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
yesterday
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$
but If I had answered I would also have suggestedalign*
rather than[begin{aligned}
:-)
– David Carlisle
yesterday
|
show 1 more comment
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle
? It is very hard to read the fractions! Use tfrac
instead!
You should remove ;
in the &;={scriptstyle...
lines to align the =
s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
yesterday
1
@chole Then you should usetfrac
instead ofscriptstylefrac
.
– JouleV
yesterday
2
+1 for recommendingtfrac
in place ofscriptstylefrac
.
– Mico
yesterday
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
yesterday
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$
but If I had answered I would also have suggestedalign*
rather than[begin{aligned}
:-)
– David Carlisle
yesterday
|
show 1 more comment
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle
? It is very hard to read the fractions! Use tfrac
instead!
You should remove ;
in the &;={scriptstyle...
lines to align the =
s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle
? It is very hard to read the fractions! Use tfrac
instead!
You should remove ;
in the &;={scriptstyle...
lines to align the =
s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
edited yesterday
answered yesterday
JouleVJouleV
7,41221952
7,41221952
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
yesterday
1
@chole Then you should usetfrac
instead ofscriptstylefrac
.
– JouleV
yesterday
2
+1 for recommendingtfrac
in place ofscriptstylefrac
.
– Mico
yesterday
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
yesterday
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$
but If I had answered I would also have suggestedalign*
rather than[begin{aligned}
:-)
– David Carlisle
yesterday
|
show 1 more comment
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
yesterday
1
@chole Then you should usetfrac
instead ofscriptstylefrac
.
– JouleV
yesterday
2
+1 for recommendingtfrac
in place ofscriptstylefrac
.
– Mico
yesterday
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
yesterday
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$
but If I had answered I would also have suggestedalign*
rather than[begin{aligned}
:-)
– David Carlisle
yesterday
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
yesterday
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
yesterday
1
1
@chole Then you should use
tfrac
instead of scriptstylefrac
.– JouleV
yesterday
@chole Then you should use
tfrac
instead of scriptstylefrac
.– JouleV
yesterday
2
2
+1 for recommending
tfrac
in place of scriptstylefrac
.– Mico
yesterday
+1 for recommending
tfrac
in place of scriptstylefrac
.– Mico
yesterday
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
yesterday
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
yesterday
1
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using
$$
but If I had answered I would also have suggested align*
rather than [begin{aligned}
:-)– David Carlisle
yesterday
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using
$$
but If I had answered I would also have suggested align*
rather than [begin{aligned}
:-)– David Carlisle
yesterday
|
show 1 more comment
I propose this layout, using the fleqn
environment and, as in my opinion, medium sized fractions will look best, I also use the medmath
and mfrac
commands, each from nccmath
:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
add a comment |
I propose this layout, using the fleqn
environment and, as in my opinion, medium sized fractions will look best, I also use the medmath
and mfrac
commands, each from nccmath
:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
add a comment |
I propose this layout, using the fleqn
environment and, as in my opinion, medium sized fractions will look best, I also use the medmath
and mfrac
commands, each from nccmath
:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
I propose this layout, using the fleqn
environment and, as in my opinion, medium sized fractions will look best, I also use the medmath
and mfrac
commands, each from nccmath
:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
edited yesterday
answered yesterday
BernardBernard
174k776206
174k776206
add a comment |
add a comment |
chole is a new contributor. Be nice, and check out our Code of Conduct.
chole is a new contributor. Be nice, and check out our Code of Conduct.
chole is a new contributor. Be nice, and check out our Code of Conduct.
chole is a new contributor. Be nice, and check out our Code of Conduct.
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never use
$$
in latex, use[
and then thefleqn
option will left align equations.– David Carlisle
yesterday