tikz grid without top edge
4
In this code from TikZ (finite) grid with character in each cell
documentclass{article}
usepackage{tikz}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
I would like to delete the top and left edges of the grid.
I have found solutions using nodes but much prefer this one with a matrix.
tikz-pgf
asked 2 days ago
Ethan BolkerEthan Bolker
6,68832453
add a comment |
4
In this code from TikZ (finite) grid with character in each cell
documentclass{article}
usepackage{tikz}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
I would like to delete the top and left edges of the grid.
I have found solutions using nodes but much prefer this one with a matrix.
tikz-pgf
asked 2 days ago
Ethan BolkerEthan Bolker
6,68832453
Off topic: You have a very nice reputation number :)
– JouleV
2 days ago
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
2 days ago
add a comment |
4
4
4
In this code from TikZ (finite) grid with character in each cell
documentclass{article}
usepackage{tikz}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
I would like to delete the top and left edges of the grid.
I have found solutions using nodes but much prefer this one with a matrix.
tikz-pgf
asked 2 days ago
Ethan BolkerEthan Bolker
6,68832453
In this code from TikZ (finite) grid with character in each cell
documentclass{article}
usepackage{tikz}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
I would like to delete the top and left edges of the grid.
I have found solutions using nodes but much prefer this one with a matrix.
tikz-pgf
tikz-pgf
asked 2 days ago
Ethan BolkerEthan Bolker
6,68832453
asked 2 days ago
Ethan BolkerEthan Bolker
6,68832453
asked 2 days ago
Ethan BolkerEthan Bolker
6,68832453
asked 2 days ago
Ethan BolkerEthan Bolker
6,68832453
asked 2 days ago
Ethan BolkerEthan Bolker
6,68832453
6,68832453
Off topic: You have a very nice reputation number :)
– JouleV
2 days ago
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
2 days ago
add a comment |
Off topic: You have a very nice reputation number :)
– JouleV
2 days ago
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
2 days ago
Off topic: You have a very nice reputation number :)
– JouleV
2 days ago
Off topic: You have a very nice reputation number :)
– JouleV
2 days ago
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
2 days ago
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
2 days ago
add a comment |
2 Answers
2
active
oldest
votes
4
We can use foreach:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in {-0.5,0,0.5,1} {
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
}
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
answered 2 days ago
JouleVJouleV
8,38022154
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
2 days ago
@EthanBolker No problem. You are welcome ;)
– JouleV
2 days ago
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
2 days ago
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– JouleV
2 days ago
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
2 days ago
|
show 4 more comments
3
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
end{tikzpicture}
end{document}
answered 2 days ago
IgnasiIgnasi
95.4k4175319
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
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oldest
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4
We can use foreach:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in {-0.5,0,0.5,1} {
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
}
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
answered 2 days ago
JouleVJouleV
8,38022154
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
2 days ago
@EthanBolker No problem. You are welcome ;)
– JouleV
2 days ago
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
2 days ago
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– JouleV
2 days ago
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
2 days ago
|
show 4 more comments
4
We can use foreach:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in {-0.5,0,0.5,1} {
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
}
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
answered 2 days ago
JouleVJouleV
8,38022154
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
2 days ago
@EthanBolker No problem. You are welcome ;)
– JouleV
2 days ago
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
2 days ago
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– JouleV
2 days ago
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
2 days ago
|
show 4 more comments
4
4
4
We can use foreach:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in {-0.5,0,0.5,1} {
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
}
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
answered 2 days ago
JouleVJouleV
8,38022154
We can use foreach:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
%draw[step=0.5cm,color=gray] (-1,-1) grid (1,1);
foreach i in {-0.5,0,0.5,1} {
draw[gray] (-1,-i)--(1,-i);
draw[gray] (i,-1)--(i,1);
}
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
Honestly I don't think nodes or matrices have any thing to do here.
This approach is based on marmot's creative way, which is nicer and more tricky:
documentclass[tikz]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
draw[step=0.5cm,color=gray] ({-1cm+0.2pt},-1) grid (1cm,{1cm-0.2pt});
matrix[matrix of nodes,nodes={inner sep=0pt,text width=.5cm,align=center,minimum height=.5cm}]{
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
end{tikzpicture}
end{document}
answered 2 days ago
JouleVJouleV
8,38022154
edited 2 days ago
answered 2 days ago
JouleVJouleV
8,38022154
answered 2 days ago
JouleVJouleV
8,38022154
answered 2 days ago
JouleVJouleV
8,38022154
8,38022154
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
2 days ago
@EthanBolker No problem. You are welcome ;)
– JouleV
2 days ago
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
2 days ago
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– JouleV
2 days ago
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
2 days ago
|
show 4 more comments
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
2 days ago
@EthanBolker No problem. You are welcome ;)
– JouleV
2 days ago
Maybe mention alsodraw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99);which is shorter and gives (for all practical purposes) the same output.
– marmot
2 days ago
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– JouleV
2 days ago
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
2 days ago
1
1
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
2 days ago
Thanks. There is a "matrix" in the code. Other answers to my original question used nodes.
– Ethan Bolker
2 days ago
@EthanBolker No problem. You are welcome ;)
– JouleV
2 days ago
@EthanBolker No problem. You are welcome ;)
– JouleV
2 days ago
Maybe mention also
draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.– marmot
2 days ago
Maybe mention also
draw[step=0.5cm,color=gray] (-0.99,-1) grid (1,0.99); which is shorter and gives (for all practical purposes) the same output.– marmot
2 days ago
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– JouleV
2 days ago
@marmot Ohh your way is wonderfully creative :)) I did not even think of that. However they are not mathematically correct.
– JouleV
2 days ago
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
2 days ago
@JouleV What do you mean by "not mathematically correct"? It is as correct as a truncated grid can be.
– marmot
2 days ago
|
show 4 more comments
3
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
end{tikzpicture}
end{document}
answered 2 days ago
IgnasiIgnasi
95.4k4175319
add a comment |
3
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
end{tikzpicture}
end{document}
answered 2 days ago
IgnasiIgnasi
95.4k4175319
add a comment |
3
3
3
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
end{tikzpicture}
end{document}
answered 2 days ago
IgnasiIgnasi
95.4k4175319
Another solution. It draws the grid with a matrix of drawn nodes. After that, left and top border are deleted with a white supperposed line.
documentclass[tikz,border=2mm]{standalone}
usetikzlibrary{matrix}
begin{document}
begin{tikzpicture}
matrix[matrix of nodes,nodes={draw=gray, anchor=center, minimum size=.6cm}, column sep=-pgflinewidth, row sep=-pgflinewidth] (A) {
A & B & C & D \
E & F & & H \
I & J & K & L \
M & N & O & P\};
draw[white] ([xshift=.5pgflinewidth]A-4-1.south west)|-([yshift=-.5pgflinewidth]A-1-4.north east);
end{tikzpicture}
end{document}
answered 2 days ago
IgnasiIgnasi
95.4k4175319
answered 2 days ago
IgnasiIgnasi
95.4k4175319
answered 2 days ago
IgnasiIgnasi
95.4k4175319
answered 2 days ago
IgnasiIgnasi
95.4k4175319
95.4k4175319
add a comment |
add a comment |
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Off topic: You have a very nice reputation number :)
– JouleV
2 days ago
@JouleV Indeed, It won't survive any votes on this question.
– Ethan Bolker
2 days ago