Negative to positive number range in regex in bash scripting
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I am trying to make a regex expression that will validate a number that is in the range of -100 to 100.
I made this regex expression: (^-[1-100]* |^[0-100]*) but it doesn't work as expected.
I am looking for a number pattern in a string, not just a number by itself.
the script:
#!/bin/bash
check(){
input="test1.txt"
while read -r line; do
a=( $line )
for i in "${a[@]:1}"; do
if [[ "$i" =~ (^-[1-100]*|^[0-100]*) ]]; then
echo "$i"
fi
done
done < "$input"
}
check
the input file:
add $s0 $s1 $s3
sub $s0 $s1
addi $s1 $s2 76
lw $s2 -50($s2)
the actual result: add $s0 $s1 $s3 sub $s0 $s1 addi $s1 $s2 76 lw $s2 -50($s2)
the expected result: 76 -50($s2).
command-line bash scripts regex
asked Mar 29 at 11:57
DavidDavid
61
add a comment |
I am trying to make a regex expression that will validate a number that is in the range of -100 to 100.
I made this regex expression: (^-[1-100]* |^[0-100]*) but it doesn't work as expected.
I am looking for a number pattern in a string, not just a number by itself.
the script:
#!/bin/bash
check(){
input="test1.txt"
while read -r line; do
a=( $line )
for i in "${a[@]:1}"; do
if [[ "$i" =~ (^-[1-100]*|^[0-100]*) ]]; then
echo "$i"
fi
done
done < "$input"
}
check
the input file:
add $s0 $s1 $s3
sub $s0 $s1
addi $s1 $s2 76
lw $s2 -50($s2)
the actual result: add $s0 $s1 $s3 sub $s0 $s1 addi $s1 $s2 76 lw $s2 -50($s2)
the expected result: 76 -50($s2).
command-line bash scripts regex
asked Mar 29 at 11:57
DavidDavid
61
Why do you absolutely want a regex for that? A regex is a good tool... for some cases but not all. Bash has numeric comparison operators.
– Patrick Mevzek
Mar 29 at 19:20
One misconception in your writing:[0-100]will not be parsed as a range from 0 to 100 like you expect, but as 3 items:0-1,0,0.0-1will indeed be the range from0to1, so all added[0-100]is the same as[0100]which is just[01]or(0|1).[1-100]will in fact be the exact same thing.[..]is for character classes so things in it are understood character by character. Also the*applies to the token before it and means the token can appear never or once or multiple times (unbounded), so your [0-100]* means in fact: empty string, or unlimited amounts of0or1.
– Patrick Mevzek
Mar 29 at 19:23
add a comment |
I am trying to make a regex expression that will validate a number that is in the range of -100 to 100.
I made this regex expression: (^-[1-100]* |^[0-100]*) but it doesn't work as expected.
I am looking for a number pattern in a string, not just a number by itself.
the script:
#!/bin/bash
check(){
input="test1.txt"
while read -r line; do
a=( $line )
for i in "${a[@]:1}"; do
if [[ "$i" =~ (^-[1-100]*|^[0-100]*) ]]; then
echo "$i"
fi
done
done < "$input"
}
check
the input file:
add $s0 $s1 $s3
sub $s0 $s1
addi $s1 $s2 76
lw $s2 -50($s2)
the actual result: add $s0 $s1 $s3 sub $s0 $s1 addi $s1 $s2 76 lw $s2 -50($s2)
the expected result: 76 -50($s2).
command-line bash scripts regex
asked Mar 29 at 11:57
DavidDavid
61
I am trying to make a regex expression that will validate a number that is in the range of -100 to 100.
I made this regex expression: (^-[1-100]* |^[0-100]*) but it doesn't work as expected.
I am looking for a number pattern in a string, not just a number by itself.
the script:
#!/bin/bash
check(){
input="test1.txt"
while read -r line; do
a=( $line )
for i in "${a[@]:1}"; do
if [[ "$i" =~ (^-[1-100]*|^[0-100]*) ]]; then
echo "$i"
fi
done
done < "$input"
}
check
the input file:
add $s0 $s1 $s3
sub $s0 $s1
addi $s1 $s2 76
lw $s2 -50($s2)
the actual result: add $s0 $s1 $s3 sub $s0 $s1 addi $s1 $s2 76 lw $s2 -50($s2)
the expected result: 76 -50($s2).
command-line bash scripts regex
command-line bash scripts regex
asked Mar 29 at 11:57
DavidDavid
61
asked Mar 29 at 11:57
DavidDavid
61
asked Mar 29 at 11:57
DavidDavid
61
asked Mar 29 at 11:57
DavidDavid
61
asked Mar 29 at 11:57
DavidDavid
61
61
Why do you absolutely want a regex for that? A regex is a good tool... for some cases but not all. Bash has numeric comparison operators.
– Patrick Mevzek
Mar 29 at 19:20
One misconception in your writing:[0-100]will not be parsed as a range from 0 to 100 like you expect, but as 3 items:0-1,0,0.0-1will indeed be the range from0to1, so all added[0-100]is the same as[0100]which is just[01]or(0|1).[1-100]will in fact be the exact same thing.[..]is for character classes so things in it are understood character by character. Also the*applies to the token before it and means the token can appear never or once or multiple times (unbounded), so your [0-100]* means in fact: empty string, or unlimited amounts of0or1.
– Patrick Mevzek
Mar 29 at 19:23
add a comment |
Why do you absolutely want a regex for that? A regex is a good tool... for some cases but not all. Bash has numeric comparison operators.
– Patrick Mevzek
Mar 29 at 19:20
One misconception in your writing:[0-100]will not be parsed as a range from 0 to 100 like you expect, but as 3 items:0-1,0,0.0-1will indeed be the range from0to1, so all added[0-100]is the same as[0100]which is just[01]or(0|1).[1-100]will in fact be the exact same thing.[..]is for character classes so things in it are understood character by character. Also the*applies to the token before it and means the token can appear never or once or multiple times (unbounded), so your [0-100]* means in fact: empty string, or unlimited amounts of0or1.
– Patrick Mevzek
Mar 29 at 19:23
Why do you absolutely want a regex for that? A regex is a good tool... for some cases but not all. Bash has numeric comparison operators.
– Patrick Mevzek
Mar 29 at 19:20
Why do you absolutely want a regex for that? A regex is a good tool... for some cases but not all. Bash has numeric comparison operators.
– Patrick Mevzek
Mar 29 at 19:20
One misconception in your writing:
[0-100] will not be parsed as a range from 0 to 100 like you expect, but as 3 items: 0-1, 0, 0. 0-1 will indeed be the range from 0 to 1, so all added [0-100] is the same as [0100] which is just [01] or (0|1). [1-100] will in fact be the exact same thing. [..] is for character classes so things in it are understood character by character. Also the * applies to the token before it and means the token can appear never or once or multiple times (unbounded), so your [0-100]* means in fact: empty string, or unlimited amounts of0or1.– Patrick Mevzek
Mar 29 at 19:23
One misconception in your writing:
[0-100] will not be parsed as a range from 0 to 100 like you expect, but as 3 items: 0-1, 0, 0. 0-1 will indeed be the range from 0 to 1, so all added [0-100] is the same as [0100] which is just [01] or (0|1). [1-100] will in fact be the exact same thing. [..] is for character classes so things in it are understood character by character. Also the * applies to the token before it and means the token can appear never or once or multiple times (unbounded), so your [0-100]* means in fact: empty string, or unlimited amounts of0or1.– Patrick Mevzek
Mar 29 at 19:23
add a comment |
1 Answer
1
active
oldest
votes
The expression [0-100] isn't a range of integers; it's a set of characters that happens to include a range 0-1 (so matches 0 or 1 or 0 or 0).
To match the range of integers -100 to 100, you could use:
- a decimal digit
[0-9]; optionally followed by - a second decimal digit
[0-9]
or
- the sequence
100
all preceded by an optional sign. So
^[-+]?([0-9][0-9]?|100)$
Ex.
while read num; do
[[ $num =~ ^[-+]?([0-9][0-9]?|100)$ ]] && echo "$num is valid" || echo "$num is invalid"
done
-101
-101 is invalid
-100
-100 is valid
-83
-83 is valid
22
22 is valid
100
100 is valid
102
102 is invalid
^C
answered Mar 29 at 12:24
steeldriversteeldriver
70.9k11115187
when I use this expression I don't get any results
– David
Mar 29 at 13:06
1
@David then there are likely other issues with your code: I only tried to answer the "Negative to positive number range in regex in bash scripting" part
– steeldriver
Mar 29 at 13:13
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The expression [0-100] isn't a range of integers; it's a set of characters that happens to include a range 0-1 (so matches 0 or 1 or 0 or 0).
To match the range of integers -100 to 100, you could use:
- a decimal digit
[0-9]; optionally followed by - a second decimal digit
[0-9]
or
- the sequence
100
all preceded by an optional sign. So
^[-+]?([0-9][0-9]?|100)$
Ex.
while read num; do
[[ $num =~ ^[-+]?([0-9][0-9]?|100)$ ]] && echo "$num is valid" || echo "$num is invalid"
done
-101
-101 is invalid
-100
-100 is valid
-83
-83 is valid
22
22 is valid
100
100 is valid
102
102 is invalid
^C
answered Mar 29 at 12:24
steeldriversteeldriver
70.9k11115187
when I use this expression I don't get any results
– David
Mar 29 at 13:06
1
@David then there are likely other issues with your code: I only tried to answer the "Negative to positive number range in regex in bash scripting" part
– steeldriver
Mar 29 at 13:13
add a comment |
The expression [0-100] isn't a range of integers; it's a set of characters that happens to include a range 0-1 (so matches 0 or 1 or 0 or 0).
To match the range of integers -100 to 100, you could use:
- a decimal digit
[0-9]; optionally followed by - a second decimal digit
[0-9]
or
- the sequence
100
all preceded by an optional sign. So
^[-+]?([0-9][0-9]?|100)$
Ex.
while read num; do
[[ $num =~ ^[-+]?([0-9][0-9]?|100)$ ]] && echo "$num is valid" || echo "$num is invalid"
done
-101
-101 is invalid
-100
-100 is valid
-83
-83 is valid
22
22 is valid
100
100 is valid
102
102 is invalid
^C
answered Mar 29 at 12:24
steeldriversteeldriver
70.9k11115187
when I use this expression I don't get any results
– David
Mar 29 at 13:06
1
@David then there are likely other issues with your code: I only tried to answer the "Negative to positive number range in regex in bash scripting" part
– steeldriver
Mar 29 at 13:13
add a comment |
The expression [0-100] isn't a range of integers; it's a set of characters that happens to include a range 0-1 (so matches 0 or 1 or 0 or 0).
To match the range of integers -100 to 100, you could use:
- a decimal digit
[0-9]; optionally followed by - a second decimal digit
[0-9]
or
- the sequence
100
all preceded by an optional sign. So
^[-+]?([0-9][0-9]?|100)$
Ex.
while read num; do
[[ $num =~ ^[-+]?([0-9][0-9]?|100)$ ]] && echo "$num is valid" || echo "$num is invalid"
done
-101
-101 is invalid
-100
-100 is valid
-83
-83 is valid
22
22 is valid
100
100 is valid
102
102 is invalid
^C
answered Mar 29 at 12:24
steeldriversteeldriver
70.9k11115187
The expression [0-100] isn't a range of integers; it's a set of characters that happens to include a range 0-1 (so matches 0 or 1 or 0 or 0).
To match the range of integers -100 to 100, you could use:
- a decimal digit
[0-9]; optionally followed by - a second decimal digit
[0-9]
or
- the sequence
100
all preceded by an optional sign. So
^[-+]?([0-9][0-9]?|100)$
Ex.
while read num; do
[[ $num =~ ^[-+]?([0-9][0-9]?|100)$ ]] && echo "$num is valid" || echo "$num is invalid"
done
-101
-101 is invalid
-100
-100 is valid
-83
-83 is valid
22
22 is valid
100
100 is valid
102
102 is invalid
^C
answered Mar 29 at 12:24
steeldriversteeldriver
70.9k11115187
edited Mar 29 at 13:11
answered Mar 29 at 12:24
steeldriversteeldriver
70.9k11115187
answered Mar 29 at 12:24
steeldriversteeldriver
70.9k11115187
answered Mar 29 at 12:24
steeldriversteeldriver
70.9k11115187
70.9k11115187
when I use this expression I don't get any results
– David
Mar 29 at 13:06
1
@David then there are likely other issues with your code: I only tried to answer the "Negative to positive number range in regex in bash scripting" part
– steeldriver
Mar 29 at 13:13
add a comment |
when I use this expression I don't get any results
– David
Mar 29 at 13:06
1
@David then there are likely other issues with your code: I only tried to answer the "Negative to positive number range in regex in bash scripting" part
– steeldriver
Mar 29 at 13:13
when I use this expression I don't get any results
– David
Mar 29 at 13:06
when I use this expression I don't get any results
– David
Mar 29 at 13:06
1
1
@David then there are likely other issues with your code: I only tried to answer the "Negative to positive number range in regex in bash scripting" part
– steeldriver
Mar 29 at 13:13
@David then there are likely other issues with your code: I only tried to answer the "Negative to positive number range in regex in bash scripting" part
– steeldriver
Mar 29 at 13:13
add a comment |
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Why do you absolutely want a regex for that? A regex is a good tool... for some cases but not all. Bash has numeric comparison operators.
– Patrick Mevzek
Mar 29 at 19:20
One misconception in your writing:
[0-100]will not be parsed as a range from 0 to 100 like you expect, but as 3 items:0-1,0,0.0-1will indeed be the range from0to1, so all added[0-100]is the same as[0100]which is just[01]or(0|1).[1-100]will in fact be the exact same thing.[..]is for character classes so things in it are understood character by character. Also the*applies to the token before it and means the token can appear never or once or multiple times (unbounded), so your [0-100]* means in fact: empty string, or unlimited amounts of0or1.– Patrick Mevzek
Mar 29 at 19:23