'Var' does not name a type!
I don't have much experience in C++ programming. I'm getting this error
'z' does not name a type!!!
which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!
float x=10; float y=50; float z;
z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
arduino-uno programming c++ error
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I don't have much experience in C++ programming. I'm getting this error
'z' does not name a type!!!
which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!
float x=10; float y=50; float z;
z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
arduino-uno programming c++ error
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I don't have much experience in C++ programming. I'm getting this error
'z' does not name a type!!!
which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!
float x=10; float y=50; float z;
z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
arduino-uno programming c++ error
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I don't have much experience in C++ programming. I'm getting this error
'z' does not name a type!!!
which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!
float x=10; float y=50; float z;
z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
arduino-uno programming c++ error
arduino-uno programming c++ error
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 6 hours ago
Michel Keijzers
7,13451939
7,13451939
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2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 6 hours ago
2012User2012User
154
154
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
5 hours ago
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
4 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
47 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
5 hours ago
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
4 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
47 mins ago
add a comment |
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
5 hours ago
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
4 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
47 mins ago
add a comment |
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
edited 48 mins ago
answered 6 hours ago
Michel KeijzersMichel Keijzers
7,13451939
7,13451939
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
5 hours ago
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
4 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
47 mins ago
add a comment |
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
5 hours ago
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
4 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
47 mins ago
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
5 hours ago
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
5 hours ago
1
1
You can put an expression outside a function (e.g.
float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).– Ruslan
4 hours ago
You can put an expression outside a function (e.g.
float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).– Ruslan
4 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
47 mins ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
47 mins ago
add a comment |
2012User is a new contributor. Be nice, and check out our Code of Conduct.
2012User is a new contributor. Be nice, and check out our Code of Conduct.
2012User is a new contributor. Be nice, and check out our Code of Conduct.
2012User is a new contributor. Be nice, and check out our Code of Conduct.
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