Bulk file rename, maintaining timestamps, excluding some












0















In Ubuntu 18.10 have beeen using mmv to prepend folder names (a date) to file names within multiple folders ('-n' flag here to review results):



mmv -n './????-??-??*/*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-#10.#11'


which for example converts:



./2018-12-11/DSC05287.ARW -> ./2018-12-11/20181211-DSC05287.ARW


It also converts:



./2018-12-11/20181211-DSC05287.ARW -> ./2018-12-11/20181211-20181211-DSC05287.ARW


whilst maintaining the timestamps.



Some files have already been renamed, some have not.



How can I filter the command to exclude files matching a pattern - those which start with an 8-digit number followed by a hyphen?



Or do I need a different approach?










share|improve this question























  • Could it be as simple as making the leading DSC substring explicit? i.e. mmv -n './????-??-??*/DSC*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-DSC#10.#11'

    – steeldriver
    8 hours ago











  • That'd be a possibility except there are a whole range of filenames, so DSC* includes a proportion. But possibly I could do it folder by folder.

    – user118684
    5 hours ago


















0















In Ubuntu 18.10 have beeen using mmv to prepend folder names (a date) to file names within multiple folders ('-n' flag here to review results):



mmv -n './????-??-??*/*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-#10.#11'


which for example converts:



./2018-12-11/DSC05287.ARW -> ./2018-12-11/20181211-DSC05287.ARW


It also converts:



./2018-12-11/20181211-DSC05287.ARW -> ./2018-12-11/20181211-20181211-DSC05287.ARW


whilst maintaining the timestamps.



Some files have already been renamed, some have not.



How can I filter the command to exclude files matching a pattern - those which start with an 8-digit number followed by a hyphen?



Or do I need a different approach?










share|improve this question























  • Could it be as simple as making the leading DSC substring explicit? i.e. mmv -n './????-??-??*/DSC*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-DSC#10.#11'

    – steeldriver
    8 hours ago











  • That'd be a possibility except there are a whole range of filenames, so DSC* includes a proportion. But possibly I could do it folder by folder.

    – user118684
    5 hours ago
















0












0








0








In Ubuntu 18.10 have beeen using mmv to prepend folder names (a date) to file names within multiple folders ('-n' flag here to review results):



mmv -n './????-??-??*/*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-#10.#11'


which for example converts:



./2018-12-11/DSC05287.ARW -> ./2018-12-11/20181211-DSC05287.ARW


It also converts:



./2018-12-11/20181211-DSC05287.ARW -> ./2018-12-11/20181211-20181211-DSC05287.ARW


whilst maintaining the timestamps.



Some files have already been renamed, some have not.



How can I filter the command to exclude files matching a pattern - those which start with an 8-digit number followed by a hyphen?



Or do I need a different approach?










share|improve this question














In Ubuntu 18.10 have beeen using mmv to prepend folder names (a date) to file names within multiple folders ('-n' flag here to review results):



mmv -n './????-??-??*/*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-#10.#11'


which for example converts:



./2018-12-11/DSC05287.ARW -> ./2018-12-11/20181211-DSC05287.ARW


It also converts:



./2018-12-11/20181211-DSC05287.ARW -> ./2018-12-11/20181211-20181211-DSC05287.ARW


whilst maintaining the timestamps.



Some files have already been renamed, some have not.



How can I filter the command to exclude files matching a pattern - those which start with an 8-digit number followed by a hyphen?



Or do I need a different approach?







rename timestamp






share|improve this question













share|improve this question











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share|improve this question










asked 10 hours ago









user118684user118684

6618




6618













  • Could it be as simple as making the leading DSC substring explicit? i.e. mmv -n './????-??-??*/DSC*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-DSC#10.#11'

    – steeldriver
    8 hours ago











  • That'd be a possibility except there are a whole range of filenames, so DSC* includes a proportion. But possibly I could do it folder by folder.

    – user118684
    5 hours ago





















  • Could it be as simple as making the leading DSC substring explicit? i.e. mmv -n './????-??-??*/DSC*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-DSC#10.#11'

    – steeldriver
    8 hours ago











  • That'd be a possibility except there are a whole range of filenames, so DSC* includes a proportion. But possibly I could do it folder by folder.

    – user118684
    5 hours ago



















Could it be as simple as making the leading DSC substring explicit? i.e. mmv -n './????-??-??*/DSC*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-DSC#10.#11'

– steeldriver
8 hours ago





Could it be as simple as making the leading DSC substring explicit? i.e. mmv -n './????-??-??*/DSC*.*' './#1#2#3#4-#5#6-#7#8#9/#1#2#3#4#5#6#7#8-DSC#10.#11'

– steeldriver
8 hours ago













That'd be a possibility except there are a whole range of filenames, so DSC* includes a proportion. But possibly I could do it folder by folder.

– user118684
5 hours ago







That'd be a possibility except there are a whole range of filenames, so DSC* includes a proportion. But possibly I could do it folder by folder.

– user118684
5 hours ago












1 Answer
1






active

oldest

votes


















2














I'm not a fan of all-in-one renaming utilities, so here's how I would do it using only "standard (GNU) equipment", specifically bash, find and mv.



Assuming you're only interested in files that are one directory level down (so find -maxdepth 2), and specifically ignoring files that have already been previously renamed (but doing a sanity check with regex backreferences to avoid making assumptions):



find -regextype egrep -maxdepth 2 -type f ! -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-.+' | while read f; do

if [[ $f =~ ^(./([0-9]{4}-[0-9]{2}-[0-9]{2}).*)/(.+)$ ]]; then
# The above regex groups its matches into:
# ${BASH_REMATCH[1]} = the dir pathname
# ${BASH_REMATCH[2]} = the date in the dir pathname (remember to strip its dashes)
# ${BASH_REMATCH[3]} = the file name

mv -v "$f" "${BASH_REMATCH[1]}"/"${BASH_REMATCH[2]//-}-${BASH_REMATCH[3]}"

fi

done


And to fix the ones that have already been incorrectly "double-dated" (again, using backreferences to avoid making unwarranted assumptions):



find -regextype egrep -maxdepth 2 -type f -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-123-.+' | while read f; do

if [[ $f =~ ^(./.+)/([0-9]{8})-[0-9]{8}-(.+)$ ]]; then
# The above regex groups its matches into:
# ${BASH_REMATCH[1]} = the dir pathname
# ${BASH_REMATCH[2]} = the first date chunk
# ${BASH_REMATCH[3]} = the filename "tail"

mv -v "$f" "${BASH_REMATCH[1]}/${BASH_REMATCH[2]}-${BASH_REMATCH[3]}"

fi

done


Further Reading:





  • Regular-Expressions.info: in case you need help with regexes


  • bash(1) man page: search for the =~ operator, then read up on the special BASH_REMATCH array


  • findutils | Regular Expressions: details on the surprising variety of regexes supported by GNU find and locate.






share|improve this answer








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    1 Answer
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    1 Answer
    1






    active

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    active

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    2














    I'm not a fan of all-in-one renaming utilities, so here's how I would do it using only "standard (GNU) equipment", specifically bash, find and mv.



    Assuming you're only interested in files that are one directory level down (so find -maxdepth 2), and specifically ignoring files that have already been previously renamed (but doing a sanity check with regex backreferences to avoid making assumptions):



    find -regextype egrep -maxdepth 2 -type f ! -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-.+' | while read f; do

    if [[ $f =~ ^(./([0-9]{4}-[0-9]{2}-[0-9]{2}).*)/(.+)$ ]]; then
    # The above regex groups its matches into:
    # ${BASH_REMATCH[1]} = the dir pathname
    # ${BASH_REMATCH[2]} = the date in the dir pathname (remember to strip its dashes)
    # ${BASH_REMATCH[3]} = the file name

    mv -v "$f" "${BASH_REMATCH[1]}"/"${BASH_REMATCH[2]//-}-${BASH_REMATCH[3]}"

    fi

    done


    And to fix the ones that have already been incorrectly "double-dated" (again, using backreferences to avoid making unwarranted assumptions):



    find -regextype egrep -maxdepth 2 -type f -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-123-.+' | while read f; do

    if [[ $f =~ ^(./.+)/([0-9]{8})-[0-9]{8}-(.+)$ ]]; then
    # The above regex groups its matches into:
    # ${BASH_REMATCH[1]} = the dir pathname
    # ${BASH_REMATCH[2]} = the first date chunk
    # ${BASH_REMATCH[3]} = the filename "tail"

    mv -v "$f" "${BASH_REMATCH[1]}/${BASH_REMATCH[2]}-${BASH_REMATCH[3]}"

    fi

    done


    Further Reading:





    • Regular-Expressions.info: in case you need help with regexes


    • bash(1) man page: search for the =~ operator, then read up on the special BASH_REMATCH array


    • findutils | Regular Expressions: details on the surprising variety of regexes supported by GNU find and locate.






    share|improve this answer








    New contributor




    Adrian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.

























      2














      I'm not a fan of all-in-one renaming utilities, so here's how I would do it using only "standard (GNU) equipment", specifically bash, find and mv.



      Assuming you're only interested in files that are one directory level down (so find -maxdepth 2), and specifically ignoring files that have already been previously renamed (but doing a sanity check with regex backreferences to avoid making assumptions):



      find -regextype egrep -maxdepth 2 -type f ! -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-.+' | while read f; do

      if [[ $f =~ ^(./([0-9]{4}-[0-9]{2}-[0-9]{2}).*)/(.+)$ ]]; then
      # The above regex groups its matches into:
      # ${BASH_REMATCH[1]} = the dir pathname
      # ${BASH_REMATCH[2]} = the date in the dir pathname (remember to strip its dashes)
      # ${BASH_REMATCH[3]} = the file name

      mv -v "$f" "${BASH_REMATCH[1]}"/"${BASH_REMATCH[2]//-}-${BASH_REMATCH[3]}"

      fi

      done


      And to fix the ones that have already been incorrectly "double-dated" (again, using backreferences to avoid making unwarranted assumptions):



      find -regextype egrep -maxdepth 2 -type f -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-123-.+' | while read f; do

      if [[ $f =~ ^(./.+)/([0-9]{8})-[0-9]{8}-(.+)$ ]]; then
      # The above regex groups its matches into:
      # ${BASH_REMATCH[1]} = the dir pathname
      # ${BASH_REMATCH[2]} = the first date chunk
      # ${BASH_REMATCH[3]} = the filename "tail"

      mv -v "$f" "${BASH_REMATCH[1]}/${BASH_REMATCH[2]}-${BASH_REMATCH[3]}"

      fi

      done


      Further Reading:





      • Regular-Expressions.info: in case you need help with regexes


      • bash(1) man page: search for the =~ operator, then read up on the special BASH_REMATCH array


      • findutils | Regular Expressions: details on the surprising variety of regexes supported by GNU find and locate.






      share|improve this answer








      New contributor




      Adrian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.























        2












        2








        2







        I'm not a fan of all-in-one renaming utilities, so here's how I would do it using only "standard (GNU) equipment", specifically bash, find and mv.



        Assuming you're only interested in files that are one directory level down (so find -maxdepth 2), and specifically ignoring files that have already been previously renamed (but doing a sanity check with regex backreferences to avoid making assumptions):



        find -regextype egrep -maxdepth 2 -type f ! -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-.+' | while read f; do

        if [[ $f =~ ^(./([0-9]{4}-[0-9]{2}-[0-9]{2}).*)/(.+)$ ]]; then
        # The above regex groups its matches into:
        # ${BASH_REMATCH[1]} = the dir pathname
        # ${BASH_REMATCH[2]} = the date in the dir pathname (remember to strip its dashes)
        # ${BASH_REMATCH[3]} = the file name

        mv -v "$f" "${BASH_REMATCH[1]}"/"${BASH_REMATCH[2]//-}-${BASH_REMATCH[3]}"

        fi

        done


        And to fix the ones that have already been incorrectly "double-dated" (again, using backreferences to avoid making unwarranted assumptions):



        find -regextype egrep -maxdepth 2 -type f -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-123-.+' | while read f; do

        if [[ $f =~ ^(./.+)/([0-9]{8})-[0-9]{8}-(.+)$ ]]; then
        # The above regex groups its matches into:
        # ${BASH_REMATCH[1]} = the dir pathname
        # ${BASH_REMATCH[2]} = the first date chunk
        # ${BASH_REMATCH[3]} = the filename "tail"

        mv -v "$f" "${BASH_REMATCH[1]}/${BASH_REMATCH[2]}-${BASH_REMATCH[3]}"

        fi

        done


        Further Reading:





        • Regular-Expressions.info: in case you need help with regexes


        • bash(1) man page: search for the =~ operator, then read up on the special BASH_REMATCH array


        • findutils | Regular Expressions: details on the surprising variety of regexes supported by GNU find and locate.






        share|improve this answer








        New contributor




        Adrian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.










        I'm not a fan of all-in-one renaming utilities, so here's how I would do it using only "standard (GNU) equipment", specifically bash, find and mv.



        Assuming you're only interested in files that are one directory level down (so find -maxdepth 2), and specifically ignoring files that have already been previously renamed (but doing a sanity check with regex backreferences to avoid making assumptions):



        find -regextype egrep -maxdepth 2 -type f ! -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-.+' | while read f; do

        if [[ $f =~ ^(./([0-9]{4}-[0-9]{2}-[0-9]{2}).*)/(.+)$ ]]; then
        # The above regex groups its matches into:
        # ${BASH_REMATCH[1]} = the dir pathname
        # ${BASH_REMATCH[2]} = the date in the dir pathname (remember to strip its dashes)
        # ${BASH_REMATCH[3]} = the file name

        mv -v "$f" "${BASH_REMATCH[1]}"/"${BASH_REMATCH[2]//-}-${BASH_REMATCH[3]}"

        fi

        done


        And to fix the ones that have already been incorrectly "double-dated" (again, using backreferences to avoid making unwarranted assumptions):



        find -regextype egrep -maxdepth 2 -type f -regex './([0-9]{4})-([0-9]{2})-([0-9]{2}).*/123-123-.+' | while read f; do

        if [[ $f =~ ^(./.+)/([0-9]{8})-[0-9]{8}-(.+)$ ]]; then
        # The above regex groups its matches into:
        # ${BASH_REMATCH[1]} = the dir pathname
        # ${BASH_REMATCH[2]} = the first date chunk
        # ${BASH_REMATCH[3]} = the filename "tail"

        mv -v "$f" "${BASH_REMATCH[1]}/${BASH_REMATCH[2]}-${BASH_REMATCH[3]}"

        fi

        done


        Further Reading:





        • Regular-Expressions.info: in case you need help with regexes


        • bash(1) man page: search for the =~ operator, then read up on the special BASH_REMATCH array


        • findutils | Regular Expressions: details on the surprising variety of regexes supported by GNU find and locate.







        share|improve this answer








        New contributor




        Adrian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|improve this answer



        share|improve this answer






        New contributor




        Adrian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered 8 hours ago









        AdrianAdrian

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        1212




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        Check out our Code of Conduct.






        Adrian is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






























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