Convert seconds to minutes
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2
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music(){
if ps -C cmus > /dev/null; then
position=`cmus-remote -Q |
grep --text '^position' |
sed -e 's/position //' |
awk '{gsub("position ", "");print}'`
duration=`cmus-remote -Q |
grep --text '^duration' |
sed -e 's/duration //' |
awk '{gsub("duration ", "");print}'`
echo "[$position/$duration]"; else echo "";
fi
}
bash awk
edited Apr 2 at 20:05
αғsнιη
17.1k103069
asked Apr 2 at 19:09
JoeJoe
223
add a comment |
2
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music(){
if ps -C cmus > /dev/null; then
position=`cmus-remote -Q |
grep --text '^position' |
sed -e 's/position //' |
awk '{gsub("position ", "");print}'`
duration=`cmus-remote -Q |
grep --text '^duration' |
sed -e 's/duration //' |
awk '{gsub("duration ", "");print}'`
echo "[$position/$duration]"; else echo "";
fi
}
bash awk
edited Apr 2 at 20:05
αғsнιη
17.1k103069
asked Apr 2 at 19:09
JoeJoe
223
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
Apr 2 at 20:02
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
Apr 2 at 20:18
add a comment |
2
2
2
0
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music(){
if ps -C cmus > /dev/null; then
position=`cmus-remote -Q |
grep --text '^position' |
sed -e 's/position //' |
awk '{gsub("position ", "");print}'`
duration=`cmus-remote -Q |
grep --text '^duration' |
sed -e 's/duration //' |
awk '{gsub("duration ", "");print}'`
echo "[$position/$duration]"; else echo "";
fi
}
bash awk
edited Apr 2 at 20:05
αғsнιη
17.1k103069
asked Apr 2 at 19:09
JoeJoe
223
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music(){
if ps -C cmus > /dev/null; then
position=`cmus-remote -Q |
grep --text '^position' |
sed -e 's/position //' |
awk '{gsub("position ", "");print}'`
duration=`cmus-remote -Q |
grep --text '^duration' |
sed -e 's/duration //' |
awk '{gsub("duration ", "");print}'`
echo "[$position/$duration]"; else echo "";
fi
}
bash awk
bash awk
edited Apr 2 at 20:05
αғsнιη
17.1k103069
asked Apr 2 at 19:09
JoeJoe
223
edited Apr 2 at 20:05
αғsнιη
17.1k103069
asked Apr 2 at 19:09
JoeJoe
223
edited Apr 2 at 20:05
αғsнιη
17.1k103069
edited Apr 2 at 20:05
αғsнιη
17.1k103069
edited Apr 2 at 20:05
αғsнιη
17.1k103069
17.1k103069
asked Apr 2 at 19:09
JoeJoe
223
asked Apr 2 at 19:09
JoeJoe
223
asked Apr 2 at 19:09
JoeJoe
223
223
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
Apr 2 at 20:02
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
Apr 2 at 20:18
add a comment |
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
Apr 2 at 20:02
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
Apr 2 at 20:18
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
Apr 2 at 20:02
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
Apr 2 at 20:02
Using
date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.– bu5hman
Apr 2 at 20:18
Using
date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.– bu5hman
Apr 2 at 20:18
add a comment |
1 Answer
1
active
oldest
votes
6
This will help you:
sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }
$ sec2min 500
8:20
$ sec2min 1
0:01
answered Apr 2 at 20:02
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
Apr 2 at 22:08
Here's the same operation using a second iteration of awk ...awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'
– RubberStamp
Apr 3 at 0:41
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
6
This will help you:
sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }
$ sec2min 500
8:20
$ sec2min 1
0:01
answered Apr 2 at 20:02
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
Apr 2 at 22:08
Here's the same operation using a second iteration of awk ...awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'
– RubberStamp
Apr 3 at 0:41
add a comment |
6
This will help you:
sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }
$ sec2min 500
8:20
$ sec2min 1
0:01
answered Apr 2 at 20:02
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
Apr 2 at 22:08
Here's the same operation using a second iteration of awk ...awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'
– RubberStamp
Apr 3 at 0:41
add a comment |
6
6
6
This will help you:
sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }
$ sec2min 500
8:20
$ sec2min 1
0:01
answered Apr 2 at 20:02
glenn jackmanglenn jackman
53k573114
This will help you:
sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }
$ sec2min 500
8:20
$ sec2min 1
0:01
answered Apr 2 at 20:02
glenn jackmanglenn jackman
53k573114
answered Apr 2 at 20:02
glenn jackmanglenn jackman
53k573114
answered Apr 2 at 20:02
glenn jackmanglenn jackman
53k573114
answered Apr 2 at 20:02
glenn jackmanglenn jackman
53k573114
53k573114
Thanks! That's working perfectly :)
– Joe
Apr 2 at 22:08
Here's the same operation using a second iteration of awk ...awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'
– RubberStamp
Apr 3 at 0:41
add a comment |
Thanks! That's working perfectly :)
– Joe
Apr 2 at 22:08
Here's the same operation using a second iteration of awk ...awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'
– RubberStamp
Apr 3 at 0:41
Thanks! That's working perfectly :)
– Joe
Apr 2 at 22:08
Thanks! That's working perfectly :)
– Joe
Apr 2 at 22:08
Here's the same operation using a second iteration of awk ...
awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'– RubberStamp
Apr 3 at 0:41
Here's the same operation using a second iteration of awk ...
awk '{ min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec}'– RubberStamp
Apr 3 at 0:41
add a comment |
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Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
Apr 2 at 20:02
Using
date -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.– bu5hman
Apr 2 at 20:18