How do I exit BASH while loop using modulus operator?
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4
So practically for my assignment I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0, ex: (25 % 5 = 0 break loop) Where in my attempt below have I gone wrong?
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
else
echo "you entered right"
break
fi
done
command-line bash scripts
asked Apr 2 at 18:04
Roosevelt MendietaRoosevelt Mendieta
4915
add a comment |
4
So practically for my assignment I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0, ex: (25 % 5 = 0 break loop) Where in my attempt below have I gone wrong?
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
else
echo "you entered right"
break
fi
done
command-line bash scripts
asked Apr 2 at 18:04
Roosevelt MendietaRoosevelt Mendieta
4915
2
If the assignment specifiesbash, then you might consider using its built-in arithmetic expansion syntax e.g.(( INPUT % 5 == 0 ))
– steeldriver
Apr 2 at 18:45
the loop does not end when entering 25 @steeldriver
– Roosevelt Mendieta
Apr 2 at 18:50
add a comment |
4
4
4
So practically for my assignment I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0, ex: (25 % 5 = 0 break loop) Where in my attempt below have I gone wrong?
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
else
echo "you entered right"
break
fi
done
command-line bash scripts
asked Apr 2 at 18:04
Roosevelt MendietaRoosevelt Mendieta
4915
So practically for my assignment I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0, ex: (25 % 5 = 0 break loop) Where in my attempt below have I gone wrong?
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
else
echo "you entered right"
break
fi
done
command-line bash scripts
command-line bash scripts
asked Apr 2 at 18:04
Roosevelt MendietaRoosevelt Mendieta
4915
asked Apr 2 at 18:04
Roosevelt MendietaRoosevelt Mendieta
4915
edited Apr 2 at 19:09
Roosevelt Mendieta
asked Apr 2 at 18:04
Roosevelt MendietaRoosevelt Mendieta
4915
asked Apr 2 at 18:04
Roosevelt MendietaRoosevelt Mendieta
4915
asked Apr 2 at 18:04
Roosevelt MendietaRoosevelt Mendieta
4915
4915
2
If the assignment specifiesbash, then you might consider using its built-in arithmetic expansion syntax e.g.(( INPUT % 5 == 0 ))
– steeldriver
Apr 2 at 18:45
the loop does not end when entering 25 @steeldriver
– Roosevelt Mendieta
Apr 2 at 18:50
add a comment |
2
If the assignment specifiesbash, then you might consider using its built-in arithmetic expansion syntax e.g.(( INPUT % 5 == 0 ))
– steeldriver
Apr 2 at 18:45
the loop does not end when entering 25 @steeldriver
– Roosevelt Mendieta
Apr 2 at 18:50
2
2
If the assignment specifies
bash, then you might consider using its built-in arithmetic expansion syntax e.g. (( INPUT % 5 == 0 ))– steeldriver
Apr 2 at 18:45
If the assignment specifies
bash, then you might consider using its built-in arithmetic expansion syntax e.g. (( INPUT % 5 == 0 ))– steeldriver
Apr 2 at 18:45
the loop does not end when entering 25 @steeldriver
– Roosevelt Mendieta
Apr 2 at 18:50
the loop does not end when entering 25 @steeldriver
– Roosevelt Mendieta
Apr 2 at 18:50
add a comment |
4 Answers
4
active
oldest
votes
7
Move the break from the else part to the if part:
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
break
else
echo "you entered right"
fi
done
answered Apr 2 at 18:16
PerlDuckPerlDuck
7,98611636
this doesn't work, when I enter 40 the code exits
– Roosevelt Mendieta
Apr 2 at 18:46
6
@RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.
– Kulfy
Apr 2 at 18:58
2
@Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.
– Roosevelt Mendieta
Apr 2 at 19:04
@RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.
– Kulfy
Apr 2 at 19:07
i version controlled the code back to it's original state @Kulfy
– Roosevelt Mendieta
Apr 2 at 19:10
add a comment |
5
It works for me according to @steeldriver's tips,
make sure you use
bash
#!/bin/bash
use the bash syntax for arithmetic evaluation
((...))
Otherwise the shellscript can remain the same,
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if (( INPUT % 5 == 0 )) ; then
echo "you entered right"
break
else
echo "you entered wrong"
fi
done
Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)
answered Apr 2 at 19:03
sudodussudodus
25.7k33078
add a comment |
4
Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))
$ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
Enter number:11
alright
Enter number:7
alright
Enter number:10
Wrong
Portably, you might want to use [ aka test
$ [ $((25%5)) -eq 0 ] && echo "Zero"
Zero
$ [ $((26%5)) -eq 0 ] && echo "Zero"
$
answered Apr 2 at 18:54
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75k9155326
add a comment |
0
There is also an example for trap's usage in Bash-Beginners-Guide
You can use trap to catch signal to exit your process or whatever you want.
#!/bin/bash
# traptest.sh
trap "echo Booh!;exit" SIGINT SIGTERM
echo "pid is $$"
while : # This is the same as "while true".
do
sleep 60 # This script is not really doing anything.
done
answered 2 days ago
ChingKun YuChingKun Yu
1
New contributor
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
OP's question is basically an assignment, so they do have to use modulo operator and arithmetic, so your answer misses that. Since you're new on the site, I won't downvote the answer, but I suggest you address that part soon. There's many other ways in which you could do arithmetic in Bash, so consider addressing one of them not already mentioned
– Sergiy Kolodyazhnyy
2 days ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
7
Move the break from the else part to the if part:
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
break
else
echo "you entered right"
fi
done
answered Apr 2 at 18:16
PerlDuckPerlDuck
7,98611636
this doesn't work, when I enter 40 the code exits
– Roosevelt Mendieta
Apr 2 at 18:46
6
@RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.
– Kulfy
Apr 2 at 18:58
2
@Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.
– Roosevelt Mendieta
Apr 2 at 19:04
@RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.
– Kulfy
Apr 2 at 19:07
i version controlled the code back to it's original state @Kulfy
– Roosevelt Mendieta
Apr 2 at 19:10
add a comment |
7
Move the break from the else part to the if part:
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
break
else
echo "you entered right"
fi
done
answered Apr 2 at 18:16
PerlDuckPerlDuck
7,98611636
this doesn't work, when I enter 40 the code exits
– Roosevelt Mendieta
Apr 2 at 18:46
6
@RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.
– Kulfy
Apr 2 at 18:58
2
@Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.
– Roosevelt Mendieta
Apr 2 at 19:04
@RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.
– Kulfy
Apr 2 at 19:07
i version controlled the code back to it's original state @Kulfy
– Roosevelt Mendieta
Apr 2 at 19:10
add a comment |
7
7
7
Move the break from the else part to the if part:
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
break
else
echo "you entered right"
fi
done
answered Apr 2 at 18:16
PerlDuckPerlDuck
7,98611636
Move the break from the else part to the if part:
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if [ `expr $INPUT % 5` -eq 0 ]; then
echo "you entered wrong"
break
else
echo "you entered right"
fi
done
answered Apr 2 at 18:16
PerlDuckPerlDuck
7,98611636
answered Apr 2 at 18:16
PerlDuckPerlDuck
7,98611636
answered Apr 2 at 18:16
PerlDuckPerlDuck
7,98611636
answered Apr 2 at 18:16
PerlDuckPerlDuck
7,98611636
7,98611636
this doesn't work, when I enter 40 the code exits
– Roosevelt Mendieta
Apr 2 at 18:46
6
@RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.
– Kulfy
Apr 2 at 18:58
2
@Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.
– Roosevelt Mendieta
Apr 2 at 19:04
@RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.
– Kulfy
Apr 2 at 19:07
i version controlled the code back to it's original state @Kulfy
– Roosevelt Mendieta
Apr 2 at 19:10
add a comment |
this doesn't work, when I enter 40 the code exits
– Roosevelt Mendieta
Apr 2 at 18:46
6
@RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.
– Kulfy
Apr 2 at 18:58
2
@Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.
– Roosevelt Mendieta
Apr 2 at 19:04
@RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.
– Kulfy
Apr 2 at 19:07
i version controlled the code back to it's original state @Kulfy
– Roosevelt Mendieta
Apr 2 at 19:10
this doesn't work, when I enter 40 the code exits
– Roosevelt Mendieta
Apr 2 at 18:46
this doesn't work, when I enter 40 the code exits
– Roosevelt Mendieta
Apr 2 at 18:46
6
6
@RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.
– Kulfy
Apr 2 at 18:58
@RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.
– Kulfy
Apr 2 at 18:58
2
2
@Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.
– Roosevelt Mendieta
Apr 2 at 19:04
@Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.
– Roosevelt Mendieta
Apr 2 at 19:04
@RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.
– Kulfy
Apr 2 at 19:07
@RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.
– Kulfy
Apr 2 at 19:07
i version controlled the code back to it's original state @Kulfy
– Roosevelt Mendieta
Apr 2 at 19:10
i version controlled the code back to it's original state @Kulfy
– Roosevelt Mendieta
Apr 2 at 19:10
add a comment |
5
It works for me according to @steeldriver's tips,
make sure you use
bash
#!/bin/bash
use the bash syntax for arithmetic evaluation
((...))
Otherwise the shellscript can remain the same,
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if (( INPUT % 5 == 0 )) ; then
echo "you entered right"
break
else
echo "you entered wrong"
fi
done
Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)
answered Apr 2 at 19:03
sudodussudodus
25.7k33078
add a comment |
5
It works for me according to @steeldriver's tips,
make sure you use
bash
#!/bin/bash
use the bash syntax for arithmetic evaluation
((...))
Otherwise the shellscript can remain the same,
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if (( INPUT % 5 == 0 )) ; then
echo "you entered right"
break
else
echo "you entered wrong"
fi
done
Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)
answered Apr 2 at 19:03
sudodussudodus
25.7k33078
add a comment |
5
5
5
It works for me according to @steeldriver's tips,
make sure you use
bash
#!/bin/bash
use the bash syntax for arithmetic evaluation
((...))
Otherwise the shellscript can remain the same,
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if (( INPUT % 5 == 0 )) ; then
echo "you entered right"
break
else
echo "you entered wrong"
fi
done
Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)
answered Apr 2 at 19:03
sudodussudodus
25.7k33078
It works for me according to @steeldriver's tips,
make sure you use
bash
#!/bin/bash
use the bash syntax for arithmetic evaluation
((...))
Otherwise the shellscript can remain the same,
#!/bin/bash
while true
do
echo "Please input anything here: "
read INPUT
if (( INPUT % 5 == 0 )) ; then
echo "you entered right"
break
else
echo "you entered wrong"
fi
done
Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)
answered Apr 2 at 19:03
sudodussudodus
25.7k33078
edited Apr 2 at 19:14
answered Apr 2 at 19:03
sudodussudodus
25.7k33078
answered Apr 2 at 19:03
sudodussudodus
25.7k33078
answered Apr 2 at 19:03
sudodussudodus
25.7k33078
25.7k33078
add a comment |
add a comment |
4
Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))
$ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
Enter number:11
alright
Enter number:7
alright
Enter number:10
Wrong
Portably, you might want to use [ aka test
$ [ $((25%5)) -eq 0 ] && echo "Zero"
Zero
$ [ $((26%5)) -eq 0 ] && echo "Zero"
$
answered Apr 2 at 18:54
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75k9155326
add a comment |
4
Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))
$ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
Enter number:11
alright
Enter number:7
alright
Enter number:10
Wrong
Portably, you might want to use [ aka test
$ [ $((25%5)) -eq 0 ] && echo "Zero"
Zero
$ [ $((26%5)) -eq 0 ] && echo "Zero"
$
answered Apr 2 at 18:54
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75k9155326
add a comment |
4
4
4
Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))
$ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
Enter number:11
alright
Enter number:7
alright
Enter number:10
Wrong
Portably, you might want to use [ aka test
$ [ $((25%5)) -eq 0 ] && echo "Zero"
Zero
$ [ $((26%5)) -eq 0 ] && echo "Zero"
$
answered Apr 2 at 18:54
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75k9155326
Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))
$ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
Enter number:11
alright
Enter number:7
alright
Enter number:10
Wrong
Portably, you might want to use [ aka test
$ [ $((25%5)) -eq 0 ] && echo "Zero"
Zero
$ [ $((26%5)) -eq 0 ] && echo "Zero"
$
answered Apr 2 at 18:54
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75k9155326
edited Apr 2 at 18:59
answered Apr 2 at 18:54
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75k9155326
answered Apr 2 at 18:54
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75k9155326
answered Apr 2 at 18:54
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75k9155326
75k9155326
add a comment |
add a comment |
0
There is also an example for trap's usage in Bash-Beginners-Guide
You can use trap to catch signal to exit your process or whatever you want.
#!/bin/bash
# traptest.sh
trap "echo Booh!;exit" SIGINT SIGTERM
echo "pid is $$"
while : # This is the same as "while true".
do
sleep 60 # This script is not really doing anything.
done
answered 2 days ago
ChingKun YuChingKun Yu
1
New contributor
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
OP's question is basically an assignment, so they do have to use modulo operator and arithmetic, so your answer misses that. Since you're new on the site, I won't downvote the answer, but I suggest you address that part soon. There's many other ways in which you could do arithmetic in Bash, so consider addressing one of them not already mentioned
– Sergiy Kolodyazhnyy
2 days ago
add a comment |
0
There is also an example for trap's usage in Bash-Beginners-Guide
You can use trap to catch signal to exit your process or whatever you want.
#!/bin/bash
# traptest.sh
trap "echo Booh!;exit" SIGINT SIGTERM
echo "pid is $$"
while : # This is the same as "while true".
do
sleep 60 # This script is not really doing anything.
done
answered 2 days ago
ChingKun YuChingKun Yu
1
New contributor
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
OP's question is basically an assignment, so they do have to use modulo operator and arithmetic, so your answer misses that. Since you're new on the site, I won't downvote the answer, but I suggest you address that part soon. There's many other ways in which you could do arithmetic in Bash, so consider addressing one of them not already mentioned
– Sergiy Kolodyazhnyy
2 days ago
add a comment |
0
0
0
There is also an example for trap's usage in Bash-Beginners-Guide
You can use trap to catch signal to exit your process or whatever you want.
#!/bin/bash
# traptest.sh
trap "echo Booh!;exit" SIGINT SIGTERM
echo "pid is $$"
while : # This is the same as "while true".
do
sleep 60 # This script is not really doing anything.
done
answered 2 days ago
ChingKun YuChingKun Yu
1
New contributor
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
There is also an example for trap's usage in Bash-Beginners-Guide
You can use trap to catch signal to exit your process or whatever you want.
#!/bin/bash
# traptest.sh
trap "echo Booh!;exit" SIGINT SIGTERM
echo "pid is $$"
while : # This is the same as "while true".
do
sleep 60 # This script is not really doing anything.
done
answered 2 days ago
ChingKun YuChingKun Yu
1
New contributor
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
ChingKun YuChingKun Yu
1
New contributor
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
ChingKun YuChingKun Yu
1
answered 2 days ago
ChingKun YuChingKun Yu
1
1
New contributor
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ChingKun Yu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
OP's question is basically an assignment, so they do have to use modulo operator and arithmetic, so your answer misses that. Since you're new on the site, I won't downvote the answer, but I suggest you address that part soon. There's many other ways in which you could do arithmetic in Bash, so consider addressing one of them not already mentioned
– Sergiy Kolodyazhnyy
2 days ago
add a comment |
3
OP's question is basically an assignment, so they do have to use modulo operator and arithmetic, so your answer misses that. Since you're new on the site, I won't downvote the answer, but I suggest you address that part soon. There's many other ways in which you could do arithmetic in Bash, so consider addressing one of them not already mentioned
– Sergiy Kolodyazhnyy
2 days ago
3
3
OP's question is basically an assignment, so they do have to use modulo operator and arithmetic, so your answer misses that. Since you're new on the site, I won't downvote the answer, but I suggest you address that part soon. There's many other ways in which you could do arithmetic in Bash, so consider addressing one of them not already mentioned
– Sergiy Kolodyazhnyy
2 days ago
OP's question is basically an assignment, so they do have to use modulo operator and arithmetic, so your answer misses that. Since you're new on the site, I won't downvote the answer, but I suggest you address that part soon. There's many other ways in which you could do arithmetic in Bash, so consider addressing one of them not already mentioned
– Sergiy Kolodyazhnyy
2 days ago
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2
If the assignment specifies
bash, then you might consider using its built-in arithmetic expansion syntax e.g.(( INPUT % 5 == 0 ))– steeldriver
Apr 2 at 18:45
the loop does not end when entering 25 @steeldriver
– Roosevelt Mendieta
Apr 2 at 18:50