Cfxtrjtrk

I have a big list of ordered files with name like this (videos)

S1-E18-(Date)-(Title)-(Random numbers).mp4

Here is the example of list

S1-E1-20100526-title-of-video-1400316375.mp4

S1-E3-20100547-title-of-video-15457547.mp4

S10-E5-20100463-title-of-video-14467457.mp4

In this case its easy to see that the files S1-E2 and S10-E4 are missing.
but if I have a big list then how can I find the missing files.
(Leave Season number S1, S2) just need to check E means episode number

The largest existing file's number is S50-E2184 and
The Smallest existing file's number is S1-E1

Using awk:

$ awk -F- '{n = substr($2, 2)} (n - prev) != 1 {for (i = prev + 1; i < n; i++) print i} {prev = n}' input-file

2

4

• 
  -F - sets the field separator to - (so S1, E1, etc. become different fields).


• Then we extract the episode number (n = substr($2, 2)), by taking everything but the first character from the second field ($2).


• If the episode number is not the previous episode + 1 ( (n - prev) != 1), we print all the numbers in between.


• We save the current episode number in prev for the next iteration.

If the output isn't sorted, split up the extraction and check to insert a sort in between:

awk -F- '{print substr($2, 2)}' input-file | sort -n | awk '{n=$1} (n - prev) != 1 {for (i = prev + 1; i < n; i++) print i} {prev = n}'

A bit more straight forward script.
The script assumes the last episode exists and extracts its episode number. Then it iterates over [1..last] and check the existence of all episodes in between. Note this would not work for episodes numbered with leading zeroes.

#!/bin/bash



if [ -z "$1" ]; then

    echo "please specify season prefix"

fi



# extract last episode number

last=`ls $1-*.* -1 --reverse | head -n 1 | grep --only-matching "E[[:digit:]+]" | cut -c 2-`



for ((i=1; i<=$last; i++)); do

    if [ ! -f $1-E$i-*.* ]; then

        echo "missing episode $i"

    fi

done

The script takes the season prefix as its first argument, i.e. S1