What is the highest possible scrabble score for placing a single tile
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What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard North American rules.
scrabble
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add a comment |
$begingroup$
What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard North American rules.
scrabble
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$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
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– Matt
2 days ago
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Can we assume that the tiles already on the board are exactly as we want them?
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– Hugh
2 days ago
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@doppelgreener Norh should you - it's been fixed now ;-)
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– Rand al'Thor
yesterday
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@Randal'Thor Many hanks!
$endgroup$
– doppelgreener
yesterday
add a comment |
$begingroup$
What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard North American rules.
scrabble
$endgroup$
What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard North American rules.
scrabble
scrabble
edited yesterday
noedne
7,33712059
7,33712059
asked 2 days ago
user3294068user3294068
5,7641629
5,7641629
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
2 days ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
2 days ago
$begingroup$
@doppelgreener Norh should you - it's been fixed now ;-)
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
@Randal'Thor Many hanks!
$endgroup$
– doppelgreener
yesterday
add a comment |
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
2 days ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
2 days ago
$begingroup$
@doppelgreener Norh should you - it's been fixed now ;-)
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
@Randal'Thor Many hanks!
$endgroup$
– doppelgreener
yesterday
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
2 days ago
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
2 days ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
2 days ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
2 days ago
$begingroup$
@doppelgreener Norh should you - it's been fixed now ;-)
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
@doppelgreener Norh should you - it's been fixed now ;-)
$endgroup$
– Rand al'Thor
yesterday
$begingroup$
@Randal'Thor Many hanks!
$endgroup$
– doppelgreener
yesterday
$begingroup$
@Randal'Thor Many hanks!
$endgroup$
– doppelgreener
yesterday
add a comment |
2 Answers
2
active
oldest
votes
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According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:

...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...

...is 303 points.
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6
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
2 days ago
6
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
2 days ago
2
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
yesterday
6
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
yesterday
19
$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
yesterday
|
show 9 more comments
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In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.
A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O
An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.
(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.
$endgroup$
3
$begingroup$
That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
$endgroup$
– James
yesterday
1
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@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
$endgroup$
– supercat
yesterday
$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
yesterday
$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
yesterday
$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
yesterday
|
show 3 more comments
Your Answer
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2 Answers
2
active
oldest
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2 Answers
2
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:

...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...

...is 303 points.
$endgroup$
6
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
2 days ago
6
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
2 days ago
2
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
yesterday
6
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
yesterday
19
$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
yesterday
|
show 9 more comments
$begingroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:

...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...

...is 303 points.
$endgroup$
6
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
2 days ago
6
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
2 days ago
2
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
yesterday
6
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
yesterday
19
$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
yesterday
|
show 9 more comments
$begingroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:

...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...

...is 303 points.
$endgroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:

...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...

...is 303 points.
answered 2 days ago
Deusovi♦Deusovi
62.4k6215268
62.4k6215268
6
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
2 days ago
6
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
2 days ago
2
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
yesterday
6
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
yesterday
19
$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
yesterday
|
show 9 more comments
6
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
2 days ago
6
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
2 days ago
2
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
yesterday
6
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
yesterday
19
$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
yesterday
6
6
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
2 days ago
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
2 days ago
6
6
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
2 days ago
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
2 days ago
2
2
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
yesterday
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
yesterday
6
6
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
yesterday
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
yesterday
19
19
$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
yesterday
$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
yesterday
|
show 9 more comments
$begingroup$
In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.
A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O
An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.
(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.
$endgroup$
3
$begingroup$
That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
$endgroup$
– James
yesterday
1
$begingroup$
@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
$endgroup$
– supercat
yesterday
$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
yesterday
$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
yesterday
$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
yesterday
|
show 3 more comments
$begingroup$
In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.
A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O
An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.
(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.
$endgroup$
3
$begingroup$
That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
$endgroup$
– James
yesterday
1
$begingroup$
@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
$endgroup$
– supercat
yesterday
$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
yesterday
$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
yesterday
$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
yesterday
|
show 3 more comments
$begingroup$
In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.
A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O
An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.
(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.
$endgroup$
In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.
A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O
An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.
(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.
edited yesterday
doppelgreener
298213
298213
answered yesterday
Rosie FRosie F
5,9382944
5,9382944
3
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That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
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– James
yesterday
1
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@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
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– supercat
yesterday
$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
yesterday
$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
yesterday
$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
yesterday
|
show 3 more comments
3
$begingroup$
That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
$endgroup$
– James
yesterday
1
$begingroup$
@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
$endgroup$
– supercat
yesterday
$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
yesterday
$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
yesterday
$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
yesterday
3
3
$begingroup$
That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
$endgroup$
– James
yesterday
$begingroup$
That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
$endgroup$
– James
yesterday
1
1
$begingroup$
@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
$endgroup$
– supercat
yesterday
$begingroup$
@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
$endgroup$
– supercat
yesterday
$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
yesterday
$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
yesterday
$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
yesterday
$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
yesterday
$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
yesterday
$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
yesterday
|
show 3 more comments
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You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
2 days ago
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Can we assume that the tiles already on the board are exactly as we want them?
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– Hugh
2 days ago
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@doppelgreener Norh should you - it's been fixed now ;-)
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– Rand al'Thor
yesterday
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@Randal'Thor Many hanks!
$endgroup$
– doppelgreener
yesterday